Python how do i find second connections?
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python class methods
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To get an answer for your question, you need to give a lot more background. What doA-Hmean? I'm assuming they're objects of some class, but you've not named the class or described what its purpose is. Where exactly are you creating yourconnectionsvariable? If it's at the top level of the class, then all your instances are sharing the samesetinstance, which may be problematic. But we can't know for sure, since you've shown us so little of your code, and explained almost nothing.
– Blckknght
Nov 17 '18 at 0:01
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removed I should not ask this question
python class methods
asked Nov 16 '18 at 23:56
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133
removed I should not ask this question
python class methods
python class methods
asked Nov 16 '18 at 23:56
BeginCs123BeginCs123
133
asked Nov 16 '18 at 23:56
BeginCs123BeginCs123
133
edited Nov 17 '18 at 8:30
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asked Nov 16 '18 at 23:56
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133
asked Nov 16 '18 at 23:56
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asked Nov 16 '18 at 23:56
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133
To get an answer for your question, you need to give a lot more background. What doA-Hmean? I'm assuming they're objects of some class, but you've not named the class or described what its purpose is. Where exactly are you creating yourconnectionsvariable? If it's at the top level of the class, then all your instances are sharing the samesetinstance, which may be problematic. But we can't know for sure, since you've shown us so little of your code, and explained almost nothing.
– Blckknght
Nov 17 '18 at 0:01
add a comment |
To get an answer for your question, you need to give a lot more background. What doA-Hmean? I'm assuming they're objects of some class, but you've not named the class or described what its purpose is. Where exactly are you creating yourconnectionsvariable? If it's at the top level of the class, then all your instances are sharing the samesetinstance, which may be problematic. But we can't know for sure, since you've shown us so little of your code, and explained almost nothing.
– Blckknght
Nov 17 '18 at 0:01
To get an answer for your question, you need to give a lot more background. What do
A-H mean? I'm assuming they're objects of some class, but you've not named the class or described what its purpose is. Where exactly are you creating your connections variable? If it's at the top level of the class, then all your instances are sharing the same set instance, which may be problematic. But we can't know for sure, since you've shown us so little of your code, and explained almost nothing.– Blckknght
Nov 17 '18 at 0:01
To get an answer for your question, you need to give a lot more background. What do
A-H mean? I'm assuming they're objects of some class, but you've not named the class or described what its purpose is. Where exactly are you creating your connections variable? If it's at the top level of the class, then all your instances are sharing the same set instance, which may be problematic. But we can't know for sure, since you've shown us so little of your code, and explained almost nothing.– Blckknght
Nov 17 '18 at 0:01
add a comment |
2 Answers
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I'll keep this at a low level of technology; you can stuff this into a comprehension if you like.
Iterate over the list of first-order connections. For each connection, get their first-order connections and add them to the current second-order set -- which I've called friend_of_friend.
def second_connections(self):
for other in self.connections:
self.friend_of_friend.union(other.connections)
answered Nov 17 '18 at 0:01
PrunePrune
43.1k143456
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Since I can't see your class I'm just going to implement the solution without integrating it into a class. I'm also only going to describe the connections as below, since you didn't share your data structure.
sets = set([("A", "B"),("A", "D"),("A", "C"),("A", "E"),("B", "F"),("D", "G"), ("F","H")])
def up_to_second(name, sets):
connectables = [name] + [x[1] for x in sets if x[0] == name]
return [x for x in sets if x[0] in connectables]
up_to_second("A", sets)
This gives your expected outcome:
[('A', 'B'), ('A', 'D'), ('A', 'C'), ('A', 'E'), ('D', 'G'), ('B', 'F')]
Assuming your data structure is at least a bit different from this, you'll need to tweak this solution to conform to your patterns. But as best I can tell this is a solution.
answered Nov 17 '18 at 0:08
Charles LandauCharles Landau
2,1551215
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
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active
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active
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votes
I'll keep this at a low level of technology; you can stuff this into a comprehension if you like.
Iterate over the list of first-order connections. For each connection, get their first-order connections and add them to the current second-order set -- which I've called friend_of_friend.
def second_connections(self):
for other in self.connections:
self.friend_of_friend.union(other.connections)
answered Nov 17 '18 at 0:01
PrunePrune
43.1k143456
add a comment |
I'll keep this at a low level of technology; you can stuff this into a comprehension if you like.
Iterate over the list of first-order connections. For each connection, get their first-order connections and add them to the current second-order set -- which I've called friend_of_friend.
def second_connections(self):
for other in self.connections:
self.friend_of_friend.union(other.connections)
answered Nov 17 '18 at 0:01
PrunePrune
43.1k143456
add a comment |
I'll keep this at a low level of technology; you can stuff this into a comprehension if you like.
