Program to replace each string with an integer value in a given list of strings












0















Write a program to replace each string with an integer value in a given list of strings. The replacement integer value should be a sum of Ascci values of each character of the corresponding string.



list_rivers  =["Ganges", "Godavari", "Brahmaputra", "Narmada","Yamuna", "Mahanadi", "Kaveri", "Tapti"]


I tried the following which is correct but I want to optimize the code.



list_rivers  =["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
river = // empty list
for i in list_rivers:
num=0
for j in i:
num = num + ord(j)
river.append(num) // [597, 813, 1143, 692, 619, 787, 610, 514]


Can anyone help how to optimize the above code?

Thanks in advance.










share|improve this question





























    0















    Write a program to replace each string with an integer value in a given list of strings. The replacement integer value should be a sum of Ascci values of each character of the corresponding string.



    list_rivers  =["Ganges", "Godavari", "Brahmaputra", "Narmada","Yamuna", "Mahanadi", "Kaveri", "Tapti"]


    I tried the following which is correct but I want to optimize the code.



    list_rivers  =["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
    river = // empty list
    for i in list_rivers:
    num=0
    for j in i:
    num = num + ord(j)
    river.append(num) // [597, 813, 1143, 692, 619, 787, 610, 514]


    Can anyone help how to optimize the above code?

    Thanks in advance.










    share|improve this question



























      0












      0








      0


      0






      Write a program to replace each string with an integer value in a given list of strings. The replacement integer value should be a sum of Ascci values of each character of the corresponding string.



      list_rivers  =["Ganges", "Godavari", "Brahmaputra", "Narmada","Yamuna", "Mahanadi", "Kaveri", "Tapti"]


      I tried the following which is correct but I want to optimize the code.



      list_rivers  =["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
      river = // empty list
      for i in list_rivers:
      num=0
      for j in i:
      num = num + ord(j)
      river.append(num) // [597, 813, 1143, 692, 619, 787, 610, 514]


      Can anyone help how to optimize the above code?

      Thanks in advance.










      share|improve this question
















      Write a program to replace each string with an integer value in a given list of strings. The replacement integer value should be a sum of Ascci values of each character of the corresponding string.



      list_rivers  =["Ganges", "Godavari", "Brahmaputra", "Narmada","Yamuna", "Mahanadi", "Kaveri", "Tapti"]


      I tried the following which is correct but I want to optimize the code.



      list_rivers  =["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
      river = // empty list
      for i in list_rivers:
      num=0
      for j in i:
      num = num + ord(j)
      river.append(num) // [597, 813, 1143, 692, 619, 787, 610, 514]


      Can anyone help how to optimize the above code?

      Thanks in advance.







      python python-3.x python-2.7






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 20 '18 at 17:39









      Brian Minton

      2,07212232




      2,07212232










      asked Nov 20 '18 at 17:23









      user_not_defineuser_not_define

      186




      186
























          3 Answers
          3






          active

          oldest

          votes


















          1














          You can use list compréhension :



          [sum([ord(i) for i in word]) for word in list_rivers]


          it's equivalent to do



          tmp_1 = 
          for word in list_rivers:
          tmp_2 =
          for i in word:
          tmp_2.append(ord(i))
          tmp_1.append(sum(tmp_2))





          share|improve this answer































            0














            As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.



            Your method:



            %%timeit
            river =
            for i in list_rivers:
            num=0
            for j in i:
            num = num + ord(j)
            river.append(num)

            # 100000 loops, best of 3: 6.57 µs per loop


            List comprehension:



            %%timeit
            result = [sum([ord(i) for i in word]) for word in list_rivers]

            # 100000 loops, best of 3: 9.37 µs per loop


            (Even slower) using map:



            %%timeit
            result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)

            # 100000 loops, best of 3: 10.3 µs per loop





            share|improve this answer

































              0














              It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]



              def string_to_int(string):
              retval = 0
              for c in string:
              retval += ord(c)
              return retval


              def main(data):
              retval =
              for item in data:
              retval.append(string_to_int(item))
              return retval


              if __name__ == "__main__":
              list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
              results = main(list_rivers)
              print results





              share|improve this answer























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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                1














                You can use list compréhension :



                [sum([ord(i) for i in word]) for word in list_rivers]


                it's equivalent to do



                tmp_1 = 
                for word in list_rivers:
                tmp_2 =
                for i in word:
                tmp_2.append(ord(i))
                tmp_1.append(sum(tmp_2))





                share|improve this answer




























                  1














                  You can use list compréhension :



                  [sum([ord(i) for i in word]) for word in list_rivers]


                  it's equivalent to do



                  tmp_1 = 
                  for word in list_rivers:
                  tmp_2 =
                  for i in word:
                  tmp_2.append(ord(i))
                  tmp_1.append(sum(tmp_2))





                  share|improve this answer


























                    1












                    1








                    1







                    You can use list compréhension :



                    [sum([ord(i) for i in word]) for word in list_rivers]


                    it's equivalent to do



                    tmp_1 = 
                    for word in list_rivers:
                    tmp_2 =
                    for i in word:
                    tmp_2.append(ord(i))
                    tmp_1.append(sum(tmp_2))





                    share|improve this answer













                    You can use list compréhension :



                    [sum([ord(i) for i in word]) for word in list_rivers]


                    it's equivalent to do



                    tmp_1 = 
                    for word in list_rivers:
                    tmp_2 =
                    for i in word:
                    tmp_2.append(ord(i))
                    tmp_1.append(sum(tmp_2))






                    share|improve this answer












                    share|improve this answer



                    share|improve this answer










                    answered Nov 20 '18 at 17:30









                    iEldeniElden

                    692517




                    692517

























                        0














                        As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.



