Linux command to print some characters from a long string
2
I have a file called text.txt which contain:
id="qwidget_lastsale" class="qwidget-dollar">$2020.22div
I really need to print out the word 2020.22 from that text file.
I used the command:
awk '{print $2}' text.txt | grep 2020.22
but my output will print:
class="qwidget-dollar">$2020.22dev
Which command can I use to print out only 2020.22 from that string?
linux ubuntu awk sed grep
edited Nov 21 '18 at 1:33
Jonathan Leffler
571k916841034
asked Nov 21 '18 at 1:10
Nyimeh GeraldNyimeh Gerald
132
add a comment |
2
I have a file called text.txt which contain:
id="qwidget_lastsale" class="qwidget-dollar">$2020.22div
I really need to print out the word 2020.22 from that text file.
I used the command:
awk '{print $2}' text.txt | grep 2020.22
but my output will print:
class="qwidget-dollar">$2020.22dev
Which command can I use to print out only 2020.22 from that string?
linux ubuntu awk sed grep
edited Nov 21 '18 at 1:33
Jonathan Leffler
571k916841034
asked Nov 21 '18 at 1:10
Nyimeh GeraldNyimeh Gerald
132
If you just want 2020.22, why notecho 2020.22? Since that doesn't make sense, it isn't quite what you want? What should happen if2020.22is not present in the file? Presumably nothing. What about if there are multiple lines containing2020.22? Are you going to be upset at seeing2020x22since the.is a metacharacter togrep?
– Jonathan Leffler
Nov 21 '18 at 1:35
add a comment |
2
2
2
I have a file called text.txt which contain:
id="qwidget_lastsale" class="qwidget-dollar">$2020.22div
I really need to print out the word 2020.22 from that text file.
I used the command:
awk '{print $2}' text.txt | grep 2020.22
but my output will print:
class="qwidget-dollar">$2020.22dev
Which command can I use to print out only 2020.22 from that string?
linux ubuntu awk sed grep
edited Nov 21 '18 at 1:33
Jonathan Leffler
571k916841034
asked Nov 21 '18 at 1:10
Nyimeh GeraldNyimeh Gerald
132
I have a file called text.txt which contain:
id="qwidget_lastsale" class="qwidget-dollar">$2020.22div
I really need to print out the word 2020.22 from that text file.
I used the command:
awk '{print $2}' text.txt | grep 2020.22
but my output will print:
class="qwidget-dollar">$2020.22dev
Which command can I use to print out only 2020.22 from that string?
linux ubuntu awk sed grep
linux ubuntu awk sed grep
edited Nov 21 '18 at 1:33
Jonathan Leffler
571k916841034
asked Nov 21 '18 at 1:10
Nyimeh GeraldNyimeh Gerald
132
edited Nov 21 '18 at 1:33
Jonathan Leffler
571k916841034
asked Nov 21 '18 at 1:10
Nyimeh GeraldNyimeh Gerald
132
edited Nov 21 '18 at 1:33
Jonathan Leffler
571k916841034
edited Nov 21 '18 at 1:33
Jonathan Leffler
571k916841034
edited Nov 21 '18 at 1:33
Jonathan Leffler
571k916841034
571k916841034
asked Nov 21 '18 at 1:10
Nyimeh GeraldNyimeh Gerald
132
asked Nov 21 '18 at 1:10
Nyimeh GeraldNyimeh Gerald
132
asked Nov 21 '18 at 1:10
Nyimeh GeraldNyimeh Gerald
132
132
If you just want 2020.22, why notecho 2020.22? Since that doesn't make sense, it isn't quite what you want? What should happen if2020.22is not present in the file? Presumably nothing. What about if there are multiple lines containing2020.22? Are you going to be upset at seeing2020x22since the.is a metacharacter togrep?
– Jonathan Leffler
Nov 21 '18 at 1:35
add a comment |
If you just want 2020.22, why notecho 2020.22? Since that doesn't make sense, it isn't quite what you want? What should happen if2020.22is not present in the file? Presumably nothing. What about if there are multiple lines containing2020.22? Are you going to be upset at seeing2020x22since the.is a metacharacter togrep?
