Dropping column from one dataframe based on column value of second dataframe in pandas












1















I have 2 dataframes df1 and df2, both consisting of 8 columns each as seen below :



**df1**
╔══════════════════════════════════════════════════════════╗
║John ║ Mark ║ Jane ║ Natasha ║ Oliver ║ Tony ║ Judd ║ Ron ║
╚══════════════════════════════════════════════════════════╝


**df2**
╔══════════════════════════════════════════════════╗
║True ║True ║False ║True ║False ║False ║False ║True║
╚══════════════════════════════════════════════════╝


df1 has columns that are names of different people while df2 has column names that are boolean values. What I want to do is drop all columns in df1 that have a corresponding value of False in df2. So the resulting output should look like this :



**output**
╔════════════════════════════╗
║John ║ Mark ║ Natasha ║ Ron ║
╚════════════════════════════╝


I am reading both the dataframes from csv files.



Any and all help would be appreciated.



Note : The actual dataframes have 500 columns each. Used 8 as an example for visualization purposes as well as to show that the dataframes have equal number of columns



Thanks in advance










share|improve this question

























  • It seems an odd way to set up and transform your dataset. I'd rename df2 to have the same headers as df1 with the boolean values as the first row. Then you could easily pd.concat both dataframes and select columns based on the last row of the new df.

    – Tim Gottgetreu
    Nov 20 '18 at 19:33











  • Renaming 500 boolean values to 500 unique different names would be cumbersome to say the least. Hence I am trying this approach

    – Stevi G
    Nov 20 '18 at 19:36











  • not really. If they are in the same order: df1head = list(df1) df2head = list(df2) to get both header names, then df2.rename(columns = (dict(zip(df2head,df1head)),inplace = True)

    – Tim Gottgetreu
    Nov 20 '18 at 19:42













  • does df1 have any data under the header names? Or are both df's only headers? If they are both only headers, transpose them and join on index, then select by the boolean value.

    – Tim Gottgetreu
    Nov 20 '18 at 19:48











  • df1 has data under header. It is salary for each day. df1 has 19164 rows

    – Stevi G
    Nov 20 '18 at 19:50
















1















I have 2 dataframes df1 and df2, both consisting of 8 columns each as seen below :



**df1**
╔══════════════════════════════════════════════════════════╗
║John ║ Mark ║ Jane ║ Natasha ║ Oliver ║ Tony ║ Judd ║ Ron ║
╚══════════════════════════════════════════════════════════╝


**df2**
╔══════════════════════════════════════════════════╗
║True ║True ║False ║True ║False ║False ║False ║True║
╚══════════════════════════════════════════════════╝


df1 has columns that are names of different people while df2 has column names that are boolean values. What I want to do is drop all columns in df1 that have a corresponding value of False in df2. So the resulting output should look like this :



**output**
╔════════════════════════════╗
║John ║ Mark ║ Natasha ║ Ron ║
╚════════════════════════════╝


I am reading both the dataframes from csv files.



Any and all help would be appreciated.



Note : The actual dataframes have 500 columns each. Used 8 as an example for visualization purposes as well as to show that the dataframes have equal number of columns



Thanks in advance










share|improve this question

























  • It seems an odd way to set up and transform your dataset. I'd rename df2 to have the same headers as df1 with the boolean values as the first row. Then you could easily pd.concat both dataframes and select columns based on the last row of the new df.

    – Tim Gottgetreu
    Nov 20 '18 at 19:33











  • Renaming 500 boolean values to 500 unique different names would be cumbersome to say the least. Hence I am trying this approach

    – Stevi G
    Nov 20 '18 at 19:36











  • not really. If they are in the same order: df1head = list(df1) df2head = list(df2) to get both header names, then df2.rename(columns = (dict(zip(df2head,df1head)),inplace = True)

    – Tim Gottgetreu
    Nov 20 '18 at 19:42













  • does df1 have any data under the header names? Or are both df's only headers? If they are both only headers, transpose them and join on index, then select by the boolean value.

