Create a matrix out of a dataframe
0
I am very new to R and script writing in general. Please be patient if this is a very basic question. My search for a solution has not been successful.
date.depature <- c("2016.06.16", "2016.11.16", "2017.01.05", "2017.01.12", "2017.02.25")
airport.departure <- c("CDG", "QNY", "QXO", "CDG", "QNY")
airport.arrival <- c("SYD", "CDG", "QNY", "SYD", "QXO")
amount <- c("1", "3", "1", "10", "5")
df <- data.frame(date.depature, airport.departure, airport.arrival, amount)
I want to change the df to a matrix which has the airport.departure as rows and the airport.arrival as columns with the cumulated amount for a given month/years in the cells of the matrix.
r dataframe matrix
asked Nov 19 '18 at 15:44
ConfusulumConfusulum
225
add a comment |
0
I am very new to R and script writing in general. Please be patient if this is a very basic question. My search for a solution has not been successful.
date.depature <- c("2016.06.16", "2016.11.16", "2017.01.05", "2017.01.12", "2017.02.25")
airport.departure <- c("CDG", "QNY", "QXO", "CDG", "QNY")
airport.arrival <- c("SYD", "CDG", "QNY", "SYD", "QXO")
amount <- c("1", "3", "1", "10", "5")
df <- data.frame(date.depature, airport.departure, airport.arrival, amount)
I want to change the df to a matrix which has the airport.departure as rows and the airport.arrival as columns with the cumulated amount for a given month/years in the cells of the matrix.
r dataframe matrix
asked Nov 19 '18 at 15:44
ConfusulumConfusulum
225
1
Your title is bad for my OCD :)
– Sotos
Nov 19 '18 at 15:50
Sorry. I did not notice it. Now it gives me slight pain too...
– Confusulum
Nov 19 '18 at 15:56
hehehe, you don't expect it to be such a big deal until you 'see' it
– Sotos
Nov 19 '18 at 15:57
Good thing it´s possible here to change the title. It would be mean to trigger OCDs all over the world. ;)
– Confusulum
Nov 19 '18 at 16:16
add a comment |
0
0
0
I am very new to R and script writing in general. Please be patient if this is a very basic question. My search for a solution has not been successful.
date.depature <- c("2016.06.16", "2016.11.16", "2017.01.05", "2017.01.12", "2017.02.25")
airport.departure <- c("CDG", "QNY", "QXO", "CDG", "QNY")
airport.arrival <- c("SYD", "CDG", "QNY", "SYD", "QXO")
amount <- c("1", "3", "1", "10", "5")
df <- data.frame(date.depature, airport.departure, airport.arrival, amount)
I want to change the df to a matrix which has the airport.departure as rows and the airport.arrival as columns with the cumulated amount for a given month/years in the cells of the matrix.
r dataframe matrix
asked Nov 19 '18 at 15:44
ConfusulumConfusulum
225
I am very new to R and script writing in general. Please be patient if this is a very basic question. My search for a solution has not been successful.
date.depature <- c("2016.06.16", "2016.11.16", "2017.01.05", "2017.01.12", "2017.02.25")
airport.departure <- c("CDG", "QNY", "QXO", "CDG", "QNY")
airport.arrival <- c("SYD", "CDG", "QNY", "SYD", "QXO")
amount <- c("1", "3", "1", "10", "5")
df <- data.frame(date.depature, airport.departure, airport.arrival, amount)
I want to change the df to a matrix which has the airport.departure as rows and the airport.arrival as columns with the cumulated amount for a given month/years in the cells of the matrix.
r dataframe matrix
r dataframe matrix
asked Nov 19 '18 at 15:44
ConfusulumConfusulum
225
asked Nov 19 '18 at 15:44
ConfusulumConfusulum
225
edited Nov 19 '18 at 16:07
Confusulum
asked Nov 19 '18 at 15:44
ConfusulumConfusulum
225
asked Nov 19 '18 at 15:44
ConfusulumConfusulum
225
asked Nov 19 '18 at 15:44
ConfusulumConfusulum
225
225
1
Your title is bad for my OCD :)
– Sotos
Nov 19 '18 at 15:50
Sorry. I did not notice it. Now it gives me slight pain too...
– Confusulum
Nov 19 '18 at 15:56
hehehe, you don't expect it to be such a big deal until you 'see' it
– Sotos
Nov 19 '18 at 15:57
Good thing it´s possible here to change the title. It would be mean to trigger OCDs all over the world. ;)
– Confusulum
Nov 19 '18 at 16:16
add a comment |
1
Your title is bad for my OCD :)
– Sotos
Nov 19 '18 at 15:50
Sorry. I did not notice it. Now it gives me slight pain too...
