Short(er) hand for min max percentage?
I have a function that converts two values to a percentage within a range, in this case between 15000 and 100000. It feels very clunky. Is there a more simple way to express this which is easy/easier to understand?
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
// Specifically these values
price = price > 100000 ? 100000 : price;
price = price < 15000 ? 15000 : price;
return (price - 1500) / 85000;
}
javascript ecmascript-6
edited Nov 20 '18 at 11:12
Will Madden
2,48321517
asked Nov 20 '18 at 10:55
HimmatorsHimmators
5,7092687175
add a comment |
I have a function that converts two values to a percentage within a range, in this case between 15000 and 100000. It feels very clunky. Is there a more simple way to express this which is easy/easier to understand?
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
// Specifically these values
price = price > 100000 ? 100000 : price;
price = price < 15000 ? 15000 : price;
return (price - 1500) / 85000;
}
javascript ecmascript-6
edited Nov 20 '18 at 11:12
Will Madden
2,48321517
asked Nov 20 '18 at 10:55
HimmatorsHimmators
5,7092687175
add a comment |
I have a function that converts two values to a percentage within a range, in this case between 15000 and 100000. It feels very clunky. Is there a more simple way to express this which is easy/easier to understand?
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
// Specifically these values
price = price > 100000 ? 100000 : price;
price = price < 15000 ? 15000 : price;
return (price - 1500) / 85000;
}
javascript ecmascript-6
edited Nov 20 '18 at 11:12
Will Madden
2,48321517
asked Nov 20 '18 at 10:55
HimmatorsHimmators
5,7092687175
I have a function that converts two values to a percentage within a range, in this case between 15000 and 100000. It feels very clunky. Is there a more simple way to express this which is easy/easier to understand?
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
// Specifically these values
price = price > 100000 ? 100000 : price;
price = price < 15000 ? 15000 : price;
return (price - 1500) / 85000;
}
javascript ecmascript-6
javascript ecmascript-6
edited Nov 20 '18 at 11:12
Will Madden
2,48321517
asked Nov 20 '18 at 10:55
HimmatorsHimmators
5,7092687175
edited Nov 20 '18 at 11:12
Will Madden
2,48321517
asked Nov 20 '18 at 10:55
HimmatorsHimmators
5,7092687175
edited Nov 20 '18 at 11:12
Will Madden
2,48321517
edited Nov 20 '18 at 11:12
Will Madden
2,48321517
edited Nov 20 '18 at 11:12
Will Madden
2,48321517
2,48321517
asked Nov 20 '18 at 10:55
HimmatorsHimmators
5,7092687175
asked Nov 20 '18 at 10:55
HimmatorsHimmators
5,7092687175
asked Nov 20 '18 at 10:55
HimmatorsHimmators
5,7092687175
5,7092687175
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
You might use Math.min and Math.max to constrain the ranges:
const adjustedPrice = Math.min(
100000, // can be no higher than 100000
Math.max(price, 15000) // can be no lower than 15000
);
return (adjustedPrice - 1500) / 85000;
Another option is nested conditionals, which will reduce the number of unnecessary reassignments, though it doesn't exactly make the code clearer:
const adjustedPrice =
price > 100000 ? 100000 :
price < 15000 ? 15000 : price
answered Nov 20 '18 at 10:58
CertainPerformanceCertainPerformance
89k154977
add a comment |
I usually use this utility for things like that:
const clamp = (value, min, max) => value > min? value < max? value: max: min;
price2percent = (sale) => {
let price = clamp(sale.soldPrice / sale.livingArea, 15000, 100000);
return (price - 1500) / 85000;
}
I find that more readable than the Math.min(max, Math.max(min, value)) construct.
Downside, in its current version it doesn't play well with NaN.
answered Nov 20 '18 at 11:13
ThomasThomas
4,867159
add a comment |
Is there a more simple way to express this which is easy/easier to understand?
