How do I create a dataset using computed values?











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Please see here the input and desired output tables.



I have a dataset (df_report) that looks like this:



city <- c("New York","Mexico City","Cape Town")

A <- c(3,4,1)

B <- c(5,1,3)

C <- c(0,3,2)

category <- c("Complete","Incomplete","Complete")

df_report <- data.frame(city, category, A, B, C)


Then the logic/ formula for the variables:



RB_1 <- df_report["Complete","A"] + df_report["Complete","B"]

RB_2 <- sum(df_report["Incomplete",]) - df_report["Incomplete","C"]

RB_3 <- sum(df_report["Complete",])

RB_4 <- RB_1 + RB_2


How do I make a separate dataset with the following? Row header: Variable; Column: City






r dataset aggregate







share|improve this question




















  • 2




    How your result should looks like?
    – jogo
    Nov 9 at 13:17












  • Do you want to create a data frame with specified column names like so: RB_4 <- data.frame(Variable=RB_1, City=RB_2) or what?
    – eikooc
    Nov 9 at 13:19










  • Sorry, corrected. The output should be, rows are RB_1, RB_2, etc. Columns are cities.
    – tiffinie
    Nov 9 at 13:20






  • 1




    Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables and Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables
    – Andre Elrico
    Nov 9 at 13:23






  • 1




    There's no row name 'Complete' so df_report["Complete","A"] results in NA. Did you mean df_report[df_report['category'] == "Complete","A"]? The latter subsetting results in vector of two elements - what should be a desired value of RB_1?
    – Kuba_
    Nov 9 at 13:28

















up vote
0
down vote

favorite












Please see here the input and desired output tables.



I have a dataset (df_report) that looks like this:



city <- c("New York","Mexico City","Cape Town")

A <- c(3,4,1)

B <- c(5,1,3)

C <- c(0,3,2)

category <- c("Complete","Incomplete","Complete")

df_report <- data.frame(city, category, A, B, C)


Then the logic/ formula for the variables:



RB_1 <- df_report["Complete","A"] + df_report["Complete","B"]

RB_2 <- sum(df_report["Incomplete",]) - df_report["Incomplete","C"]

RB_3 <- sum(df_report["Complete",])

RB_4 <- RB_1 + RB_2


How do I make a separate dataset with the following? Row header: Variable; Column: City






r dataset aggregate







share|improve this question




















  • 2




    How your result should looks like?
    – jogo
    Nov 9 at 13:17












  • Do you want to create a data frame with specified column names like so: RB_4 <- data.frame(Variable=RB_1, City=RB_2) or what?
    – eikooc
    Nov 9 at 13:19










  • Sorry, corrected. The output should be, rows are RB_1, RB_2, etc. Columns are cities.
    – tiffinie
    Nov 9 at 13:20






  • 1




    Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables and Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables
    – Andre Elrico
    Nov 9 at 13:23






  • 1




    There's no row name 'Complete' so df_report["Complete","A"] results in NA. Did you mean df_report[df_report['category'] == "Complete","A"]? The latter subsetting results in vector of two elements - what should be a desired value of RB_1?
    – Kuba_
    Nov 9 at 13:28















up vote
0
down vote

favorite









up vote
0
down vote

favorite











Please see here the input and desired output tables.



I have a dataset (df_report) that looks like this:



city <- c("New York","Mexico City","Cape Town")

A <- c(3,4,1)

B <- c(5,1,3)

C <- c(0,3,2)

category <- c("Complete","Incomplete","Complete")

df_report <- data.frame(city, category, A, B, C)


Then the logic/ formula for the variables:



RB_1 <- df_report["Complete","A"] + df_report["Complete","B"]

RB_2 <- sum(df_report["Incomplete",]) - df_report["Incomplete","C"]

RB_3 <- sum(df_report["Complete",])

RB_4 <- RB_1 + RB_2


How do I make a separate dataset with the following? Row header: Variable; Column: City






r dataset aggregate







share|improve this question















Please see here the input and desired output tables.