– Confusulum
Nov 19 '18 at 15:56
hehehe, you don't expect it to be such a big deal until you 'see' it
– Sotos
Nov 19 '18 at 15:57
Good thing it´s possible here to change the title. It would be mean to trigger OCDs all over the world. ;)
– Confusulum
Nov 19 '18 at 16:16
1
1
Your title is bad for my OCD :)
– Sotos
Nov 19 '18 at 15:50
Your title is bad for my OCD :)
– Sotos
Nov 19 '18 at 15:50
Sorry. I did not notice it. Now it gives me slight pain too...
– Confusulum
Nov 19 '18 at 15:56
Sorry. I did not notice it. Now it gives me slight pain too...
– Confusulum
Nov 19 '18 at 15:56
hehehe, you don't expect it to be such a big deal until you 'see' it
– Sotos
Nov 19 '18 at 15:57
hehehe, you don't expect it to be such a big deal until you 'see' it
– Sotos
Nov 19 '18 at 15:57
Good thing it´s possible here to change the title. It would be mean to trigger OCDs all over the world. ;)
– Confusulum
Nov 19 '18 at 16:16
Good thing it´s possible here to change the title. It would be mean to trigger OCDs all over the world. ;)
– Confusulum
Nov 19 '18 at 16:16
add a comment |
2 Answers
2
active
oldest
votes
3
You are looking for xtabs, i.e.
xtabs(amount ~ airport.arrival + airport.departure, df)
which gives,
airport.departure
airport.arrival CDG QNY QXO
CDG 0 3 0
QNY 0 0 1
QXO 0 5 0
SYD 11 0 0
P.S
As @Andre Elrico mentions, for some reason you declared your amount variable as a string. You need to convert to integer prior to calculating the sums
Proposed Solution:
xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
answered Nov 19 '18 at 15:49
SotosSotos
29.6k51640
2
since amount is string:xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
– Andre Elrico
Nov 19 '18 at 15:51
if you further want to work on this: consider usingas.data.frame.matrix(xtabs( ... ))
– Andre Elrico
Nov 19 '18 at 16:02
The "for some reason" is that I barely what I am doing. So it just happend without thinking. I changed it in the real dataframe. I will look into it. Thank you for the advice & help from both of you.
– Confusulum
Nov 19 '18 at 16:19
add a comment |
0
using dplyr package:
library(dplyr)
df %>% mutate(month.departure =substr(date.depature, 1, 7)) %>%
group_by(airport.departure, airport.arrival, month.departure) %>%
summarize(total = sum(as.numeric(as.character(amount))))
- mutate adds a column that gives the month/year (without the date, because you asked to group by month)
- group_by says you want to see statistics grouped according to these variables
- summarize computes the statistic you're looking for, in this case the total amount per 'group.' The
as.numeric(as.character())is included because 'amount' started as a factor type, which can't be summed [theas.character()is needed because as.numeric would have unexpected behavior if called directly on the factor].total =gives an arbitrary column name to include in the output table; you could leave it out and this will still work. - the %>% is used to pipe output from one command as input to the next command in dplyr
Output:
(format of output table is different than you described, but it contains all the info you're looking for. and dplyr is a great package to start learning for this sort of data manipulation!)
answered Nov 19 '18 at 15:53
R-PeysR-Peys
435
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
You are looking for xtabs, i.e.
xtabs(amount ~ airport.arrival + airport.departure, df)
which gives,
airport.departure
airport.arrival CDG QNY QXO
CDG 0 3 0
QNY 0 0 1
QXO 0 5 0
SYD 11 0 0
P.S
As @Andre Elrico mentions, for some reason you declared your amount variable as a string. You need to convert to integer prior to calculating the sums
Proposed Solution:
xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
answered Nov 19 '18 at 15:49
SotosSotos
29.6k51640
2
since amount is string:xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
– Andre Elrico
Nov 19 '18 at 15:51
if you further want to work on this: consider usingas.data.frame.matrix(xtabs( ... ))
– Andre Elrico
Nov 19 '18 at 16:02
The "for some reason" is that I barely what I am doing. So it just happend without thinking. I changed it in the real dataframe. I will look into it. Thank you for the advice & help from both of you.
