Groupby and cumcount for valid rows only











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0
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I have a dataframe looks like this:



    ids    valid        date
0 1 False 2012-06-10
1 1 True 2012-07-11
2 1 True 2012-09-20
3 2 False 2012-01-12
4 2 True 2012-07-11
5 3 True 2012-03-09
6 3 True 2012-07-11
7 3 False 2012-12-09
8 4 False 2012-07-11


I want to count how many valid case the person has so far and going through them in ascending date order



ids              valid           date         occur
1 False 2012-06-10 0
1 True 2012-07-11 1
1 True 2012-09-20 2
2 False 2012-01-12 0
2 True 2012-07-11 1
3 True 2012-03-09 1
3 True 2012-07-11 2
3 False 2012-12-09 0
4 False 2012-07-11 0


What I have tried so far:



df = df.sort_values(['id', 'date'])
df['occur'] = df.groupby('valid').cumcount()+1









share|improve this question
























  • "valid" in the input is integer but is boolean in the output? How does that work?
    – coldspeed
    Nov 9 at 22:13










  • @coldspeed I multiply the column by one to translate from true false
    – Matt-pow
    Nov 9 at 22:16










  • That doesn't explain how 1 * 1= False in row #2.
    – coldspeed
    Nov 9 at 22:16










  • Made an edit to correct mistakes
    – Matt-pow
    Nov 9 at 22:18










  • My question is how is it possible for any False values to be present if all of the rows are > 0?
    – coldspeed
    Nov 9 at 22:19















up vote
0
down vote

favorite












I have a dataframe looks like this:



    ids    valid        date
0 1 False 2012-06-10
1 1 True 2012-07-11
2 1 True 2012-09-20
3 2 False 2012-01-12
4 2 True 2012-07-11
5 3 True 2012-03-09
6 3 True 2012-07-11
7 3 False 2012-12-09
8 4 False 2012-07-11


I want to count how many valid case the person has so far and going through them in ascending date order



ids              valid           date         occur
1 False 2012-06-10 0
1 True 2012-07-11 1
1 True 2012-09-20 2
2 False 2012-01-12 0
2 True 2012-07-11 1
3 True 2012-03-09 1
3 True 2012-07-11 2
3 False 2012-12-09 0
4 False 2012-07-11 0


What I have tried so far:



df = df.sort_values(['id', 'date'])
df['occur'] = df.groupby('valid').cumcount()+1









share|improve this question
























  • "valid" in the input is integer but is boolean in the output? How does that work?
    – coldspeed
    Nov 9 at 22:13










  • @coldspeed I multiply the column by one to translate from true false
    – Matt-pow
    Nov 9 at 22:16










  • That doesn't explain how 1 * 1= False in row #2.
    – coldspeed
    Nov 9 at 22:16










  • Made an edit to correct mistakes
    – Matt-pow
    Nov 9 at 22:18










  • My question is how is it possible for any False values to be present if all of the rows are > 0?
    – coldspeed
    Nov 9 at 22:19













up vote
0
down vote

favorite









up vote
0
down vote

favorite











I have a dataframe looks like this:



    ids    valid        date
0 1 False 2012-06-10
1 1 True 2012-07-11
2 1 True 2012-09-20
3 2 False 2012-01-12
4 2 True 2012-07-11
5 3 True 2012-03-09
6 3 True 2012-07-11
7 3 False 2012-12-09
8 4 False 2012-07-11


I want to count how many valid case the person has so far and going through them in ascending date order



ids              valid           date         occur
1 False 2012-06-10 0
1 True 2012-07-11 1
1 True 2012-09-20 2
2 False 2012-01-12 0
2 True 2012-07-11 1
3 True 2012-03-09 1
3 True 2012-07-11 2
3 False 2012-12-09 0
4 False 2012-07-11 0


What I have tried so far:



df = df.sort_values(['id', 'date'])
df['occur'] = df.groupby('valid').cumcount()+1









share|improve this question















I have a dataframe looks like this:



    ids    valid        date
0 1 False 2012-06-10
1 1 True 2012-07-11
2 1 True 2012-09-20
3 2 False 2012-01-12
4 2 True 2012-07-11
5 3 True 2012-03-09
6 3 True 2012-07-11
7 3 False 2012-12-09
8 4 False 2012-07-11


I want to count how many valid case the person has so far and going through them in ascending date order



ids              valid           date         occur
1 False 2012-06-10 0
1 True 2012-07-11 1
1 True 2012-09-20 2
2 False 2012-01-12 0
2 True 2012-07-11 1
3 True 2012-03-09 1
3 True 2012-07-11 2
3 False 2012-12-09 0
4 False 2012-07-11 0


What I have tried so far:



df = df.sort_values(['id', 'date'])
df['occur'] = df.groupby('valid').cumcount()+1






python pandas dataframe group-by pandas-groupby






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edited Nov 9 at 22:59









coldspeed

111k17101170




111k17101170










asked Nov 9 at 22:11









Matt-pow

114214




114214












  • "valid" in the input is integer but is boolean in the output? How does that work?
    – coldspeed
    Nov 9 at 22:13










  • @coldspeed I multiply the column by one to translate from true false
    – Matt-pow
    Nov 9 at 22:16










