Add class to parent span element jquery
I am attempting to change the class of a checkbox parent element (span) to checked. I'm following these steps but am getting the error:
$checkbox.parentNode.addClass is not a function
at HTMLInputElement.
Here is the website
Here is the JS code:
<script type="text/javascript">
document.getElementById("generateVin").addEventListener("click", function(){
var $checkbox = document.querySelectorAll("input[type='checkbox']")[1];
var $span=$checkbox.closest("span");
$checkbox.parentNode.addClass("checked");
});
</script>
javascript jquery
asked Nov 19 '18 at 21:59
AlexAlex
43
add a comment |
I am attempting to change the class of a checkbox parent element (span) to checked. I'm following these steps but am getting the error:
$checkbox.parentNode.addClass is not a function
at HTMLInputElement.
Here is the website
Here is the JS code:
<script type="text/javascript">
document.getElementById("generateVin").addEventListener("click", function(){
var $checkbox = document.querySelectorAll("input[type='checkbox']")[1];
var $span=$checkbox.closest("span");
$checkbox.parentNode.addClass("checked");
});
</script>
javascript jquery
asked Nov 19 '18 at 21:59
AlexAlex
43
add a comment |
I am attempting to change the class of a checkbox parent element (span) to checked. I'm following these steps but am getting the error:
$checkbox.parentNode.addClass is not a function
at HTMLInputElement.
Here is the website
Here is the JS code:
<script type="text/javascript">
document.getElementById("generateVin").addEventListener("click", function(){
var $checkbox = document.querySelectorAll("input[type='checkbox']")[1];
var $span=$checkbox.closest("span");
$checkbox.parentNode.addClass("checked");
});
</script>
javascript jquery
asked Nov 19 '18 at 21:59
AlexAlex
43
I am attempting to change the class of a checkbox parent element (span) to checked. I'm following these steps but am getting the error:
$checkbox.parentNode.addClass is not a function
at HTMLInputElement.
Here is the website
Here is the JS code:
<script type="text/javascript">
document.getElementById("generateVin").addEventListener("click", function(){
var $checkbox = document.querySelectorAll("input[type='checkbox']")[1];
var $span=$checkbox.closest("span");
$checkbox.parentNode.addClass("checked");
});
</script>
javascript jquery
javascript jquery
asked Nov 19 '18 at 21:59
AlexAlex
43
asked Nov 19 '18 at 21:59
AlexAlex
43
asked Nov 19 '18 at 21:59
AlexAlex
43
asked Nov 19 '18 at 21:59
AlexAlex
43
asked Nov 19 '18 at 21:59
AlexAlex
43
43
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
You're mixing jQuery with vanilla JavaScript. .addClass() is a jQuery method, meaning it can only be called on jQuery elements.
$checkbox.parentNode is not a jQuery element, but rather a standard JS element.
If you're committed to using jQuery, then it's highly suggested that you go "all the way", rather than going back and forth. The code would look more like this:
$("#generateVin").on("click", function() {
var $checkbox = $("input[type=checkbox]").eq(1);
var $span = $checkox.closest("span"); //This doesn't seem to be needed
$checkbox.parent().addClass("checked");
});Used jQuery selector syntax to target
generateVin:$("#generateVin")Used jQuery event handlers:
.on("click", function() { ... })Converted
$checkboxto a jQuery element by using jQuery selector and.eq():var $checkbox = $("input[type=checkbox]").eq(1);Used jQuery's
parent()in place ofparentNode
answered Nov 19 '18 at 22:03
Tyler RoperTyler Roper
13.7k32041
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You're mixing jQuery with vanilla JavaScript. .addClass() is a jQuery method, meaning it can only be called on jQuery elements.
$checkbox.parentNode is not a jQuery element, but rather a standard JS element.
