Matcher for keyword and its children spacy
I have a set of keywords I am already matching for. It is a medical context so I've made up a equivalent scenario at least for the parsing I'm trying to do:
I have a car with chrome 1000-inch rims.
Let's say I want to return as a phrase all children words/tokens of the keyword rims where rims is already marked as an entity by SpaCy as CARPART.
In python this is what I'm doing:
test_phrases = nlp("""I have a car with chrome 100-inch rims.""")
print(test_phrases.cats)
for t in test_phrases:
print('Token: {} || POS: {} || DEP: {} CHILDREN: {} || ent_type: {}'.format(t,t.pos_,t.dep_,[c for c in t.children],t.ent_type_))
Token: I || POS: PRON || DEP: nsubj CHILDREN: || ent_type:
Token: have || POS: VERB || DEP: ROOT CHILDREN: [I, car, .] ||
ent_type:
Token: a || POS: DET || DEP: det CHILDREN: || ent_type:
Token: car || POS: NOUN || DEP: dobj CHILDREN: [a, with] || ent_type:
Token: with || POS: ADP || DEP: prep CHILDREN: [rims] || ent_type:
Token: chrome || POS: ADJ || DEP: amod CHILDREN: || ent_type:
Token: 100-inch || POS: NOUN || DEP: compound CHILDREN: || ent_type:
Token: rims || POS: NOUN || DEP: pobj CHILDREN: [chrome, 100-inch] ||
ent_type:
Token: . || POS: PUNCT || DEP: punct CHILDREN: || ent_type: CARPART
So, what I want to do is use is something like:
test_matcher = Matcher(nlp.vocab)
test_phrase = ['']
patterns = [[{'ENT':'CARPART',????}] for kp in test_phrase]
test_matcher.add('CARPHRASE', None, *patterns)
call the test_matcher on test_doc have it return:
chrome 100-inch rims
parsing nlp spacy
add a comment |
I have a set of keywords I am already matching for. It is a medical context so I've made up a equivalent scenario at least for the parsing I'm trying to do:
I have a car with chrome 1000-inch rims.
Let's say I want to return as a phrase all children words/tokens of the keyword rims where rims is already marked as an entity by SpaCy as CARPART.
In python this is what I'm doing:
test_phrases = nlp("""I have a car with chrome 100-inch rims.""")
print(test_phrases.cats)
for t in test_phrases:
print('Token: {} || POS: {} || DEP: {} CHILDREN: {} || ent_type: {}'.format(t,t.pos_,t.dep_,[c for c in t.children],t.ent_type_))
Token: I || POS: PRON || DEP: nsubj CHILDREN: || ent_type:
Token: have || POS: VERB || DEP: ROOT CHILDREN: [I, car, .] ||
ent_type:
Token: a || POS: DET || DEP: det CHILDREN: || ent_type:
Token: car || POS: NOUN || DEP: dobj CHILDREN: [a, with] || ent_type:
Token: with || POS: ADP || DEP: prep CHILDREN: [rims] || ent_type:
Token: chrome || POS: ADJ || DEP: amod CHILDREN: || ent_type:
Token: 100-inch || POS: NOUN || DEP: compound CHILDREN: || ent_type:
Token: rims || POS: NOUN || DEP: pobj CHILDREN: [chrome, 100-inch] ||
ent_type:
Token: . || POS: PUNCT || DEP: punct CHILDREN: || ent_type: CARPART
So, what I want to do is use is something like:
test_matcher = Matcher(nlp.vocab)
test_phrase = ['']
patterns = [[{'ENT':'CARPART',????}] for kp in test_phrase]
test_matcher.add('CARPHRASE', None, *patterns)
call the test_matcher on test_doc have it return:
chrome 100-inch rims
parsing nlp spacy
add a comment |
I have a set of keywords I am already matching for. It is a medical context so I've made up a equivalent scenario at least for the parsing I'm trying to do:
I have a car with chrome 1000-inch rims.
Let's say I want to return as a phrase all children words/tokens of the keyword rims where rims is already marked as an entity by SpaCy as CARPART.
