scala - restricted way of converting string to number
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2
I have a string variable that needs to be parsed to a double
Code:
val myString = "9d"
myString.toDouble // produces "9.0" which i don't want. this should throws an error
How do I make my string to be interpreted literally so that it produces an exception?
java scala number-formatting
edited Nov 22 '18 at 13:50
ygor
1,1521616
asked Nov 22 '18 at 10:24
Vincent ClaesVincent Claes
442723
add a comment |
2
I have a string variable that needs to be parsed to a double
Code:
val myString = "9d"
myString.toDouble // produces "9.0" which i don't want. this should throws an error
How do I make my string to be interpreted literally so that it produces an exception?
java scala number-formatting
edited Nov 22 '18 at 13:50
ygor
1,1521616
asked Nov 22 '18 at 10:24
Vincent ClaesVincent Claes
442723
Interesting question! This applies to pure Java too. One solution:BigDecimal(myString).toDouble
– ygor
Nov 22 '18 at 11:01
add a comment |
2
2
2
I have a string variable that needs to be parsed to a double
Code:
val myString = "9d"
myString.toDouble // produces "9.0" which i don't want. this should throws an error
How do I make my string to be interpreted literally so that it produces an exception?
java scala number-formatting
edited Nov 22 '18 at 13:50
ygor
1,1521616
asked Nov 22 '18 at 10:24
Vincent ClaesVincent Claes
442723
I have a string variable that needs to be parsed to a double
Code:
val myString = "9d"
myString.toDouble // produces "9.0" which i don't want. this should throws an error
How do I make my string to be interpreted literally so that it produces an exception?
java scala number-formatting
java scala number-formatting
edited Nov 22 '18 at 13:50
ygor
1,1521616
asked Nov 22 '18 at 10:24
Vincent ClaesVincent Claes
442723
edited Nov 22 '18 at 13:50
ygor
1,1521616
asked Nov 22 '18 at 10:24
Vincent ClaesVincent Claes
442723
edited Nov 22 '18 at 13:50
ygor
1,1521616
edited Nov 22 '18 at 13:50
ygor
1,1521616
edited Nov 22 '18 at 13:50
ygor
1,1521616
1,1521616
asked Nov 22 '18 at 10:24
Vincent ClaesVincent Claes
442723
asked Nov 22 '18 at 10:24
Vincent ClaesVincent Claes
442723
asked Nov 22 '18 at 10:24
Vincent ClaesVincent Claes
442723
442723
Interesting question! This applies to pure Java too. One solution:BigDecimal(myString).toDouble
– ygor
Nov 22 '18 at 11:01
add a comment |
Interesting question! This applies to pure Java too. One solution:BigDecimal(myString).toDouble
– ygor
Nov 22 '18 at 11:01
Interesting question! This applies to pure Java too. One solution:
BigDecimal(myString).toDouble– ygor
Nov 22 '18 at 11:01
Interesting question! This applies to pure Java too. One solution:
BigDecimal(myString).toDouble– ygor
Nov 22 '18 at 11:01
add a comment |
2 Answers
2
active
oldest
votes
3
So, apparently, Java's java.lang.Double#parseDouble is able to parse all kinds of strings, e.g. NaN, Infinity and other.
The answer to your problem seems to be BigDecimal(myString).toDouble
Out of curiosity, here is, what three different approaches return for various kinds of input strings:
def main(args: Array[String]): Unit = {
val strings = Seq("Infinity", "NaN", "9.0d", "9d", "9f", "9.0", "9.1", "1.4e14")
val parsers = Seq(
("Double", (s: String) => s.toDouble),
("BigDecimal", (s: String) => BigDecimal(s).toDouble),
("NumberFormat", (s: String) => NumberFormat.getNumberInstance.parse(s).doubleValue()),
)
for (string <- strings) {
println(s"n------------- $string ------------")
for ((name, parser) <- parsers) {
val result = Try(parser(string)) match {
case scala.util.Success(value) => value
case scala.util.Failure(ex) => ex.toString
}
println(name.reverse.padTo(20, " ").reverse.mkString + " -> " + result)
}
}
}
Result:
------------- Infinity ------------
Double -> Infinity
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "Infinity"
------------- NaN ------------
Double -> NaN
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "NaN"
------------- 9.0d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9f ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9.0 ------------
Double -> 9.0
BigDecimal -> 9.0
NumberFormat -> 9.0
------------- 9.1 ------------
Double -> 9.1
BigDecimal -> 9.1
NumberFormat -> 9.1
------------- 1.4e14 ------------
Double -> 1.4E14
BigDecimal -> 1.4E14
NumberFormat -> 1.4
answered Nov 22 '18 at 11:12
ygorygor
1,1521616
1
The second one doesn't work as desired:val n = NumberFormat.getNumberInstance.parse("9d")results inn: Number = 9
– Kolmar
Nov 22 '18 at 11:29
For the second one to work, you'd need something like:val s = "9d"; val pos = new ParsePosition(0); val n = NumberFormat.getNumberInstance.parse(s, pos); if (pos.getIndex != s.length) throw new NumberFormatException
– Kolmar
Nov 22 '18 at 11:33
Thanks, I edited my answer
– ygor
Nov 22 '18 at 11:38
add a comment |
0
I found a solution with scalaz:
import scalaz.Scalaz._
println("34b".parseDouble) // Failure(java.lang.NumberFormatException: For input string: "34b")
println("34.4".parseDouble) // Success(34.4)
answered Nov 22 '18 at 11:08
pmepme
3,61811933
No, that still doesn't work:"9d".parseDouble->Success(9.0)
– Kolmar
Nov 22 '18 at 11:26
Strange in ScalaFiddle that works?!
