Why const someValue = this.props.dispatch(someMethod()) is working fine on localhost but not in production?
I've one method called onChange and it's working as expected on localhost but not on production. Checkout the code below for better understanding:
onChange() {
const someValue = this.props.dispatch(divideTenByFive()) // returns 2 on both local and prod
console.log(someValue) // prints 2 on localhost and undefined on production
console.log(this.props.dispatch(divideTenByFive())) // prints 2 on localhost and undefined on production
return someValue;
}
Is it related to Synchronous/Asynchronous programming? How to fix this for production?
Note: I can't share the actual business logic so I've written divideTenByFive() for better understanding. However, I've tried to provide max details but if you're looking for more info please comment below.
Update: I'm not using any middleware
javascript reactjs ecmascript-6 redux react-redux
asked Nov 14 '18 at 12:20
Abhi
186110
add a comment |
I've one method called onChange and it's working as expected on localhost but not on production. Checkout the code below for better understanding:
onChange() {
const someValue = this.props.dispatch(divideTenByFive()) // returns 2 on both local and prod
console.log(someValue) // prints 2 on localhost and undefined on production
console.log(this.props.dispatch(divideTenByFive())) // prints 2 on localhost and undefined on production
return someValue;
}
Is it related to Synchronous/Asynchronous programming? How to fix this for production?
Note: I can't share the actual business logic so I've written divideTenByFive() for better understanding. However, I've tried to provide max details but if you're looking for more info please comment below.
Update: I'm not using any middleware
javascript reactjs ecmascript-6 redux react-redux
asked Nov 14 '18 at 12:20
Abhi
186110
are you using some middleware to return the value
– Shubham Khatri
Nov 14 '18 at 13:17
@ShubhamKhatri No, I'm not using any middleware to return the value. It's simple try catch and if else going on inside divideTenByFive() which returns the expected value in production also.
– Abhi
Nov 14 '18 at 14:12
Need a fully working code rather than 3 lines of code if you need help. Preferably on any open source website like GitHub.
– SamwellTarly
Nov 14 '18 at 17:38
add a comment |
I've one method called onChange and it's working as expected on localhost but not on production. Checkout the code below for better understanding:
onChange() {
const someValue = this.props.dispatch(divideTenByFive()) // returns 2 on both local and prod
console.log(someValue) // prints 2 on localhost and undefined on production
console.log(this.props.dispatch(divideTenByFive())) // prints 2 on localhost and undefined on production
return someValue;
}
Is it related to Synchronous/Asynchronous programming? How to fix this for production?
Note: I can't share the actual business logic so I've written divideTenByFive() for better understanding. However, I've tried to provide max details but if you're looking for more info please comment below.
Update: I'm not using any middleware
javascript reactjs ecmascript-6 redux react-redux
asked Nov 14 '18 at 12:20
Abhi
186110
I've one method called onChange and it's working as expected on localhost but not on production. Checkout the code below for better understanding:
onChange() {
const someValue = this.props.dispatch(divideTenByFive()) // returns 2 on both local and prod
console.log(someValue) // prints 2 on localhost and undefined on production
console.log(this.props.dispatch(divideTenByFive())) // prints 2 on localhost and undefined on production
return someValue;
}
Is it related to Synchronous/Asynchronous programming? How to fix this for production?
Note: I can't share the actual business logic so I've written divideTenByFive() for better understanding. However, I've tried to provide max details but if you're looking for more info please comment below.
Update: I'm not using any middleware
javascript reactjs ecmascript-6 redux react-redux
javascript reactjs ecmascript-6 redux react-redux
asked Nov 14 '18 at 12:20
Abhi
186110
asked Nov 14 '18 at 12:20
Abhi
186110
edited Nov 24 '18 at 8:24
asked Nov 14 '18 at 12:20
Abhi
186110
asked Nov 14 '18 at 12:20
Abhi
186110
asked Nov 14 '18 at 12:20
Abhi
186110
186110
are you using some middleware to return the value
– Shubham Khatri
Nov 14 '18 at 13:17
@ShubhamKhatri No, I'm not using any middleware to return the value. It's simple try catch and if else going on inside divideTenByFive() which returns the expected value in production also.
– Abhi
Nov 14 '18 at 14:12
Need a fully working code rather than 3 lines of code if you need help. Preferably on any open source website like GitHub.
– SamwellTarly
Nov 14 '18 at 17:38
add a comment |
are you using some middleware to return the value
– Shubham Khatri
Nov 14 '18 at 13:17
@ShubhamKhatri No, I'm not using any middleware to return the value. It's simple try catch and if else going on inside divideTenByFive() which returns the expected value in production also.
– Abhi
Nov 14 '18 at 14:12
Need a fully working code rather than 3 lines of code if you need help. Preferably on any open source website like GitHub.
– SamwellTarly
Nov 14 '18 at 17:38
are you using some middleware to return the value
– Shubham Khatri
Nov 14 '18 at 13:17
are you using some middleware to return the value
– Shubham Khatri
Nov 14 '18 at 13:17
@ShubhamKhatri No, I'm not using any middleware to return the value. It's simple try catch and if else going on inside divideTenByFive() which returns the expected value in production also.
