Unable to map ManyToOne relashionship












0















I have Book User and Basket class.



1 user can have one or more book in basket table.



I want to map that relation but i keep getting the following error:



javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.persister.walking.spi.WalkingException: Association has already been visited: AssociationKey(table=basket,
columns={book_id})



Basket Class



@Entity
public class Basket {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;

@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name="book_id")
private Book book;
private long user_id;


public Basket() {}
public Basket(Book book, long user_id) {
this.book = book;
this.user_id = user_id;
}


// Getters and Setters
}


Book Class



@Entity
@Table(name = "book")
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
public class Book implements Serializable {

private static final long serialVersionUID = 1L;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;

@Column(name = "title")
private String title;

@Column(name = "isbn")
private String isbn;

@Column(name = "quantity")
private Integer quantity;

@Column(name = "price")
private Double price;

@OneToMany(mappedBy = "book", fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONE)
@JsonIgnoreProperties("book")
private Set<SaleDetails> saleDetails = new HashSet<>();

@ManyToMany(fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@JoinTable(name = "book_author",
joinColumns = @JoinColumn(name = "books_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "authors_id", referencedColumnName = "id"))
@JsonIgnoreProperties("books")
private Set<Author> authors = new HashSet<>();

@ManyToMany(fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@JoinTable(name = "book_genre",
joinColumns = @JoinColumn(name = "books_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "genres_id", referencedColumnName = "id"))
private Set<Genre> genres = new HashSet<>();









share|improve this question























  • Basket domain can not have List<book> it makes no sense. I only need that fot each basket object, instead of id i need the object it self...

    – Bruno Miguel
    Nov 19 '18 at 15:20











  • So a Basket can only contain 1 Book, so your description is wrong. Doesn't fix the problem mind, that is utterly Hibernate specific

    – Billy Frost
    Nov 19 '18 at 16:08











  • Sorry if i miss explain the problem. I have 3 tables User Book and Basket(id, user_id, book_id) and i'm able to get a list of baskets. But if instead of having private long book_id i try to map to and object i get the error

    – Bruno Miguel
    Nov 19 '18 at 16:27











  • If you have some User class perhaps actually post it in the question. Otherwise if it is not related to the problem then don't even mention it ... keep the question concise

    – Billy Frost
    Nov 19 '18 at 17:57


















0















I have Book User and Basket class.



1 user can have one or more book in basket table.



I want to map that relation but i keep getting the following error:



javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.persister.walking.spi.WalkingException: Association has already been visited: AssociationKey(table=basket,
columns={book_id})



Basket Class



@Entity
public class Basket {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;

@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name="book_id")
private Book book;
private long user_id;


public Basket() {}
public Basket(Book book, long user_id) {
this.book = book;
this.user_id = user_id;
}


// Getters and Setters
}


Book Class



@Entity
@Table(name = "book")
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
public class Book implements Serializable {

private static final long serialVersionUID = 1L;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;

@Column(name = "title")
private String title;

@Column(name = "isbn")
private String isbn;

@Column(name = "quantity")
private Integer quantity;

@Column(name = "price")
private Double price;

@OneToMany(mappedBy = "book", fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONE)
@JsonIgnoreProperties("book")
private Set<SaleDetails> saleDetails = new HashSet<>();

@ManyToMany(fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@JoinTable(name = "book_author",
joinColumns = @JoinColumn(name = "books_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "authors_id", referencedColumnName = "id"))
@JsonIgnoreProperties("books")
private Set<Author> authors = new HashSet<>();

@ManyToMany(fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@JoinTable(name = "book_genre",
joinColumns = @JoinColumn(name = "books_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "genres_id", referencedColumnName = "id"))
private Set<Genre> genres = new HashSet<>();









share|improve this question























  • Basket domain can not have List<book> it makes no sense. I only need that fot each basket object, instead of id i need the object it self...

    – Bruno Miguel
    Nov 19 '18 at 15:20











  • So a Basket can only contain 1 Book, so your description is wrong. Doesn't fix the problem mind, that is utterly Hibernate specific

    – Billy Frost
    Nov 19 '18 at 16:08











  • Sorry if i miss explain the problem. I have 3 tables User Book and Basket(id, user_id, book_id) and i'm able to get a list of baskets. But if instead of having private long book_id i try to map to and object i get the error

    – Bruno Miguel
    Nov 19 '18 at 16:27











  • If you have some User class perhaps actually post it in the question. Otherwise if it is not related to the problem then don't even mention it ... keep the question concise

    – Billy Frost
    Nov 19 '18 at 17:57
















0












0








0








I have Book User and Basket class.



1 user can have one or more book in basket table.



I want to map that relation but i keep getting the following error:



javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.persister.walking.spi.WalkingException: Association has already been visited: AssociationKey(table=basket,
columns={book_id})



Basket Class



@Entity
public class Basket {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;

@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name="book_id")
private Book book;
private long user_id;


public Basket() {}
public Basket(Book book, long user_id) {
this.book = book;
this.user_id = user_id;
}


// Getters and Setters
}


Book Class



@Entity
@Table(name = "book")
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
public class Book implements Serializable {

private static final long serialVersionUID = 1L;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;

@Column(name = "title")
private String title;

@Column(name = "isbn")
private String isbn;

@Column(name = "quantity")
private Integer quantity;

@Column(name = "price")
private Double price;

@OneToMany(mappedBy = "book", fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONE)
@JsonIgnoreProperties("book")
private Set<SaleDetails> saleDetails = new HashSet<>();

@ManyToMany(fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@JoinTable(name = "book_author",
joinColumns = @JoinColumn(name = "books_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "authors_id", referencedColumnName = "id"))
@JsonIgnoreProperties("books")
private Set<Author> authors = new HashSet<>();

@ManyToMany(fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@JoinTable(name = "book_genre",
joinColumns = @JoinColumn(name = "books_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "genres_id", referencedColumnName = "id"))
private Set<Genre> genres = new HashSet<>();









share|improve this question














I have Book User and Basket class.



