Extracting a body of an email using [Python 3.6]











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0
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I have an inbox and I need to write a code that triggers every time a new message arrives, and extracts a body of that email.



I have this code so far:



import poplib, email
from email import parser

pop_conn = poplib.POP3_SSL('pop.gmail.com')
email_user = 'email@gmail.com'
email_pass = 'password'

pop_conn.user(email_user)
pop_conn.pass_(email_pass)

#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1,
len(pop_conn.list()[1]) + 1)]

#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]
for message in messages:
print(message.get_payload(None, True))

pop_conn.quit()


The error I am getting is:



---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-6-2a08d6a8ccf9> in <module>()
2 #Parse message intom an email object:
3 #messages = [email.message_from_bytes(mssg) for mssg in messages]
----> 4 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
5 for message in messages:
6 # print(message['body'])

<ipython-input-6-2a08d6a8ccf9> in <listcomp>(.0)
2 #Parse message intom an email object:
3 #messages = [email.message_from_bytes(mssg) for mssg in messages]
----> 4 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
5 for message in messages:
6 # print(message['body'])

/Applications/anaconda3/lib/python3.6/email/parser.py in parsestr(self, text, headersonly)
66 the file.
67 """
---> 68 return self.parse(StringIO(text), headersonly=headersonly)
69
70

TypeError: initial_value must be str or None, not tuple

TypeError: initial_value must be str or None, not tuple


Why am I getting a tuple? How do I extract a body from the messages[n]?










share|improve this question
























  • Which line in this script is giving you the error? What does the full traceback look like?
    – tripleee
    Nov 9 at 6:14










  • @tripleee updated an error message
    – Feyzi Bagirov
    Nov 11 at 16:46















up vote
0
down vote

favorite












I have an inbox and I need to write a code that triggers every time a new message arrives, and extracts a body of that email.



I have this code so far:



import poplib, email
from email import parser

pop_conn = poplib.POP3_SSL('pop.gmail.com')
email_user = 'email@gmail.com'
email_pass = 'password'

pop_conn.user(email_user)
pop_conn.pass_(email_pass)

#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1,
len(pop_conn.list()[1]) + 1)]

#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]
for message in messages:
print(message.get_payload(None, True))

pop_conn.quit()


The error I am getting is:



---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-6-2a08d6a8ccf9> in <module>()
2 #Parse message intom an email object:
3 #messages = [email.message_from_bytes(mssg) for mssg in messages]
----> 4 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
5 for message in messages:
6 # print(message['body'])

<ipython-input-6-2a08d6a8ccf9> in <listcomp>(.0)
2 #Parse message intom an email object:
3 #messages = [email.message_from_bytes(mssg) for mssg in messages]
----> 4 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
5 for message in messages:
6 # print(message['body'])

/Applications/anaconda3/lib/python3.6/email/parser.py in parsestr(self, text, headersonly)
66 the file.
67 """
---> 68 return self.parse(StringIO(text), headersonly=headersonly)
69
70

TypeError: initial_value must be str or None, not tuple

TypeError: initial_value must be str or None, not tuple


Why am I getting a tuple? How do I extract a body from the messages[n]?










share|improve this question
























  • Which line in this script is giving you the error? What does the full traceback look like?
    – tripleee
    Nov 9 at 6:14










  • @tripleee updated an error message
    – Feyzi Bagirov
    Nov 11 at 16:46













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have an inbox and I need to write a code that triggers every time a new message arrives, and extracts a body of that email.



I have this code so far:



import poplib, email
from email import parser

pop_conn = poplib.POP3_SSL('pop.gmail.com')
email_user = 'email@gmail.com'
email_pass = 'password'

pop_conn.user(email_user)
pop_conn.pass_(email_pass)

#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1,
len(pop_conn.list()[1]) + 1)]

#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]
for message in messages:
print(message.get_payload(None, True))

pop_conn.quit()


The error I am getting is:



---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-6-2a08d6a8ccf9> in <module>()
2 #Parse message intom an email object:
3 #messages = [email.message_from_bytes(mssg) for mssg in messages]
----> 4 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
5 for message in messages:
6 # print(message['body'])

<ipython-input-6-2a08d6a8ccf9> in <listcomp>(.0)
2 #Parse message intom an email object:
3 #messages = [email.message_from_bytes(mssg) for mssg in messages]
----> 4 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
5 for message in messages:
6 # print(message['body'])

/Applications/anaconda3/lib/python3.6/email/parser.py in parsestr(self, text, headersonly)
66 the file.
67 """
---> 68 return self.parse(StringIO(text), headersonly=headersonly)
69
70

TypeError: initial_value must be str or None, not tuple

TypeError: initial_value must be str or None, not tuple


Why am I getting a tuple? How do I extract a body from the messages[n]?










share|improve this question















I have an inbox and I need to write a code that triggers every time a new message arrives, and extracts a body of that email.