    – Tim Gottgetreu
    Nov 20 '18 at 19:48











  • df1 has data under header. It is salary for each day. df1 has 19164 rows

    – Stevi G
    Nov 20 '18 at 19:50














1












1








1








I have 2 dataframes df1 and df2, both consisting of 8 columns each as seen below :



**df1**
╔══════════════════════════════════════════════════════════╗
║John ║ Mark ║ Jane ║ Natasha ║ Oliver ║ Tony ║ Judd ║ Ron ║
╚══════════════════════════════════════════════════════════╝


**df2**
╔══════════════════════════════════════════════════╗
║True ║True ║False ║True ║False ║False ║False ║True║
╚══════════════════════════════════════════════════╝


df1 has columns that are names of different people while df2 has column names that are boolean values. What I want to do is drop all columns in df1 that have a corresponding value of False in df2. So the resulting output should look like this :



**output**
╔════════════════════════════╗
║John ║ Mark ║ Natasha ║ Ron ║
╚════════════════════════════╝


I am reading both the dataframes from csv files.



Any and all help would be appreciated.



Note : The actual dataframes have 500 columns each. Used 8 as an example for visualization purposes as well as to show that the dataframes have equal number of columns



Thanks in advance










share|improve this question
















I have 2 dataframes df1 and df2, both consisting of 8 columns each as seen below :



**df1**
╔══════════════════════════════════════════════════════════╗
║John ║ Mark ║ Jane ║ Natasha ║ Oliver ║ Tony ║ Judd ║ Ron ║
╚══════════════════════════════════════════════════════════╝


**df2**
╔══════════════════════════════════════════════════╗
║True ║True ║False ║True ║False ║False ║False ║True║
╚══════════════════════════════════════════════════╝


df1 has columns that are names of different people while df2 has column names that are boolean values. What I want to do is drop all columns in df1 that have a corresponding value of False in df2. So the resulting output should look like this :



**output**
╔════════════════════════════╗
║John ║ Mark ║ Natasha ║ Ron ║
╚════════════════════════════╝


I am reading both the dataframes from csv files.



Any and all help would be appreciated.



Note : The actual dataframes have 500 columns each. Used 8 as an example for visualization purposes as well as to show that the dataframes have equal number of columns



Thanks in advance







python pandas dataframe






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 20 '18 at 19:34







Stevi G

















asked Nov 20 '18 at 19:08









Stevi GStevi G

536




536













  • It seems an odd way to set up and transform your dataset. I'd rename df2 to have the same headers as df1 with the boolean values as the first row. Then you could easily pd.concat both dataframes and select columns based on the last row of the new df.

    – Tim Gottgetreu
    Nov 20 '18 at 19:33











  • Renaming 500 boolean values to 500 unique different names would be cumbersome to say the least. Hence I am trying this approach

    – Stevi G
    Nov 20 '18 at 19:36











  • not really. If they are in the same order: df1head = list(df1) df2head = list(df2) to get both header names, then df2.rename(columns = (dict(zip(df2head,df1head)),inplace = True)

    – Tim Gottgetreu
    Nov 20 '18 at 19:42













  • does df1 have any data under the header names? Or are both df's only headers? If they are both only headers, transpose them and join on index, then select by the boolean value.

    – Tim Gottgetreu
    Nov 20 '18 at 19:48











  • df1 has data under header. It is salary for each day. df1 has 19164 rows

    – Stevi G
    Nov 20 '18 at 19:50



















  • It seems an odd way to set up and transform your dataset. I'd rename df2 to have the same headers as df1 with the boolean values as the first row. Then you could easily pd.concat both dataframes and select columns based on the last row of the new df.

    – Tim Gottgetreu
    Nov 20 '18 at 19:33











  • Renaming 500 boolean values to 500 unique different names would be cumbersome to say the least. Hence I am trying this approach

    – Stevi G
    Nov 20 '18 at 19:36











  • not really. If they are in the same order: df1head = list(df1) df2head = list(df2) to get both header names, then df2.rename(columns = (dict(zip(df2head,df1head)),inplace = True)

    – Tim Gottgetreu
    Nov 20 '18 at 19:42













  • does df1 have any data under the header names? Or are both df's only headers? If they are both only headers, transpose them and join on index, then select by the boolean value.