– pme
Nov 22 '18 at 12:07
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
3
So, apparently, Java's java.lang.Double#parseDouble is able to parse all kinds of strings, e.g. NaN, Infinity and other.
The answer to your problem seems to be BigDecimal(myString).toDouble
Out of curiosity, here is, what three different approaches return for various kinds of input strings:
def main(args: Array[String]): Unit = {
val strings = Seq("Infinity", "NaN", "9.0d", "9d", "9f", "9.0", "9.1", "1.4e14")
val parsers = Seq(
("Double", (s: String) => s.toDouble),
("BigDecimal", (s: String) => BigDecimal(s).toDouble),
("NumberFormat", (s: String) => NumberFormat.getNumberInstance.parse(s).doubleValue()),
)
for (string <- strings) {
println(s"n------------- $string ------------")
for ((name, parser) <- parsers) {
val result = Try(parser(string)) match {
case scala.util.Success(value) => value
case scala.util.Failure(ex) => ex.toString
}
println(name.reverse.padTo(20, " ").reverse.mkString + " -> " + result)
}
}
}
Result:
------------- Infinity ------------
Double -> Infinity
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "Infinity"
------------- NaN ------------
Double -> NaN
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "NaN"
------------- 9.0d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9f ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9.0 ------------
Double -> 9.0
BigDecimal -> 9.0
NumberFormat -> 9.0
------------- 9.1 ------------
Double -> 9.1
BigDecimal -> 9.1
NumberFormat -> 9.1
------------- 1.4e14 ------------
Double -> 1.4E14
BigDecimal -> 1.4E14
NumberFormat -> 1.4
answered Nov 22 '18 at 11:12
ygorygor
1,1521616
1
The second one doesn't work as desired:val n = NumberFormat.getNumberInstance.parse("9d")results inn: Number = 9
– Kolmar
Nov 22 '18 at 11:29
For the second one to work, you'd need something like:val s = "9d"; val pos = new ParsePosition(0); val n = NumberFormat.getNumberInstance.parse(s, pos); if (pos.getIndex != s.length) throw new NumberFormatException
– Kolmar
Nov 22 '18 at 11:33
Thanks, I edited my answer
– ygor
Nov 22 '18 at 11:38
add a comment |
3
So, apparently, Java's java.lang.Double#parseDouble is able to parse all kinds of strings, e.g. NaN, Infinity and other.
The answer to your problem seems to be BigDecimal(myString).toDouble
Out of curiosity, here is, what three different approaches return for various kinds of input strings:
def main(args: Array[String]): Unit = {
val strings = Seq("Infinity", "NaN", "9.0d", "9d", "9f", "9.0", "9.1", "1.4e14")
val parsers = Seq(
("Double", (s: String) => s.toDouble),
("BigDecimal", (s: String) => BigDecimal(s).toDouble),
("NumberFormat", (s: String) => NumberFormat.getNumberInstance.parse(s).doubleValue()),
)
for (string <- strings) {
println(s"n------------- $string ------------")
for ((name, parser) <- parsers) {
val result = Try(parser(string)) match {
case scala.util.Success(value) => value
case scala.util.Failure(ex) => ex.toString
}
println(name.reverse.padTo(20, " ").reverse.mkString + " -> " + result)
}
}
}
Result:
------------- Infinity ------------
Double -> Infinity
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "Infinity"
------------- NaN ------------
Double -> NaN
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "NaN"
------------- 9.0d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9f ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9.0 ------------
Double -> 9.0
BigDecimal -> 9.0
NumberFormat -> 9.0
------------- 9.1 ------------
Double -> 9.1
BigDecimal -> 9.1
NumberFormat -> 9.1
------------- 1.4e14 ------------
Double -> 1.4E14
BigDecimal -> 1.4E14
NumberFormat -> 1.4
answered Nov 22 '18 at 11:12
ygorygor
1,1521616
1
The second one doesn't work as desired:val n = NumberFormat.getNumberInstance.parse("9d")results inn: Number = 9
– Kolmar
Nov 22 '18 at 11:29
For the second one to work, you'd need something like:val s = "9d"; val pos = new ParsePosition(0); val n = NumberFormat.getNumberInstance.parse(s, pos); if (pos.getIndex != s.length) throw new NumberFormatException
– Kolmar
Nov 22 '18 at 11:33
Thanks, I edited my answer
– ygor
Nov 22 '18 at 11:38
add a comment |
3
3
3
So, apparently, Java's java.lang.Double#parseDouble is able to parse all kinds of strings, e.g. NaN, Infinity and other.