                        Your method:



                        %%timeit
                        river =
                        for i in list_rivers:
                        num=0
                        for j in i:
                        num = num + ord(j)
                        river.append(num)

                        # 100000 loops, best of 3: 6.57 µs per loop


                        List comprehension:



                        %%timeit
                        result = [sum([ord(i) for i in word]) for word in list_rivers]

                        # 100000 loops, best of 3: 9.37 µs per loop


                        (Even slower) using map:



                        %%timeit
                        result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)

                        # 100000 loops, best of 3: 10.3 µs per loop





                        share|improve this answer






























                          0














                          As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.



                          Your method:



                          %%timeit
                          river =
                          for i in list_rivers:
                          num=0
                          for j in i:
                          num = num + ord(j)
                          river.append(num)

                          # 100000 loops, best of 3: 6.57 µs per loop


                          List comprehension:



                          %%timeit
                          result = [sum([ord(i) for i in word]) for word in list_rivers]

                          # 100000 loops, best of 3: 9.37 µs per loop


                          (Even slower) using map:



                          %%timeit
                          result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)

                          # 100000 loops, best of 3: 10.3 µs per loop





                          share|improve this answer




























                            0












                            0








                            0







                            As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.



                            Your method:



                            %%timeit
                            river =
                            for i in list_rivers:
                            num=0
                            for j in i:
                            num = num + ord(j)
                            river.append(num)

                            # 100000 loops, best of 3: 6.57 µs per loop


                            List comprehension:



                            %%timeit
                            result = [sum([ord(i) for i in word]) for word in list_rivers]

                            # 100000 loops, best of 3: 9.37 µs per loop


                            (Even slower) using map:



                            %%timeit
                            result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)

                            # 100000 loops, best of 3: 10.3 µs per loop





                            share|improve this answer















                            As iElden mentions, you may use list comprehension here. Note that in this case, doing so does not necessarily optimize your code for efficiency.



                            Your method:



                            %%timeit
                            river =
                            for i in list_rivers:
                            num=0
                            for j in i:
                            num = num + ord(j)
                            river.append(num)

                            # 100000 loops, best of 3: 6.57 µs per loop


                            List comprehension:



                            %%timeit
                            result = [sum([ord(i) for i in word]) for word in list_rivers]

                            # 100000 loops, best of 3: 9.37 µs per loop


                            (Even slower) using map:



                            %%timeit
                            result = map(lambda x: sum([ord(letter) for letter in x]), list_rivers)

                            # 100000 loops, best of 3: 10.3 µs per loop






                            share|improve this answer














                            share|improve this answer



                            share|improve this answer








                            edited Nov 20 '18 at 17:42

























                            answered Nov 20 '18 at 17:36









                            Wes DoyleWes Doyle

                            1,0792719




                            1,0792719























                                0














                                It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]



                                def string_to_int(string):
                                retval = 0
                                for c in string:
                                retval += ord(c)
                                return retval


                                def main(data):
                                retval =
                                for item in data:
                                retval.append(string_to_int(item))
                                return retval


                                if __name__ == "__main__":
                                list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
                                results = main(list_rivers)
                                print results





                                share|improve this answer




























                                  0














                                  It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]



                                  def string_to_int(string):
                                  retval = 0
                                  for c in string:
                                  retval += ord(c)
                                  return retval


                                  def main(data):
                                  retval =
                                  for item in data:
                                  retval.append(string_to_int(item))
                                  return retval


                                  if __name__ == "__main__":
                                  list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
                                  results = main(list_rivers)
                                  print results





                                  share|improve this answer


























                                    0












                                    0








                                    0







                                    It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]



                                    def string_to_int(string):
                                    retval = 0
                                    for c in string:
                                    retval += ord(c)
                                    return retval


                                    def main(data):
                                    retval =
                                    for item in data:
                                    retval.append(string_to_int(item))
                                    return retval


                                    if __name__ == "__main__":
                                    list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
                                    results = main(list_rivers)
                                    print results





                                    share|improve this answer













                                    It says write a program to do it, so here's a program to do so. Example output: [597, 813, 1143, 692, 619, 787, 610, 514]



                                    def string_to_int(string):
                                    retval = 0
                                    for c in string:
                                    retval += ord(c)
                                    return retval


                                    def main(data):
                                    retval =
                                    for item in data:
                                    retval.append(string_to_int(item))
                                    return retval


                                    if __name__ == "__main__":
                                    list_rivers = ["Ganges", "Godavari", "Brahmaputra", "Narmada", "Yamuna", "Mahanadi", "Kaveri", "Tapti"]
                                    results = main(list_rivers)
                                    print results






                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered Nov 20 '18 at 20:04









                                    13aal13aal

                                    8921136




                                    8921136






























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