Error in match.names(clabs, names(xi)) : names do not match previous names












-1
















  1. I am creating a vector having 5 age values and named it as boys_age. Likewise created a vector named girls_age.


eg :



boys_age <- c(18,15,16,17,19)

girls_age<- c(16,14,18,17,15)



  1. Then Append rbind() the two vectors to create data.frame such that I have two columns named group and age.


  2. The values from boys_age and girls_age should be in the column age. The group column should have the category values, boys/girls, to identify the source vector.







r rbind







share|improve this question





























    -1
















    1. I am creating a vector having 5 age values and named it as boys_age. Likewise created a vector named girls_age.


    eg :



    boys_age <- c(18,15,16,17,19)
    
girls_age<- c(16,14,18,17,15)



    1. Then Append rbind() the two vectors to create data.frame such that I have two columns named group and age.


    2. The values from boys_age and girls_age should be in the column age. The group column should have the category values, boys/girls, to identify the source vector.







    r rbind







    share|improve this question



























      -1












      -1








      -1









      1. I am creating a vector having 5 age values and named it as boys_age. Likewise created a vector named girls_age.


      eg :



      boys_age <- c(18,15,16,17,19)
      
girls_age<- c(16,14,18,17,15)



      1. Then Append rbind() the two vectors to create data.frame such that I have two columns named group and age.


      2. The values from boys_age and girls_age should be in the column age. The group column should have the category values, boys/girls, to identify the source vector.







      r rbind







      share|improve this question

















      1. I am creating a vector having 5 age values and named it as boys_age. Likewise created a vector named girls_age.


      eg :



      boys_age <- c(18,15,16,17,19)
      
girls_age<- c(16,14,18,17,15)



      1. Then Append rbind() the two vectors to create data.frame such that I have two columns named group and age.


      2. The values from boys_age and girls_age should be in the column age. The group column should have the category values, boys/girls, to identify the source vector.







      r rbind




      r rbind






      share|improve this question















      share|improve this question













      share|improve this question




      share|improve this question








      edited Nov 20 '18 at 9:28









      Sotos

      30k51640




      30k51640










      asked Nov 20 '18 at 9:26









      Himanshu GehlotHimanshu Gehlot

      13




      13
























          2 Answers
          2






          active

          oldest

          votes


















          2














          Its actually the most primal thing to do in R:



          data:



          df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))


          code:



          library(data.table)
          
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]


          result:



          #    age group
          
# 1:  18  boys
          
# 2:  15  boys
          
# 3:  16  boys
          
# 4:  17  boys
          
# 5:  19  boys
          
# 6:  16 girls
          
# 7:  14 girls
          
# 8:  18 girls
          
# 9:  17 girls
          
#10:  15 girls



          You seem to be keen on using ?rbind: (not practical though)



          rbind(
          
    cbind.data.frame(age = df1$boys_age,  group = "boys"),
          
    cbind.data.frame(age = df1$girls_age,  group = "girls")
          
    )
          

          
#   age group
          
#1   18  boys
          
#2   15  boys
          
#3   16  boys
          
#4   17  boys
          
#5   19  boys
          
#6   16 girls
          
#7   14 girls
          
#8   18 girls
          
#9   17 girls
          
#10  15 girls



          • In the ?cbind section I'm making use of the recycling functionality R provides. Read about it.

          • Why am I using cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.






          share|improve this answer

































            3














            Here is one option using stack



            out <- stack(list(boys = boys_age, girls = girls_age))
            
out
            
#   values   ind
            
#1      18  boys
            
#2      15  boys
            
#3      16  boys
            
#4      17  boys
            
#5      19  boys
            
#6      16 girls
            
#7      14 girls
            
#8      18 girls
            
#9      17 girls
            
#10     15 girls


            Now change names



            names(out) <- c("age", "group")
            
out
            
#   age group
            
#1   18  boys
            
#2   15  boys
            
#3   16  boys
            
#4   17  boys
            
#5   19  boys
            
#6   16 girls
            
#7   14 girls
            
#8   18 girls
            
#9   17 girls
            
#10  15 girls



            You could also do the same in one line, thanks to @Sotos



            setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))





            share|improve this answer





















            • 3





              Nice 1. You can also do all in 1 line, i.e. setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))

              – Sotos
              Nov 20 '18 at 9:37











            • Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.

              – Himanshu Gehlot
              Nov 20 '18 at 9:39








            • 1





              That smells like homework...