The answer to your problem seems to be BigDecimal(myString).toDouble
Out of curiosity, here is, what three different approaches return for various kinds of input strings:
def main(args: Array[String]): Unit = {
val strings = Seq("Infinity", "NaN", "9.0d", "9d", "9f", "9.0", "9.1", "1.4e14")
val parsers = Seq(
("Double", (s: String) => s.toDouble),
("BigDecimal", (s: String) => BigDecimal(s).toDouble),
("NumberFormat", (s: String) => NumberFormat.getNumberInstance.parse(s).doubleValue()),
)
for (string <- strings) {
println(s"n------------- $string ------------")
for ((name, parser) <- parsers) {
val result = Try(parser(string)) match {
case scala.util.Success(value) => value
case scala.util.Failure(ex) => ex.toString
}
println(name.reverse.padTo(20, " ").reverse.mkString + " -> " + result)
}
}
}
Result:
------------- Infinity ------------
Double -> Infinity
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "Infinity"
------------- NaN ------------
Double -> NaN
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "NaN"
------------- 9.0d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9f ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9.0 ------------
Double -> 9.0
BigDecimal -> 9.0
NumberFormat -> 9.0
------------- 9.1 ------------
Double -> 9.1
BigDecimal -> 9.1
NumberFormat -> 9.1
------------- 1.4e14 ------------
Double -> 1.4E14
BigDecimal -> 1.4E14
NumberFormat -> 1.4
answered Nov 22 '18 at 11:12
ygorygor
1,1521616
So, apparently, Java's java.lang.Double#parseDouble is able to parse all kinds of strings, e.g. NaN, Infinity and other.
The answer to your problem seems to be BigDecimal(myString).toDouble
Out of curiosity, here is, what three different approaches return for various kinds of input strings:
def main(args: Array[String]): Unit = {
val strings = Seq("Infinity", "NaN", "9.0d", "9d", "9f", "9.0", "9.1", "1.4e14")
val parsers = Seq(
("Double", (s: String) => s.toDouble),
("BigDecimal", (s: String) => BigDecimal(s).toDouble),
("NumberFormat", (s: String) => NumberFormat.getNumberInstance.parse(s).doubleValue()),
)
for (string <- strings) {
println(s"n------------- $string ------------")
for ((name, parser) <- parsers) {
val result = Try(parser(string)) match {
case scala.util.Success(value) => value
case scala.util.Failure(ex) => ex.toString
}
println(name.reverse.padTo(20, " ").reverse.mkString + " -> " + result)
}
}
}
Result:
------------- Infinity ------------
Double -> Infinity
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "Infinity"
------------- NaN ------------
Double -> NaN
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> java.text.ParseException: Unparseable number: "NaN"
------------- 9.0d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9d ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9f ------------
Double -> 9.0
BigDecimal -> java.lang.NumberFormatException
NumberFormat -> 9.0
------------- 9.0 ------------
Double -> 9.0
BigDecimal -> 9.0
NumberFormat -> 9.0
------------- 9.1 ------------
Double -> 9.1
BigDecimal -> 9.1
NumberFormat -> 9.1
------------- 1.4e14 ------------
Double -> 1.4E14
BigDecimal -> 1.4E14
NumberFormat -> 1.4
answered Nov 22 '18 at 11:12
ygorygor
1,1521616
edited Nov 22 '18 at 11:36
answered Nov 22 '18 at 11:12
ygorygor
1,1521616
answered Nov 22 '18 at 11:12
ygorygor
1,1521616
answered Nov 22 '18 at 11:12
ygorygor
1,1521616
1,1521616
1
The second one doesn't work as desired:val n = NumberFormat.getNumberInstance.parse("9d")results inn: Number = 9
– Kolmar
Nov 22 '18 at 11:29
For the second one to work, you'd need something like:val s = "9d"; val pos = new ParsePosition(0); val n = NumberFormat.getNumberInstance.parse(s, pos); if (pos.getIndex != s.length) throw new NumberFormatException
