My code is not executing anything after the for loop
1
I am having a problem with a test project in a visual studio.
From my understanding, the problem comes from the function 'yeet'.
The function does not finish the loop, since it does not print out "why!!" .
Could someone help me in identifying what is wrong with my code?
Here is my code
string reet(char reet) {
switch (reet) {
case 'a':
return "Zg";
break;
case'b':
return "dA";
break;
case 'c':
return "dG";
break;
case 'd':
return "aw";
break;
case 'e':
return "bw";
break;
case 'f':
return "dQ";
break;
case 'g':
return "cg";
break;
case 'h':
return "ZA";
break;
case 'i':
return "cQ";
break;
case 'j':
return "YQ";
break;
case 'k':
return "eA";
break;
case 'l':
return "dw";
break;
case 'm':
return "cw";
break;
case 'n':
return "ag";
break;
case 'o':
return "eQ";
break;
case 'p':
return "bA";
break;
case 'q':
return "aA";
break;
case 'r':
return "ZQ";
break;
case 's':
return "cA";
break;
case 't':
return "aw";
break;
case 'u':
return "eg";
break;
case 'v':
return "bg";
break;
case 'w':
return "aq";
break;
case 'x':
return "bQ";
break;
case 'y':
return "Yg";
break;
case 'z':
return "Zw";
break;
}
}
void yeet(string input) {
string yeet = input;
string bigBoi = "";
int yeetL = yeet.length() + 1;
for (int x = 0; x < yeetL;) {
bigBoi = bigBoi + reet(yeet[x]);
x++;
cout << bigBoi << endl;
}
cout << "why!" << endl;
}
int main() {
string input;
cin >> input;
yeet(input);
}
For further Information, I am Using C++ on Microsoft Visual Studio 2013.
c++ visual-c++
edited Nov 13 at 3:58
Bandi Kishore
3,3341730
asked Nov 12 at 21:02
NipIsTrue
196
add a comment |
1
I am having a problem with a test project in a visual studio.
From my understanding, the problem comes from the function 'yeet'.
The function does not finish the loop, since it does not print out "why!!" .
Could someone help me in identifying what is wrong with my code?
Here is my code
string reet(char reet) {
switch (reet) {
case 'a':
return "Zg";
break;
case'b':
return "dA";
break;
case 'c':
return "dG";
break;
case 'd':
return "aw";
break;
case 'e':
return "bw";
break;
case 'f':
return "dQ";
break;
case 'g':
return "cg";
break;
case 'h':
return "ZA";
break;
case 'i':
return "cQ";
break;
case 'j':
return "YQ";
break;
case 'k':
return "eA";
break;
case 'l':
return "dw";
break;
case 'm':
return "cw";
break;
case 'n':
return "ag";
break;
case 'o':
return "eQ";
break;
case 'p':
return "bA";
break;
case 'q':
return "aA";
break;
case 'r':
return "ZQ";
break;
case 's':
return "cA";
break;
case 't':
return "aw";
break;
case 'u':
return "eg";
break;
case 'v':
return "bg";
break;
case 'w':
return "aq";
break;
case 'x':
return "bQ";
break;
case 'y':
return "Yg";
break;
case 'z':
return "Zw";
break;
}
}
void yeet(string input) {
string yeet = input;
string bigBoi = "";
int yeetL = yeet.length() + 1;
for (int x = 0; x < yeetL;) {
bigBoi = bigBoi + reet(yeet[x]);
x++;
cout << bigBoi << endl;
}
cout << "why!" << endl;
}
int main() {
string input;
cin >> input;
yeet(input);
}
For further Information, I am Using C++ on Microsoft Visual Studio 2013.
c++ visual-c++
edited Nov 13 at 3:58
Bandi Kishore
3,3341730
asked Nov 12 at 21:02
NipIsTrue
196
What input are you entering?reetdoes not return a value in all cases.
– Johnny Mopp
Nov 12 at 21:07
1
On the last iteration of the loop, you callreet(yeet[yeet.length()]). Here,yeet[yeet.length()is the character- the terminating NUL character.reet('')exhibits undefined behavior, by way of non-voidfunction reaching the closing brace without encountering areturnstatement. In fact, depending on user input, it's possible you hit this case of undefined behavior sooner; but you definitely hit it on the last iteration regardless.
– Igor Tandetnik
Nov 12 at 21:09
2
Which is why you should: 1. Usestd::string::atinstead as it will throw astd::out_of_rangeexception. 2. Enable all compiler warnings which should tell you that not all paths return a value.
– Johnny Mopp
Nov 12 at 21:14
Ok, adding a default case worked. Thank you for helping!!
– NipIsTrue
Nov 12 at 22:53
1
You can also considerstd::map<char, std::string> mp{{'a',"str1"},{'b',"str2"}}->mp['a']prints"str1"
– Barmak Shemirani
Nov 12 at 23:42
add a comment |
1
1
1
I am having a problem with a test project in a visual studio.
