Using PHP preg_replace to append text to pattern found with regex












0















I want to append a tag div before and after all tags img.



So I have



<img src=%random url image% />


And it should be replaced with



<div class="demo"><img src=%random url image% /></div>


Can I do it with preg_replace?



$string = %page source code%;

$find = array("/<img(.*?)/>/");

$replace = array('<div class="demo">'.$find[0].'</div>');

$result = preg_replace($find, $replace, $string);


But it not work :/






php regex







share|improve this question




















  • 3





    You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.

    – Tim Biegeleisen
    Nov 18 '18 at 2:30






  • 1





    Please don't try to parse [X]HTML using regex. You may want to take a look at this.

    – K.Dᴀᴠɪs
    Nov 18 '18 at 3:05
















0















I want to append a tag div before and after all tags img.



So I have



<img src=%random url image% />


And it should be replaced with



<div class="demo"><img src=%random url image% /></div>


Can I do it with preg_replace?



$string = %page source code%;

$find = array("/<img(.*?)/>/");

$replace = array('<div class="demo">'.$find[0].'</div>');

$result = preg_replace($find, $replace, $string);


But it not work :/






php regex







share|improve this question




















  • 3





    You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.

    – Tim Biegeleisen
    Nov 18 '18 at 2:30






  • 1





    Please don't try to parse [X]HTML using regex. You may want to take a look at this.

    – K.Dᴀᴠɪs
    Nov 18 '18 at 3:05














0












0








0








I want to append a tag div before and after all tags img.



So I have



<img src=%random url image% />


And it should be replaced with



<div class="demo"><img src=%random url image% /></div>


Can I do it with preg_replace?



$string = %page source code%;

$find = array("/<img(.*?)/>/");

$replace = array('<div class="demo">'.$find[0].'</div>');

$result = preg_replace($find, $replace, $string);


But it not work :/






php regex







share|improve this question
















I want to append a tag div before and after all tags img.



So I have



<img src=%random url image% />


And it should be replaced with



<div class="demo"><img src=%random url image% /></div>


Can I do it with preg_replace?



$string = %page source code%;

$find = array("/<img(.*?)/>/");

$replace = array('<div class="demo">'.$find[0].'</div>');

$result = preg_replace($find, $replace, $string);


But it not work :/






php regex




php regex






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 18 '18 at 2:29







Migu3litto

















asked Nov 18 '18 at 2:24









Migu3littoMigu3litto

315




315








  • 3





    You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.

    – Tim Biegeleisen
    Nov 18 '18 at 2:30






  • 1





    Please don't try to parse [X]HTML using regex. You may want to take a look at this.

    – K.Dᴀᴠɪs
    Nov 18 '18 at 3:05














  • 3





    You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.

    – Tim Biegeleisen
    Nov 18 '18 at 2:30






  • 1





    Please don't try to parse [X]HTML using regex. You may want to take a look at this.

    – K.Dᴀᴠɪs
    Nov 18 '18 at 3:05








3




3





You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.

– Tim Biegeleisen
Nov 18 '18 at 2:30





You can probably do this with `preg_replace_, but that doesn't mean that you should do it. Consider using an XML/HTML parser instead.

– Tim Biegeleisen
Nov 18 '18 at 2:30




1




1





Please don't try to parse [X]HTML using regex. You may want to take a look at this.

– K.Dᴀᴠɪs
Nov 18 '18 at 3:05





Please don't try to parse [X]HTML using regex. You may want to take a look at this.

