Camel - How to use properties set in a file in a route written in xml
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i've encountered some trouble using properties in a camel xml route without spring. I'm trying to use the properties in 'to uri' tag and so far i've achieved this result:
<to uri="properties:{{url}}{{delimiter}}throwExceptionOnFailure=false?locations=endpoint.properties"/>
url is the key for something like 'http4://localhost:8080' and delimiter is the key for '?'. I used this workaround to be able to use throwExceptionOnFailure option for the http4 component and avoid a FailedToCreateRouteException.
Is there another way to not get the exception? I'm also trying to get another solution using simple and recipientList, but until now i got only errors.
Thank you in advance
xml properties apache-camel
asked Nov 8 at 11:16
heartlex
107
add a comment |
up vote
1
down vote
favorite
i've encountered some trouble using properties in a camel xml route without spring. I'm trying to use the properties in 'to uri' tag and so far i've achieved this result:
<to uri="properties:{{url}}{{delimiter}}throwExceptionOnFailure=false?locations=endpoint.properties"/>
url is the key for something like 'http4://localhost:8080' and delimiter is the key for '?'. I used this workaround to be able to use throwExceptionOnFailure option for the http4 component and avoid a FailedToCreateRouteException.
Is there another way to not get the exception? I'm also trying to get another solution using simple and recipientList, but until now i got only errors.
Thank you in advance
xml properties apache-camel
asked Nov 8 at 11:16
heartlex
107
add a comment |
up vote
1
down vote
favorite
up vote
1
down vote
favorite
i've encountered some trouble using properties in a camel xml route without spring. I'm trying to use the properties in 'to uri' tag and so far i've achieved this result:
<to uri="properties:{{url}}{{delimiter}}throwExceptionOnFailure=false?locations=endpoint.properties"/>
url is the key for something like 'http4://localhost:8080' and delimiter is the key for '?'. I used this workaround to be able to use throwExceptionOnFailure option for the http4 component and avoid a FailedToCreateRouteException.
Is there another way to not get the exception? I'm also trying to get another solution using simple and recipientList, but until now i got only errors.
Thank you in advance
xml properties apache-camel
asked Nov 8 at 11:16
heartlex
107
i've encountered some trouble using properties in a camel xml route without spring. I'm trying to use the properties in 'to uri' tag and so far i've achieved this result:
<to uri="properties:{{url}}{{delimiter}}throwExceptionOnFailure=false?locations=endpoint.properties"/>
url is the key for something like 'http4://localhost:8080' and delimiter is the key for '?'. I used this workaround to be able to use throwExceptionOnFailure option for the http4 component and avoid a FailedToCreateRouteException.
Is there another way to not get the exception? I'm also trying to get another solution using simple and recipientList, but until now i got only errors.
Thank you in advance
xml properties apache-camel
xml properties apache-camel
asked Nov 8 at 11:16
heartlex
107
asked Nov 8 at 11:16
heartlex
107
edited Nov 8 at 11:43
asked Nov 8 at 11:16
heartlex
107
asked Nov 8 at 11:16
heartlex
107
asked Nov 8 at 11:16
heartlex
107
107
add a comment |
add a comment |
1 Answer
1
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oldest
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up vote
0
down vote
accepted
You need to ensure that the property placeholder is loaded before you can use it.
PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class);
props.setLocation("classpath:yourfile.properties:);
in XML :
<bean id="props" class="org.apache.camel.component.properties.PropertiesComponent">
<property name="location" value="classpath:yourfile.properties" />
</bean>
answered Nov 8 at 12:59
fg78nc
2,1981516
i tried to use a bean inside the camel config file, but i got an xml error so i changed strategy. i give it another try
– heartlex
Nov 8 at 13:46
my camel config file begins with the tag routes, not beans, and i can't load a bean inside it
– heartlex
Nov 8 at 13:54
beanelement should be outside ofcamelContextelement. Are you using Blueprint XML?