I have this code so far:



import poplib, email
from email import parser

pop_conn = poplib.POP3_SSL('pop.gmail.com')
email_user = 'email@gmail.com'
email_pass = 'password'

pop_conn.user(email_user)
pop_conn.pass_(email_pass)

#Get messages from server:
messages = [pop_conn.retr(i) for i in range(1,
len(pop_conn.list()[1]) + 1)]

#Parse message intom an email object:
messages = [parser.Parser().parsestr(mssg) for mssg in messages]
for message in messages:
print(message.get_payload(None, True))

pop_conn.quit()


The error I am getting is:



---------------------------------------------------------------------------
TypeError Traceback (most recent call last)
<ipython-input-6-2a08d6a8ccf9> in <module>()
2 #Parse message intom an email object:
3 #messages = [email.message_from_bytes(mssg) for mssg in messages]
----> 4 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
5 for message in messages:
6 # print(message['body'])

<ipython-input-6-2a08d6a8ccf9> in <listcomp>(.0)
2 #Parse message intom an email object:
3 #messages = [email.message_from_bytes(mssg) for mssg in messages]
----> 4 messages = [parser.Parser().parsestr(mssg) for mssg in messages]
5 for message in messages:
6 # print(message['body'])

/Applications/anaconda3/lib/python3.6/email/parser.py in parsestr(self, text, headersonly)
66 the file.
67 """
---> 68 return self.parse(StringIO(text), headersonly=headersonly)
69
70

TypeError: initial_value must be str or None, not tuple

TypeError: initial_value must be str or None, not tuple


Why am I getting a tuple? How do I extract a body from the messages[n]?







email python-3.6 poplib






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 11 at 16:46

























asked Nov 9 at 6:10









Feyzi Bagirov

363722




363722












  • Which line in this script is giving you the error? What does the full traceback look like?
    – tripleee
    Nov 9 at 6:14










  • @tripleee updated an error message
    – Feyzi Bagirov
    Nov 11 at 16:46


















  • Which line in this script is giving you the error? What does the full traceback look like?
    – tripleee
    Nov 9 at 6:14










  • @tripleee updated an error message
    – Feyzi Bagirov
    Nov 11 at 16:46
















Which line in this script is giving you the error? What does the full traceback look like?
– tripleee
Nov 9 at 6:14




Which line in this script is giving you the error? What does the full traceback look like?
– tripleee
Nov 9 at 6:14












@tripleee updated an error message
– Feyzi Bagirov
Nov 11 at 16:46




@tripleee updated an error message
– Feyzi Bagirov
Nov 11 at 16:46












1 Answer
1






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up vote
0
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The return value from retr() is a tuple. The second value in the tuple is a list of lines which comprise the actual message. See the Python poplib documentation for details.



# Get messages from server
popped = ['n'.join(pop_conn.retr(i)[1])
for i in range(1, len(pop_conn.list()[1]) + 1)]

# Parse message into an email object
messages = [parser.Parser().parsestr(mssg) for mssg in popped]


Notice also how we avoid reusing the same variable name for objects of different types.






share|improve this answer























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    1 Answer
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    up vote
    0
    down vote













    The return value from retr() is a tuple. The second value in the tuple is a list of lines which comprise the actual message. See the Python poplib documentation for details.



    # Get messages from server
    popped = ['n'.join(pop_conn.retr(i)[1])
    for i in range(1, len(pop_conn.list()[1]) + 1)]

    # Parse message into an email object
    messages = [parser.Parser().parsestr(mssg) for mssg in popped]


    Notice also how we avoid reusing the same variable name for objects of different types.






    share|improve this answer



























      up vote
      0
      down vote













      The return value from retr() is a tuple. The second value in the tuple is a list of lines which comprise the actual message. See the Python poplib documentation for details.



      # Get messages from server
      popped = ['n'.join(pop_conn.retr(i)[1])
      for i in range(1, len(pop_conn.list()[1]) + 1)]

      # Parse message into an email object
      messages = [parser.Parser().parsestr(mssg) for mssg in popped]


      Notice also how we avoid reusing the same variable name for objects of different types.






      share|improve this answer

























        up vote
        0
        down vote










        up vote
        0
        down vote









        The return value from retr() is a tuple. The second value in the tuple is a list of lines which comprise the actual message. See the Python poplib documentation for details.



        # Get messages from server
        popped = ['n'.join(pop_conn.retr(i)[1])
        for i in range(1, len(pop_conn.list()[1]) + 1)]

        # Parse message into an email object
        messages = [parser.Parser().parsestr(mssg) for mssg in popped]


        Notice also how we avoid reusing the same variable name for objects of different types.






        share|improve this answer














        The return value from retr() is a tuple. The second value in the tuple is a list of lines which comprise the actual message. See the Python poplib documentation for details.



        # Get messages from server
        popped = ['n'.join(pop_conn.retr(i)[1])
        for i in range(1, len(pop_conn.list()[1]) + 1)]

        # Parse message into an email object
        messages = [parser.Parser().parsestr(mssg) for mssg in popped]


        Notice also how we avoid reusing the same variable name for objects of different types.







        share|improve this answer














        share|improve this answer



        share|improve this answer








        edited Nov 11 at 19:11

























        answered Nov 11 at 19:05









        tripleee

        87.4k12122177




        87.4k12122177






























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