  • That doesn't explain how 1 * 1= False in row #2.
    – coldspeed
    Nov 9 at 22:16










  • Made an edit to correct mistakes
    – Matt-pow
    Nov 9 at 22:18










  • My question is how is it possible for any False values to be present if all of the rows are > 0?
    – coldspeed
    Nov 9 at 22:19


















  • "valid" in the input is integer but is boolean in the output? How does that work?
    – coldspeed
    Nov 9 at 22:13










  • @coldspeed I multiply the column by one to translate from true false
    – Matt-pow
    Nov 9 at 22:16










  • That doesn't explain how 1 * 1= False in row #2.
    – coldspeed
    Nov 9 at 22:16










  • Made an edit to correct mistakes
    – Matt-pow
    Nov 9 at 22:18










  • My question is how is it possible for any False values to be present if all of the rows are > 0?
    – coldspeed
    Nov 9 at 22:19
















"valid" in the input is integer but is boolean in the output? How does that work?
– coldspeed
Nov 9 at 22:13




"valid" in the input is integer but is boolean in the output? How does that work?
– coldspeed
Nov 9 at 22:13












@coldspeed I multiply the column by one to translate from true false
– Matt-pow
Nov 9 at 22:16




@coldspeed I multiply the column by one to translate from true false
– Matt-pow
Nov 9 at 22:16












That doesn't explain how 1 * 1= False in row #2.
– coldspeed
Nov 9 at 22:16




That doesn't explain how 1 * 1= False in row #2.
– coldspeed
Nov 9 at 22:16












Made an edit to correct mistakes
– Matt-pow
Nov 9 at 22:18




Made an edit to correct mistakes
– Matt-pow
Nov 9 at 22:18












My question is how is it possible for any False values to be present if all of the rows are > 0?
– coldspeed
Nov 9 at 22:19




My question is how is it possible for any False values to be present if all of the rows are > 0?
– coldspeed
Nov 9 at 22:19












1 Answer
1






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oldest

votes

















up vote
1
down vote



accepted










Use groupby and cumcount:



df['occur'] = (df.groupby(['ids', 'valid'])
.cumcount()
.add(1)
.where(df.valid, 0))
print(df)
ids valid date occur
0 1 False 2012-06-10 0
1 1 True 2012-07-11 1
2 1 True 2012-09-20 2
3 2 False 2012-01-12 0
4 2 True 2012-07-11 1
5 3 True 2012-03-09 1
6 3 True 2012-07-11 2
7 3 False 2012-12-09 0
8 4 False 2012-07-11 0





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    1 Answer
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    active

    oldest

    votes








    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes








    up vote
    1
    down vote



    accepted










    Use groupby and cumcount:



    df['occur'] = (df.groupby(['ids', 'valid'])
    .cumcount()
    .add(1)
    .where(df.valid, 0))
    print(df)
    ids valid date occur
    0 1 False 2012-06-10 0
    1 1 True 2012-07-11 1
    2 1 True 2012-09-20 2
    3 2 False 2012-01-12 0
    4 2 True 2012-07-11 1
    5 3 True 2012-03-09 1
    6 3 True 2012-07-11 2
    7 3 False 2012-12-09 0
    8 4 False 2012-07-11 0





    share|improve this answer

























      up vote
      1
      down vote



      accepted










      Use groupby and cumcount:



      df['occur'] = (df.groupby(['ids', 'valid'])
      .cumcount()
      .add(1)
      .where(df.valid, 0))
      print(df)
      ids valid date occur
      0 1 False 2012-06-10 0
      1 1 True 2012-07-11 1
      2 1 True 2012-09-20 2
      3 2 False 2012-01-12 0
      4 2 True 2012-07-11 1
      5 3 True 2012-03-09 1
      6 3 True 2012-07-11 2
      7 3 False 2012-12-09 0
      8 4 False 2012-07-11 0





      share|improve this answer























        up vote
        1
        down vote



        accepted







        up vote
        1
        down vote



        accepted






        Use groupby and cumcount:



        df['occur'] = (df.groupby(['ids', 'valid'])
        .cumcount()
        .add(1)
        .where(df.valid, 0))
        print(df)
        ids valid date occur
        0 1 False 2012-06-10 0
        1 1 True 2012-07-11 1
        2 1 True 2012-09-20 2
        3 2 False 2012-01-12 0
        4 2 True 2012-07-11 1
        5 3 True 2012-03-09 1
        6 3 True 2012-07-11 2
        7 3 False 2012-12-09 0
        8 4 False 2012-07-11 0





        share|improve this answer












        Use groupby and cumcount:



        df['occur'] = (df.groupby(['ids', 'valid'])
        .cumcount()
        .add(1)
        .where(df.valid, 0))
        print(df)
        ids valid date occur
        0 1 False 2012-06-10 0
        1 1 True 2012-07-11 1
        2 1 True 2012-09-20 2
        3 2 False 2012-01-12 0
        4 2 True 2012-07-11 1
        5 3 True 2012-03-09 1
        6 3 True 2012-07-11 2
        7 3 False 2012-12-09 0
        8 4 False 2012-07-11 0






        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 9 at 22:57









        coldspeed

        111k17101170




        111k17101170






























             

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