– Jonathan Leffler
Nov 21 '18 at 1:35
If you just want 2020.22, why not
echo 2020.22? Since that doesn't make sense, it isn't quite what you want? What should happen if 2020.22 is not present in the file? Presumably nothing. What about if there are multiple lines containing 2020.22? Are you going to be upset at seeing 2020x22 since the . is a metacharacter to grep?– Jonathan Leffler
Nov 21 '18 at 1:35
If you just want 2020.22, why not
echo 2020.22? Since that doesn't make sense, it isn't quite what you want? What should happen if 2020.22 is not present in the file? Presumably nothing. What about if there are multiple lines containing 2020.22? Are you going to be upset at seeing 2020x22 since the . is a metacharacter to grep?– Jonathan Leffler
Nov 21 '18 at 1:35
add a comment |
2 Answers
2
active
oldest
votes
0
you want to extract the dollar value?
$ grep -oP '(?<=$)[0-9.]+' file
answered Nov 21 '18 at 1:23
karakfakarakfa
50.6k52839
add a comment |
0
echo 'id="qwidget_lastsale" class="qwidget-dollar">$2020.22div' | awk '{print gensub(/[^0-9.]+([0-9.]+).*/, "\1","1", $2)}'
2020.22
In gensub we replace most of $2 with just the numeric component, and then print that using the print statement.
answered Nov 21 '18 at 1:19
tinktink
6,83032735
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
0
you want to extract the dollar value?
$ grep -oP '(?<=$)[0-9.]+' file
answered Nov 21 '18 at 1:23
karakfakarakfa
50.6k52839
add a comment |
0
you want to extract the dollar value?
$ grep -oP '(?<=$)[0-9.]+' file
answered Nov 21 '18 at 1:23
karakfakarakfa
50.6k52839
add a comment |
0
0
0
you want to extract the dollar value?
$ grep -oP '(?<=$)[0-9.]+' file
answered Nov 21 '18 at 1:23
karakfakarakfa
50.6k52839
you want to extract the dollar value?
$ grep -oP '(?<=$)[0-9.]+' file
answered Nov 21 '18 at 1:23
karakfakarakfa
50.6k52839
answered Nov 21 '18 at 1:23
karakfakarakfa
50.6k52839
answered Nov 21 '18 at 1:23
karakfakarakfa
50.6k52839
answered Nov 21 '18 at 1:23
karakfakarakfa
50.6k52839
50.6k52839
add a comment |
add a comment |
0
echo 'id="qwidget_lastsale" class="qwidget-dollar">$2020.22div' | awk '{print gensub(/[^0-9.]+([0-9.]+).*/, "\1","1", $2)}'
2020.22
In gensub we replace most of $2 with just the numeric component, and then print that using the print statement.
answered Nov 21 '18 at 1:19
tinktink
6,83032735
add a comment |
0
echo 'id="qwidget_lastsale" class="qwidget-dollar">$2020.22div' | awk '{print gensub(/[^0-9.]+([0-9.]+).*/, "\1","1", $2)}'
2020.22
In gensub we replace most of $2 with just the numeric component, and then print that using the print statement.
answered Nov 21 '18 at 1:19
tinktink
6,83032735
add a comment |
0
0
0
echo 'id="qwidget_lastsale" class="qwidget-dollar">$2020.22div' | awk '{print gensub(/[^0-9.]+([0-9.]+).*/, "\1","1", $2)}'
2020.22
In gensub we replace most of $2 with just the numeric component, and then print that using the print statement.
answered Nov 21 '18 at 1:19
tinktink
6,83032735
echo 'id="qwidget_lastsale" class="qwidget-dollar">$2020.22div' | awk '{print gensub(/[^0-9.]+([0-9.]+).*/, "\1","1", $2)}'
2020.22
In gensub we replace most of $2 with just the numeric component, and then print that using the print statement.
answered Nov 21 '18 at 1:19
tinktink
6,83032735
answered Nov 21 '18 at 1:19
tinktink
6,83032735
answered Nov 21 '18 at 1:19
tinktink
6,83032735
answered Nov 21 '18 at 1:19
tinktink
6,83032735
6,83032735
add a comment |
add a comment |
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If you just want 2020.22, why not
echo 2020.22? Since that doesn't make sense, it isn't quite what you want? What should happen if2020.22is not present in the file? Presumably nothing. What about if there are multiple lines containing2020.22? Are you going to be upset at seeing2020x22since the.is a metacharacter togrep?– Jonathan Leffler
Nov 21 '18 at 1:35