How to resolve Invalid Query selector when dynamically generating ID in .net
I am trying to access an element using id.
The catch is as follows:
- I am generating the id using razor Syntax.
- I am then passing the string as parameters to a function.
- In that function I am using document.Query("#id") selector.
My function:
function upload(x , y, z ) {
var selector = """ + "#" + z + x + """;
console.log(selector);
var form = document.querySelector(selector);
var formData = new FormData(form);
...}
The console.log() is correct.
It shows "#a1.3"
which is the id of the dynamically generated HTML element. Just to be sure,I removed special characters from id and gave just characters.
But I still get the same error.
I have no clue why it might be happening.
javascript razor
add a comment |
I am trying to access an element using id.
The catch is as follows:
- I am generating the id using razor Syntax.
- I am then passing the string as parameters to a function.
- In that function I am using document.Query("#id") selector.
My function:
function upload(x , y, z ) {
var selector = """ + "#" + z + x + """;
console.log(selector);
var form = document.querySelector(selector);
var formData = new FormData(form);
...}
The console.log() is correct.
It shows "#a1.3"
which is the id of the dynamically generated HTML element. Just to be sure,I removed special characters from id and gave just characters.
But I still get the same error.
I have no clue why it might be happening.
javascript razor
1
Is the id"#a1.3"
a valid id? maybe you meant to say#a1.3
without the double quotes.var selector = "#" + z + x;
– Ahmad
Nov 20 '18 at 12:39
add a comment |
I am trying to access an element using id.
The catch is as follows:
- I am generating the id using razor Syntax.
- I am then passing the string as parameters to a function.
- In that function I am using document.Query("#id") selector.
My function:
function upload(x , y, z ) {
var selector = """ + "#" + z + x + """;
console.log(selector);
var form = document.querySelector(selector);
var formData = new FormData(form);
...}
The console.log() is correct.
It shows "#a1.3"
which is the id of the dynamically generated HTML element. Just to be sure,I removed special characters from id and gave just characters.
But I still get the same error.
I have no clue why it might be happening.
javascript razor
I am trying to access an element using id.
The catch is as follows:
- I am generating the id using razor Syntax.
- I am then passing the string as parameters to a function.
- In that function I am using document.Query("#id") selector.
My function:
function upload(x , y, z ) {
var selector = """ + "#" + z + x + """;
console.log(selector);
var form = document.querySelector(selector);
var formData = new FormData(form);
...}
The console.log() is correct.
It shows "#a1.3"
which is the id of the dynamically generated HTML element. Just to be sure,I removed special characters from id and gave just characters.
But I still get the same error.
I have no clue why it might be happening.
javascript razor
javascript razor
edited Nov 20 '18 at 14:54
Foo
1
1
asked Nov 20 '18 at 12:37
Abhilash GopalakrishnaAbhilash Gopalakrishna
138115
138115
1
Is the id"#a1.3"
a valid id? maybe you meant to say#a1.3
without the double quotes.var selector = "#" + z + x;
– Ahmad
Nov 20 '18 at 12:39
add a comment |
1
Is the id"#a1.3"
a valid id? maybe you meant to say#a1.3
without the double quotes.var selector = "#" + z + x;
– Ahmad
Nov 20 '18 at 12:39
1
1
Is the id
"#a1.3"
a valid id? maybe you meant to say #a1.3
without the double quotes. var selector = "#" + z + x;
– Ahmad
Nov 20 '18 at 12:39
Is the id
"#a1.3"
a valid id? maybe you meant to say #a1.3
without the double quotes. var selector = "#" + z + x;
– Ahmad
Nov 20 '18 at 12:39
add a comment |
1 Answer
1
active
oldest
votes
You need to escape the period in that selector...
"#a1\.3"
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53393149%2fhow-to-resolve-invalid-query-selector-when-dynamically-generating-id-in-net%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You need to escape the period in that selector...
"#a1\.3"
add a comment |
You need to escape the period in that selector...
"#a1\.3"
add a comment |
You need to escape the period in that selector...
"#a1\.3"
You need to escape the period in that selector...
"#a1\.3"
answered Nov 20 '18 at 12:40
peeebeeepeeebeee
1,08511219
1,08511219
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53393149%2fhow-to-resolve-invalid-query-selector-when-dynamically-generating-id-in-net%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
1
Is the id
"#a1.3"
a valid id? maybe you meant to say#a1.3
without the double quotes.var selector = "#" + z + x;
– Ahmad
Nov 20 '18 at 12:39