Using jQuery to update price based on menu drop down selections
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1
I have a hard-coded form that cannot be altered, but I need to assign price values to the options selected, and add them to the base price. I've created a codepen with notes, and I would appreciate any help anyone can offer. I think I'm close, but it still isn't working.
https://codepen.io/ophello/pen/ZoNWrB
<form>
<select name="dropdown1">
<option value="Option1">Option 1</option>
<option value="Option2">Option 2</option>
<option value="Option3">Option 3</option>
<option value="Option4">Option 4</option>
<option value="Option5">Option 5</option>
<option value="Option6">Option 6</option>
</select>
<br><br>
<select name="dropdown2">
<option value="OtherOption1">Other Option 1</option>
<option value="OtherOption2">Other Option 2</option>
<option value="OtherOption3">Other Option 3</option>
</select>
</form>
<br>Total Price<br>
$<span id="result">1350</span>
And here's the jquery:
$(document).ready(function() {
var dropdown1 = [0,70,250,404,474,450];
var dropdown2 = [0,80,160];
function updatePrice() {
var dd1 = dropdown1[($("#dropdown1")[0].selectedIndex)];
var dd2 = dropdown2[($("#dropdown2")[0].selectedIndex)];
$("#result").html(1350 + dd1 + dd2);
}
$("select").on("change", updatePrice);
});
jquery html
asked May 23 '18 at 22:13
Patrick HennesseyPatrick Hennessey
1219
add a comment |
1
I have a hard-coded form that cannot be altered, but I need to assign price values to the options selected, and add them to the base price. I've created a codepen with notes, and I would appreciate any help anyone can offer. I think I'm close, but it still isn't working.
https://codepen.io/ophello/pen/ZoNWrB
<form>
<select name="dropdown1">
<option value="Option1">Option 1</option>
<option value="Option2">Option 2</option>
<option value="Option3">Option 3</option>
<option value="Option4">Option 4</option>
<option value="Option5">Option 5</option>
<option value="Option6">Option 6</option>
</select>
<br><br>
<select name="dropdown2">
<option value="OtherOption1">Other Option 1</option>
<option value="OtherOption2">Other Option 2</option>
<option value="OtherOption3">Other Option 3</option>
</select>
</form>
<br>Total Price<br>
$<span id="result">1350</span>
And here's the jquery:
$(document).ready(function() {
var dropdown1 = [0,70,250,404,474,450];
var dropdown2 = [0,80,160];
function updatePrice() {
var dd1 = dropdown1[($("#dropdown1")[0].selectedIndex)];
var dd2 = dropdown2[($("#dropdown2")[0].selectedIndex)];
$("#result").html(1350 + dd1 + dd2);
}
$("select").on("change", updatePrice);
});
jquery html
asked May 23 '18 at 22:13
Patrick HennesseyPatrick Hennessey
1219
add a comment |
1
1
1
I have a hard-coded form that cannot be altered, but I need to assign price values to the options selected, and add them to the base price. I've created a codepen with notes, and I would appreciate any help anyone can offer. I think I'm close, but it still isn't working.
https://codepen.io/ophello/pen/ZoNWrB
<form>
<select name="dropdown1">
<option value="Option1">Option 1</option>
<option value="Option2">Option 2</option>
<option value="Option3">Option 3</option>
<option value="Option4">Option 4</option>
<option value="Option5">Option 5</option>
<option value="Option6">Option 6</option>
</select>
<br><br>
<select name="dropdown2">
<option value="OtherOption1">Other Option 1</option>
<option value="OtherOption2">Other Option 2</option>
<option value="OtherOption3">Other Option 3</option>
</select>
</form>
<br>Total Price<br>
$<span id="result">1350</span>
And here's the jquery:
$(document).ready(function() {
var dropdown1 = [0,70,250,404,474,450];
var dropdown2 = [0,80,160];
function updatePrice() {
var dd1 = dropdown1[($("#dropdown1")[0].selectedIndex)];
var dd2 = dropdown2[($("#dropdown2")[0].selectedIndex)];
$("#result").html(1350 + dd1 + dd2);
}
$("select").on("change", updatePrice);
});
jquery html
asked May 23 '18 at 22:13
Patrick HennesseyPatrick Hennessey
1219
I have a hard-coded form that cannot be altered, but I need to assign price values to the options selected, and add them to the base price. I've created a codepen with notes, and I would appreciate any help anyone can offer. I think I'm close, but it still isn't working.
https://codepen.io/ophello/pen/ZoNWrB
<form>
<select name="dropdown1">
<option value="Option1">Option 1</option>
<option value="Option2">Option 2</option>
<option value="Option3">Option 3</option>
<option value="Option4">Option 4</option>
<option value="Option5">Option 5</option>
<option value="Option6">Option 6</option>
</select>
<br><br>
<select name="dropdown2">
<option value="OtherOption1">Other Option 1</option>
<option value="OtherOption2">Other Option 2</option>
<option value="OtherOption3">Other Option 3</option>
</select>
</form>
<br>Total Price<br>
$<span id="result">1350</span>
And here's the jquery:
$(document).ready(function() {
var dropdown1 = [0,70,250,404,474,450];
var dropdown2 = [0,80,160];
function updatePrice() {
var dd1 = dropdown1[($("#dropdown1")[0].selectedIndex)];
var dd2 = dropdown2[($("#dropdown2")[0].selectedIndex)];
$("#result").html(1350 + dd1 + dd2);
}
$("select").on("change", updatePrice);
});
jquery html
jquery html
asked May 23 '18 at 22:13
Patrick HennesseyPatrick Hennessey
1219
asked May 23 '18 at 22:13
Patrick HennesseyPatrick Hennessey
1219
edited May 23 '18 at 22:25
Patrick Hennessey
asked May 23 '18 at 22:13
Patrick HennesseyPatrick Hennessey
1219
asked May 23 '18 at 22:13
Patrick HennesseyPatrick Hennessey
1219
asked May 23 '18 at 22:13
Patrick HennesseyPatrick Hennessey
1219
1219
add a comment |
add a comment |
1 Answer
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You are using the wrong selector.