    – Tim Gottgetreu
    Nov 20 '18 at 19:48











  • df1 has data under header. It is salary for each day. df1 has 19164 rows

    – Stevi G
    Nov 20 '18 at 19:50

















It seems an odd way to set up and transform your dataset. I'd rename df2 to have the same headers as df1 with the boolean values as the first row. Then you could easily pd.concat both dataframes and select columns based on the last row of the new df.

– Tim Gottgetreu
Nov 20 '18 at 19:33





It seems an odd way to set up and transform your dataset. I'd rename df2 to have the same headers as df1 with the boolean values as the first row. Then you could easily pd.concat both dataframes and select columns based on the last row of the new df.

– Tim Gottgetreu
Nov 20 '18 at 19:33













Renaming 500 boolean values to 500 unique different names would be cumbersome to say the least. Hence I am trying this approach

– Stevi G
Nov 20 '18 at 19:36





Renaming 500 boolean values to 500 unique different names would be cumbersome to say the least. Hence I am trying this approach

– Stevi G
Nov 20 '18 at 19:36













not really. If they are in the same order: df1head = list(df1) df2head = list(df2) to get both header names, then df2.rename(columns = (dict(zip(df2head,df1head)),inplace = True)

– Tim Gottgetreu
Nov 20 '18 at 19:42







not really. If they are in the same order: df1head = list(df1) df2head = list(df2) to get both header names, then df2.rename(columns = (dict(zip(df2head,df1head)),inplace = True)

– Tim Gottgetreu
Nov 20 '18 at 19:42















does df1 have any data under the header names? Or are both df's only headers? If they are both only headers, transpose them and join on index, then select by the boolean value.

– Tim Gottgetreu
Nov 20 '18 at 19:48





does df1 have any data under the header names? Or are both df's only headers? If they are both only headers, transpose them and join on index, then select by the boolean value.

– Tim Gottgetreu
Nov 20 '18 at 19:48













df1 has data under header. It is salary for each day. df1 has 19164 rows

– Stevi G
Nov 20 '18 at 19:50





df1 has data under header. It is salary for each day. df1 has 19164 rows

– Stevi G
Nov 20 '18 at 19:50












1 Answer
1






active

oldest

votes


















2














You can, using basic indexing. However, when you parse your df2, the column names have duplicates and are altered, so it requires a bit of cleaning.



Setup



names = ['John', 'Mark', 'Jane', 'Natasha', 'Oliver', 'Tony', 'Judd', 'Ron']
cols = ['TRUE', 'TRUE.1', 'FALSE', 'FALSE.1', 'TRUE.2', 'FALSE.2', 'FALSE.3', 'TRUE.3']

df1 = pd.DataFrame(columns=names)
df2 = pd.DataFrame(columns=cols)




df1.loc[:, df2.columns.str.contains('TRUE')]




Empty DataFrame
Columns: [John, Mark, Oliver, Ron]
Index:





share|improve this answer


























  • I am reading the dataframes from csv files so when I try this method I the KeyError : "None of the [Index('0','1','2','3','4','5','6','7','8',.......'499' are in [columns]. Also both the dataframes have 500 columns not 8. I used 8 as an example for simplicity and convenience.

    – Stevi G
    Nov 20 '18 at 19:21






  • 2





    Then you haven't accurately represented your data. I'm guessing your columns aren't boolean, but str, in which case you need to convert to bool

    – user3483203
    Nov 20 '18 at 19:23













  • Post edited to give more accurate description of problem. I apologize for the misleading post

    – Stevi G
    Nov 20 '18 at 19:35











  • @SteviG try indexing with df1.loc[:, (df2.columns == 'True')]

    – user3483203
    Nov 20 '18 at 19:36






  • 1





    Thanks alot man works perfectly now :)

    – Stevi G
    Nov 20 '18 at 19:55













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1 Answer
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1 Answer
1






active

oldest

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active

oldest

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active

oldest

votes









2














You can, using basic indexing. However, when you parse your df2, the column names have duplicates and are altered, so it requires a bit of cleaning.



