Compile-Time Creation of Array of Templated Objects in High Level Synthesis
up vote
-2
down vote
favorite
I'm trying to accomplish this with HLS, not with "normal" C++, so most libraries (STL, boost, etc.) won't work as they can't be synthesized (manual memory management is not allowed). I think this should be possible with template metaprogramming, but I'm a little stuck.
I want to create an array of shift registers, each with a variable depth. I have N inputs, and I want to create N shift registers, with depths 1 to N, where N is known at compile time. My shift register class basically looks like
template<int DEPTH>
class shift_register{
int registers[DEPTH];
...
};
I tried following this and adapting it: Programmatically create static arrays at compile time in C++ , however, the issue is with the last line. Each templated shift register is going to be a different type, and so can't be put together in an array. But I do need an array, as there wouldn't be a way to access each shift register.
Any help would be appreciated!
c++ templates metaprogramming template-meta-programming
|
show 12 more comments
up vote
-2
down vote
favorite
I'm trying to accomplish this with HLS, not with "normal" C++, so most libraries (STL, boost, etc.) won't work as they can't be synthesized (manual memory management is not allowed). I think this should be possible with template metaprogramming, but I'm a little stuck.
I want to create an array of shift registers, each with a variable depth. I have N inputs, and I want to create N shift registers, with depths 1 to N, where N is known at compile time. My shift register class basically looks like
template<int DEPTH>
class shift_register{
int registers[DEPTH];
...
};
I tried following this and adapting it: Programmatically create static arrays at compile time in C++ , however, the issue is with the last line. Each templated shift register is going to be a different type, and so can't be put together in an array. But I do need an array, as there wouldn't be a way to access each shift register.
Any help would be appreciated!
c++ templates metaprogramming template-meta-programming
3
Sounds like an x/y-problem to me. Explain what "HLS" is and what you want to accomplish (not how). Up to now you said nothing but showed a trivial class containing an array.
– Swordfish
Nov 12 at 1:28
1
yes, but what you showed is basicallystd::array<>
so why not use that?
– Swordfish
Nov 12 at 1:41
1
You can't have an array of elements which types are different from another.
– Swordfish
Nov 12 at 1:46
1
You introduced a term "HLS" which you didn't explain and now you want to add "what needs to happen is that delays need to be added" some mysterious delays ... you aren't making any sense.
– Swordfish
Nov 12 at 1:47
2
So "array" means packed buffer of uniform type that can be accessed by runtime index. I have no idea what subset of this you need, but apparently you don't want uniform types. We cannot solve a problem without aidea what the problem is.
– Yakk - Adam Nevraumont
Nov 12 at 4:03
|
show 12 more comments
up vote
-2
down vote
favorite
up vote
-2
down vote
favorite
I'm trying to accomplish this with HLS, not with "normal" C++, so most libraries (STL, boost, etc.) won't work as they can't be synthesized (manual memory management is not allowed). I think this should be possible with template metaprogramming, but I'm a little stuck.
I want to create an array of shift registers, each with a variable depth. I have N inputs, and I want to create N shift registers, with depths 1 to N, where N is known at compile time. My shift register class basically looks like
template<int DEPTH>
class shift_register{
int registers[DEPTH];
...
};
I tried following this and adapting it: Programmatically create static arrays at compile time in C++ , however, the issue is with the last line. Each templated shift register is going to be a different type, and so can't be put together in an array. But I do need an array, as there wouldn't be a way to access each shift register.
Any help would be appreciated!
c++ templates metaprogramming template-meta-programming
I'm trying to accomplish this with HLS, not with "normal" C++, so most libraries (STL, boost, etc.) won't work as they can't be synthesized (manual memory management is not allowed). I think this should be possible with template metaprogramming, but I'm a little stuck.
I want to create an array of shift registers, each with a variable depth. I have N inputs, and I want to create N shift registers, with depths 1 to N, where N is known at compile time. My shift register class basically looks like
template<int DEPTH>
class shift_register{
int registers[DEPTH];
...
