PowerShell operators, select before first period
0
I need some help with operators in PowerShell please. I'm trying to select anything before the first period.
For example, filename contains string first.last@domain.com and I'd like to select first
$path = "c:file.txt"
$Firstname = get-content -path $path | where-object {$_<WHAT SHOULD I USE HERE?>}
powershell operators
edited Nov 20 '18 at 9:43
James C.
8,92122131
asked Nov 20 '18 at 9:13
KDDKDD
135
add a comment |
0
I need some help with operators in PowerShell please. I'm trying to select anything before the first period.
For example, filename contains string first.last@domain.com and I'd like to select first
$path = "c:file.txt"
$Firstname = get-content -path $path | where-object {$_<WHAT SHOULD I USE HERE?>}
powershell operators
edited Nov 20 '18 at 9:43
James C.
8,92122131
asked Nov 20 '18 at 9:13
KDDKDD
135
4
$Firstname = (get-content -path $path).Split(".")[0]
– Vivek Kumar Singh
Nov 20 '18 at 9:20
This works perfectly, thanks!
– KDD
Nov 20 '18 at 13:56
add a comment |
0
0
0
I need some help with operators in PowerShell please. I'm trying to select anything before the first period.
For example, filename contains string first.last@domain.com and I'd like to select first
$path = "c:file.txt"
$Firstname = get-content -path $path | where-object {$_<WHAT SHOULD I USE HERE?>}
powershell operators
edited Nov 20 '18 at 9:43
James C.
8,92122131
asked Nov 20 '18 at 9:13
KDDKDD
135
I need some help with operators in PowerShell please. I'm trying to select anything before the first period.
For example, filename contains string first.last@domain.com and I'd like to select first
$path = "c:file.txt"
$Firstname = get-content -path $path | where-object {$_<WHAT SHOULD I USE HERE?>}
powershell operators
powershell operators
edited Nov 20 '18 at 9:43
James C.
8,92122131
asked Nov 20 '18 at 9:13
KDDKDD
135
edited Nov 20 '18 at 9:43
James C.
8,92122131
asked Nov 20 '18 at 9:13
KDDKDD
135
edited Nov 20 '18 at 9:43
James C.
8,92122131
edited Nov 20 '18 at 9:43
James C.
8,92122131
edited Nov 20 '18 at 9:43
James C.
8,92122131
8,92122131
asked Nov 20 '18 at 9:13
KDDKDD
135
asked Nov 20 '18 at 9:13
KDDKDD
135
asked Nov 20 '18 at 9:13
KDDKDD
135
135
4
$Firstname = (get-content -path $path).Split(".")[0]
– Vivek Kumar Singh
Nov 20 '18 at 9:20
This works perfectly, thanks!
– KDD
Nov 20 '18 at 13:56
add a comment |
4
$Firstname = (get-content -path $path).Split(".")[0]
– Vivek Kumar Singh
Nov 20 '18 at 9:20
This works perfectly, thanks!
– KDD
Nov 20 '18 at 13:56
4
4
$Firstname = (get-content -path $path).Split(".")[0]– Vivek Kumar Singh
Nov 20 '18 at 9:20
$Firstname = (get-content -path $path).Split(".")[0]– Vivek Kumar Singh
Nov 20 '18 at 9:20
This works perfectly, thanks!
– KDD
Nov 20 '18 at 13:56
This works perfectly, thanks!
– KDD
Nov 20 '18 at 13:56
add a comment |
2 Answers
2
active
oldest
votes
0
You could do it with -replace and some RegEx
$path = "c:file.txt"
$Firstname = get-content -path $path | where-object { $_ -replace '^(.*?)..*$', '$1' }
answered Nov 20 '18 at 12:58
TobyUTobyU
2,39311021
add a comment |
0
Use the split method -
$Firstname = (get-content -path $path).Split(".")[0]
answered Nov 20 '18 at 14:02
Vivek Kumar SinghVivek Kumar Singh
2,0121816
add a comment |
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2 Answers
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active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
You could do it with -replace and some RegEx
$path = "c:file.txt"
$Firstname = get-content -path $path | where-object { $_ -replace '^(.*?)..*$', '$1' }
answered Nov 20 '18 at 12:58
TobyUTobyU
2,39311021
add a comment |
0
You could do it with -replace and some RegEx
$path = "c:file.txt"
$Firstname = get-content -path $path | where-object { $_ -replace '^(.*?)..*$', '$1' }
answered Nov 20 '18 at 12:58
TobyUTobyU
2,39311021
add a comment |
0
0
0
You could do it with -replace and some RegEx
$path = "c:file.txt"
$Firstname = get-content -path $path | where-object { $_ -replace '^(.*?)..*$', '$1' }
answered Nov 20 '18 at 12:58
TobyUTobyU
2,39311021
You could do it with -replace and some RegEx
$path = "c:file.txt"
$Firstname = get-content -path $path | where-object { $_ -replace '^(.*?)..*$', '$1' }
answered Nov 20 '18 at 12:58
TobyUTobyU
2,39311021
answered Nov 20 '18 at 12:58
TobyUTobyU
2,39311021
answered Nov 20 '18 at 12:58
TobyUTobyU
2,39311021
answered Nov 20 '18 at 12:58
TobyUTobyU
2,39311021
2,39311021
add a comment |
add a comment |
0
Use the split method -
$Firstname = (get-content -path $path).Split(".")[0]
answered Nov 20 '18 at 14:02
Vivek Kumar SinghVivek Kumar Singh
2,0121816
add a comment |
0
Use the split method -
$Firstname = (get-content -path $path).Split(".")[0]
answered Nov 20 '18 at 14:02
Vivek Kumar SinghVivek Kumar Singh
2,0121816
add a comment |
0
0
0
Use the split method -
$Firstname = (get-content -path $path).Split(".")[0]
answered Nov 20 '18 at 14:02
Vivek Kumar SinghVivek Kumar Singh
2,0121816
Use the split method -
$Firstname = (get-content -path $path).Split(".")[0]
answered Nov 20 '18 at 14:02
Vivek Kumar SinghVivek Kumar Singh
2,0121816
answered Nov 20 '18 at 14:02
Vivek Kumar SinghVivek Kumar Singh
2,0121816
answered Nov 20 '18 at 14:02
Vivek Kumar SinghVivek Kumar Singh
2,0121816
answered Nov 20 '18 at 14:02
Vivek Kumar SinghVivek Kumar Singh
2,0121816
2,0121816
add a comment |
add a comment |
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4
$Firstname = (get-content -path $path).Split(".")[0]– Vivek Kumar Singh
Nov 20 '18 at 9:20
This works perfectly, thanks!
– KDD
Nov 20 '18 at 13:56