Setup



names = ['John', 'Mark', 'Jane', 'Natasha', 'Oliver', 'Tony', 'Judd', 'Ron']
cols = ['TRUE', 'TRUE.1', 'FALSE', 'FALSE.1', 'TRUE.2', 'FALSE.2', 'FALSE.3', 'TRUE.3']

df1 = pd.DataFrame(columns=names)
df2 = pd.DataFrame(columns=cols)




df1.loc[:, df2.columns.str.contains('TRUE')]




Empty DataFrame
Columns: [John, Mark, Oliver, Ron]
Index:





share|improve this answer


























  • I am reading the dataframes from csv files so when I try this method I the KeyError : "None of the [Index('0','1','2','3','4','5','6','7','8',.......'499' are in [columns]. Also both the dataframes have 500 columns not 8. I used 8 as an example for simplicity and convenience.

    – Stevi G
    Nov 20 '18 at 19:21






  • 2





    Then you haven't accurately represented your data. I'm guessing your columns aren't boolean, but str, in which case you need to convert to bool

    – user3483203
    Nov 20 '18 at 19:23













  • Post edited to give more accurate description of problem. I apologize for the misleading post

    – Stevi G
    Nov 20 '18 at 19:35











  • @SteviG try indexing with df1.loc[:, (df2.columns == 'True')]

    – user3483203
    Nov 20 '18 at 19:36






  • 1





    Thanks alot man works perfectly now :)

    – Stevi G
    Nov 20 '18 at 19:55


















2














You can, using basic indexing. However, when you parse your df2, the column names have duplicates and are altered, so it requires a bit of cleaning.



Setup



names = ['John', 'Mark', 'Jane', 'Natasha', 'Oliver', 'Tony', 'Judd', 'Ron']
cols = ['TRUE', 'TRUE.1', 'FALSE', 'FALSE.1', 'TRUE.2', 'FALSE.2', 'FALSE.3', 'TRUE.3']

df1 = pd.DataFrame(columns=names)
df2 = pd.DataFrame(columns=cols)




df1.loc[:, df2.columns.str.contains('TRUE')]




Empty DataFrame
Columns: [John, Mark, Oliver, Ron]
Index:





share|improve this answer


























  • I am reading the dataframes from csv files so when I try this method I the KeyError : "None of the [Index('0','1','2','3','4','5','6','7','8',.......'499' are in [columns]. Also both the dataframes have 500 columns not 8. I used 8 as an example for simplicity and convenience.

    – Stevi G
    Nov 20 '18 at 19:21






  • 2





    Then you haven't accurately represented your data. I'm guessing your columns aren't boolean, but str, in which case you need to convert to bool

    – user3483203
    Nov 20 '18 at 19:23













  • Post edited to give more accurate description of problem. I apologize for the misleading post

    – Stevi G
    Nov 20 '18 at 19:35











  • @SteviG try indexing with df1.loc[:, (df2.columns == 'True')]

    – user3483203
    Nov 20 '18 at 19:36






  • 1





    Thanks alot man works perfectly now :)

    – Stevi G
    Nov 20 '18 at 19:55
















2












2








2







You can, using basic indexing. However, when you parse your df2, the column names have duplicates and are altered, so it requires a bit of cleaning.



Setup



names = ['John', 'Mark', 'Jane', 'Natasha', 'Oliver', 'Tony', 'Judd', 'Ron']
cols = ['TRUE', 'TRUE.1', 'FALSE', 'FALSE.1', 'TRUE.2', 'FALSE.2', 'FALSE.3', 'TRUE.3']

df1 = pd.DataFrame(columns=names)
df2 = pd.DataFrame(columns=cols)




df1.loc[:, df2.columns.str.contains('TRUE')]




Empty DataFrame
Columns: [John, Mark, Oliver, Ron]
Index:





share|improve this answer















You can, using basic indexing. However, when you parse your df2, the column names have duplicates and are altered, so it requires a bit of cleaning.