};
I tried following this and adapting it: Programmatically create static arrays at compile time in C++ , however, the issue is with the last line. Each templated shift register is going to be a different type, and so can't be put together in an array. But I do need an array, as there wouldn't be a way to access each shift register.
Any help would be appreciated!
c++ templates metaprogramming template-meta-programming
c++ templates metaprogramming template-meta-programming
asked Nov 12 at 1:10
Kartik Prabhu
1611210
1611210
3
Sounds like an x/y-problem to me. Explain what "HLS" is and what you want to accomplish (not how). Up to now you said nothing but showed a trivial class containing an array.
– Swordfish
Nov 12 at 1:28
1
yes, but what you showed is basicallystd::array<>
so why not use that?
– Swordfish
Nov 12 at 1:41
1
You can't have an array of elements which types are different from another.
– Swordfish
Nov 12 at 1:46
1
You introduced a term "HLS" which you didn't explain and now you want to add "what needs to happen is that delays need to be added" some mysterious delays ... you aren't making any sense.
– Swordfish
Nov 12 at 1:47
2
So "array" means packed buffer of uniform type that can be accessed by runtime index. I have no idea what subset of this you need, but apparently you don't want uniform types. We cannot solve a problem without aidea what the problem is.
– Yakk - Adam Nevraumont
Nov 12 at 4:03
|
show 12 more comments
3
Sounds like an x/y-problem to me. Explain what "HLS" is and what you want to accomplish (not how). Up to now you said nothing but showed a trivial class containing an array.
– Swordfish
Nov 12 at 1:28
1
yes, but what you showed is basicallystd::array<>
so why not use that?
– Swordfish
Nov 12 at 1:41
1
You can't have an array of elements which types are different from another.
– Swordfish
Nov 12 at 1:46
1
You introduced a term "HLS" which you didn't explain and now you want to add "what needs to happen is that delays need to be added" some mysterious delays ... you aren't making any sense.
– Swordfish
Nov 12 at 1:47
2
So "array" means packed buffer of uniform type that can be accessed by runtime index. I have no idea what subset of this you need, but apparently you don't want uniform types. We cannot solve a problem without aidea what the problem is.
– Yakk - Adam Nevraumont
Nov 12 at 4:03
3
3
Sounds like an x/y-problem to me. Explain what "HLS" is and what you want to accomplish (not how). Up to now you said nothing but showed a trivial class containing an array.
– Swordfish
Nov 12 at 1:28
Sounds like an x/y-problem to me. Explain what "HLS" is and what you want to accomplish (not how). Up to now you said nothing but showed a trivial class containing an array.
– Swordfish
Nov 12 at 1:28
1
1
yes, but what you showed is basically
std::array<>
so why not use that?– Swordfish
Nov 12 at 1:41
yes, but what you showed is basically
std::array<>
so why not use that?– Swordfish
Nov 12 at 1:41
1
1
You can't have an array of elements which types are different from another.
– Swordfish
Nov 12 at 1:46
You can't have an array of elements which types are different from another.
– Swordfish
Nov 12 at 1:46
1
1
You introduced a term "HLS" which you didn't explain and now you want to add "what needs to happen is that delays need to be added" some mysterious delays ... you aren't making any sense.
– Swordfish
Nov 12 at 1:47
You introduced a term "HLS" which you didn't explain and now you want to add "what needs to happen is that delays need to be added" some mysterious delays ... you aren't making any sense.
– Swordfish
Nov 12 at 1:47
2
2
So "array" means packed buffer of uniform type that can be accessed by runtime index. I have no idea what subset of this you need, but apparently you don't want uniform types. We cannot solve a problem without aidea what the problem is.
– Yakk - Adam Nevraumont
Nov 12 at 4:03
So "array" means packed buffer of uniform type that can be accessed by runtime index. I have no idea what subset of this you need, but apparently you don't want uniform types. We cannot solve a problem without aidea what the problem is.
