Querying by attribute or related attribute with SQLAlchemy











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My abstraction is: Book has only one User (as author), and a many to many relationship with User (as collaborators):



class UserBook(Base):
__tablename__ = 'user_book'
user_id = Column(String(512), ForeignKey('user.id'), primary_key=True)
book_id = Column(String(512), ForeignKey('book.id'), primary_key=True)
collaboration_type = Column(Integer, default=1)
book = relationship('Book', back_populates='users')
user = relationship('User', back_populates='books')


class User(Base):
__tablename__ = 'user'

id = Column(String(512), primary_key=True)
books = relationship('UserBook', back_populates='user')


class Book(Base):
__tablename__ = 'book'

id = Column(String(512), primary_key=True)
author = Column(String(512), ForeignKey('user.id'), nullable=False)
collaborators = relationship('UserBook', back_populates='book')
name = Column(String(512))
description = Column(String(512), default='')


I'm looking to select all books where I'm an author or I'm a collaborator using SQLAlchemy declarative queries if possible.



I was able to make the join with collaborator, but I'm not sure how to or with the author filter.










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    up vote
    1
    down vote

    favorite












    My abstraction is: Book has only one User (as author), and a many to many relationship with User (as collaborators):



    class UserBook(Base):
    __tablename__ = 'user_book'
    user_id = Column(String(512), ForeignKey('user.id'), primary_key=True)
    book_id = Column(String(512), ForeignKey('book.id'), primary_key=True)
    collaboration_type = Column(Integer, default=1)
    book = relationship('Book', back_populates='users')
    user = relationship('User', back_populates='books')


    class User(Base):
    __tablename__ = 'user'

    id = Column(String(512), primary_key=True)
    books = relationship('UserBook', back_populates='user')


    class Book(Base):
    __tablename__ = 'book'

    id = Column(String(512), primary_key=True)
    author = Column(String(512), ForeignKey('user.id'), nullable=False)
    collaborators = relationship('UserBook', back_populates='book')
    name = Column(String(512))
    description = Column(String(512), default='')


    I'm looking to select all books where I'm an author or I'm a collaborator using SQLAlchemy declarative queries if possible.



    I was able to make the join with collaborator, but I'm not sure how to or with the author filter.










    share|improve this question


























      up vote
      1
      down vote

      favorite









      up vote
      1
      down vote

      favorite











      My abstraction is: Book has only one User (as author), and a many to many relationship with User (as collaborators):



      class UserBook(Base):
      __tablename__ = 'user_book'
      user_id = Column(String(512), ForeignKey('user.id'), primary_key=True)
      book_id = Column(String(512), ForeignKey('book.id'), primary_key=True)
      collaboration_type = Column(Integer, default=1)
      book = relationship('Book', back_populates='users')
      user = relationship('User', back_populates='books')


      class User(Base):
      __tablename__ = 'user'

      id = Column(String(512), primary_key=True)
      books = relationship('UserBook', back_populates='user')


      class Book(Base):
      __tablename__ = 'book'

      id = Column(String(512), primary_key=True)
      author = Column(String(512), ForeignKey('user.id'), nullable=False)
      collaborators = relationship('UserBook', back_populates='book')
      name = Column(String(512))
      description = Column(String(512), default='')


      I'm looking to select all books where I'm an author or I'm a collaborator using SQLAlchemy declarative queries if possible.



      I was able to make the join with collaborator, but I'm not sure how to or with the author filter.










      share|improve this question















      My abstraction is: Book has only one User (as author), and a many to many relationship with User (as collaborators):



      class UserBook(Base):
      __tablename__ = 'user_book'
      user_id = Column(String(512), ForeignKey('user.id'), primary_key=True)
      book_id = Column(String(512), ForeignKey('book.id'), primary_key=True)
      collaboration_type = Column(Integer, default=1)
      book = relationship('Book', back_populates='users')
      user = relationship('User', back_populates='books')


      class User(Base):
      __tablename__ = 'user'

      id = Column(String(512), primary_key=True)
      books = relationship('UserBook', back_populates='user')


      class Book(Base):
      __tablename__ = 'book'

      id = Column(String(512), primary_key=True)
      author = Column(String(512), ForeignKey('user.id'), nullable=False)
      collaborators = relationship('UserBook', back_populates='book')
      name = Column(String(512))
      description = Column(String(512), default='')


      I'm looking to select all books where I'm an author or I'm a collaborator using SQLAlchemy declarative queries if possible.



      I was able to make the join with collaborator, but I'm not sure how to or with the author filter.







      python sqlalchemy






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      edited Nov 9 at 18:52









      benvc

      3,2821319




      3,2821319










      asked Nov 9 at 18:15









      martincho

      2,24952334




      2,24952334
























          1 Answer
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          up vote
          2
          down vote













          You can use the or_ operator with your filter to get all the books where the current user is an author or a collaborator. For example:



          from sqlalchemy import or_


          curr_id = 'current_user_id'

          session.query(Book).
          outerjoin(UserBook).
          filter(or_(Book.author == curr_id, UserBook.user_id == curr_id)).
          all()





          share|improve this answer





















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            up vote
            2
            down vote













            You can use the or_ operator with your filter to get all the books where the current user is an author or a collaborator. For example:



            from sqlalchemy import or_


            curr_id = 'current_user_id'

            session.query(Book).
            outerjoin(UserBook).
            filter(or_(Book.author == curr_id, UserBook.user_id == curr_id)).
            all()





            share|improve this answer

























              up vote
              2
              down vote













              You can use the or_ operator with your filter to get all the books where the current user is an author or a collaborator. For example:



              from sqlalchemy import or_


              curr_id = 'current_user_id'

              session.query(Book).
              outerjoin(UserBook).
              filter(or_(Book.author == curr_id, UserBook.user_id == curr_id)).
              all()





              share|improve this answer























                up vote
                2
                down vote










                up vote
                2
                down vote









                You can use the or_ operator with your filter to get all the books where the current user is an author or a collaborator. For example:



                from sqlalchemy import or_


                curr_id = 'current_user_id'

                session.query(Book).
                outerjoin(UserBook).
                filter(or_(Book.author == curr_id, UserBook.user_id == curr_id)).
                all()





                share|improve this answer












                You can use the or_ operator with your filter to get all the books where the current user is an author or a collaborator. For example:



                from sqlalchemy import or_


                curr_id = 'current_user_id'

                session.query(Book).
                outerjoin(UserBook).
                filter(or_(Book.author == curr_id, UserBook.user_id == curr_id)).
                all()






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered Nov 9 at 18:46









                benvc

                3,2821319




                3,2821319






























                     

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