I have a dataset (df_report) that looks like this:



city <- c("New York","Mexico City","Cape Town")

A <- c(3,4,1)

B <- c(5,1,3)

C <- c(0,3,2)

category <- c("Complete","Incomplete","Complete")

df_report <- data.frame(city, category, A, B, C)


Then the logic/ formula for the variables:



RB_1 <- df_report["Complete","A"] + df_report["Complete","B"]

RB_2 <- sum(df_report["Incomplete",]) - df_report["Incomplete","C"]

RB_3 <- sum(df_report["Complete",])

RB_4 <- RB_1 + RB_2


How do I make a separate dataset with the following? Row header: Variable; Column: City






r dataset aggregate




r dataset aggregate






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 9 at 13:39

























asked Nov 9 at 13:15









tiffinie

613




613








  • 2




    How your result should looks like?
    – jogo
    Nov 9 at 13:17












  • Do you want to create a data frame with specified column names like so: RB_4 <- data.frame(Variable=RB_1, City=RB_2) or what?
    – eikooc
    Nov 9 at 13:19










  • Sorry, corrected. The output should be, rows are RB_1, RB_2, etc. Columns are cities.
    – tiffinie
    Nov 9 at 13:20






  • 1




    Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables and Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables
    – Andre Elrico
    Nov 9 at 13:23






  • 1




    There's no row name 'Complete' so df_report["Complete","A"] results in NA. Did you mean df_report[df_report['category'] == "Complete","A"]? The latter subsetting results in vector of two elements - what should be a desired value of RB_1?
    – Kuba_
    Nov 9 at 13:28
















  • 2




    How your result should looks like?
    – jogo
    Nov 9 at 13:17












  • Do you want to create a data frame with specified column names like so: RB_4 <- data.frame(Variable=RB_1, City=RB_2) or what?
    – eikooc
    Nov 9 at 13:19










  • Sorry, corrected. The output should be, rows are RB_1, RB_2, etc. Columns are cities.
    – tiffinie
    Nov 9 at 13:20






  • 1




    Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables and Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables
    – Andre Elrico
    Nov 9 at 13:23






  • 1




    There's no row name 'Complete' so df_report["Complete","A"] results in NA. Did you mean df_report[df_report['category'] == "Complete","A"]? The latter subsetting results in vector of two elements - what should be a desired value of RB_1?
    – Kuba_
    Nov 9 at 13:28










2




2




How your result should looks like?
– jogo
Nov 9 at 13:17






How your result should looks like?
– jogo
Nov 9 at 13:17














Do you want to create a data frame with specified column names like so: RB_4 <- data.frame(Variable=RB_1, City=RB_2) or what?
– eikooc
Nov 9 at 13:19




Do you want to create a data frame with specified column names like so: RB_4 <- data.frame(Variable=RB_1, City=RB_2) or what?
– eikooc
Nov 9 at 13:19












Sorry, corrected. The output should be, rows are RB_1, RB_2, etc. Columns are cities.
– tiffinie
Nov 9 at 13:20




Sorry, corrected. The output should be, rows are RB_1, RB_2, etc. Columns are cities.
– tiffinie
Nov 9 at 13:20




1




1




Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables and Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables
– Andre Elrico
Nov 9 at 13:23




Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables and Error in FUN(X[[i]], ...) : only defined on a data frame with all numeric variables
– Andre Elrico
Nov 9 at 13:23




1




1




There's no row name 'Complete' so df_report["Complete","A"] results in NA. Did you mean df_report[df_report['category'] == "Complete","A"]? The latter subsetting results in vector of two elements - what should be a desired value of RB_1?
– Kuba_
Nov 9 at 13:28






There's no row name 'Complete' so df_report["Complete","A"] results in NA. Did you mean df_report[df_report['category'] == "Complete","A"]? The latter subsetting results in vector of two elements - what should be a desired value of RB_1?
– Kuba_
Nov 9 at 13:28



















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