Iterate over the list of first-order connections. For each connection, get their first-order connections and add them to the current second-order set -- which I've called friend_of_friend.
def second_connections(self):
for other in self.connections:
self.friend_of_friend.union(other.connections)
answered Nov 17 '18 at 0:01
PrunePrune
43.1k143456
I'll keep this at a low level of technology; you can stuff this into a comprehension if you like.
Iterate over the list of first-order connections. For each connection, get their first-order connections and add them to the current second-order set -- which I've called friend_of_friend.
def second_connections(self):
for other in self.connections:
self.friend_of_friend.union(other.connections)
answered Nov 17 '18 at 0:01
PrunePrune
43.1k143456
answered Nov 17 '18 at 0:01
PrunePrune
43.1k143456
answered Nov 17 '18 at 0:01
PrunePrune
43.1k143456
answered Nov 17 '18 at 0:01
PrunePrune
43.1k143456
43.1k143456
add a comment |
add a comment |
Since I can't see your class I'm just going to implement the solution without integrating it into a class. I'm also only going to describe the connections as below, since you didn't share your data structure.
sets = set([("A", "B"),("A", "D"),("A", "C"),("A", "E"),("B", "F"),("D", "G"), ("F","H")])
def up_to_second(name, sets):
connectables = [name] + [x[1] for x in sets if x[0] == name]
return [x for x in sets if x[0] in connectables]
up_to_second("A", sets)
This gives your expected outcome:
[('A', 'B'), ('A', 'D'), ('A', 'C'), ('A', 'E'), ('D', 'G'), ('B', 'F')]
Assuming your data structure is at least a bit different from this, you'll need to tweak this solution to conform to your patterns. But as best I can tell this is a solution.
answered Nov 17 '18 at 0:08
Charles LandauCharles Landau
2,1551215
add a comment |
Since I can't see your class I'm just going to implement the solution without integrating it into a class. I'm also only going to describe the connections as below, since you didn't share your data structure.
sets = set([("A", "B"),("A", "D"),("A", "C"),("A", "E"),("B", "F"),("D", "G"), ("F","H")])
def up_to_second(name, sets):
connectables = [name] + [x[1] for x in sets if x[0] == name]
return [x for x in sets if x[0] in connectables]
up_to_second("A", sets)
This gives your expected outcome:
[('A', 'B'), ('A', 'D'), ('A', 'C'), ('A', 'E'), ('D', 'G'), ('B', 'F')]
Assuming your data structure is at least a bit different from this, you'll need to tweak this solution to conform to your patterns. But as best I can tell this is a solution.
answered Nov 17 '18 at 0:08
Charles LandauCharles Landau
2,1551215
add a comment |
Since I can't see your class I'm just going to implement the solution without integrating it into a class. I'm also only going to describe the connections as below, since you didn't share your data structure.
sets = set([("A", "B"),("A", "D"),("A", "C"),("A", "E"),("B", "F"),("D", "G"), ("F","H")])
def up_to_second(name, sets):
connectables = [name] + [x[1] for x in sets if x[0] == name]
return [x for x in sets if x[0] in connectables]
up_to_second("A", sets)
This gives your expected outcome:
[('A', 'B'), ('A', 'D'), ('A', 'C'), ('A', 'E'), ('D', 'G'), ('B', 'F')]
Assuming your data structure is at least a bit different from this, you'll need to tweak this solution to conform to your patterns. But as best I can tell this is a solution.
answered Nov 17 '18 at 0:08
Charles LandauCharles Landau
2,1551215
Since I can't see your class I'm just going to implement the solution without integrating it into a class. I'm also only going to describe the connections as below, since you didn't share your data structure.
sets = set([("A", "B"),("A", "D"),("A", "C"),("A", "E"),("B", "F"),("D", "G"), ("F","H")])
def up_to_second(name, sets):
connectables = [name] + [x[1] for x in sets if x[0] == name]
return [x for x in sets if x[0] in connectables]
up_to_second("A", sets)
This gives your expected outcome:
[('A', 'B'), ('A', 'D'), ('A', 'C'), ('A', 'E'), ('D', 'G'), ('B', 'F')]
Assuming your data structure is at least a bit different from this, you'll need to tweak this solution to conform to your patterns. But as best I can tell this is a solution.
answered Nov 17 '18 at 0:08
Charles LandauCharles Landau
2,1551215
answered Nov 17 '18 at 0:08
Charles LandauCharles Landau
2,1551215
answered Nov 17 '18 at 0:08
Charles LandauCharles Landau
2,1551215
answered Nov 17 '18 at 0:08
Charles LandauCharles Landau
2,1551215
2,1551215
add a comment |
add a comment |
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To get an answer for your question, you need to give a lot more background. What do
A-Hmean? I'm assuming they're objects of some class, but you've not named the class or described what its purpose is. Where exactly are you creating yourconnectionsvariable? If it's at the top level of the class, then all your instances are sharing the samesetinstance, which may be problematic. But we can't know for sure, since you've shown us so little of your code, and explained almost nothing.– Blckknght
Nov 17 '18 at 0:01