In python this is what I'm doing:
test_phrases = nlp("""I have a car with chrome 100-inch rims.""")
print(test_phrases.cats)
for t in test_phrases:
print('Token: {} || POS: {} || DEP: {} CHILDREN: {} || ent_type: {}'.format(t,t.pos_,t.dep_,[c for c in t.children],t.ent_type_))
Token: I || POS: PRON || DEP: nsubj CHILDREN: || ent_type:
Token: have || POS: VERB || DEP: ROOT CHILDREN: [I, car, .] ||
ent_type:
Token: a || POS: DET || DEP: det CHILDREN: || ent_type:
Token: car || POS: NOUN || DEP: dobj CHILDREN: [a, with] || ent_type:
Token: with || POS: ADP || DEP: prep CHILDREN: [rims] || ent_type:
Token: chrome || POS: ADJ || DEP: amod CHILDREN: || ent_type:
Token: 100-inch || POS: NOUN || DEP: compound CHILDREN: || ent_type:
Token: rims || POS: NOUN || DEP: pobj CHILDREN: [chrome, 100-inch] ||
ent_type:
Token: . || POS: PUNCT || DEP: punct CHILDREN: || ent_type: CARPART
So, what I want to do is use is something like:
test_matcher = Matcher(nlp.vocab)
test_phrase = ['']
patterns = [[{'ENT':'CARPART',????}] for kp in test_phrase]
test_matcher.add('CARPHRASE', None, *patterns)
call the test_matcher on test_doc have it return:
chrome 100-inch rims
parsing nlp spacy
I have a set of keywords I am already matching for. It is a medical context so I've made up a equivalent scenario at least for the parsing I'm trying to do:
I have a car with chrome 1000-inch rims.
Let's say I want to return as a phrase all children words/tokens of the keyword rims where rims is already marked as an entity by SpaCy as CARPART.
In python this is what I'm doing:
test_phrases = nlp("""I have a car with chrome 100-inch rims.""")
print(test_phrases.cats)
for t in test_phrases:
print('Token: {} || POS: {} || DEP: {} CHILDREN: {} || ent_type: {}'.format(t,t.pos_,t.dep_,[c for c in t.children],t.ent_type_))
Token: I || POS: PRON || DEP: nsubj CHILDREN: || ent_type:
Token: have || POS: VERB || DEP: ROOT CHILDREN: [I, car, .] ||
ent_type:
Token: a || POS: DET || DEP: det CHILDREN: || ent_type:
Token: car || POS: NOUN || DEP: dobj CHILDREN: [a, with] || ent_type:
Token: with || POS: ADP || DEP: prep CHILDREN: [rims] || ent_type:
Token: chrome || POS: ADJ || DEP: amod CHILDREN: || ent_type:
Token: 100-inch || POS: NOUN || DEP: compound CHILDREN: || ent_type:
Token: rims || POS: NOUN || DEP: pobj CHILDREN: [chrome, 100-inch] ||
ent_type:
Token: . || POS: PUNCT || DEP: punct CHILDREN: || ent_type: CARPART
So, what I want to do is use is something like:
test_matcher = Matcher(nlp.vocab)
test_phrase = ['']
patterns = [[{'ENT':'CARPART',????}] for kp in test_phrase]
test_matcher.add('CARPHRASE', None, *patterns)
call the test_matcher on test_doc have it return:
chrome 100-inch rims
parsing nlp spacy
parsing nlp spacy
asked Nov 21 '18 at 0:44
Aus_10Aus_10
13318
13318
add a comment |
add a comment |
1 Answer
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I think I found a satisfactory solution that will work when creating a Spacy Class object. You can test this out to make sure it works with your solution then add to something like this in Spacy pipeline:
from spacy.matcher import Matcher
keyword_list = ['rims']
patterns = [[{'LOWER':kw}] for kw in keyword_list]
test_matcher.add('TESTPHRASE',None, *patterns)
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
doc = nlp("""I have a car with chrome 1000-inch rims.""")