Setup



names = ['John', 'Mark', 'Jane', 'Natasha', 'Oliver', 'Tony', 'Judd', 'Ron']
cols = ['TRUE', 'TRUE.1', 'FALSE', 'FALSE.1', 'TRUE.2', 'FALSE.2', 'FALSE.3', 'TRUE.3']

df1 = pd.DataFrame(columns=names)
df2 = pd.DataFrame(columns=cols)




df1.loc[:, df2.columns.str.contains('TRUE')]




Empty DataFrame
Columns: [John, Mark, Oliver, Ron]
Index:






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 20 '18 at 19:52

























answered Nov 20 '18 at 19:10









user3483203user3483203

31.3k82656




31.3k82656













  • I am reading the dataframes from csv files so when I try this method I the KeyError : "None of the [Index('0','1','2','3','4','5','6','7','8',.......'499' are in [columns]. Also both the dataframes have 500 columns not 8. I used 8 as an example for simplicity and convenience.

    – Stevi G
    Nov 20 '18 at 19:21






  • 2





    Then you haven't accurately represented your data. I'm guessing your columns aren't boolean, but str, in which case you need to convert to bool

    – user3483203
    Nov 20 '18 at 19:23













  • Post edited to give more accurate description of problem. I apologize for the misleading post

    – Stevi G
    Nov 20 '18 at 19:35











  • @SteviG try indexing with df1.loc[:, (df2.columns == 'True')]

    – user3483203
    Nov 20 '18 at 19:36






  • 1





    Thanks alot man works perfectly now :)

    – Stevi G
    Nov 20 '18 at 19:55





















  • I am reading the dataframes from csv files so when I try this method I the KeyError : "None of the [Index('0','1','2','3','4','5','6','7','8',.......'499' are in [columns]. Also both the dataframes have 500 columns not 8. I used 8 as an example for simplicity and convenience.

    – Stevi G
    Nov 20 '18 at 19:21






  • 2





    Then you haven't accurately represented your data. I'm guessing your columns aren't boolean, but str, in which case you need to convert to bool

    – user3483203
    Nov 20 '18 at 19:23













  • Post edited to give more accurate description of problem. I apologize for the misleading post

    – Stevi G
    Nov 20 '18 at 19:35











  • @SteviG try indexing with df1.loc[:, (df2.columns == 'True')]

    – user3483203
    Nov 20 '18 at 19:36






  • 1





    Thanks alot man works perfectly now :)

    – Stevi G
    Nov 20 '18 at 19:55



















I am reading the dataframes from csv files so when I try this method I the KeyError : "None of the [Index('0','1','2','3','4','5','6','7','8',.......'499' are in [columns]. Also both the dataframes have 500 columns not 8. I used 8 as an example for simplicity and convenience.

– Stevi G
Nov 20 '18 at 19:21





I am reading the dataframes from csv files so when I try this method I the KeyError : "None of the [Index('0','1','2','3','4','5','6','7','8',.......'499' are in [columns]. Also both the dataframes have 500 columns not 8. I used 8 as an example for simplicity and convenience.

– Stevi G
Nov 20 '18 at 19:21




2




2





Then you haven't accurately represented your data. I'm guessing your columns aren't boolean, but str, in which case you need to convert to bool

– user3483203
Nov 20 '18 at 19:23







Then you haven't accurately represented your data. I'm guessing your columns aren't boolean, but str, in which case you need to convert to bool

– user3483203
Nov 20 '18 at 19:23















Post edited to give more accurate description of problem. I apologize for the misleading post

– Stevi G
Nov 20 '18 at 19:35





Post edited to give more accurate description of problem. I apologize for the misleading post

– Stevi G
Nov 20 '18 at 19:35













@SteviG try indexing with df1.loc[:, (df2.columns == 'True')]

– user3483203
Nov 20 '18 at 19:36





@SteviG try indexing with df1.loc[:, (df2.columns == 'True')]

– user3483203
Nov 20 '18 at 19:36




1




1





Thanks alot man works perfectly now :)

– Stevi G
Nov 20 '18 at 19:55







Thanks alot man works perfectly now :)

