Bspline boundary type for parametric curve
I want to impose conditions on the derivative at the boundaries for a parametric Bspline.
r=[1.08,1.08, 0.987, 0.82, 0.734, 0.692, 0.40]
phi=np.linspace(0,np.pi/2,len(r))
x, y = r*np.cos(phi), r*np.sin(phi)
l, r = [(1, 0)], [(1, 0)]
spl = make_interp_spline(phi, np.c_[x, y], bc_type=(l,r))
I got a ValueError: "cannot reshape array of size 1 into shape (2)" related to rhs[:nleft] = deriv_l_vals.reshape(-1, extradim)
I suspect I imposed the BCs in a wrong way. But when reading the documentation, I only see this way to impose BCs (for a spline in cartesian coordinates).
No explicit mention of how to do this in a parametric curve.
Anyone knows how to sort it out? I would avoid to re-write all in a non-parametric form....
python numpy bspline
edited Nov 19 '18 at 16:22
glibdud
5,63921731
asked Nov 19 '18 at 15:32
LaoZeLaoZe
113
add a comment |
I want to impose conditions on the derivative at the boundaries for a parametric Bspline.
r=[1.08,1.08, 0.987, 0.82, 0.734, 0.692, 0.40]
phi=np.linspace(0,np.pi/2,len(r))
x, y = r*np.cos(phi), r*np.sin(phi)
l, r = [(1, 0)], [(1, 0)]
spl = make_interp_spline(phi, np.c_[x, y], bc_type=(l,r))
I got a ValueError: "cannot reshape array of size 1 into shape (2)" related to rhs[:nleft] = deriv_l_vals.reshape(-1, extradim)
I suspect I imposed the BCs in a wrong way. But when reading the documentation, I only see this way to impose BCs (for a spline in cartesian coordinates).
No explicit mention of how to do this in a parametric curve.
Anyone knows how to sort it out? I would avoid to re-write all in a non-parametric form....
python numpy bspline
edited Nov 19 '18 at 16:22
glibdud
5,63921731
asked Nov 19 '18 at 15:32
LaoZeLaoZe
113
add a comment |
I want to impose conditions on the derivative at the boundaries for a parametric Bspline.
r=[1.08,1.08, 0.987, 0.82, 0.734, 0.692, 0.40]
phi=np.linspace(0,np.pi/2,len(r))
x, y = r*np.cos(phi), r*np.sin(phi)
l, r = [(1, 0)], [(1, 0)]
spl = make_interp_spline(phi, np.c_[x, y], bc_type=(l,r))
I got a ValueError: "cannot reshape array of size 1 into shape (2)" related to rhs[:nleft] = deriv_l_vals.reshape(-1, extradim)
I suspect I imposed the BCs in a wrong way. But when reading the documentation, I only see this way to impose BCs (for a spline in cartesian coordinates).
No explicit mention of how to do this in a parametric curve.
Anyone knows how to sort it out? I would avoid to re-write all in a non-parametric form....
python numpy bspline
edited Nov 19 '18 at 16:22
glibdud
5,63921731
asked Nov 19 '18 at 15:32
LaoZeLaoZe
113
I want to impose conditions on the derivative at the boundaries for a parametric Bspline.
r=[1.08,1.08, 0.987, 0.82, 0.734, 0.692, 0.40]
phi=np.linspace(0,np.pi/2,len(r))
x, y = r*np.cos(phi), r*np.sin(phi)
l, r = [(1, 0)], [(1, 0)]
spl = make_interp_spline(phi, np.c_[x, y], bc_type=(l,r))
I got a ValueError: "cannot reshape array of size 1 into shape (2)" related to rhs[:nleft] = deriv_l_vals.reshape(-1, extradim)
I suspect I imposed the BCs in a wrong way. But when reading the documentation, I only see this way to impose BCs (for a spline in cartesian coordinates).
No explicit mention of how to do this in a parametric curve.
Anyone knows how to sort it out? I would avoid to re-write all in a non-parametric form....
python numpy bspline
python numpy bspline
edited Nov 19 '18 at 16:22
glibdud
5,63921731
asked Nov 19 '18 at 15:32
LaoZeLaoZe
113
edited Nov 19 '18 at 16:22
glibdud
5,63921731
asked Nov 19 '18 at 15:32
LaoZeLaoZe
113
edited Nov 19 '18 at 16:22
glibdud
5,63921731
edited Nov 19 '18 at 16:22
glibdud
5,63921731
edited Nov 19 '18 at 16:22
glibdud
5,63921731
5,63921731
asked Nov 19 '18 at 15:32
LaoZeLaoZe
113
asked Nov 19 '18 at 15:32
LaoZeLaoZe
113
asked Nov 19 '18 at 15:32
LaoZeLaoZe
113
113
add a comment |
add a comment |
1 Answer
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Self-answer: as suspected, BCs imposed in the wrong way: obviously, two components needed...
e.g.
l, r = [(1, (0,-1))], [(1, (1,0))]
answered Nov 20 '18 at 7:53
LaoZeLaoZe
113
add a comment |
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1 Answer
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active
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Self-answer: as suspected, BCs imposed in the wrong way: obviously, two components needed...
e.g.
l, r = [(1, (0,-1))], [(1, (1,0))]
answered Nov 20 '18 at 7:53
LaoZeLaoZe
113
add a comment |
Self-answer: as suspected, BCs imposed in the wrong way: obviously, two components needed...
e.g.
l, r = [(1, (0,-1))], [(1, (1,0))]
answered Nov 20 '18 at 7:53
LaoZeLaoZe
113
add a comment |
Self-answer: as suspected, BCs imposed in the wrong way: obviously, two components needed...
e.g.
l, r = [(1, (0,-1))], [(1, (1,0))]
answered Nov 20 '18 at 7:53
LaoZeLaoZe
113
Self-answer: as suspected, BCs imposed in the wrong way: obviously, two components needed...
e.g.
l, r = [(1, (0,-1))], [(1, (1,0))]
answered Nov 20 '18 at 7:53
LaoZeLaoZe
113
answered Nov 20 '18 at 7:53
LaoZeLaoZe
113
answered Nov 20 '18 at 7:53
LaoZeLaoZe
113
answered Nov 20 '18 at 7:53
LaoZeLaoZe
113
113
add a comment |
add a comment |
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