– fg78nc
Nov 8 at 14:48
i started from the exampe camel-example-servlet-tomcat-no-spring where i have a camel-config.xml which contains only routes (the file itself starts with the tag routes). No camel context or blueprint is provided. Changing approach using spring with a camelContext gives me the possibility to use beans (i used a propertyPlaceholder though). I'm only curious to know if another way is possible in the first scenario i mentioned
– heartlex
Nov 8 at 15:41
Add tobeforeStartmethod of theMyLifecycleclass the following lines :PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class); props.setLocation("classpath:yourfile.properties:);
– fg78nc
Nov 8 at 16:06
|
show 5 more comments
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
0
down vote
accepted
You need to ensure that the property placeholder is loaded before you can use it.
PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class);
props.setLocation("classpath:yourfile.properties:);
in XML :
<bean id="props" class="org.apache.camel.component.properties.PropertiesComponent">
<property name="location" value="classpath:yourfile.properties" />
</bean>
answered Nov 8 at 12:59
fg78nc
2,1981516
i tried to use a bean inside the camel config file, but i got an xml error so i changed strategy. i give it another try
– heartlex
Nov 8 at 13:46
my camel config file begins with the tag routes, not beans, and i can't load a bean inside it
– heartlex
Nov 8 at 13:54
beanelement should be outside ofcamelContextelement. Are you using Blueprint XML?
– fg78nc
Nov 8 at 14:48
i started from the exampe camel-example-servlet-tomcat-no-spring where i have a camel-config.xml which contains only routes (the file itself starts with the tag routes). No camel context or blueprint is provided. Changing approach using spring with a camelContext gives me the possibility to use beans (i used a propertyPlaceholder though). I'm only curious to know if another way is possible in the first scenario i mentioned
– heartlex
Nov 8 at 15:41
Add tobeforeStartmethod of theMyLifecycleclass the following lines :PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class); props.setLocation("classpath:yourfile.properties:);
– fg78nc
Nov 8 at 16:06
|
show 5 more comments
up vote
0
down vote
accepted
You need to ensure that the property placeholder is loaded before you can use it.
PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class);
props.setLocation("classpath:yourfile.properties:);
in XML :
<bean id="props" class="org.apache.camel.component.properties.PropertiesComponent">
<property name="location" value="classpath:yourfile.properties" />
</bean>
answered Nov 8 at 12:59
fg78nc
2,1981516
i tried to use a bean inside the camel config file, but i got an xml error so i changed strategy. i give it another try
– heartlex
Nov 8 at 13:46
my camel config file begins with the tag routes, not beans, and i can't load a bean inside it
– heartlex
Nov 8 at 13:54
beanelement should be outside ofcamelContextelement. Are you using Blueprint XML?
– fg78nc
Nov 8 at 14:48
i started from the exampe camel-example-servlet-tomcat-no-spring where i have a camel-config.xml which contains only routes (the file itself starts with the tag routes). No camel context or blueprint is provided. Changing approach using spring with a camelContext gives me the possibility to use beans (i used a propertyPlaceholder though). I'm only curious to know if another way is possible in the first scenario i mentioned
– heartlex
Nov 8 at 15:41
Add tobeforeStartmethod of theMyLifecycleclass the following lines :PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class); props.setLocation("classpath:yourfile.properties:);
– fg78nc
Nov 8 at 16:06
|
show 5 more comments
up vote
0
down vote
accepted
up vote
0
down vote
accepted
You need to ensure that the property placeholder is loaded before you can use it.
PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class);
props.setLocation("classpath:yourfile.properties:);
in XML :
<bean id="props" class="org.apache.camel.component.properties.PropertiesComponent">
<property name="location" value="classpath:yourfile.properties" />
</bean>
answered Nov 8 at 12:59
fg78nc
2,1981516
You need to ensure that the property placeholder is loaded before you can use it.
PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class);
props.setLocation("classpath:yourfile.properties:);
in XML :
<bean id="props" class="org.apache.camel.component.properties.PropertiesComponent">
<property name="location" value="classpath:yourfile.properties" />
</bean>
answered Nov 8 at 12:59
fg78nc
2,1981516
answered Nov 8 at 12:59
fg78nc
2,1981516
answered Nov 8 at 12:59
fg78nc
2,1981516
answered Nov 8 at 12:59
fg78nc
2,1981516
2,1981516
i tried to use a bean inside the camel config file, but i got an xml error so i changed strategy. i give it another try
– heartlex
Nov 8 at 13:46
my camel config file begins with the tag routes, not beans, and i can't load a bean inside it
– heartlex
Nov 8 at 13:54
beanelement should be outside ofcamelContextelement. Are you using Blueprint XML?
– fg78nc
Nov 8 at 14:48
i started from the exampe camel-example-servlet-tomcat-no-spring where i have a camel-config.xml which contains only routes (the file itself starts with the tag routes). No camel context or blueprint is provided. Changing approach using spring with a camelContext gives me the possibility to use beans (i used a propertyPlaceholder though). I'm only curious to know if another way is possible in the first scenario i mentioned
– heartlex
Nov 8 at 15:41
Add tobeforeStartmethod of theMyLifecycleclass the following lines :PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class); props.setLocation("classpath:yourfile.properties:);
– fg78nc
Nov 8 at 16:06
|
show 5 more comments
i tried to use a bean inside the camel config file, but i got an xml error so i changed strategy. i give it another try
– heartlex
Nov 8 at 13:46
my camel config file begins with the tag routes, not beans, and i can't load a bean inside it
– heartlex
Nov 8 at 13:54
beanelement should be outside ofcamelContextelement. Are you using Blueprint XML?
– fg78nc
Nov 8 at 14:48
i started from the exampe camel-example-servlet-tomcat-no-spring where i have a camel-config.xml which contains only routes (the file itself starts with the tag routes). No camel context or blueprint is provided. Changing approach using spring with a camelContext gives me the possibility to use beans (i used a propertyPlaceholder though). I'm only curious to know if another way is possible in the first scenario i mentioned
– heartlex
Nov 8 at 15:41
Add tobeforeStartmethod of theMyLifecycleclass the following lines :PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class); props.setLocation("classpath:yourfile.properties:);
– fg78nc
Nov 8 at 16:06
i tried to use a bean inside the camel config file, but i got an xml error so i changed strategy. i give it another try
– heartlex
Nov 8 at 13:46
i tried to use a bean inside the camel config file, but i got an xml error so i changed strategy. i give it another try
– heartlex
Nov 8 at 13:46
my camel config file begins with the tag routes, not beans, and i can't load a bean inside it
– heartlex
Nov 8 at 13:54
my camel config file begins with the tag routes, not beans, and i can't load a bean inside it
– heartlex
Nov 8 at 13:54
bean element should be outside of camelContext element. Are you using Blueprint XML?– fg78nc
Nov 8 at 14:48
bean element should be outside of camelContext element. Are you using Blueprint XML?– fg78nc
Nov 8 at 14:48
i started from the exampe camel-example-servlet-tomcat-no-spring where i have a camel-config.xml which contains only routes (the file itself starts with the tag routes). No camel context or blueprint is provided. Changing approach using spring with a camelContext gives me the possibility to use beans (i used a propertyPlaceholder though). I'm only curious to know if another way is possible in the first scenario i mentioned
– heartlex
Nov 8 at 15:41
i started from the exampe camel-example-servlet-tomcat-no-spring where i have a camel-config.xml which contains only routes (the file itself starts with the tag routes). No camel context or blueprint is provided. Changing approach using spring with a camelContext gives me the possibility to use beans (i used a propertyPlaceholder though). I'm only curious to know if another way is possible in the first scenario i mentioned
– heartlex
Nov 8 at 15:41
Add to
beforeStart method of the MyLifecycle class the following lines : PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class); props.setLocation("classpath:yourfile.properties:);– fg78nc
Nov 8 at 16:06
Add to
beforeStart method of the MyLifecycle class the following lines : PropertiesComponent props = camelContext.getComponent("properties", PropertiesComponent.class); props.setLocation("classpath:yourfile.properties:);– fg78nc
Nov 8 at 16:06
|
show 5 more comments
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