              – Sotos
              Nov 20 '18 at 9:41











            • Not exactly, i am making some practice questions and got stuck with this.

              – Himanshu Gehlot
              Nov 20 '18 at 9:43






            • 2





              @HimanshuGehlot You can't do it directly with rbind() and data.frame() only. You could do something like setNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group')) which includes them, but are not explicit

              – Sotos
              Nov 20 '18 at 10:00











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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2














            Its actually the most primal thing to do in R:



            data:



            df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))


            code:



            library(data.table)
            
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]


            result:



            #    age group
            
# 1:  18  boys
            
# 2:  15  boys
            
# 3:  16  boys
            
# 4:  17  boys
            
# 5:  19  boys
            
# 6:  16 girls
            
# 7:  14 girls
            
# 8:  18 girls
            
# 9:  17 girls
            
#10:  15 girls



            You seem to be keen on using ?rbind: (not practical though)



            rbind(
            
    cbind.data.frame(age = df1$boys_age,  group = "boys"),
            
    cbind.data.frame(age = df1$girls_age,  group = "girls")
            
    )
            

            
#   age group
            
#1   18  boys
            
#2   15  boys
            
#3   16  boys
            
#4   17  boys
            
#5   19  boys
            
#6   16 girls
            
#7   14 girls
            
#8   18 girls
            
#9   17 girls
            
#10  15 girls



            • In the ?cbind section I'm making use of the recycling functionality R provides. Read about it.

            • Why am I using cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.






            share|improve this answer






























              2














              Its actually the most primal thing to do in R:



              data:



              df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))


              code:



              library(data.table)
              
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]


              result:



              #    age group
              
# 1:  18  boys
              
# 2:  15  boys
              
# 3:  16  boys
              
# 4:  17  boys
              
# 5:  19  boys
              
# 6:  16 girls
              
# 7:  14 girls
              
# 8:  18 girls
              
# 9:  17 girls
              
#10:  15 girls



              You seem to be keen on using ?rbind: (not practical though)



              rbind(
              
    cbind.data.frame(age = df1$boys_age,  group = "boys"),
              
    cbind.data.frame(age = df1$girls_age,  group = "girls")
              
    )
              

              
#   age group
              
#1   18  boys
              
#2   15  boys
              
#3   16  boys
              
#4   17  boys
              
#5   19  boys
              
#6   16 girls
              
#7   14 girls
              
#8   18 girls
              
#9   17 girls
              
#10  15 girls



              • In the ?cbind section I'm making use of the recycling functionality R provides. Read about it.

              • Why am I using cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.






              share|improve this answer




























                2












                2








                2







                Its actually the most primal thing to do in R:



                data:



                df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))


                code:



                library(data.table)
                
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]


                result:



                #    age group
                
# 1:  18  boys
                
# 2:  15  boys
                
# 3:  16  boys
                
# 4:  17  boys
                
# 5:  19  boys
                
# 6:  16 girls
                
# 7:  14 girls
                
# 8:  18 girls
                
# 9:  17 girls
                
#10:  15 girls



                You seem to be keen on using ?rbind: (not practical though)



                rbind(
                
    cbind.data.frame(age = df1$boys_age,  group = "boys"),
                
    cbind.data.frame(age = df1$girls_age,  group = "girls")
                
    )
                

                
#   age group
                
#1   18  boys
                
#2   15  boys
                
#3   16  boys
                
#4   17  boys
                
#5   19  boys
                
#6   16 girls
                
#7   14 girls
                
#8   18 girls
                
#9   17 girls
                
#10  15 girls



                • In the ?cbind section I'm making use of the recycling functionality R provides. Read about it.

                • Why am I using cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.






                share|improve this answer















                Its actually the most primal thing to do in R:



                data:



                df1 <- data.frame(boys_age = c(18,15,16,17,19), girls_age = c(16,14,18,17,15))


                code:



                library(data.table)
                
melt(setDT(df1), variable.name = "group", value.name = "age", measure.vars = c("boys_age", "girls_age"))[,2:1][,group:=sub("_.*$","",group)]


                result:



                #    age group
                
# 1:  18  boys
                
# 2:  15  boys
                
# 3:  16  boys
                
# 4:  17  boys
                
# 5:  19  boys
                
# 6:  16 girls
                
# 7:  14 girls
                
# 8:  18 girls
                
# 9:  17 girls
                
#10:  15 girls



                You seem to be keen on using ?rbind: (not practical though)



                rbind(
                
    cbind.data.frame(age = df1$boys_age,  group = "boys"),
                
    cbind.data.frame(age = df1$girls_age,  group = "girls")
                
    )
                

                
#   age group
                
#1   18  boys
                
#2   15  boys
                
#3   16  boys
                
#4   17  boys
                
#5   19  boys
                
#6   16 girls
                
#7   14 girls
                
#8   18 girls
                
#9   17 girls
                
#10  15 girls



                • In the ?cbind section I'm making use of the recycling functionality R provides. Read about it.