– Stevi G
Nov 20 '18 at 19:55






















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ꓛꓣだゔៀៅຸ໢ທຮ໕໒ ,ໂ'໥໓າ໼ឨឲ៵៭ៈゎゔit''䖳𥁄卿' ☨₤₨こゎもょの;ꜹꟚꞖꞵꟅꞛေၦေɯ,ɨɡ𛃵𛁹ޝ޳ޠ޾,ޤޒޯ޾𫝒𫠁သ𛅤チョ'サノބޘދ𛁐ᶿᶇᶀᶋᶠ㨑㽹⻮ꧬ꧹؍۩وَؠ㇕㇃㇪ ㇦㇋㇋ṜẰᵡᴠ 軌ᵕ搜۳ٰޗޮ޷ސޯ𫖾𫅀ल, ꙭ꙰ꚅꙁꚊꞻꝔ꟠Ꝭㄤﺟޱސꧨꧼ꧴ꧯꧽ꧲ꧯ'⽹⽭⾁⿞⼳⽋២៩ញណើꩯꩤ꩸ꩮᶻᶺᶧᶂ𫳲𫪭𬸄𫵰𬖩𬫣𬊉ၲ𛅬㕦䬺𫝌𫝼,,𫟖𫞽ហៅ஫㆔ాఆఅꙒꚞꙍ,Ꙟ꙱エ ,ポテ,フࢰࢯ𫟠𫞶 𫝤𫟠ﺕﹱﻜﻣ𪵕𪭸𪻆𪾩𫔷ġ,ŧآꞪ꟥,ꞔꝻ♚☹⛵𛀌ꬷꭞȄƁƪƬșƦǙǗdžƝǯǧⱦⱰꓕꓢႋ神 ဴ၀க௭எ௫ឫោ ' េㇷㇴㇼ神ㇸㇲㇽㇴㇼㇻㇸ'ㇸㇿㇸㇹㇰㆣꓚꓤ₡₧ ㄨㄟ㄂ㄖㄎ໗ツڒذ₶।ऩछएोञयूटक़कयँृी,冬'𛅢𛅥ㇱㇵㇶ𥄥𦒽𠣧𠊓𧢖𥞘𩔋цѰㄠſtʯʭɿʆʗʍʩɷɛ,əʏダヵㄐㄘR{gỚṖḺờṠṫảḙḭᴮᵏᴘᵀᵷᵕᴜᴏᵾq﮲ﲿﴽﭙ軌ﰬﶚﶧ﫲Ҝжюїкӈㇴffצּ﬘﭅﬈軌'ffistfflſtffतभफɳɰʊɲʎ𛁱𛁖𛁮𛀉 𛂯𛀞నఋŀŲ 𫟲𫠖𫞺ຆຆ ໹້໕໗ๆทԊꧢꧠ꧰ꓱ⿝⼑ŎḬẃẖỐẅ ,ờỰỈỗﮊDžȩꭏꭎꬻ꭮ꬿꭖꭥꭅ㇭神 ⾈ꓵꓑ⺄㄄ㄪㄙㄅㄇstA۵䞽ॶ𫞑𫝄㇉㇇゜軌𩜛𩳠Jﻺ‚Üမ႕ႌႊၐၸဓၞၞၡ៸wyvtᶎᶪᶹစဎ꣡꣰꣢꣤ٗ؋لㇳㇾㇻㇱ㆐㆔,,㆟Ⱶヤマފ޼ޝަݿݞݠݷݐ',ݘ,ݪݙݵ𬝉𬜁𫝨𫞘くせぉて¼óû×ó£…𛅑הㄙくԗԀ5606神45,神796'𪤻𫞧ꓐ㄁ㄘɥɺꓵꓲ3''7034׉ⱦⱠˆ“𫝋ȍ,ꩲ軌꩷ꩶꩧꩫఞ۔فڱێظペサ神ナᴦᵑ47 9238їﻂ䐊䔉㠸﬎ffiﬣ,לּᴷᴦᵛᵽ,ᴨᵤ ᵸᵥᴗᵈꚏꚉꚟ⻆rtǟƴ𬎎

Guess what letter conforming each word