C# Argument 1: cannot convert from 'string' to 'char'

-3

I am trying to pull files in a directory where the selected path in the combo box item is selected.

I'm used to vb.net and when doing a split in C# I get error message below:

Argument 1: cannot convert from 'string' to 'char'

I want to get all the files and then for each file add the filename to a listbox.

Anyone can point me in the right direction or let me know what I am doing wrong in split.

Here is the code:

private void cbLogFileLocations_SelectedIndexChanged(object sender, EventArgs e)

{

    string Files = Directory.GetFiles(cbLogFileLocations.SelectedItem.ToString());



    foreach (string file in Files)

    {

        string strSplittedFileName = file.Split(@"");

    }

}

edited Nov 21 '18 at 13:43

Lennart

6,167125266

asked Nov 21 '18 at 13:29

Breau

You can post your code here in your question.

– Matthew Watson
Nov 21 '18 at 13:31

You passed a string to a method that expects Char

– Panagiotis Kanavos
Nov 21 '18 at 13:32

add a comment |

-3

I am trying to pull files in a directory where the selected path in the combo box item is selected.

I'm used to vb.net and when doing a split in C# I get error message below:

Argument 1: cannot convert from 'string' to 'char'

I want to get all the files and then for each file add the filename to a listbox.

Anyone can point me in the right direction or let me know what I am doing wrong in split.

Here is the code:

private void cbLogFileLocations_SelectedIndexChanged(object sender, EventArgs e)

{

    string Files = Directory.GetFiles(cbLogFileLocations.SelectedItem.ToString());



    foreach (string file in Files)

    {

        string strSplittedFileName = file.Split(@"");

    }

}

edited Nov 21 '18 at 13:43

Lennart

6,167125266

asked Nov 21 '18 at 13:29

Breau

You can post your code here in your question.

– Matthew Watson
Nov 21 '18 at 13:31

You passed a string to a method that expects Char

– Panagiotis Kanavos
Nov 21 '18 at 13:32

add a comment |

-3

I am trying to pull files in a directory where the selected path in the combo box item is selected.

I'm used to vb.net and when doing a split in C# I get error message below:

Argument 1: cannot convert from 'string' to 'char'

I want to get all the files and then for each file add the filename to a listbox.

Anyone can point me in the right direction or let me know what I am doing wrong in split.

Here is the code:

private void cbLogFileLocations_SelectedIndexChanged(object sender, EventArgs e)

{

    string Files = Directory.GetFiles(cbLogFileLocations.SelectedItem.ToString());



    foreach (string file in Files)

    {

        string strSplittedFileName = file.Split(@"");

    }

}

edited Nov 21 '18 at 13:43

Lennart

6,167125266

asked Nov 21 '18 at 13:29

Breau

I am trying to pull files in a directory where the selected path in the combo box item is selected.

I'm used to vb.net and when doing a split in C# I get error message below:

Argument 1: cannot convert from 'string' to 'char'

I want to get all the files and then for each file add the filename to a listbox.

Anyone can point me in the right direction or let me know what I am doing wrong in split.

Here is the code:

private void cbLogFileLocations_SelectedIndexChanged(object sender, EventArgs e)

{

    string Files = Directory.GetFiles(cbLogFileLocations.SelectedItem.ToString());



    foreach (string file in Files)

    {

        string strSplittedFileName = file.Split(@"");

    }

}

edited Nov 21 '18 at 13:43

Lennart

6,167125266

asked Nov 21 '18 at 13:29

Breau

edited Nov 21 '18 at 13:43

Lennart

6,167125266

asked Nov 21 '18 at 13:29

Breau

edited Nov 21 '18 at 13:43

Lennart

6,167125266

edited Nov 21 '18 at 13:43

Lennart

6,167125266

edited Nov 21 '18 at 13:43

Lennart

6,167125266

asked Nov 21 '18 at 13:29

Breau

asked Nov 21 '18 at 13:29

Breau

asked Nov 21 '18 at 13:29

Breau

You can post your code here in your question.

– Matthew Watson
Nov 21 '18 at 13:31

You passed a string to a method that expects Char

– Panagiotis Kanavos
Nov 21 '18 at 13:32

add a comment |

You can post your code here in your question.