Easy to understand would be using if/else condition:
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
if(price > 100000) price = 100000
else if(price < 15000) price = 15000
return (price - 1500) / 85000;
}
Which can be expressed shorter as: (the harder way)
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
price = price > 100000 ? 100000 : (price < 15000 ? 15000 : price)
return (price - 1500) / 85000;
}
answered Nov 20 '18 at 12:47
Bhojendra RauniyarBhojendra Rauniyar
51.6k2079127
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
You might use Math.min and Math.max to constrain the ranges:
const adjustedPrice = Math.min(
100000, // can be no higher than 100000
Math.max(price, 15000) // can be no lower than 15000
);
return (adjustedPrice - 1500) / 85000;
Another option is nested conditionals, which will reduce the number of unnecessary reassignments, though it doesn't exactly make the code clearer:
const adjustedPrice =
price > 100000 ? 100000 :
price < 15000 ? 15000 : price
answered Nov 20 '18 at 10:58
CertainPerformanceCertainPerformance
89k154977
add a comment |
You might use Math.min and Math.max to constrain the ranges:
const adjustedPrice = Math.min(
100000, // can be no higher than 100000
Math.max(price, 15000) // can be no lower than 15000
);
return (adjustedPrice - 1500) / 85000;
Another option is nested conditionals, which will reduce the number of unnecessary reassignments, though it doesn't exactly make the code clearer:
const adjustedPrice =
price > 100000 ? 100000 :
price < 15000 ? 15000 : price
answered Nov 20 '18 at 10:58
CertainPerformanceCertainPerformance
89k154977
add a comment |
You might use Math.min and Math.max to constrain the ranges:
const adjustedPrice = Math.min(
100000, // can be no higher than 100000
Math.max(price, 15000) // can be no lower than 15000
);
return (adjustedPrice - 1500) / 85000;
Another option is nested conditionals, which will reduce the number of unnecessary reassignments, though it doesn't exactly make the code clearer:
const adjustedPrice =
price > 100000 ? 100000 :
price < 15000 ? 15000 : price
answered Nov 20 '18 at 10:58
CertainPerformanceCertainPerformance
89k154977
You might use Math.min and Math.max to constrain the ranges:
const adjustedPrice = Math.min(
100000, // can be no higher than 100000
Math.max(price, 15000) // can be no lower than 15000
);
return (adjustedPrice - 1500) / 85000;
Another option is nested conditionals, which will reduce the number of unnecessary reassignments, though it doesn't exactly make the code clearer:
const adjustedPrice =
price > 100000 ? 100000 :
price < 15000 ? 15000 : price
answered Nov 20 '18 at 10:58
CertainPerformanceCertainPerformance
89k154977
answered Nov 20 '18 at 10:58
CertainPerformanceCertainPerformance
89k154977
answered Nov 20 '18 at 10:58
CertainPerformanceCertainPerformance
89k154977
answered Nov 20 '18 at 10:58
CertainPerformanceCertainPerformance
89k154977
89k154977
add a comment |
add a comment |
I usually use this utility for things like that:
const clamp = (value, min, max) => value > min? value < max? value: max: min;
price2percent = (sale) => {
let price = clamp(sale.soldPrice / sale.livingArea, 15000, 100000);
return (price - 1500) / 85000;
}
I find that more readable than the Math.min(max, Math.max(min, value)) construct.
Downside, in its current version it doesn't play well with NaN.
answered Nov 20 '18 at 11:13
ThomasThomas
4,867159
add a comment |
I usually use this utility for things like that:
const clamp = (value, min, max) => value > min? value < max? value: max: min;
price2percent = (sale) => {
let price = clamp(sale.soldPrice / sale.livingArea, 15000, 100000);
return (price - 1500) / 85000;
}
I find that more readable than the Math.min(max, Math.max(min, value)) construct.