From my understanding, the problem comes from the function 'yeet'.
The function does not finish the loop, since it does not print out "why!!" .
Could someone help me in identifying what is wrong with my code?
Here is my code
string reet(char reet) {
switch (reet) {
case 'a':
return "Zg";
break;
case'b':
return "dA";
break;
case 'c':
return "dG";
break;
case 'd':
return "aw";
break;
case 'e':
return "bw";
break;
case 'f':
return "dQ";
break;
case 'g':
return "cg";
break;
case 'h':
return "ZA";
break;
case 'i':
return "cQ";
break;
case 'j':
return "YQ";
break;
case 'k':
return "eA";
break;
case 'l':
return "dw";
break;
case 'm':
return "cw";
break;
case 'n':
return "ag";
break;
case 'o':
return "eQ";
break;
case 'p':
return "bA";
break;
case 'q':
return "aA";
break;
case 'r':
return "ZQ";
break;
case 's':
return "cA";
break;
case 't':
return "aw";
break;
case 'u':
return "eg";
break;
case 'v':
return "bg";
break;
case 'w':
return "aq";
break;
case 'x':
return "bQ";
break;
case 'y':
return "Yg";
break;
case 'z':
return "Zw";
break;
}
}
void yeet(string input) {
string yeet = input;
string bigBoi = "";
int yeetL = yeet.length() + 1;
for (int x = 0; x < yeetL;) {
bigBoi = bigBoi + reet(yeet[x]);
x++;
cout << bigBoi << endl;
}
cout << "why!" << endl;
}
int main() {
string input;
cin >> input;
yeet(input);
}
For further Information, I am Using C++ on Microsoft Visual Studio 2013.
c++ visual-c++
edited Nov 13 at 3:58
Bandi Kishore
3,3341730
asked Nov 12 at 21:02
NipIsTrue
196
I am having a problem with a test project in a visual studio.
From my understanding, the problem comes from the function 'yeet'.
The function does not finish the loop, since it does not print out "why!!" .
Could someone help me in identifying what is wrong with my code?
Here is my code
string reet(char reet) {
switch (reet) {
case 'a':
return "Zg";
break;
case'b':
return "dA";
break;
case 'c':
return "dG";
break;
case 'd':
return "aw";
break;
case 'e':
return "bw";
break;
case 'f':
return "dQ";
break;
case 'g':
return "cg";
break;
case 'h':
return "ZA";
break;
case 'i':
return "cQ";
break;
case 'j':
return "YQ";
break;
case 'k':
return "eA";
break;
case 'l':
return "dw";
break;
case 'm':
return "cw";
break;
case 'n':
return "ag";
break;
case 'o':
return "eQ";
break;
case 'p':
return "bA";
break;
case 'q':
return "aA";
break;
case 'r':
return "ZQ";
break;
case 's':
return "cA";
break;
case 't':
return "aw";
break;
case 'u':
return "eg";
break;
case 'v':
return "bg";
break;
case 'w':
return "aq";
break;
case 'x':
return "bQ";
break;
case 'y':
return "Yg";
break;
case 'z':
return "Zw";
break;
}
}
void yeet(string input) {
string yeet = input;
string bigBoi = "";
int yeetL = yeet.length() + 1;
for (int x = 0; x < yeetL;) {
bigBoi = bigBoi + reet(yeet[x]);
x++;
cout << bigBoi << endl;
}
cout << "why!" << endl;
}
int main() {
string input;
cin >> input;
yeet(input);
}
For further Information, I am Using C++ on Microsoft Visual Studio 2013.
c++ visual-c++
c++ visual-c++
edited Nov 13 at 3:58
Bandi Kishore
3,3341730
asked Nov 12 at 21:02
NipIsTrue
196
edited Nov 13 at 3:58
Bandi Kishore
3,3341730
asked Nov 12 at 21:02
NipIsTrue
196
edited Nov 13 at 3:58
Bandi Kishore
3,3341730
edited Nov 13 at 3:58
Bandi Kishore
3,3341730
edited Nov 13 at 3:58
Bandi Kishore
3,3341730
3,3341730
asked Nov 12 at 21:02
NipIsTrue
196
asked Nov 12 at 21:02
NipIsTrue
196
asked Nov 12 at 21:02
NipIsTrue
196
196
What input are you entering?reetdoes not return a value in all cases.
– Johnny Mopp
Nov 12 at 21:07
1
On the last iteration of the loop, you callreet(yeet[yeet.length()]). Here,yeet[yeet.length()is the character- the terminating NUL character.reet('')exhibits undefined behavior, by way of non-voidfunction reaching the closing brace without encountering areturnstatement. In fact, depending on user input, it's possible you hit this case of undefined behavior sooner; but you definitely hit it on the last iteration regardless.