– Matthew Watson
Nov 21 '18 at 13:31

You passed a string to a method that expects Char

– Panagiotis Kanavos
Nov 21 '18 at 13:32

You can post your code here in your question.

– Matthew Watson
Nov 21 '18 at 13:31

You passed a string to a method that expects Char

– Panagiotis Kanavos
Nov 21 '18 at 13:32

add a comment |

2 Answers
2

active

oldest

votes

You need to use single quotes if you are going to split on a character, so change to this:

//You have to escape the back slash or use the ampersand on the front

string strSplittedFileName = file.Split('\');

OR if you want to split using a string:

//When splitting by a string, 

//you need to pass a string array and an Enum of StringSplitOptions

string strSplittedFileName = file.Split(new string { "\" }, StringSplitOptions.RemoveEmptyEntries);

answered Nov 21 '18 at 13:33

Ryan Wilson

4,0391620

I dont have enough reputation to vote up but thanks the first one helped. Cheers

– Breau
Nov 21 '18 at 13:43

@Breau No problem. Glad I could help.

– Ryan Wilson
Nov 21 '18 at 14:12

add a comment |

Please in the future make sure to include source code in post: the reason being that link rot happens etc and it's always nice to use as reference for people having the same issue as you.

As alluded to in a previous answer using the char representation in C# (string literals) will invoke the overload that accepts a char.

From: mystring.Split(@"")
To: mystring.Split('\')

If you are attempting to split by new lines rather use:

Environment.NewLineChar

edited Nov 21 '18 at 13:45

answered Nov 21 '18 at 13:33

Neal

293111

Thanks for the info much appreciated.

– Breau
Nov 21 '18 at 13:58

Good luck Breau. Apologies that I didn't take time to compile before sending.

– Neal
Nov 21 '18 at 13:59

add a comment |

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2 Answers
2

active

oldest

votes

2 Answers
2

active

oldest

votes

You need to use single quotes if you are going to split on a character, so change to this:

//You have to escape the back slash or use the ampersand on the front

string strSplittedFileName = file.Split('\');

OR if you want to split using a string:

//When splitting by a string, 

//you need to pass a string array and an Enum of StringSplitOptions

string strSplittedFileName = file.Split(new string { "\" }, StringSplitOptions.RemoveEmptyEntries);

answered Nov 21 '18 at 13:33

Ryan Wilson

4,0391620

I dont have enough reputation to vote up but thanks the first one helped. Cheers

– Breau
Nov 21 '18 at 13:43

@Breau No problem. Glad I could help.

– Ryan Wilson
Nov 21 '18 at 14:12

add a comment |

You need to use single quotes if you are going to split on a character, so change to this:

//You have to escape the back slash or use the ampersand on the front

string strSplittedFileName = file.Split('\');

OR if you want to split using a string:

//When splitting by a string, 

//you need to pass a string array and an Enum of StringSplitOptions

string strSplittedFileName = file.Split(new string { "\" }, StringSplitOptions.RemoveEmptyEntries);

answered Nov 21 '18 at 13:33

Ryan Wilson

4,0391620

I dont have enough reputation to vote up but thanks the first one helped. Cheers

– Breau
Nov 21 '18 at 13:43

@Breau No problem. Glad I could help.

– Ryan Wilson
Nov 21 '18 at 14:12

add a comment |

You need to use single quotes if you are going to split on a character, so change to this:

//You have to escape the back slash or use the ampersand on the front

string strSplittedFileName = file.Split('\');

OR if you want to split using a string:

//When splitting by a string, 

//you need to pass a string array and an Enum of StringSplitOptions

string strSplittedFileName = file.Split(new string { "\" }, StringSplitOptions.RemoveEmptyEntries);

answered Nov 21 '18 at 13:33

Ryan Wilson

4,0391620

You need to use single quotes if you are going to split on a character, so change to this:

//You have to escape the back slash or use the ampersand on the front

string strSplittedFileName = file.Split('\');

OR if you want to split using a string:

//When splitting by a string, 

//you need to pass a string array and an Enum of StringSplitOptions

string strSplittedFileName = file.Split(new string { "\" }, StringSplitOptions.RemoveEmptyEntries);

answered Nov 21 '18 at 13:33

Ryan Wilson

4,0391620

answered Nov 21 '18 at 13:33

Ryan Wilson

4,0391620

answered Nov 21 '18 at 13:33

Ryan Wilson

4,0391620

answered Nov 21 '18 at 13:33

Ryan Wilson

4,0391620

I dont have enough reputation to vote up but thanks the first one helped. Cheers

– Breau
Nov 21 '18 at 13:43

@Breau No problem. Glad I could help.