– Yakk - Adam Nevraumont
Nov 12 at 4:03
|
show 12 more comments
3 Answers
3
active
oldest
votes
up vote
0
down vote
Just to clarify, my problem was the following: generate N shift_registers, templated from 1 to N, where N is a compile time constant.
For example, if I had N=4, I could easily write this as:
shift_register<1> sr1;
shift_register<2> sr2;
shift_register<3> sr3;
shift_register<4> sr4;
But this wouldn't be easy to change, if I wanted a different value for N in the future.
I ended up using the preprocessor and took the solution from here: How do I write a recursive for-loop "repeat" macro to generate C code with the CPP preprocessor?
I used the macros from that solution like this:
#define CAT(a, ...) PRIMITIVE_CAT(a, __VA_ARGS__)
#define PRIMITIVE_CAT(a, ...) a ## __VA_ARGS__
#define BODY(i) shift_register<i> CAT(sr,i)
REPEAT_ADD_ONE(BODY, N, 1);
And then something similar to that in order to access the shift registers, in a sort of array fashion.
This let me achieve the compile time generation that I was looking for, and get the array type access I needed.
Does my solution help you?
– David Ledger
Nov 12 at 9:30
add a comment |
up vote
0
down vote
Your question was somewhat difficult to understand but I'll do my best...
template <typename ... Args>
constexpr auto make_array(Args && ... pArgs)
{
using type = std::common_type_t<std::decay_t<Args>...>;
return std::array<type, sizeof...(Args)>{ (type)pArgs ... };
}
Then use it like this:
auto constexpr var_array_of_arrays = std::make_tuple
(
make_array(1, 2, 3, 3),
make_array(2, 3, 4),
make_array(1, 2, 3 ,4 ,3, 5)
);
To get the M'th element you access it like this, n has to actually be a compile-time constant:
std::get<M>(var_array_of_arrays);
To access the Nth element in the Mth array:
auto constexpr value = std::get<M>(var_array_of_arrays)[N]
An to improve the interface:
template <size_t M, size_t N, typename T >
constexpr decltype(auto) get_element(T && pInput)
{
return std::get<M>(std::forward<T>(pInput))[N];
}
Used like this:
auto constexpr element0_1 = get_element<0, 1>(var_array_of_arrays);
This will allow you to use an array of variable length arrays, or atleast something that behaves like that and is identical to that in memory.
A full example is here:
Online compiler
add a comment |
up vote
0
down vote
Whenever I hear "compile time number sequence" I think std::index_sequence
namespace detail {
template <typename>
struct shift_registers;
template <std::size_t ... Is> // 0, 1, ... N-1
struct shift_registers<std::index_sequence<Is...> > {
using type = std::tuple<shift_register<Is + 1>...>;
};
template <typename T>
using shift_registers_t = typename shift_registers<T>::type
}
template <std::size_t N>
using shift_registers = detail::shift_registers_t<std::make_index_sequence<N>>;
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
Just to clarify, my problem was the following: generate N shift_registers, templated from 1 to N, where N is a compile time constant.
For example, if I had N=4, I could easily write this as:
shift_register<1> sr1;
shift_register<2> sr2;
shift_register<3> sr3;
shift_register<4> sr4;
But this wouldn't be easy to change, if I wanted a different value for N in the future.
I ended up using the preprocessor and took the solution from here: How do I write a recursive for-loop "repeat" macro to generate C code with the CPP preprocessor?
I used the macros from that solution like this:
#define CAT(a, ...) PRIMITIVE_CAT(a, __VA_ARGS__)
#define PRIMITIVE_CAT(a, ...) a ## __VA_ARGS__
#define BODY(i) shift_register<i> CAT(sr,i)
REPEAT_ADD_ONE(BODY, N, 1);
And then something similar to that in order to access the shift registers, in a sort of array fashion.