Downside, in its current version it doesn't play well with NaN.
answered Nov 20 '18 at 11:13
ThomasThomas
4,867159
add a comment |
I usually use this utility for things like that:
const clamp = (value, min, max) => value > min? value < max? value: max: min;
price2percent = (sale) => {
let price = clamp(sale.soldPrice / sale.livingArea, 15000, 100000);
return (price - 1500) / 85000;
}
I find that more readable than the Math.min(max, Math.max(min, value)) construct.
Downside, in its current version it doesn't play well with NaN.
answered Nov 20 '18 at 11:13
ThomasThomas
4,867159
I usually use this utility for things like that:
const clamp = (value, min, max) => value > min? value < max? value: max: min;
price2percent = (sale) => {
let price = clamp(sale.soldPrice / sale.livingArea, 15000, 100000);
return (price - 1500) / 85000;
}
I find that more readable than the Math.min(max, Math.max(min, value)) construct.
Downside, in its current version it doesn't play well with NaN.
answered Nov 20 '18 at 11:13
ThomasThomas
4,867159
edited Nov 20 '18 at 20:05
answered Nov 20 '18 at 11:13
ThomasThomas
4,867159
answered Nov 20 '18 at 11:13
ThomasThomas
4,867159
answered Nov 20 '18 at 11:13
ThomasThomas
4,867159
4,867159
add a comment |
add a comment |
Is there a more simple way to express this which is easy/easier to understand?
Easy to understand would be using if/else condition:
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
if(price > 100000) price = 100000
else if(price < 15000) price = 15000
return (price - 1500) / 85000;
}
Which can be expressed shorter as: (the harder way)
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
price = price > 100000 ? 100000 : (price < 15000 ? 15000 : price)
return (price - 1500) / 85000;
}
answered Nov 20 '18 at 12:47
Bhojendra RauniyarBhojendra Rauniyar
51.6k2079127
add a comment |
Is there a more simple way to express this which is easy/easier to understand?
Easy to understand would be using if/else condition:
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
if(price > 100000) price = 100000
else if(price < 15000) price = 15000
return (price - 1500) / 85000;
}
Which can be expressed shorter as: (the harder way)
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
price = price > 100000 ? 100000 : (price < 15000 ? 15000 : price)
return (price - 1500) / 85000;
}
answered Nov 20 '18 at 12:47
Bhojendra RauniyarBhojendra Rauniyar
51.6k2079127
add a comment |
Is there a more simple way to express this which is easy/easier to understand?
Easy to understand would be using if/else condition:
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
if(price > 100000) price = 100000
else if(price < 15000) price = 15000
return (price - 1500) / 85000;
}
Which can be expressed shorter as: (the harder way)
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
price = price > 100000 ? 100000 : (price < 15000 ? 15000 : price)
return (price - 1500) / 85000;
}
answered Nov 20 '18 at 12:47
Bhojendra RauniyarBhojendra Rauniyar
51.6k2079127
Is there a more simple way to express this which is easy/easier to understand?
Easy to understand would be using if/else condition:
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
if(price > 100000) price = 100000
else if(price < 15000) price = 15000
return (price - 1500) / 85000;
}
Which can be expressed shorter as: (the harder way)
price2percent = (sale) => {
let price = sale.soldPrice / sale.livingArea;
price = price > 100000 ? 100000 : (price < 15000 ? 15000 : price)
return (price - 1500) / 85000;
}
answered Nov 20 '18 at 12:47
Bhojendra RauniyarBhojendra Rauniyar
51.6k2079127
edited Nov 20 '18 at 12:52
answered Nov 20 '18 at 12:47
Bhojendra RauniyarBhojendra Rauniyar
51.6k2079127
answered Nov 20 '18 at 12:47
Bhojendra RauniyarBhojendra Rauniyar
51.6k2079127
answered Nov 20 '18 at 12:47
Bhojendra RauniyarBhojendra Rauniyar
51.6k2079127
51.6k2079127
add a comment |
add a comment |
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