– Confusulum
Nov 19 '18 at 16:19
add a comment |
3
You are looking for xtabs, i.e.
xtabs(amount ~ airport.arrival + airport.departure, df)
which gives,
airport.departure
airport.arrival CDG QNY QXO
CDG 0 3 0
QNY 0 0 1
QXO 0 5 0
SYD 11 0 0
P.S
As @Andre Elrico mentions, for some reason you declared your amount variable as a string. You need to convert to integer prior to calculating the sums
Proposed Solution:
xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
answered Nov 19 '18 at 15:49
SotosSotos
29.6k51640
2
since amount is string:xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
– Andre Elrico
Nov 19 '18 at 15:51
if you further want to work on this: consider usingas.data.frame.matrix(xtabs( ... ))
– Andre Elrico
Nov 19 '18 at 16:02
The "for some reason" is that I barely what I am doing. So it just happend without thinking. I changed it in the real dataframe. I will look into it. Thank you for the advice & help from both of you.
– Confusulum
Nov 19 '18 at 16:19
add a comment |
3
3
3
You are looking for xtabs, i.e.
xtabs(amount ~ airport.arrival + airport.departure, df)
which gives,
airport.departure
airport.arrival CDG QNY QXO
CDG 0 3 0
QNY 0 0 1
QXO 0 5 0
SYD 11 0 0
P.S
As @Andre Elrico mentions, for some reason you declared your amount variable as a string. You need to convert to integer prior to calculating the sums
Proposed Solution:
xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
answered Nov 19 '18 at 15:49
SotosSotos
29.6k51640
You are looking for xtabs, i.e.
xtabs(amount ~ airport.arrival + airport.departure, df)
which gives,
airport.departure
airport.arrival CDG QNY QXO
CDG 0 3 0
QNY 0 0 1
QXO 0 5 0
SYD 11 0 0
P.S
As @Andre Elrico mentions, for some reason you declared your amount variable as a string. You need to convert to integer prior to calculating the sums
Proposed Solution:
xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
answered Nov 19 '18 at 15:49
SotosSotos
29.6k51640
edited Nov 19 '18 at 15:55
answered Nov 19 '18 at 15:49
SotosSotos
29.6k51640
answered Nov 19 '18 at 15:49
SotosSotos
29.6k51640
answered Nov 19 '18 at 15:49
SotosSotos
29.6k51640
29.6k51640
2
since amount is string:xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
– Andre Elrico
Nov 19 '18 at 15:51
if you further want to work on this: consider usingas.data.frame.matrix(xtabs( ... ))
– Andre Elrico
Nov 19 '18 at 16:02
The "for some reason" is that I barely what I am doing. So it just happend without thinking. I changed it in the real dataframe. I will look into it. Thank you for the advice & help from both of you.
– Confusulum
Nov 19 '18 at 16:19
add a comment |
2
since amount is string:xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)
– Andre Elrico
Nov 19 '18 at 15:51
if you further want to work on this: consider usingas.data.frame.matrix(xtabs( ... ))
– Andre Elrico
Nov 19 '18 at 16:02
The "for some reason" is that I barely what I am doing. So it just happend without thinking. I changed it in the real dataframe. I will look into it. Thank you for the advice & help from both of you.
– Confusulum
Nov 19 '18 at 16:19
2
2
since amount is string:
xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)– Andre Elrico
Nov 19 '18 at 15:51
since amount is string:
xtabs(as.integer(amount) ~ airport.arrival + airport.departure, df)– Andre Elrico
Nov 19 '18 at 15:51
if you further want to work on this: consider using
as.data.frame.matrix(xtabs( ... ))– Andre Elrico
Nov 19 '18 at 16:02
if you further want to work on this: consider using
as.data.frame.matrix(xtabs( ... ))– Andre Elrico
Nov 19 '18 at 16:02
The "for some reason" is that I barely what I am doing. So it just happend without thinking. I changed it in the real dataframe. I will look into it. Thank you for the advice & help from both of you.
– Confusulum
Nov 19 '18 at 16:19
The "for some reason" is that I barely what I am doing. So it just happend without thinking. I changed it in the real dataframe. I will look into it. Thank you for the advice & help from both of you.