This let me achieve the compile time generation that I was looking for, and get the array type access I needed.
Does my solution help you?
– David Ledger
Nov 12 at 9:30
add a comment |
up vote
0
down vote
Just to clarify, my problem was the following: generate N shift_registers, templated from 1 to N, where N is a compile time constant.
For example, if I had N=4, I could easily write this as:
shift_register<1> sr1;
shift_register<2> sr2;
shift_register<3> sr3;
shift_register<4> sr4;
But this wouldn't be easy to change, if I wanted a different value for N in the future.
I ended up using the preprocessor and took the solution from here: How do I write a recursive for-loop "repeat" macro to generate C code with the CPP preprocessor?
I used the macros from that solution like this:
#define CAT(a, ...) PRIMITIVE_CAT(a, __VA_ARGS__)
#define PRIMITIVE_CAT(a, ...) a ## __VA_ARGS__
#define BODY(i) shift_register<i> CAT(sr,i)
REPEAT_ADD_ONE(BODY, N, 1);
And then something similar to that in order to access the shift registers, in a sort of array fashion.
This let me achieve the compile time generation that I was looking for, and get the array type access I needed.
Does my solution help you?
– David Ledger
Nov 12 at 9:30
add a comment |
up vote
0
down vote
up vote
0
down vote
Just to clarify, my problem was the following: generate N shift_registers, templated from 1 to N, where N is a compile time constant.
For example, if I had N=4, I could easily write this as:
shift_register<1> sr1;
shift_register<2> sr2;
shift_register<3> sr3;
shift_register<4> sr4;
But this wouldn't be easy to change, if I wanted a different value for N in the future.
I ended up using the preprocessor and took the solution from here: How do I write a recursive for-loop "repeat" macro to generate C code with the CPP preprocessor?
I used the macros from that solution like this:
#define CAT(a, ...) PRIMITIVE_CAT(a, __VA_ARGS__)
#define PRIMITIVE_CAT(a, ...) a ## __VA_ARGS__
#define BODY(i) shift_register<i> CAT(sr,i)
REPEAT_ADD_ONE(BODY, N, 1);
And then something similar to that in order to access the shift registers, in a sort of array fashion.
This let me achieve the compile time generation that I was looking for, and get the array type access I needed.
Just to clarify, my problem was the following: generate N shift_registers, templated from 1 to N, where N is a compile time constant.
For example, if I had N=4, I could easily write this as:
shift_register<1> sr1;
shift_register<2> sr2;
shift_register<3> sr3;
shift_register<4> sr4;
But this wouldn't be easy to change, if I wanted a different value for N in the future.
I ended up using the preprocessor and took the solution from here: How do I write a recursive for-loop "repeat" macro to generate C code with the CPP preprocessor?
I used the macros from that solution like this:
#define CAT(a, ...) PRIMITIVE_CAT(a, __VA_ARGS__)
#define PRIMITIVE_CAT(a, ...) a ## __VA_ARGS__
#define BODY(i) shift_register<i> CAT(sr,i)
REPEAT_ADD_ONE(BODY, N, 1);
And then something similar to that in order to access the shift registers, in a sort of array fashion.
This let me achieve the compile time generation that I was looking for, and get the array type access I needed.
answered Nov 12 at 7:12
Kartik Prabhu
1611210
1611210
Does my solution help you?
– David Ledger
Nov 12 at 9:30
add a comment |
Does my solution help you?
– David Ledger
Nov 12 at 9:30
Does my solution help you?
– David Ledger
Nov 12 at 9:30
Does my solution help you?
