Having Javascript logic issues..again
I have this line of code to test 2 conditions
if (
micStock[k].splice(0,2).join(" ")) == actMic[actMicMod]
&& micStock[k][micStkAka] == actMic[actMicAka]
)
I need them to both be true to continue but for some reason it doesn't work. If I test each one individually they are true but when tested together with && its false.
Very confused. Help Please!
javascript google-apps-script
edited Nov 21 '18 at 17:50
Patrick Roberts
21k33677
asked Nov 21 '18 at 17:45
Chris BarrettChris Barrett
1208
add a comment |
I have this line of code to test 2 conditions
if (
micStock[k].splice(0,2).join(" ")) == actMic[actMicMod]
&& micStock[k][micStkAka] == actMic[actMicAka]
)
I need them to both be true to continue but for some reason it doesn't work. If I test each one individually they are true but when tested together with && its false.
Very confused. Help Please!
javascript google-apps-script
edited Nov 21 '18 at 17:50
Patrick Roberts
21k33677
asked Nov 21 '18 at 17:45
Chris BarrettChris Barrett
1208
1
You have a syntax error. An extra)afterjoin(" ").
– Paulpro
Nov 21 '18 at 17:49
2
splice modifies the array. You may want slice instead, since splice could be changing the value ofmicStock[k][micStkAka].
– Paulpro
Nov 21 '18 at 17:50
That's got it @PaulPro. Didn't know that. Will need to read up. The extra bracket was just a typo whilst I formatted it for the here BTW. Thanks a ton!
– Chris Barrett
Nov 21 '18 at 17:55
add a comment |
I have this line of code to test 2 conditions
if (
micStock[k].splice(0,2).join(" ")) == actMic[actMicMod]
&& micStock[k][micStkAka] == actMic[actMicAka]
)
I need them to both be true to continue but for some reason it doesn't work. If I test each one individually they are true but when tested together with && its false.
Very confused. Help Please!
javascript google-apps-script
edited Nov 21 '18 at 17:50
Patrick Roberts
21k33677
asked Nov 21 '18 at 17:45
Chris BarrettChris Barrett
1208
I have this line of code to test 2 conditions
if (
micStock[k].splice(0,2).join(" ")) == actMic[actMicMod]
&& micStock[k][micStkAka] == actMic[actMicAka]
)
I need them to both be true to continue but for some reason it doesn't work. If I test each one individually they are true but when tested together with && its false.
Very confused. Help Please!
javascript google-apps-script
javascript google-apps-script
edited Nov 21 '18 at 17:50
Patrick Roberts
21k33677
asked Nov 21 '18 at 17:45
Chris BarrettChris Barrett
1208
edited Nov 21 '18 at 17:50
Patrick Roberts
21k33677
asked Nov 21 '18 at 17:45
Chris BarrettChris Barrett
1208
edited Nov 21 '18 at 17:50
Patrick Roberts
21k33677
edited Nov 21 '18 at 17:50
Patrick Roberts
21k33677
edited Nov 21 '18 at 17:50
Patrick Roberts
21k33677
21k33677
asked Nov 21 '18 at 17:45
Chris BarrettChris Barrett
1208
asked Nov 21 '18 at 17:45
Chris BarrettChris Barrett
1208
asked Nov 21 '18 at 17:45
Chris BarrettChris Barrett
1208
1208
1
You have a syntax error. An extra)afterjoin(" ").
– Paulpro
Nov 21 '18 at 17:49
2
splice modifies the array. You may want slice instead, since splice could be changing the value ofmicStock[k][micStkAka].
– Paulpro
Nov 21 '18 at 17:50
That's got it @PaulPro. Didn't know that. Will need to read up. The extra bracket was just a typo whilst I formatted it for the here BTW. Thanks a ton!
– Chris Barrett
Nov 21 '18 at 17:55
add a comment |
1
You have a syntax error. An extra)afterjoin(" ").
– Paulpro
Nov 21 '18 at 17:49
2
splice modifies the array. You may want slice instead, since splice could be changing the value ofmicStock[k][micStkAka].
– Paulpro
Nov 21 '18 at 17:50
That's got it @PaulPro. Didn't know that. Will need to read up. The extra bracket was just a typo whilst I formatted it for the here BTW. Thanks a ton!
– Chris Barrett
Nov 21 '18 at 17:55
1
1
You have a syntax error. An extra
) after join(" ").– Paulpro
Nov 21 '18 at 17:49
You have a syntax error. An extra
) after join(" ").– Paulpro
Nov 21 '18 at 17:49
2
2
splice modifies the array. You may want slice instead, since splice could be changing the value of
micStock[k][micStkAka].– Paulpro
Nov 21 '18 at 17:50
splice modifies the array. You may want slice instead, since splice could be changing the value of
micStock[k][micStkAka].– Paulpro
Nov 21 '18 at 17:50
That's got it @PaulPro. Didn't know that. Will need to read up. The extra bracket was just a typo whilst I formatted it for the here BTW. Thanks a ton!