– Kolmar
Nov 22 '18 at 11:33
Thanks, I edited my answer
– ygor
Nov 22 '18 at 11:38
add a comment |
1
The second one doesn't work as desired:val n = NumberFormat.getNumberInstance.parse("9d")results inn: Number = 9
– Kolmar
Nov 22 '18 at 11:29
For the second one to work, you'd need something like:val s = "9d"; val pos = new ParsePosition(0); val n = NumberFormat.getNumberInstance.parse(s, pos); if (pos.getIndex != s.length) throw new NumberFormatException
– Kolmar
Nov 22 '18 at 11:33
Thanks, I edited my answer
– ygor
Nov 22 '18 at 11:38
1
1
The second one doesn't work as desired:
val n = NumberFormat.getNumberInstance.parse("9d") results in n: Number = 9– Kolmar
Nov 22 '18 at 11:29
The second one doesn't work as desired:
val n = NumberFormat.getNumberInstance.parse("9d") results in n: Number = 9– Kolmar
Nov 22 '18 at 11:29
For the second one to work, you'd need something like:
val s = "9d"; val pos = new ParsePosition(0); val n = NumberFormat.getNumberInstance.parse(s, pos); if (pos.getIndex != s.length) throw new NumberFormatException– Kolmar
Nov 22 '18 at 11:33
For the second one to work, you'd need something like:
val s = "9d"; val pos = new ParsePosition(0); val n = NumberFormat.getNumberInstance.parse(s, pos); if (pos.getIndex != s.length) throw new NumberFormatException– Kolmar
Nov 22 '18 at 11:33
Thanks, I edited my answer
– ygor
Nov 22 '18 at 11:38
Thanks, I edited my answer
– ygor
Nov 22 '18 at 11:38
add a comment |
0
I found a solution with scalaz:
import scalaz.Scalaz._
println("34b".parseDouble) // Failure(java.lang.NumberFormatException: For input string: "34b")
println("34.4".parseDouble) // Success(34.4)
answered Nov 22 '18 at 11:08
pmepme
3,61811933
No, that still doesn't work:"9d".parseDouble->Success(9.0)
– Kolmar
Nov 22 '18 at 11:26
Strange in ScalaFiddle that works?!
– pme
Nov 22 '18 at 12:07
add a comment |
0
I found a solution with scalaz:
import scalaz.Scalaz._
println("34b".parseDouble) // Failure(java.lang.NumberFormatException: For input string: "34b")
println("34.4".parseDouble) // Success(34.4)
answered Nov 22 '18 at 11:08
pmepme
3,61811933
No, that still doesn't work:"9d".parseDouble->Success(9.0)
– Kolmar
Nov 22 '18 at 11:26
Strange in ScalaFiddle that works?!
– pme
Nov 22 '18 at 12:07
add a comment |
0
0
0
I found a solution with scalaz:
import scalaz.Scalaz._
println("34b".parseDouble) // Failure(java.lang.NumberFormatException: For input string: "34b")
println("34.4".parseDouble) // Success(34.4)
answered Nov 22 '18 at 11:08
pmepme
3,61811933
I found a solution with scalaz:
import scalaz.Scalaz._
println("34b".parseDouble) // Failure(java.lang.NumberFormatException: For input string: "34b")
println("34.4".parseDouble) // Success(34.4)
answered Nov 22 '18 at 11:08
pmepme
3,61811933
answered Nov 22 '18 at 11:08
pmepme
3,61811933
answered Nov 22 '18 at 11:08
pmepme
3,61811933
answered Nov 22 '18 at 11:08
pmepme
3,61811933
3,61811933
No, that still doesn't work:"9d".parseDouble->Success(9.0)
– Kolmar
Nov 22 '18 at 11:26
Strange in ScalaFiddle that works?!
– pme
Nov 22 '18 at 12:07
add a comment |
No, that still doesn't work:"9d".parseDouble->Success(9.0)
– Kolmar
Nov 22 '18 at 11:26
Strange in ScalaFiddle that works?!
– pme
Nov 22 '18 at 12:07
No, that still doesn't work:
"9d".parseDouble -> Success(9.0)– Kolmar
Nov 22 '18 at 11:26
No, that still doesn't work:
"9d".parseDouble -> Success(9.0)– Kolmar
Nov 22 '18 at 11:26
Strange in ScalaFiddle that works?!
– pme
Nov 22 '18 at 12:07
Strange in ScalaFiddle that works?!
– pme
Nov 22 '18 at 12:07
add a comment |
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Interesting question! This applies to pure Java too. One solution:
BigDecimal(myString).toDouble– ygor
Nov 22 '18 at 11:01