Agfdhyk

Is this possible?

Here is an example:

#include <stdio.h>

#include <stdlib.h>



char testString="blunt"



#define shellscript1 "

#/bin/bash n

printf "nHi! The passed value is: $1n" n

"



int main(){



    system(shellscript1);



    return 0;

}

Now I would like to pass a value from testString to shellscript1 without having to reserve to making a temporary external script.

I've been bashing my head, and I couldn't figure out how to do it. Does anyone have any ideas?

Using the environment is possibly the simplest way to achieve it.

#include <stdio.h>

#include <stdlib.h>



char testString="blunt";

#define shellscript1 "bash -c 'printf "nHi! The passed value is: $testStringn"'"

int main()

{

    if(0>setenv("testString",testString,1)) return EXIT_FAILURE;

    if(0!=system(shellscript1)) return EXIT_FAILURE;

    return 0;

}

There are other ways, like generating the system argument in a buffer (e.g., with sprintf) or not using system.

system treats its argument like a a string to come after "/bin/sh", "-c". In my answer to using system() with command line arguments in C I coded up a simple my_system alternative that takes the arguments as a string array.

With it, you can do:

#define shellscript1 "printf "nHi! The passed value is: $1n" n"

char testString="blunt";

int main()

{

    if(0!=my_system("bash", (char*){"bash", "-c", shellscript1, "--", testString,0})) return EXIT_FAILURE;

    return 0;

}