1 user can have one or more book in basket table.



I want to map that relation but i keep getting the following error:



javax.persistence.PersistenceException: [PersistenceUnit: default] Unable to build Hibernate SessionFactory; nested exception is org.hibernate.persister.walking.spi.WalkingException: Association has already been visited: AssociationKey(table=basket,
columns={book_id})



Basket Class



@Entity
public class Basket {

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private long id;

@ManyToOne(fetch = FetchType.EAGER)
@JoinColumn(name="book_id")
private Book book;
private long user_id;


public Basket() {}
public Basket(Book book, long user_id) {
this.book = book;
this.user_id = user_id;
}


// Getters and Setters
}


Book Class



@Entity
@Table(name = "book")
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
public class Book implements Serializable {

private static final long serialVersionUID = 1L;

@Id
@GeneratedValue(strategy = GenerationType.IDENTITY)
private Long id;

@Column(name = "title")
private String title;

@Column(name = "isbn")
private String isbn;

@Column(name = "quantity")
private Integer quantity;

@Column(name = "price")
private Double price;

@OneToMany(mappedBy = "book", fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONE)
@JsonIgnoreProperties("book")
private Set<SaleDetails> saleDetails = new HashSet<>();

@ManyToMany(fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@JoinTable(name = "book_author",
joinColumns = @JoinColumn(name = "books_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "authors_id", referencedColumnName = "id"))
@JsonIgnoreProperties("books")
private Set<Author> authors = new HashSet<>();

@ManyToMany(fetch = FetchType.EAGER)
@Cache(usage = CacheConcurrencyStrategy.NONSTRICT_READ_WRITE)
@JoinTable(name = "book_genre",
joinColumns = @JoinColumn(name = "books_id", referencedColumnName = "id"),
inverseJoinColumns = @JoinColumn(name = "genres_id", referencedColumnName = "id"))
private Set<Genre> genres = new HashSet<>();






hibernate jpa






share|improve this question













share|improve this question











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asked Nov 19 '18 at 14:51









Bruno MiguelBruno Miguel

216




216













  • Basket domain can not have List<book> it makes no sense. I only need that fot each basket object, instead of id i need the object it self...

    – Bruno Miguel
    Nov 19 '18 at 15:20











  • So a Basket can only contain 1 Book, so your description is wrong. Doesn't fix the problem mind, that is utterly Hibernate specific

    – Billy Frost
    Nov 19 '18 at 16:08











  • Sorry if i miss explain the problem. I have 3 tables User Book and Basket(id, user_id, book_id) and i'm able to get a list of baskets. But if instead of having private long book_id i try to map to and object i get the error

    – Bruno Miguel
    Nov 19 '18 at 16:27











  • If you have some User class perhaps actually post it in the question. Otherwise if it is not related to the problem then don't even mention it ... keep the question concise

    – Billy Frost
    Nov 19 '18 at 17:57





















  • Basket domain can not have List<book> it makes no sense. I only need that fot each basket object, instead of id i need the object it self...

    – Bruno Miguel
    Nov 19 '18 at 15:20











  • So a Basket can only contain 1 Book, so your description is wrong. Doesn't fix the problem mind, that is utterly Hibernate specific

    – Billy Frost
    Nov 19 '18 at 16:08











  • Sorry if i miss explain the problem. I have 3 tables User Book and Basket(id, user_id, book_id) and i'm able to get a list of baskets. But if instead of having private long book_id i try to map to and object i get the error

    – Bruno Miguel
    Nov 19 '18 at 16:27











  • If you have some User class perhaps actually post it in the question. Otherwise if it is not related to the problem then don't even mention it ... keep the question concise

    – Billy Frost
    Nov 19 '18 at 17:57



















Basket domain can not have List<book> it makes no sense. I only need that fot each basket object, instead of id i need the object it self...

– Bruno Miguel
Nov 19 '18 at 15:20





Basket domain can not have List<book> it makes no sense. I only need that fot each basket object, instead of id i need the object it self...

– Bruno Miguel
Nov 19 '18 at 15:20













So a Basket can only contain 1 Book, so your description is wrong. Doesn't fix the problem mind, that is utterly Hibernate specific

– Billy Frost
Nov 19 '18 at 16:08





So a Basket can only contain 1 Book, so your description is wrong. Doesn't fix the problem mind, that is utterly Hibernate specific

– Billy Frost
Nov 19 '18 at 16:08













Sorry if i miss explain the problem. I have 3 tables User Book and Basket(id, user_id, book_id) and i'm able to get a list of baskets. But if instead of having private long book_id i try to map to and object i get the error

– Bruno Miguel
Nov 19 '18 at 16:27





Sorry if i miss explain the problem. I have 3 tables User Book and Basket(id, user_id, book_id) and i'm able to get a list of baskets. But if instead of having private long book_id i try to map to and object i get the error

– Bruno Miguel
Nov 19 '18 at 16:27













If you have some User class perhaps actually post it in the question. Otherwise if it is not related to the problem then don't even mention it ... keep the question concise

– Billy Frost
Nov 19 '18 at 17:57







If you have some User class perhaps actually post it in the question. Otherwise if it is not related to the problem then don't even mention it ... keep the question concise

– Billy Frost
Nov 19 '18 at 17:57














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