– K.Dᴀᴠɪs
Nov 18 '18 at 3:05












1 Answer
1






active

oldest

votes


















2














A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:



$html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';

$doc = new DOMDocument();

$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);

$xpath = new DOMXpath($doc);

$images = $xpath->query('//img');

foreach ($images as $image) {

    $div = $doc->createElement('div');

    $div->setAttribute('class', 'demo');

    $image->parentNode->replaceChild($div, $image);

    $div->appendChild($image);

}

echo $doc->saveHTML();


Output:



<div>

    <div class="demo"><img src="http://x.com"></div>

    <span>xyz</span>

    <a href="http://example.com">

        <div class="demo"><img src="http://example.com"></div>

    </a>

</div>


Demo on 3v4l.org






share|improve this answer























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    1 Answer
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    active

    oldest

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    1 Answer
    1






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    2














    A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:



    $html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';
    
$doc = new DOMDocument();
    
$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
    
$xpath = new DOMXpath($doc);
    
$images = $xpath->query('//img');
    
foreach ($images as $image) {
    
    $div = $doc->createElement('div');
    
    $div->setAttribute('class', 'demo');
    
    $image->parentNode->replaceChild($div, $image);
    
    $div->appendChild($image);
    
}
    
echo $doc->saveHTML();


    Output:



    <div>
    
    <div class="demo"><img src="http://x.com"></div>
    
    <span>xyz</span>
    
    <a href="http://example.com">
    
        <div class="demo"><img src="http://example.com"></div>
    
    </a>
    
</div>


    Demo on 3v4l.org






    share|improve this answer




























      2














      A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:



      $html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';
      
$doc = new DOMDocument();
      
$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
      
$xpath = new DOMXpath($doc);
      
$images = $xpath->query('//img');
      
foreach ($images as $image) {
      
    $div = $doc->createElement('div');
      
    $div->setAttribute('class', 'demo');
      
    $image->parentNode->replaceChild($div, $image);
      
    $div->appendChild($image);
      
}
      
echo $doc->saveHTML();


      Output:



      <div>
      
    <div class="demo"><img src="http://x.com"></div>
      
    <span>xyz</span>
      
    <a href="http://example.com">
      
        <div class="demo"><img src="http://example.com"></div>
      
    </a>
      
</div>


      Demo on 3v4l.org






      share|improve this answer


























        2












        2








        2







        A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:



        $html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';
        
$doc = new DOMDocument();
        
$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
        
$xpath = new DOMXpath($doc);
        
$images = $xpath->query('//img');
        
foreach ($images as $image) {
        
    $div = $doc->createElement('div');
        
    $div->setAttribute('class', 'demo');
        
    $image->parentNode->replaceChild($div, $image);
        
    $div->appendChild($image);
        
}
        
echo $doc->saveHTML();


        Output:



        <div>
        
    <div class="demo"><img src="http://x.com"></div>
        
    <span>xyz</span>
        
    <a href="http://example.com">
        
        <div class="demo"><img src="http://example.com"></div>
        
    </a>
        
</div>


        Demo on 3v4l.org






        share|improve this answer













        A better way to parse HTML is using PHPs DOMDocument and DOMXPath classes. In your case, you can use XPath to find all the images, then add a div around them as shown in this example:



        $html = '<div><img src="http://x.com" /><span>xyz</span><a href="http://example.com"><img src="http://example.com" /></a></div>';
        
$doc = new DOMDocument();
        
$doc->loadHTML($html, LIBXML_HTML_NOIMPLIED | LIBXML_HTML_NODEFDTD);
        
$xpath = new DOMXpath($doc);
        
$images = $xpath->query('//img');
        
foreach ($images as $image) {
        
    $div = $doc->createElement('div');
        
    $div->setAttribute('class', 'demo');
        
    $image->parentNode->replaceChild($div, $image);
        
    $div->appendChild($image);
        
}
        
echo $doc->saveHTML();


        Output:



        <div>
        
    <div class="demo"><img src="http://x.com"></div>
        
    <span>xyz</span>
        
    <a href="http://example.com">
        
        <div class="demo"><img src="http://example.com"></div>
        
    </a>
        
</div>


        Demo on 3v4l.org







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 18 '18 at 3:20









        NickNick

        26.4k111839




        26.4k111839






























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