– Abhi
Nov 14 '18 at 14:12
@ShubhamKhatri No, I'm not using any middleware to return the value. It's simple try catch and if else going on inside divideTenByFive() which returns the expected value in production also.
– Abhi
Nov 14 '18 at 14:12
Need a fully working code rather than 3 lines of code if you need help. Preferably on any open source website like GitHub.
– SamwellTarly
Nov 14 '18 at 17:38
Need a fully working code rather than 3 lines of code if you need help. Preferably on any open source website like GitHub.
– SamwellTarly
Nov 14 '18 at 17:38
add a comment |
1 Answer
1
active
oldest
votes
Can you please try using var instead of const to declare the variable.
Once you’ve set it (to 2 on dev and to “undefined” in production) it cannot be changed.
This is because the value is not yet available, but const will prevent any modification later on.
answered Nov 14 '18 at 16:32
bestinamir
5917
I've tried using var instead of const but it's not working for this problem.
– Abhi
Nov 15 '18 at 13:09
Can you also please try making it a global variable and pass it into your function..
– bestinamir
Nov 15 '18 at 13:18
You can make it a global variable by omitting var / const keywords.
– bestinamir
Nov 29 '18 at 21:35
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
Can you please try using var instead of const to declare the variable.
Once you’ve set it (to 2 on dev and to “undefined” in production) it cannot be changed.
This is because the value is not yet available, but const will prevent any modification later on.
answered Nov 14 '18 at 16:32
bestinamir
5917
I've tried using var instead of const but it's not working for this problem.
– Abhi
Nov 15 '18 at 13:09
Can you also please try making it a global variable and pass it into your function..
– bestinamir
Nov 15 '18 at 13:18
You can make it a global variable by omitting var / const keywords.
– bestinamir
Nov 29 '18 at 21:35
add a comment |
Can you please try using var instead of const to declare the variable.
Once you’ve set it (to 2 on dev and to “undefined” in production) it cannot be changed.
This is because the value is not yet available, but const will prevent any modification later on.
answered Nov 14 '18 at 16:32
bestinamir
5917
I've tried using var instead of const but it's not working for this problem.
– Abhi
Nov 15 '18 at 13:09
Can you also please try making it a global variable and pass it into your function..
– bestinamir
Nov 15 '18 at 13:18
You can make it a global variable by omitting var / const keywords.
– bestinamir
Nov 29 '18 at 21:35
add a comment |
Can you please try using var instead of const to declare the variable.
Once you’ve set it (to 2 on dev and to “undefined” in production) it cannot be changed.
This is because the value is not yet available, but const will prevent any modification later on.
answered Nov 14 '18 at 16:32
bestinamir
5917
Can you please try using var instead of const to declare the variable.
Once you’ve set it (to 2 on dev and to “undefined” in production) it cannot be changed.
This is because the value is not yet available, but const will prevent any modification later on.
answered Nov 14 '18 at 16:32
bestinamir
5917
answered Nov 14 '18 at 16:32
bestinamir
5917
answered Nov 14 '18 at 16:32
bestinamir
5917
answered Nov 14 '18 at 16:32
bestinamir
5917
5917
I've tried using var instead of const but it's not working for this problem.
– Abhi
Nov 15 '18 at 13:09
Can you also please try making it a global variable and pass it into your function..
– bestinamir
Nov 15 '18 at 13:18
You can make it a global variable by omitting var / const keywords.
– bestinamir
Nov 29 '18 at 21:35
add a comment |
I've tried using var instead of const but it's not working for this problem.
– Abhi
Nov 15 '18 at 13:09
Can you also please try making it a global variable and pass it into your function..
– bestinamir
Nov 15 '18 at 13:18
You can make it a global variable by omitting var / const keywords.
– bestinamir
Nov 29 '18 at 21:35
I've tried using var instead of const but it's not working for this problem.
– Abhi
Nov 15 '18 at 13:09
I've tried using var instead of const but it's not working for this problem.
– Abhi
Nov 15 '18 at 13:09
Can you also please try making it a global variable and pass it into your function..
– bestinamir
Nov 15 '18 at 13:18
Can you also please try making it a global variable and pass it into your function..
– bestinamir
Nov 15 '18 at 13:18
You can make it a global variable by omitting var / const keywords.
– bestinamir
Nov 29 '18 at 21:35
You can make it a global variable by omitting var / const keywords.
– bestinamir
Nov 29 '18 at 21:35
add a comment |
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are you using some middleware to return the value
– Shubham Khatri
Nov 14 '18 at 13:17
@ShubhamKhatri No, I'm not using any middleware to return the value. It's simple try catch and if else going on inside divideTenByFive() which returns the expected value in production also.
– Abhi
Nov 14 '18 at 14:12
Need a fully working code rather than 3 lines of code if you need help. Preferably on any open source website like GitHub.
– SamwellTarly
Nov 14 '18 at 17:38