$('#dropdown1') // Change to $('[name="dropdown1"]')
$('#dropdown2') // Change to $('[name="dropdown2"]')
Alternatively, you can simply assign id="dropdown1" and id="dropdown2" to the respective elements.
answered May 23 '18 at 22:33
Grant MillerGrant Miller
6,559133458
1
Holy crap -- you're right! Thanks!
– Patrick Hennessey
May 23 '18 at 22:38
@PatrickHennessey No problem!
– Grant Miller
May 23 '18 at 22:39
Also, as stated in the codepen, I cannot assign IDs to those elements. They're ultimately generated by a squarespace form and I have to work with what I have. Thanks again!
– Patrick Hennessey
May 23 '18 at 22:43
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You are using the wrong selector.
$('#dropdown1') // Change to $('[name="dropdown1"]')
$('#dropdown2') // Change to $('[name="dropdown2"]')
Alternatively, you can simply assign id="dropdown1" and id="dropdown2" to the respective elements.
answered May 23 '18 at 22:33
Grant MillerGrant Miller
6,559133458
1
Holy crap -- you're right! Thanks!
– Patrick Hennessey
May 23 '18 at 22:38
@PatrickHennessey No problem!
– Grant Miller
May 23 '18 at 22:39
Also, as stated in the codepen, I cannot assign IDs to those elements. They're ultimately generated by a squarespace form and I have to work with what I have. Thanks again!
– Patrick Hennessey
May 23 '18 at 22:43
add a comment |
1
You are using the wrong selector.
$('#dropdown1') // Change to $('[name="dropdown1"]')
$('#dropdown2') // Change to $('[name="dropdown2"]')
Alternatively, you can simply assign id="dropdown1" and id="dropdown2" to the respective elements.
answered May 23 '18 at 22:33
Grant MillerGrant Miller
6,559133458
1
Holy crap -- you're right! Thanks!
– Patrick Hennessey
May 23 '18 at 22:38
@PatrickHennessey No problem!
– Grant Miller
May 23 '18 at 22:39
Also, as stated in the codepen, I cannot assign IDs to those elements. They're ultimately generated by a squarespace form and I have to work with what I have. Thanks again!
– Patrick Hennessey
May 23 '18 at 22:43
add a comment |
1
1
1
You are using the wrong selector.
$('#dropdown1') // Change to $('[name="dropdown1"]')
$('#dropdown2') // Change to $('[name="dropdown2"]')
Alternatively, you can simply assign id="dropdown1" and id="dropdown2" to the respective elements.
answered May 23 '18 at 22:33
Grant MillerGrant Miller
6,559133458
You are using the wrong selector.
$('#dropdown1') // Change to $('[name="dropdown1"]')
$('#dropdown2') // Change to $('[name="dropdown2"]')
Alternatively, you can simply assign id="dropdown1" and id="dropdown2" to the respective elements.
answered May 23 '18 at 22:33
Grant MillerGrant Miller
6,559133458
edited Nov 22 '18 at 0:02
answered May 23 '18 at 22:33
Grant MillerGrant Miller
6,559133458
answered May 23 '18 at 22:33
Grant MillerGrant Miller
6,559133458
answered May 23 '18 at 22:33
Grant MillerGrant Miller
6,559133458
6,559133458
1
Holy crap -- you're right! Thanks!
– Patrick Hennessey
May 23 '18 at 22:38
@PatrickHennessey No problem!
– Grant Miller
May 23 '18 at 22:39
Also, as stated in the codepen, I cannot assign IDs to those elements. They're ultimately generated by a squarespace form and I have to work with what I have. Thanks again!
– Patrick Hennessey
May 23 '18 at 22:43
add a comment |
1
Holy crap -- you're right! Thanks!
– Patrick Hennessey
May 23 '18 at 22:38
@PatrickHennessey No problem!
– Grant Miller
May 23 '18 at 22:39
Also, as stated in the codepen, I cannot assign IDs to those elements. They're ultimately generated by a squarespace form and I have to work with what I have. Thanks again!
– Patrick Hennessey
May 23 '18 at 22:43
1
1
Holy crap -- you're right! Thanks!
– Patrick Hennessey
May 23 '18 at 22:38
Holy crap -- you're right! Thanks!
– Patrick Hennessey
May 23 '18 at 22:38
@PatrickHennessey No problem!
– Grant Miller
May 23 '18 at 22:39
@PatrickHennessey No problem!
– Grant Miller
May 23 '18 at 22:39
Also, as stated in the codepen, I cannot assign IDs to those elements. They're ultimately generated by a squarespace form and I have to work with what I have. Thanks again!
– Patrick Hennessey
May 23 '18 at 22:43
Also, as stated in the codepen, I cannot assign IDs to those elements. They're ultimately generated by a squarespace form and I have to work with what I have. Thanks again!
– Patrick Hennessey
May 23 '18 at 22:43
add a comment |
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