                • Why am I using cbind.data.frame, otherwise cbind would create a matrix and therefore the age numerics would be converted to characters.







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited Nov 20 '18 at 11:29

























                answered Nov 20 '18 at 9:48









                Andre ElricoAndre Elrico

                5,72311229




                5,72311229

























                    3














                    Here is one option using stack



                    out <- stack(list(boys = boys_age, girls = girls_age))
                    
out
                    
#   values   ind
                    
#1      18  boys
                    
#2      15  boys
                    
#3      16  boys
                    
#4      17  boys
                    
#5      19  boys
                    
#6      16 girls
                    
#7      14 girls
                    
#8      18 girls
                    
#9      17 girls
                    
#10     15 girls


                    Now change names



                    names(out) <- c("age", "group")
                    
out
                    
#   age group
                    
#1   18  boys
                    
#2   15  boys
                    
#3   16  boys
                    
#4   17  boys
                    
#5   19  boys
                    
#6   16 girls
                    
#7   14 girls
                    
#8   18 girls
                    
#9   17 girls
                    
#10  15 girls



                    You could also do the same in one line, thanks to @Sotos



                    setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))





                    share|improve this answer





















                    • 3





                      Nice 1. You can also do all in 1 line, i.e. setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))

                      – Sotos
                      Nov 20 '18 at 9:37











                    • Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.

                      – Himanshu Gehlot
                      Nov 20 '18 at 9:39








                    • 1





                      That smells like homework...

                      – Sotos
                      Nov 20 '18 at 9:41











                    • Not exactly, i am making some practice questions and got stuck with this.

                      – Himanshu Gehlot
                      Nov 20 '18 at 9:43






                    • 2





                      @HimanshuGehlot You can't do it directly with rbind() and data.frame() only. You could do something like setNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group')) which includes them, but are not explicit

                      – Sotos
                      Nov 20 '18 at 10:00
















                    3














                    Here is one option using stack



                    out <- stack(list(boys = boys_age, girls = girls_age))
                    
out
                    
#   values   ind
                    
#1      18  boys
                    
#2      15  boys
                    
#3      16  boys
                    
#4      17  boys
                    
#5      19  boys
                    
#6      16 girls
                    
#7      14 girls
                    
#8      18 girls
                    
#9      17 girls
                    
#10     15 girls


                    Now change names



                    names(out) <- c("age", "group")
                    
out
                    
#   age group
                    
#1   18  boys
                    
#2   15  boys
                    
#3   16  boys
                    
#4   17  boys
                    
#5   19  boys
                    
#6   16 girls
                    
#7   14 girls
                    
#8   18 girls
                    
#9   17 girls
                    
#10  15 girls



                    You could also do the same in one line, thanks to @Sotos



                    setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))





                    share|improve this answer





















                    • 3





                      Nice 1. You can also do all in 1 line, i.e. setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))

                      – Sotos
                      Nov 20 '18 at 9:37











                    • Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.

                      – Himanshu Gehlot
                      Nov 20 '18 at 9:39








                    • 1





                      That smells like homework...

                      – Sotos
                      Nov 20 '18 at 9:41











                    • Not exactly, i am making some practice questions and got stuck with this.

                      – Himanshu Gehlot
                      Nov 20 '18 at 9:43






                    • 2





                      @HimanshuGehlot You can't do it directly with rbind() and data.frame() only. You could do something like setNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group')) which includes them, but are not explicit