– David Ledger
Nov 12 at 9:30
add a comment |
up vote
0
down vote
Your question was somewhat difficult to understand but I'll do my best...
template <typename ... Args>
constexpr auto make_array(Args && ... pArgs)
{
using type = std::common_type_t<std::decay_t<Args>...>;
return std::array<type, sizeof...(Args)>{ (type)pArgs ... };
}
Then use it like this:
auto constexpr var_array_of_arrays = std::make_tuple
(
make_array(1, 2, 3, 3),
make_array(2, 3, 4),
make_array(1, 2, 3 ,4 ,3, 5)
);
To get the M'th element you access it like this, n has to actually be a compile-time constant:
std::get<M>(var_array_of_arrays);
To access the Nth element in the Mth array:
auto constexpr value = std::get<M>(var_array_of_arrays)[N]
An to improve the interface:
template <size_t M, size_t N, typename T >
constexpr decltype(auto) get_element(T && pInput)
{
return std::get<M>(std::forward<T>(pInput))[N];
}
Used like this:
auto constexpr element0_1 = get_element<0, 1>(var_array_of_arrays);
This will allow you to use an array of variable length arrays, or atleast something that behaves like that and is identical to that in memory.
A full example is here:
Online compiler
add a comment |
up vote
0
down vote
Your question was somewhat difficult to understand but I'll do my best...
template <typename ... Args>
constexpr auto make_array(Args && ... pArgs)
{
using type = std::common_type_t<std::decay_t<Args>...>;
return std::array<type, sizeof...(Args)>{ (type)pArgs ... };
}
Then use it like this:
auto constexpr var_array_of_arrays = std::make_tuple
(
make_array(1, 2, 3, 3),
make_array(2, 3, 4),
make_array(1, 2, 3 ,4 ,3, 5)
);
To get the M'th element you access it like this, n has to actually be a compile-time constant:
std::get<M>(var_array_of_arrays);
To access the Nth element in the Mth array:
auto constexpr value = std::get<M>(var_array_of_arrays)[N]
An to improve the interface:
template <size_t M, size_t N, typename T >
constexpr decltype(auto) get_element(T && pInput)
{
return std::get<M>(std::forward<T>(pInput))[N];
}
Used like this:
auto constexpr element0_1 = get_element<0, 1>(var_array_of_arrays);
This will allow you to use an array of variable length arrays, or atleast something that behaves like that and is identical to that in memory.
A full example is here:
Online compiler
add a comment |
up vote
0
down vote
up vote
0
down vote
Your question was somewhat difficult to understand but I'll do my best...
template <typename ... Args>
constexpr auto make_array(Args && ... pArgs)
{
using type = std::common_type_t<std::decay_t<Args>...>;
return std::array<type, sizeof...(Args)>{ (type)pArgs ... };
}
Then use it like this:
auto constexpr var_array_of_arrays = std::make_tuple
(
make_array(1, 2, 3, 3),
make_array(2, 3, 4),
make_array(1, 2, 3 ,4 ,3, 5)
);
To get the M'th element you access it like this, n has to actually be a compile-time constant:
std::get<M>(var_array_of_arrays);
To access the Nth element in the Mth array:
auto constexpr value = std::get<M>(var_array_of_arrays)[N]
An to improve the interface:
template <size_t M, size_t N, typename T >
constexpr decltype(auto) get_element(T && pInput)
{
return std::get<M>(std::forward<T>(pInput))[N];
}
Used like this:
auto constexpr element0_1 = get_element<0, 1>(var_array_of_arrays);
This will allow you to use an array of variable length arrays, or atleast something that behaves like that and is identical to that in memory.
