Print a column without 1st item of that column












0














Good night everybody, i want to print a column without printing the 1st item of that column.



I want print the 4th column of this csv file:



ID;Curso;AnoNasc;MediaAcesso;Salario;IndiceSatisfacao
1;Psicologia;1994;18;750;3
2;Psicologia;1992;17;754;4
3;Psicologia;1991;13;780;4
4;Psicologia;1993;11;900;4


So i do this:



system("awk -F ';' '{print $4}' DBcursos.csv > ficha02exer08-mediaacesso.dat");


But this print:



MediaAcesso
18
17
13
11


But i only want the numbers, so i want to print all except the first line (MediaAcesso), how can i do this? Can i do this with AWK?



Thank you!










share|improve this question
























  • Exactly, i want print the 4th column without 1st element of that column, in this case without "MediaAcesso"
    – José Miranda
    Nov 14 '18 at 20:14










  • Yeah, now i know that... I just started using awk today, so i'm kind a noobie with this.
    – José Miranda
    Nov 14 '18 at 20:18
















0














Good night everybody, i want to print a column without printing the 1st item of that column.



I want print the 4th column of this csv file:



ID;Curso;AnoNasc;MediaAcesso;Salario;IndiceSatisfacao
1;Psicologia;1994;18;750;3
2;Psicologia;1992;17;754;4
3;Psicologia;1991;13;780;4
4;Psicologia;1993;11;900;4


So i do this:



system("awk -F ';' '{print $4}' DBcursos.csv > ficha02exer08-mediaacesso.dat");


But this print:



MediaAcesso
18
17
13
11


But i only want the numbers, so i want to print all except the first line (MediaAcesso), how can i do this? Can i do this with AWK?



Thank you!










share|improve this question
























  • Exactly, i want print the 4th column without 1st element of that column, in this case without "MediaAcesso"
    – José Miranda
    Nov 14 '18 at 20:14










  • Yeah, now i know that... I just started using awk today, so i'm kind a noobie with this.
    – José Miranda
    Nov 14 '18 at 20:18














0












0








0







Good night everybody, i want to print a column without printing the 1st item of that column.



I want print the 4th column of this csv file:



ID;Curso;AnoNasc;MediaAcesso;Salario;IndiceSatisfacao
1;Psicologia;1994;18;750;3
2;Psicologia;1992;17;754;4
3;Psicologia;1991;13;780;4
4;Psicologia;1993;11;900;4


So i do this:



system("awk -F ';' '{print $4}' DBcursos.csv > ficha02exer08-mediaacesso.dat");


But this print:



MediaAcesso
18
17
13
11


But i only want the numbers, so i want to print all except the first line (MediaAcesso), how can i do this? Can i do this with AWK?



Thank you!










share|improve this question















Good night everybody, i want to print a column without printing the 1st item of that column.



I want print the 4th column of this csv file:



ID;Curso;AnoNasc;MediaAcesso;Salario;IndiceSatisfacao
1;Psicologia;1994;18;750;3
2;Psicologia;1992;17;754;4
3;Psicologia;1991;13;780;4
4;Psicologia;1993;11;900;4


So i do this:



system("awk -F ';' '{print $4}' DBcursos.csv > ficha02exer08-mediaacesso.dat");


But this print:



MediaAcesso
18
17
13
11


But i only want the numbers, so i want to print all except the first line (MediaAcesso), how can i do this? Can i do this with AWK?



Thank you!







linux awk






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share|improve this question













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edited Nov 14 '18 at 20:11









lurker

43.8k74572




43.8k74572










asked Nov 14 '18 at 20:07









José Miranda

63




63












  • Exactly, i want print the 4th column without 1st element of that column, in this case without "MediaAcesso"
    – José Miranda
    Nov 14 '18 at 20:14










  • Yeah, now i know that... I just started using awk today, so i'm kind a noobie with this.
    – José Miranda
    Nov 14 '18 at 20:18


















  • Exactly, i want print the 4th column without 1st element of that column, in this case without "MediaAcesso"
    – José Miranda
    Nov 14 '18 at 20:14










  • Yeah, now i know that... I just started using awk today, so i'm kind a noobie with this.
    – José Miranda
    Nov 14 '18 at 20:18
















Exactly, i want print the 4th column without 1st element of that column, in this case without "MediaAcesso"
– José Miranda
Nov 14 '18 at 20:14




Exactly, i want print the 4th column without 1st element of that column, in this case without "MediaAcesso"
– José Miranda
Nov 14 '18 at 20:14












Yeah, now i know that... I just started using awk today, so i'm kind a noobie with this.
– José Miranda
Nov 14 '18 at 20:18




Yeah, now i know that... I just started using awk today, so i'm kind a noobie with this.
– José Miranda
Nov 14 '18 at 20:18












1 Answer
1






active

oldest

votes


















0














Don't think of it as skipping the first element of a column, you just want to skip processing the entire first row of the file. So check the record number and only process records after that one.



awk -F ';' 'NR > 1 {print $4}' DBcursos.csv > ficha02exer08-mediaacesso.dat





share|improve this answer























  • That's it!! Thank you so much.
    – José Miranda
    Nov 14 '18 at 20:17











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1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









0














Don't think of it as skipping the first element of a column, you just want to skip processing the entire first row of the file. So check the record number and only process records after that one.



awk -F ';' 'NR > 1 {print $4}' DBcursos.csv > ficha02exer08-mediaacesso.dat





share|improve this answer























  • That's it!! Thank you so much.
    – José Miranda
    Nov 14 '18 at 20:17
















0














Don't think of it as skipping the first element of a column, you just want to skip processing the entire first row of the file. So check the record number and only process records after that one.



awk -F ';' 'NR > 1 {print $4}' DBcursos.csv > ficha02exer08-mediaacesso.dat





share|improve this answer























  • That's it!! Thank you so much.
    – José Miranda
    Nov 14 '18 at 20:17














0












0








0






Don't think of it as skipping the first element of a column, you just want to skip processing the entire first row of the file. So check the record number and only process records after that one.



awk -F ';' 'NR > 1 {print $4}' DBcursos.csv > ficha02exer08-mediaacesso.dat





share|improve this answer














Don't think of it as skipping the first element of a column, you just want to skip processing the entire first row of the file. So check the record number and only process records after that one.



awk -F ';' 'NR > 1 {print $4}' DBcursos.csv > ficha02exer08-mediaacesso.dat






share|improve this answer














share|improve this answer



share|improve this answer








edited Nov 14 '18 at 20:18

























answered Nov 14 '18 at 20:15









Barmar

420k35244344




420k35244344












  • That's it!! Thank you so much.
    – José Miranda
    Nov 14 '18 at 20:17


















  • That's it!! Thank you so much.
    – José Miranda
    Nov 14 '18 at 20:17
















That's it!! Thank you so much.
– José Miranda
Nov 14 '18 at 20:17




That's it!! Thank you so much.
– José Miranda
Nov 14 '18 at 20:17


















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