– Igor Tandetnik
Nov 12 at 21:09
2
Which is why you should: 1. Usestd::string::atinstead as it will throw astd::out_of_rangeexception. 2. Enable all compiler warnings which should tell you that not all paths return a value.
– Johnny Mopp
Nov 12 at 21:14
Ok, adding a default case worked. Thank you for helping!!
– NipIsTrue
Nov 12 at 22:53
1
You can also considerstd::map<char, std::string> mp{{'a',"str1"},{'b',"str2"}}->mp['a']prints"str1"
– Barmak Shemirani
Nov 12 at 23:42
add a comment |
What input are you entering?reetdoes not return a value in all cases.
– Johnny Mopp
Nov 12 at 21:07
1
On the last iteration of the loop, you callreet(yeet[yeet.length()]). Here,yeet[yeet.length()is the character- the terminating NUL character.reet('')exhibits undefined behavior, by way of non-voidfunction reaching the closing brace without encountering areturnstatement. In fact, depending on user input, it's possible you hit this case of undefined behavior sooner; but you definitely hit it on the last iteration regardless.
– Igor Tandetnik
Nov 12 at 21:09
2
Which is why you should: 1. Usestd::string::atinstead as it will throw astd::out_of_rangeexception. 2. Enable all compiler warnings which should tell you that not all paths return a value.
– Johnny Mopp
Nov 12 at 21:14
Ok, adding a default case worked. Thank you for helping!!
– NipIsTrue
Nov 12 at 22:53
1
You can also considerstd::map<char, std::string> mp{{'a',"str1"},{'b',"str2"}}->mp['a']prints"str1"
– Barmak Shemirani
Nov 12 at 23:42
What input are you entering?
reet does not return a value in all cases.– Johnny Mopp
Nov 12 at 21:07
What input are you entering?
reet does not return a value in all cases.– Johnny Mopp
Nov 12 at 21:07
1
1
On the last iteration of the loop, you call
reet(yeet[yeet.length()]). Here, yeet[yeet.length() is the character reet('') exhibits undefined behavior, by way of non-void function reaching the closing brace without encountering a return statement. In fact, depending on user input, it's possible you hit this case of undefined behavior sooner; but you definitely hit it on the last iteration regardless.– Igor Tandetnik
Nov 12 at 21:09
On the last iteration of the loop, you call
reet(yeet[yeet.length()]). Here, yeet[yeet.length() is the character reet('') exhibits undefined behavior, by way of non-void function reaching the closing brace without encountering a return statement. In fact, depending on user input, it's possible you hit this case of undefined behavior sooner; but you definitely hit it on the last iteration regardless.– Igor Tandetnik
Nov 12 at 21:09
2
2
Which is why you should: 1. Use
std::string::at instead as it will throw a std::out_of_range exception. 2. Enable all compiler warnings which should tell you that not all paths return a value.– Johnny Mopp
Nov 12 at 21:14
Which is why you should: 1. Use
std::string::at instead as it will throw a std::out_of_range exception. 2. Enable all compiler warnings which should tell you that not all paths return a value.– Johnny Mopp
Nov 12 at 21:14
Ok, adding a default case worked. Thank you for helping!!
– NipIsTrue
Nov 12 at 22:53
Ok, adding a default case worked. Thank you for helping!!
– NipIsTrue
Nov 12 at 22:53
1
1
You can also consider
std::map<char, std::string> mp{{'a',"str1"},{'b',"str2"}} -> mp['a'] prints "str1"– Barmak Shemirani
Nov 12 at 23:42
You can also consider
std::map<char, std::string> mp{{'a',"str1"},{'b',"str2"}} -> mp['a'] prints "str1"– Barmak Shemirani
Nov 12 at 23:42
add a comment |
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What input are you entering?
reetdoes not return a value in all cases.– Johnny Mopp
Nov 12 at 21:07
1
On the last iteration of the loop, you call
reet(yeet[yeet.length()]). Here,yeet[yeet.length()is the character- the terminating NUL character.reet('')exhibits undefined behavior, by way of non-voidfunction reaching the closing brace without encountering areturnstatement. In fact, depending on user input, it's possible you hit this case of undefined behavior sooner; but you definitely hit it on the last iteration regardless.– Igor Tandetnik
Nov 12 at 21:09
2
Which is why you should: 1. Use
std::string::atinstead as it will throw astd::out_of_rangeexception. 2. Enable all compiler warnings which should tell you that not all paths return a value.– Johnny Mopp
Nov 12 at 21:14
Ok, adding a default case worked. Thank you for helping!!
– NipIsTrue
Nov 12 at 22:53
1
You can also consider
std::map<char, std::string> mp{{'a',"str1"},{'b',"str2"}}->mp['a']prints"str1"– Barmak Shemirani
Nov 12 at 23:42