If you're committed to using jQuery, then it's highly suggested that you go "all the way", rather than going back and forth. The code would look more like this:
$("#generateVin").on("click", function() {
var $checkbox = $("input[type=checkbox]").eq(1);
var $span = $checkox.closest("span"); //This doesn't seem to be needed
$checkbox.parent().addClass("checked");
});Used jQuery selector syntax to target
generateVin:$("#generateVin")Used jQuery event handlers:
.on("click", function() { ... })Converted
$checkboxto a jQuery element by using jQuery selector and.eq():var $checkbox = $("input[type=checkbox]").eq(1);Used jQuery's
parent()in place ofparentNode
answered Nov 19 '18 at 22:03
Tyler RoperTyler Roper
13.7k32041
add a comment |
You're mixing jQuery with vanilla JavaScript. .addClass() is a jQuery method, meaning it can only be called on jQuery elements.
$checkbox.parentNode is not a jQuery element, but rather a standard JS element.
If you're committed to using jQuery, then it's highly suggested that you go "all the way", rather than going back and forth. The code would look more like this:
$("#generateVin").on("click", function() {
var $checkbox = $("input[type=checkbox]").eq(1);
var $span = $checkox.closest("span"); //This doesn't seem to be needed
$checkbox.parent().addClass("checked");
});Used jQuery selector syntax to target
generateVin:$("#generateVin")Used jQuery event handlers:
.on("click", function() { ... })Converted
$checkboxto a jQuery element by using jQuery selector and.eq():var $checkbox = $("input[type=checkbox]").eq(1);Used jQuery's
parent()in place ofparentNode
answered Nov 19 '18 at 22:03
Tyler RoperTyler Roper
13.7k32041
add a comment |
You're mixing jQuery with vanilla JavaScript. .addClass() is a jQuery method, meaning it can only be called on jQuery elements.
$checkbox.parentNode is not a jQuery element, but rather a standard JS element.
If you're committed to using jQuery, then it's highly suggested that you go "all the way", rather than going back and forth. The code would look more like this:
$("#generateVin").on("click", function() {
var $checkbox = $("input[type=checkbox]").eq(1);
var $span = $checkox.closest("span"); //This doesn't seem to be needed
$checkbox.parent().addClass("checked");
});Used jQuery selector syntax to target
generateVin:$("#generateVin")Used jQuery event handlers:
.on("click", function() { ... })Converted
$checkboxto a jQuery element by using jQuery selector and.eq():var $checkbox = $("input[type=checkbox]").eq(1);Used jQuery's
parent()in place ofparentNode
answered Nov 19 '18 at 22:03
Tyler RoperTyler Roper
13.7k32041
You're mixing jQuery with vanilla JavaScript. .addClass() is a jQuery method, meaning it can only be called on jQuery elements.
$checkbox.parentNode is not a jQuery element, but rather a standard JS element.
If you're committed to using jQuery, then it's highly suggested that you go "all the way", rather than going back and forth. The code would look more like this:
$("#generateVin").on("click", function() {
var $checkbox = $("input[type=checkbox]").eq(1);
var $span = $checkox.closest("span"); //This doesn't seem to be needed
$checkbox.parent().addClass("checked");
});Used jQuery selector syntax to target
generateVin:$("#generateVin")Used jQuery event handlers:
.on("click", function() { ... })Converted
$checkboxto a jQuery element by using jQuery selector and.eq():var $checkbox = $("input[type=checkbox]").eq(1);Used jQuery's
parent()in place ofparentNode
$("#generateVin").on("click", function() {
var $checkbox = $("input[type=checkbox]").eq(1);
var $span = $checkox.closest("span"); //This doesn't seem to be needed
$checkbox.parent().addClass("checked");
});$("#generateVin").on("click", function() {
var $checkbox = $("input[type=checkbox]").eq(1);
var $span = $checkox.closest("span"); //This doesn't seem to be needed
$checkbox.parent().addClass("checked");
});answered Nov 19 '18 at 22:03
Tyler RoperTyler Roper
13.7k32041
edited Nov 19 '18 at 22:08
answered Nov 19 '18 at 22:03
Tyler RoperTyler Roper
13.7k32041
answered Nov 19 '18 at 22:03
Tyler RoperTyler Roper
13.7k32041
answered Nov 19 '18 at 22:03
Tyler RoperTyler Roper
13.7k32041
13.7k32041
add a comment |
add a comment |
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