A full example is here:
Online compiler
Your question was somewhat difficult to understand but I'll do my best...
template <typename ... Args>
constexpr auto make_array(Args && ... pArgs)
{
using type = std::common_type_t<std::decay_t<Args>...>;
return std::array<type, sizeof...(Args)>{ (type)pArgs ... };
}
Then use it like this:
auto constexpr var_array_of_arrays = std::make_tuple
(
make_array(1, 2, 3, 3),
make_array(2, 3, 4),
make_array(1, 2, 3 ,4 ,3, 5)
);
To get the M'th element you access it like this, n has to actually be a compile-time constant:
std::get<M>(var_array_of_arrays);
To access the Nth element in the Mth array:
auto constexpr value = std::get<M>(var_array_of_arrays)[N]
An to improve the interface:
template <size_t M, size_t N, typename T >
constexpr decltype(auto) get_element(T && pInput)
{
return std::get<M>(std::forward<T>(pInput))[N];
}
Used like this:
auto constexpr element0_1 = get_element<0, 1>(var_array_of_arrays);
This will allow you to use an array of variable length arrays, or atleast something that behaves like that and is identical to that in memory.
A full example is here:
Online compiler
edited Nov 12 at 8:29
answered Nov 12 at 8:18
David Ledger
887
887
add a comment |
add a comment |
up vote
0
down vote
Whenever I hear "compile time number sequence" I think std::index_sequence
namespace detail {
template <typename>
struct shift_registers;
template <std::size_t ... Is> // 0, 1, ... N-1
struct shift_registers<std::index_sequence<Is...> > {
using type = std::tuple<shift_register<Is + 1>...>;
};
template <typename T>
using shift_registers_t = typename shift_registers<T>::type
}
template <std::size_t N>
using shift_registers = detail::shift_registers_t<std::make_index_sequence<N>>;
add a comment |
up vote
0
down vote
Whenever I hear "compile time number sequence" I think std::index_sequence
namespace detail {
template <typename>
struct shift_registers;
template <std::size_t ... Is> // 0, 1, ... N-1
struct shift_registers<std::index_sequence<Is...> > {
using type = std::tuple<shift_register<Is + 1>...>;
};
template <typename T>
using shift_registers_t = typename shift_registers<T>::type
}
template <std::size_t N>
using shift_registers = detail::shift_registers_t<std::make_index_sequence<N>>;
add a comment |
up vote
0
down vote
up vote
0
down vote
Whenever I hear "compile time number sequence" I think std::index_sequence
namespace detail {
template <typename>
struct shift_registers;
template <std::size_t ... Is> // 0, 1, ... N-1
struct shift_registers<std::index_sequence<Is...> > {
using type = std::tuple<shift_register<Is + 1>...>;
};
template <typename T>
using shift_registers_t = typename shift_registers<T>::type
}
template <std::size_t N>
using shift_registers = detail::shift_registers_t<std::make_index_sequence<N>>;
Whenever I hear "compile time number sequence" I think std::index_sequence
namespace detail {
template <typename>
struct shift_registers;
template <std::size_t ... Is> // 0, 1, ... N-1
struct shift_registers<std::index_sequence<Is...> > {
using type = std::tuple<shift_register<Is + 1>...>;
};
template <typename T>
using shift_registers_t = typename shift_registers<T>::type
}
template <std::size_t N>
using shift_registers = detail::shift_registers_t<std::make_index_sequence<N>>;
edited Nov 12 at 11:19
answered Nov 12 at 11:02
Caleth
15.7k22037
15.7k22037
add a comment |
add a comment |
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3
Sounds like an x/y-problem to me. Explain what "HLS" is and what you want to accomplish (not how). Up to now you said nothing but showed a trivial class containing an array.
– Swordfish
Nov 12 at 1:28
1
yes, but what you showed is basically
std::array<>
so why not use that?– Swordfish
Nov 12 at 1:41
1
You can't have an array of elements which types are different from another.
– Swordfish
Nov 12 at 1:46
1
You introduced a term "HLS" which you didn't explain and now you want to add "what needs to happen is that delays need to be added" some mysterious delays ... you aren't making any sense.
– Swordfish
Nov 12 at 1:47
2
So "array" means packed buffer of uniform type that can be accessed by runtime index. I have no idea what subset of this you need, but apparently you don't want uniform types. We cannot solve a problem without aidea what the problem is.
– Yakk - Adam Nevraumont
Nov 12 at 4:03