adding rows to data table using for loop in R
I am playing with some basic R functions and am trying to create a table that includes the Remainder and Quotient for the numbers 1:20
First I created this function:
Find_Remains = function(number, divisor){
Remainder = number%%divisor
Quotient = number%/%divisor
a = c(number, divisor, Remainder, Quotient)
return(a)
}
I add a blank table
final.data.frame = data.frame(matrix(NA, nrow = 1, ncol = 4))
Then I created this for loop
for(i in c(1:20)){
b[i] = Find_Remains(i,5)
final.data.frame = rbind(b[i])
}
the error I get is:
number of items to replace is not a multiple of replacement length
any help would be appreciated. Thanks
r dataframe for-loop division
asked Nov 19 '18 at 22:09
KatieMKatieM
83
add a comment |
I am playing with some basic R functions and am trying to create a table that includes the Remainder and Quotient for the numbers 1:20
First I created this function:
Find_Remains = function(number, divisor){
Remainder = number%%divisor
Quotient = number%/%divisor
a = c(number, divisor, Remainder, Quotient)
return(a)
}
I add a blank table
final.data.frame = data.frame(matrix(NA, nrow = 1, ncol = 4))
Then I created this for loop
for(i in c(1:20)){
b[i] = Find_Remains(i,5)
final.data.frame = rbind(b[i])
}
the error I get is:
number of items to replace is not a multiple of replacement length
any help would be appreciated. Thanks
r dataframe for-loop division
asked Nov 19 '18 at 22:09
KatieMKatieM
83
add a comment |
I am playing with some basic R functions and am trying to create a table that includes the Remainder and Quotient for the numbers 1:20
First I created this function:
Find_Remains = function(number, divisor){
Remainder = number%%divisor
Quotient = number%/%divisor
a = c(number, divisor, Remainder, Quotient)
return(a)
}
I add a blank table
final.data.frame = data.frame(matrix(NA, nrow = 1, ncol = 4))
Then I created this for loop
for(i in c(1:20)){
b[i] = Find_Remains(i,5)
final.data.frame = rbind(b[i])
}
the error I get is:
number of items to replace is not a multiple of replacement length
any help would be appreciated. Thanks
r dataframe for-loop division
asked Nov 19 '18 at 22:09
KatieMKatieM
83
I am playing with some basic R functions and am trying to create a table that includes the Remainder and Quotient for the numbers 1:20
First I created this function:
Find_Remains = function(number, divisor){
Remainder = number%%divisor
Quotient = number%/%divisor
a = c(number, divisor, Remainder, Quotient)
return(a)
}
I add a blank table
final.data.frame = data.frame(matrix(NA, nrow = 1, ncol = 4))
Then I created this for loop
for(i in c(1:20)){
b[i] = Find_Remains(i,5)
final.data.frame = rbind(b[i])
}
the error I get is:
number of items to replace is not a multiple of replacement length
any help would be appreciated. Thanks
r dataframe for-loop division
r dataframe for-loop division
asked Nov 19 '18 at 22:09
KatieMKatieM
83
asked Nov 19 '18 at 22:09
KatieMKatieM
83
asked Nov 19 '18 at 22:09
KatieMKatieM
83
asked Nov 19 '18 at 22:09
KatieMKatieM
83
asked Nov 19 '18 at 22:09
KatieMKatieM
83
83
add a comment |
add a comment |
1 Answer
1
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oldest
votes
Kudos on initializing final.data.frame (although initializing it with 20 rows would have been better I think). Having done that you don't need to use rbind, you can simply replace each row of the dataframe in every loop run. Here's what you need -
Find_Remains = function(number, divisor) {
Remainder = number%%divisor
Quotient = number%/%divisor
a = c(number, divisor, Remainder, Quotient)
return(a)
}
final.data.frame = data.frame(matrix(NA, nrow = 20, ncol = 4))
for(i in 1:20) {
final.data.frame[i, ] = Find_Remains(i,5)
}
> final.data.frame
X1 X2 X3 X4
1 1 5 1 0
2 2 5 2 0
3 3 5 3 0
4 4 5 4 0
5 5 5 0 1
6 6 5 1 1
7 7 5 2 1
8 8 5 3 1
9 9 5 4 1
10 10 5 0 2
11 11 5 1 2
12 12 5 2 2
13 13 5 3 2
14 14 5 4 2
15 15 5 0 3
16 16 5 1 3
17 17 5 2 3
18 18 5 3 3
19 19 5 4 3
20 20 5 0 4
answered Nov 19 '18 at 22:23
ShreeShree
3,4111323
thanks! That worked! I tried the code with final.data.frame[i] but that didn't work. the code final.data.frame[i,] allows it to be placed in a row.
