Is there a way to declare variables in list creation?












0















I'd like to create and assign new String variables when I create my list. I'd like to do something like:



l = [first = "first", second = "second"]


Is something like this possible?










share|improve this question

























  • Don't you want a dictionary instead?

    – usr2564301
    Nov 18 '18 at 22:05











  • What do you want to achieve by doing this? Assigning in separate statements is perfectly fine and being obsessed with one-liners usually leads to code that is hard to read and understand.

    – Goyo
    Nov 18 '18 at 22:26






  • 1





    Not clean from your question, but suggest you read Why you don't want to dynamically create variables.

    – martineau
    Nov 18 '18 at 22:45


















0















I'd like to create and assign new String variables when I create my list. I'd like to do something like:



l = [first = "first", second = "second"]


Is something like this possible?










share|improve this question

























  • Don't you want a dictionary instead?

    – usr2564301
    Nov 18 '18 at 22:05











  • What do you want to achieve by doing this? Assigning in separate statements is perfectly fine and being obsessed with one-liners usually leads to code that is hard to read and understand.

    – Goyo
    Nov 18 '18 at 22:26






  • 1





    Not clean from your question, but suggest you read Why you don't want to dynamically create variables.

    – martineau
    Nov 18 '18 at 22:45
















0












0








0








I'd like to create and assign new String variables when I create my list. I'd like to do something like:



l = [first = "first", second = "second"]


Is something like this possible?










share|improve this question
















I'd like to create and assign new String variables when I create my list. I'd like to do something like:



l = [first = "first", second = "second"]


Is something like this possible?







python python-3.x list declaration






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 18 '18 at 22:46









martineau

66.9k989180




66.9k989180










asked Nov 18 '18 at 22:00









yalpsid emanyalpsid eman

360720




360720













  • Don't you want a dictionary instead?

    – usr2564301
    Nov 18 '18 at 22:05











  • What do you want to achieve by doing this? Assigning in separate statements is perfectly fine and being obsessed with one-liners usually leads to code that is hard to read and understand.

    – Goyo
    Nov 18 '18 at 22:26






  • 1





    Not clean from your question, but suggest you read Why you don't want to dynamically create variables.

    – martineau
    Nov 18 '18 at 22:45





















  • Don't you want a dictionary instead?

    – usr2564301
    Nov 18 '18 at 22:05











  • What do you want to achieve by doing this? Assigning in separate statements is perfectly fine and being obsessed with one-liners usually leads to code that is hard to read and understand.

    – Goyo
    Nov 18 '18 at 22:26






  • 1





    Not clean from your question, but suggest you read Why you don't want to dynamically create variables.

    – martineau
    Nov 18 '18 at 22:45



















Don't you want a dictionary instead?

– usr2564301
Nov 18 '18 at 22:05





Don't you want a dictionary instead?

– usr2564301
Nov 18 '18 at 22:05













What do you want to achieve by doing this? Assigning in separate statements is perfectly fine and being obsessed with one-liners usually leads to code that is hard to read and understand.

– Goyo
Nov 18 '18 at 22:26





What do you want to achieve by doing this? Assigning in separate statements is perfectly fine and being obsessed with one-liners usually leads to code that is hard to read and understand.

– Goyo
Nov 18 '18 at 22:26




1




1





Not clean from your question, but suggest you read Why you don't want to dynamically create variables.

– martineau
Nov 18 '18 at 22:45







Not clean from your question, but suggest you read Why you don't want to dynamically create variables.

– martineau
Nov 18 '18 at 22:45














1 Answer
1






active

oldest

votes


















4














That syntax is not allowed. Instead you can do the following (You can name it whatever you like, in-place unpacking, iterable unpacking, etc.):



first, second = ["first", "second"]


However, very similar to what you want to do you can create a dictionary as following which also seems more efficient and Pythonic for your goal here.



In [1]: d = dict(first_k = "first", second_k = "second")

In [2]: d['first_k']
Out[2]: 'first'

In [3]: d.keys()
Out[3]: dict_keys(['first_k', 'second_k'])

In [4]: d.values()
Out[4]: dict_values(['first', 'second'])





share|improve this answer
























  • You can complete the first example: l=first, second = ["first", "second"]

    – kantal
    Nov 18 '18 at 22:31











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









4














That syntax is not allowed. Instead you can do the following (You can name it whatever you like, in-place unpacking, iterable unpacking, etc.):



first, second = ["first", "second"]


However, very similar to what you want to do you can create a dictionary as following which also seems more efficient and Pythonic for your goal here.



In [1]: d = dict(first_k = "first", second_k = "second")

In [2]: d['first_k']
Out[2]: 'first'

In [3]: d.keys()
Out[3]: dict_keys(['first_k', 'second_k'])

In [4]: d.values()
Out[4]: dict_values(['first', 'second'])





share|improve this answer
























  • You can complete the first example: l=first, second = ["first", "second"]

    – kantal
    Nov 18 '18 at 22:31
















4














That syntax is not allowed. Instead you can do the following (You can name it whatever you like, in-place unpacking, iterable unpacking, etc.):



first, second = ["first", "second"]


However, very similar to what you want to do you can create a dictionary as following which also seems more efficient and Pythonic for your goal here.



In [1]: d = dict(first_k = "first", second_k = "second")

In [2]: d['first_k']
Out[2]: 'first'

In [3]: d.keys()
Out[3]: dict_keys(['first_k', 'second_k'])

In [4]: d.values()
Out[4]: dict_values(['first', 'second'])





share|improve this answer
























  • You can complete the first example: l=first, second = ["first", "second"]

    – kantal
    Nov 18 '18 at 22:31














4












4








4







That syntax is not allowed. Instead you can do the following (You can name it whatever you like, in-place unpacking, iterable unpacking, etc.):



first, second = ["first", "second"]


However, very similar to what you want to do you can create a dictionary as following which also seems more efficient and Pythonic for your goal here.



In [1]: d = dict(first_k = "first", second_k = "second")

In [2]: d['first_k']
Out[2]: 'first'

In [3]: d.keys()
Out[3]: dict_keys(['first_k', 'second_k'])

In [4]: d.values()
Out[4]: dict_values(['first', 'second'])





share|improve this answer













That syntax is not allowed. Instead you can do the following (You can name it whatever you like, in-place unpacking, iterable unpacking, etc.):



first, second = ["first", "second"]


However, very similar to what you want to do you can create a dictionary as following which also seems more efficient and Pythonic for your goal here.



In [1]: d = dict(first_k = "first", second_k = "second")

In [2]: d['first_k']
Out[2]: 'first'

In [3]: d.keys()
Out[3]: dict_keys(['first_k', 'second_k'])

In [4]: d.values()
Out[4]: dict_values(['first', 'second'])






share|improve this answer












share|improve this answer



share|improve this answer










answered Nov 18 '18 at 22:05









KasrâmvdKasrâmvd

78.3k1089125




78.3k1089125













  • You can complete the first example: l=first, second = ["first", "second"]

    – kantal
    Nov 18 '18 at 22:31



















  • You can complete the first example: l=first, second = ["first", "second"]

    – kantal
    Nov 18 '18 at 22:31

















You can complete the first example: l=first, second = ["first", "second"]

– kantal
Nov 18 '18 at 22:31





You can complete the first example: l=first, second = ["first", "second"]

– kantal
Nov 18 '18 at 22:31


















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