– Chris Barrett
Nov 21 '18 at 17:55
That's got it @PaulPro. Didn't know that. Will need to read up. The extra bracket was just a typo whilst I formatted it for the here BTW. Thanks a ton!
– Chris Barrett
Nov 21 '18 at 17:55
add a comment |
1 Answer
1
active
oldest
votes
.splice(0,2) remove first 2 elements from array micStock[k] this is probably not desired behaviour
In Your code is also something wrong (I break line differently tan you to show it)
if ( micStock[k].splice(0,2).join(" ") )
== actMic[actMicMod]
&& micStock[k][micStkAka] == actMic[actMicAka] )
on first line end you have extra )
answered Nov 21 '18 at 17:54
Kamil KiełczewskiKamil Kiełczewski
13.5k87297
You are absolutely correct as @PaulPro pointed out as well.Splicewas wrong. Feel a bit dumb! Thanks guys. Helping the learners as ever!
– Chris Barrett
Nov 21 '18 at 17:59
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
.splice(0,2) remove first 2 elements from array micStock[k] this is probably not desired behaviour
In Your code is also something wrong (I break line differently tan you to show it)
if ( micStock[k].splice(0,2).join(" ") )
== actMic[actMicMod]
&& micStock[k][micStkAka] == actMic[actMicAka] )
on first line end you have extra )
answered Nov 21 '18 at 17:54
Kamil KiełczewskiKamil Kiełczewski
13.5k87297
You are absolutely correct as @PaulPro pointed out as well.Splicewas wrong. Feel a bit dumb! Thanks guys. Helping the learners as ever!
– Chris Barrett
Nov 21 '18 at 17:59
add a comment |
.splice(0,2) remove first 2 elements from array micStock[k] this is probably not desired behaviour
In Your code is also something wrong (I break line differently tan you to show it)
if ( micStock[k].splice(0,2).join(" ") )
== actMic[actMicMod]
&& micStock[k][micStkAka] == actMic[actMicAka] )
on first line end you have extra )
answered Nov 21 '18 at 17:54
Kamil KiełczewskiKamil Kiełczewski
13.5k87297
You are absolutely correct as @PaulPro pointed out as well.Splicewas wrong. Feel a bit dumb! Thanks guys. Helping the learners as ever!
– Chris Barrett
Nov 21 '18 at 17:59
add a comment |
.splice(0,2) remove first 2 elements from array micStock[k] this is probably not desired behaviour
In Your code is also something wrong (I break line differently tan you to show it)
if ( micStock[k].splice(0,2).join(" ") )
== actMic[actMicMod]
&& micStock[k][micStkAka] == actMic[actMicAka] )
on first line end you have extra )
answered Nov 21 '18 at 17:54
Kamil KiełczewskiKamil Kiełczewski
13.5k87297
.splice(0,2) remove first 2 elements from array micStock[k] this is probably not desired behaviour
In Your code is also something wrong (I break line differently tan you to show it)
if ( micStock[k].splice(0,2).join(" ") )
== actMic[actMicMod]
&& micStock[k][micStkAka] == actMic[actMicAka] )
on first line end you have extra )
answered Nov 21 '18 at 17:54
Kamil KiełczewskiKamil Kiełczewski
13.5k87297
answered Nov 21 '18 at 17:54
Kamil KiełczewskiKamil Kiełczewski
13.5k87297
answered Nov 21 '18 at 17:54
Kamil KiełczewskiKamil Kiełczewski
13.5k87297
answered Nov 21 '18 at 17:54
Kamil KiełczewskiKamil Kiełczewski
13.5k87297
13.5k87297
You are absolutely correct as @PaulPro pointed out as well.Splicewas wrong. Feel a bit dumb! Thanks guys. Helping the learners as ever!
– Chris Barrett
Nov 21 '18 at 17:59
add a comment |
You are absolutely correct as @PaulPro pointed out as well.Splicewas wrong. Feel a bit dumb! Thanks guys. Helping the learners as ever!
– Chris Barrett
Nov 21 '18 at 17:59
You are absolutely correct as @PaulPro pointed out as well.
Splice was wrong. Feel a bit dumb! Thanks guys. Helping the learners as ever!– Chris Barrett
Nov 21 '18 at 17:59
You are absolutely correct as @PaulPro pointed out as well.
Splice was wrong. Feel a bit dumb! Thanks guys. Helping the learners as ever!– Chris Barrett
Nov 21 '18 at 17:59
add a comment |
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1
You have a syntax error. An extra
)afterjoin(" ").– Paulpro
Nov 21 '18 at 17:49
2
splice modifies the array. You may want slice instead, since splice could be changing the value of
micStock[k][micStkAka].– Paulpro
Nov 21 '18 at 17:50
That's got it @PaulPro. Didn't know that. Will need to read up. The extra bracket was just a typo whilst I formatted it for the here BTW. Thanks a ton!
– Chris Barrett
Nov 21 '18 at 17:55