– Ryan Wilson
Nov 21 '18 at 14:12

add a comment |

I dont have enough reputation to vote up but thanks the first one helped. Cheers

– Breau
Nov 21 '18 at 13:43

@Breau No problem. Glad I could help.

– Ryan Wilson
Nov 21 '18 at 14:12

I dont have enough reputation to vote up but thanks the first one helped. Cheers

– Breau
Nov 21 '18 at 13:43

@Breau No problem. Glad I could help.

– Ryan Wilson
Nov 21 '18 at 14:12

add a comment |

Please in the future make sure to include source code in post: the reason being that link rot happens etc and it's always nice to use as reference for people having the same issue as you.

As alluded to in a previous answer using the char representation in C# (string literals) will invoke the overload that accepts a char.

From: mystring.Split(@"")
To: mystring.Split('\')

If you are attempting to split by new lines rather use:

Environment.NewLineChar

edited Nov 21 '18 at 13:45

answered Nov 21 '18 at 13:33

Neal

293111

Thanks for the info much appreciated.

– Breau
Nov 21 '18 at 13:58

Good luck Breau. Apologies that I didn't take time to compile before sending.

– Neal
Nov 21 '18 at 13:59

add a comment |

Please in the future make sure to include source code in post: the reason being that link rot happens etc and it's always nice to use as reference for people having the same issue as you.

As alluded to in a previous answer using the char representation in C# (string literals) will invoke the overload that accepts a char.

From: mystring.Split(@"")
To: mystring.Split('\')

If you are attempting to split by new lines rather use:

Environment.NewLineChar

edited Nov 21 '18 at 13:45

answered Nov 21 '18 at 13:33

Neal

293111

Thanks for the info much appreciated.

– Breau
Nov 21 '18 at 13:58

Good luck Breau. Apologies that I didn't take time to compile before sending.

– Neal
Nov 21 '18 at 13:59

add a comment |

Please in the future make sure to include source code in post: the reason being that link rot happens etc and it's always nice to use as reference for people having the same issue as you.

As alluded to in a previous answer using the char representation in C# (string literals) will invoke the overload that accepts a char.

From: mystring.Split(@"")
To: mystring.Split('\')

If you are attempting to split by new lines rather use:

Environment.NewLineChar

edited Nov 21 '18 at 13:45

answered Nov 21 '18 at 13:33

Neal

293111

Please in the future make sure to include source code in post: the reason being that link rot happens etc and it's always nice to use as reference for people having the same issue as you.

As alluded to in a previous answer using the char representation in C# (string literals) will invoke the overload that accepts a char.

From: mystring.Split(@"")
To: mystring.Split('\')

If you are attempting to split by new lines rather use:

Environment.NewLineChar

edited Nov 21 '18 at 13:45

answered Nov 21 '18 at 13:33

Neal

293111

edited Nov 21 '18 at 13:45

answered Nov 21 '18 at 13:33

Neal

293111

answered Nov 21 '18 at 13:33

Neal

293111

answered Nov 21 '18 at 13:33

Neal

293111

Thanks for the info much appreciated.

– Breau
Nov 21 '18 at 13:58

Good luck Breau. Apologies that I didn't take time to compile before sending.

– Neal
Nov 21 '18 at 13:59

add a comment |

Thanks for the info much appreciated.

– Breau
Nov 21 '18 at 13:58

Good luck Breau. Apologies that I didn't take time to compile before sending.

– Neal
Nov 21 '18 at 13:59

Thanks for the info much appreciated.

– Breau
Nov 21 '18 at 13:58

Good luck Breau. Apologies that I didn't take time to compile before sending.

– Neal
Nov 21 '18 at 13:59

add a comment |

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