                      – Sotos
                      Nov 20 '18 at 10:00














                    3












                    3








                    3







                    Here is one option using stack



                    out <- stack(list(boys = boys_age, girls = girls_age))
                    
out
                    
#   values   ind
                    
#1      18  boys
                    
#2      15  boys
                    
#3      16  boys
                    
#4      17  boys
                    
#5      19  boys
                    
#6      16 girls
                    
#7      14 girls
                    
#8      18 girls
                    
#9      17 girls
                    
#10     15 girls


                    Now change names



                    names(out) <- c("age", "group")
                    
out
                    
#   age group
                    
#1   18  boys
                    
#2   15  boys
                    
#3   16  boys
                    
#4   17  boys
                    
#5   19  boys
                    
#6   16 girls
                    
#7   14 girls
                    
#8   18 girls
                    
#9   17 girls
                    
#10  15 girls



                    You could also do the same in one line, thanks to @Sotos



                    setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))





                    share|improve this answer















                    Here is one option using stack



                    out <- stack(list(boys = boys_age, girls = girls_age))
                    
out
                    
#   values   ind
                    
#1      18  boys
                    
#2      15  boys
                    
#3      16  boys
                    
#4      17  boys
                    
#5      19  boys
                    
#6      16 girls
                    
#7      14 girls
                    
#8      18 girls
                    
#9      17 girls
                    
#10     15 girls


                    Now change names



                    names(out) <- c("age", "group")
                    
out
                    
#   age group
                    
#1   18  boys
                    
#2   15  boys
                    
#3   16  boys
                    
#4   17  boys
                    
#5   19  boys
                    
#6   16 girls
                    
#7   14 girls
                    
#8   18 girls
                    
#9   17 girls
                    
#10  15 girls



                    You could also do the same in one line, thanks to @Sotos



                    setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))






                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited Nov 20 '18 at 9:39

























                    answered Nov 20 '18 at 9:33









                    markusmarkus

                    13.1k1234




                    13.1k1234








                    • 3





                      Nice 1. You can also do all in 1 line, i.e. setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))

                      – Sotos
                      Nov 20 '18 at 9:37











                    • Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.

                      – Himanshu Gehlot
                      Nov 20 '18 at 9:39








                    • 1





                      That smells like homework...

                      – Sotos
                      Nov 20 '18 at 9:41











                    • Not exactly, i am making some practice questions and got stuck with this.

                      – Himanshu Gehlot
                      Nov 20 '18 at 9:43






                    • 2





                      @HimanshuGehlot You can't do it directly with rbind() and data.frame() only. You could do something like setNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group')) which includes them, but are not explicit

                      – Sotos
                      Nov 20 '18 at 10:00














                    • 3





                      Nice 1. You can also do all in 1 line, i.e. setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))

                      – Sotos
                      Nov 20 '18 at 9:37











                    • Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.

                      – Himanshu Gehlot
                      Nov 20 '18 at 9:39








                    • 1





                      That smells like homework...

                      – Sotos
                      Nov 20 '18 at 9:41











                    • Not exactly, i am making some practice questions and got stuck with this.

                      – Himanshu Gehlot
                      Nov 20 '18 at 9:43






                    • 2





                      @HimanshuGehlot You can't do it directly with rbind() and data.frame() only. You could do something like setNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group')) which includes them, but are not explicit

                      – Sotos
                      Nov 20 '18 at 10:00








                    3




                    3





                    Nice 1. You can also do all in 1 line, i.e. setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))

                    – Sotos
                    Nov 20 '18 at 9:37





                    Nice 1. You can also do all in 1 line, i.e. setNames(stack(list(boys = boys_age, girls = girls_age)), c('age', 'group'))

                    – Sotos
                    Nov 20 '18 at 9:37













                    Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.

                    – Himanshu Gehlot
                    Nov 20 '18 at 9:39







                    Thank you, Markus, for your response. But the problem needs to be solved by using data.frame() and rbind() only. It's an exercise for data.frame and rbind function.

                    – Himanshu Gehlot
                    Nov 20 '18 at 9:39






                    1




                    1





                    That smells like homework...

                    – Sotos
                    Nov 20 '18 at 9:41





                    That smells like homework...

                    – Sotos
                    Nov 20 '18 at 9:41













                    Not exactly, i am making some practice questions and got stuck with this.

                    – Himanshu Gehlot
                    Nov 20 '18 at 9:43





                    Not exactly, i am making some practice questions and got stuck with this.

                    – Himanshu Gehlot
                    Nov 20 '18 at 9:43




                    2




                    2





                    @HimanshuGehlot You can't do it directly with rbind() and data.frame() only. You could do something like setNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group')) which includes them, but are not explicit

                    – Sotos
                    Nov 20 '18 at 10:00





                    @HimanshuGehlot You can't do it directly with rbind() and data.frame() only. You could do something like setNames(stack(data.frame(t(rbind(boys_age, girls_age)))), c('age', 'group')) which includes them, but are not explicit

                    – Sotos
                    Nov 20 '18 at 10:00


















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