– KatieM
Nov 19 '18 at 22:56
Happy to help! If this answers your question then consider marking it correct using the tick mark at top left.
– Shree
Nov 19 '18 at 22:57
add a comment |
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1 Answer
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1 Answer
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oldest
votes
Kudos on initializing final.data.frame (although initializing it with 20 rows would have been better I think). Having done that you don't need to use rbind, you can simply replace each row of the dataframe in every loop run. Here's what you need -
Find_Remains = function(number, divisor) {
Remainder = number%%divisor
Quotient = number%/%divisor
a = c(number, divisor, Remainder, Quotient)
return(a)
}
final.data.frame = data.frame(matrix(NA, nrow = 20, ncol = 4))
for(i in 1:20) {
final.data.frame[i, ] = Find_Remains(i,5)
}
> final.data.frame
X1 X2 X3 X4
1 1 5 1 0
2 2 5 2 0
3 3 5 3 0
4 4 5 4 0
5 5 5 0 1
6 6 5 1 1
7 7 5 2 1
8 8 5 3 1
9 9 5 4 1
10 10 5 0 2
11 11 5 1 2
12 12 5 2 2
13 13 5 3 2
14 14 5 4 2
15 15 5 0 3
16 16 5 1 3
17 17 5 2 3
18 18 5 3 3
19 19 5 4 3
20 20 5 0 4
answered Nov 19 '18 at 22:23
ShreeShree
3,4111323
thanks! That worked! I tried the code with final.data.frame[i] but that didn't work. the code final.data.frame[i,] allows it to be placed in a row.
– KatieM
Nov 19 '18 at 22:56
Happy to help! If this answers your question then consider marking it correct using the tick mark at top left.
– Shree
Nov 19 '18 at 22:57
add a comment |
Kudos on initializing final.data.frame (although initializing it with 20 rows would have been better I think). Having done that you don't need to use rbind, you can simply replace each row of the dataframe in every loop run. Here's what you need -
Find_Remains = function(number, divisor) {
Remainder = number%%divisor
Quotient = number%/%divisor
a = c(number, divisor, Remainder, Quotient)
return(a)
}
final.data.frame = data.frame(matrix(NA, nrow = 20, ncol = 4))
for(i in 1:20) {
final.data.frame[i, ] = Find_Remains(i,5)
}
> final.data.frame
X1 X2 X3 X4
1 1 5 1 0
2 2 5 2 0
3 3 5 3 0
4 4 5 4 0
5 5 5 0 1
6 6 5 1 1
7 7 5 2 1
8 8 5 3 1
9 9 5 4 1
10 10 5 0 2
11 11 5 1 2
12 12 5 2 2
13 13 5 3 2
14 14 5 4 2
15 15 5 0 3
16 16 5 1 3
17 17 5 2 3
18 18 5 3 3
19 19 5 4 3
20 20 5 0 4
answered Nov 19 '18 at 22:23
ShreeShree
3,4111323
thanks! That worked! I tried the code with final.data.frame[i] but that didn't work. the code final.data.frame[i,] allows it to be placed in a row.
– KatieM
Nov 19 '18 at 22:56
Happy to help! If this answers your question then consider marking it correct using the tick mark at top left.