– Confusulum
Nov 19 '18 at 16:19
add a comment |
0
using dplyr package:
library(dplyr)
df %>% mutate(month.departure =substr(date.depature, 1, 7)) %>%
group_by(airport.departure, airport.arrival, month.departure) %>%
summarize(total = sum(as.numeric(as.character(amount))))
- mutate adds a column that gives the month/year (without the date, because you asked to group by month)
- group_by says you want to see statistics grouped according to these variables
- summarize computes the statistic you're looking for, in this case the total amount per 'group.' The
as.numeric(as.character())is included because 'amount' started as a factor type, which can't be summed [theas.character()is needed because as.numeric would have unexpected behavior if called directly on the factor].total =gives an arbitrary column name to include in the output table; you could leave it out and this will still work. - the %>% is used to pipe output from one command as input to the next command in dplyr
Output:
(format of output table is different than you described, but it contains all the info you're looking for. and dplyr is a great package to start learning for this sort of data manipulation!)
answered Nov 19 '18 at 15:53
R-PeysR-Peys
435
add a comment |
0
using dplyr package:
library(dplyr)
df %>% mutate(month.departure =substr(date.depature, 1, 7)) %>%
group_by(airport.departure, airport.arrival, month.departure) %>%
summarize(total = sum(as.numeric(as.character(amount))))
- mutate adds a column that gives the month/year (without the date, because you asked to group by month)
- group_by says you want to see statistics grouped according to these variables
- summarize computes the statistic you're looking for, in this case the total amount per 'group.' The
as.numeric(as.character())is included because 'amount' started as a factor type, which can't be summed [theas.character()is needed because as.numeric would have unexpected behavior if called directly on the factor].total =gives an arbitrary column name to include in the output table; you could leave it out and this will still work. - the %>% is used to pipe output from one command as input to the next command in dplyr
Output:
(format of output table is different than you described, but it contains all the info you're looking for. and dplyr is a great package to start learning for this sort of data manipulation!)
answered Nov 19 '18 at 15:53
R-PeysR-Peys
435
add a comment |
0
0
0
using dplyr package:
library(dplyr)
df %>% mutate(month.departure =substr(date.depature, 1, 7)) %>%
group_by(airport.departure, airport.arrival, month.departure) %>%
summarize(total = sum(as.numeric(as.character(amount))))
- mutate adds a column that gives the month/year (without the date, because you asked to group by month)
- group_by says you want to see statistics grouped according to these variables
- summarize computes the statistic you're looking for, in this case the total amount per 'group.' The
as.numeric(as.character())is included because 'amount' started as a factor type, which can't be summed [theas.character()is needed because as.numeric would have unexpected behavior if called directly on the factor].total =gives an arbitrary column name to include in the output table; you could leave it out and this will still work. - the %>% is used to pipe output from one command as input to the next command in dplyr
Output:
(format of output table is different than you described, but it contains all the info you're looking for. and dplyr is a great package to start learning for this sort of data manipulation!)
answered Nov 19 '18 at 15:53
R-PeysR-Peys
435
using dplyr package:
library(dplyr)
df %>% mutate(month.departure =substr(date.depature, 1, 7)) %>%
group_by(airport.departure, airport.arrival, month.departure) %>%
summarize(total = sum(as.numeric(as.character(amount))))
- mutate adds a column that gives the month/year (without the date, because you asked to group by month)
- group_by says you want to see statistics grouped according to these variables
- summarize computes the statistic you're looking for, in this case the total amount per 'group.' The
as.numeric(as.character())is included because 'amount' started as a factor type, which can't be summed [theas.character()is needed because as.numeric would have unexpected behavior if called directly on the factor].total =gives an arbitrary column name to include in the output table; you could leave it out and this will still work. - the %>% is used to pipe output from one command as input to the next command in dplyr
Output:
(format of output table is different than you described, but it contains all the info you're looking for. and dplyr is a great package to start learning for this sort of data manipulation!)
answered Nov 19 '18 at 15:53
R-PeysR-Peys
435
edited Nov 20 '18 at 20:19
answered Nov 19 '18 at 15:53
R-PeysR-Peys
435
answered Nov 19 '18 at 15:53
R-PeysR-Peys
435
answered Nov 19 '18 at 15:53
R-PeysR-Peys
435
435
add a comment |
add a comment |
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1
Your title is bad for my OCD :)
– Sotos
Nov 19 '18 at 15:50
Sorry. I did not notice it. Now it gives me slight pain too...
– Confusulum
Nov 19 '18 at 15:56
hehehe, you don't expect it to be such a big deal until you 'see' it
– Sotos
Nov 19 '18 at 15:57
Good thing it´s possible here to change the title. It would be mean to trigger OCDs all over the world. ;)
– Confusulum
Nov 19 '18 at 16:16