– Shree
Nov 19 '18 at 22:57
add a comment |
Kudos on initializing final.data.frame (although initializing it with 20 rows would have been better I think). Having done that you don't need to use rbind, you can simply replace each row of the dataframe in every loop run. Here's what you need -
Find_Remains = function(number, divisor) {
Remainder = number%%divisor
Quotient = number%/%divisor
a = c(number, divisor, Remainder, Quotient)
return(a)
}
final.data.frame = data.frame(matrix(NA, nrow = 20, ncol = 4))
for(i in 1:20) {
final.data.frame[i, ] = Find_Remains(i,5)
}
> final.data.frame
X1 X2 X3 X4
1 1 5 1 0
2 2 5 2 0
3 3 5 3 0
4 4 5 4 0
5 5 5 0 1
6 6 5 1 1
7 7 5 2 1
8 8 5 3 1
9 9 5 4 1
10 10 5 0 2
11 11 5 1 2
12 12 5 2 2
13 13 5 3 2
14 14 5 4 2
15 15 5 0 3
16 16 5 1 3
17 17 5 2 3
18 18 5 3 3
19 19 5 4 3
20 20 5 0 4
answered Nov 19 '18 at 22:23
ShreeShree
3,4111323
Kudos on initializing final.data.frame (although initializing it with 20 rows would have been better I think). Having done that you don't need to use rbind, you can simply replace each row of the dataframe in every loop run. Here's what you need -
Find_Remains = function(number, divisor) {
Remainder = number%%divisor
Quotient = number%/%divisor
a = c(number, divisor, Remainder, Quotient)
return(a)
}
final.data.frame = data.frame(matrix(NA, nrow = 20, ncol = 4))
for(i in 1:20) {
final.data.frame[i, ] = Find_Remains(i,5)
}
> final.data.frame
X1 X2 X3 X4
1 1 5 1 0
2 2 5 2 0
3 3 5 3 0
4 4 5 4 0
5 5 5 0 1
6 6 5 1 1
7 7 5 2 1
8 8 5 3 1
9 9 5 4 1
10 10 5 0 2
11 11 5 1 2
12 12 5 2 2
13 13 5 3 2
14 14 5 4 2
15 15 5 0 3
16 16 5 1 3
17 17 5 2 3
18 18 5 3 3
19 19 5 4 3
20 20 5 0 4
answered Nov 19 '18 at 22:23
ShreeShree
3,4111323
edited Nov 19 '18 at 22:30
answered Nov 19 '18 at 22:23
ShreeShree
3,4111323
answered Nov 19 '18 at 22:23
ShreeShree
3,4111323
answered Nov 19 '18 at 22:23
ShreeShree
3,4111323
3,4111323
thanks! That worked! I tried the code with final.data.frame[i] but that didn't work. the code final.data.frame[i,] allows it to be placed in a row.
– KatieM
Nov 19 '18 at 22:56
Happy to help! If this answers your question then consider marking it correct using the tick mark at top left.
– Shree
Nov 19 '18 at 22:57
add a comment |
thanks! That worked! I tried the code with final.data.frame[i] but that didn't work. the code final.data.frame[i,] allows it to be placed in a row.
– KatieM
Nov 19 '18 at 22:56
Happy to help! If this answers your question then consider marking it correct using the tick mark at top left.
– Shree
Nov 19 '18 at 22:57
thanks! That worked! I tried the code with final.data.frame[i] but that didn't work. the code final.data.frame[i,] allows it to be placed in a row.
– KatieM
Nov 19 '18 at 22:56
thanks! That worked! I tried the code with final.data.frame[i] but that didn't work. the code final.data.frame[i,] allows it to be placed in a row.
– KatieM
Nov 19 '18 at 22:56
Happy to help! If this answers your question then consider marking it correct using the tick mark at top left.
– Shree
Nov 19 '18 at 22:57
Happy to help! If this answers your question then consider marking it correct using the tick mark at top left.
– Shree
Nov 19 '18 at 22:57
add a comment |
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