add_children_matches(doc,test_matcher)
This gives:
keyword: rims
keyphrase: chrome 1000-inch rims
Edit: To fully answer my own question you'd have to use something like:
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
spans =
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
start_char = doc[min(sorted_children):max(sorted_children)+1].start_char
end_char = doc[min(sorted_children):max(sorted_children)+1].end_char
span = doc.char_span(start_char, end_char,label='CARPHRASE')
if span != None:
spans.append(span)
return doc
add a comment |
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1 Answer
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active
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votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
I think I found a satisfactory solution that will work when creating a Spacy Class object. You can test this out to make sure it works with your solution then add to something like this in Spacy pipeline:
from spacy.matcher import Matcher
keyword_list = ['rims']
patterns = [[{'LOWER':kw}] for kw in keyword_list]
test_matcher.add('TESTPHRASE',None, *patterns)
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
doc = nlp("""I have a car with chrome 1000-inch rims.""")
add_children_matches(doc,test_matcher)
This gives:
keyword: rims
keyphrase: chrome 1000-inch rims
Edit: To fully answer my own question you'd have to use something like:
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
spans =
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
start_char = doc[min(sorted_children):max(sorted_children)+1].start_char
end_char = doc[min(sorted_children):max(sorted_children)+1].end_char
span = doc.char_span(start_char, end_char,label='CARPHRASE')
if span != None:
spans.append(span)
return doc
add a comment |
I think I found a satisfactory solution that will work when creating a Spacy Class object. You can test this out to make sure it works with your solution then add to something like this in Spacy pipeline:
from spacy.matcher import Matcher
keyword_list = ['rims']
patterns = [[{'LOWER':kw}] for kw in keyword_list]
test_matcher.add('TESTPHRASE',None, *patterns)
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
doc = nlp("""I have a car with chrome 1000-inch rims.""")
add_children_matches(doc,test_matcher)
This gives:
keyword: rims
keyphrase: chrome 1000-inch rims
Edit: To fully answer my own question you'd have to use something like:
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
spans =
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
start_char = doc[min(sorted_children):max(sorted_children)+1].start_char
end_char = doc[min(sorted_children):max(sorted_children)+1].end_char
span = doc.char_span(start_char, end_char,label='CARPHRASE')
if span != None:
spans.append(span)
return doc
add a comment |
I think I found a satisfactory solution that will work when creating a Spacy Class object. You can test this out to make sure it works with your solution then add to something like this in Spacy pipeline:
from spacy.matcher import Matcher
keyword_list = ['rims']
patterns = [[{'LOWER':kw}] for kw in keyword_list]
test_matcher.add('TESTPHRASE',None, *patterns)
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
doc = nlp("""I have a car with chrome 1000-inch rims.""")
add_children_matches(doc,test_matcher)
This gives:
keyword: rims
keyphrase: chrome 1000-inch rims
Edit: To fully answer my own question you'd have to use something like:
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
spans =
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
start_char = doc[min(sorted_children):max(sorted_children)+1].start_char
end_char = doc[min(sorted_children):max(sorted_children)+1].end_char
span = doc.char_span(start_char, end_char,label='CARPHRASE')
if span != None:
spans.append(span)
return doc
I think I found a satisfactory solution that will work when creating a Spacy Class object. You can test this out to make sure it works with your solution then add to something like this in Spacy pipeline:
from spacy.matcher import Matcher
keyword_list = ['rims']
patterns = [[{'LOWER':kw}] for kw in keyword_list]
test_matcher.add('TESTPHRASE',None, *patterns)
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
doc = nlp("""I have a car with chrome 1000-inch rims.""")
add_children_matches(doc,test_matcher)
This gives:
keyword: rims
keyphrase: chrome 1000-inch rims
Edit: To fully answer my own question you'd have to use something like:
def add_children_matches(doc,keyword_matcher):
'''Add children to match on original single-token keyword.'''
matches = keyword_matcher(doc)
spans =
for match_id, start, end in matches:
tokens = doc[start:end]
print('keyword:',tokens)
# Since we are getting children for keyword, there should only be one token
if len(tokens) != 1:
print('Skipping {}. Too many tokens to match.'.format(tokens))
continue
keyword_token = tokens[0]
sorted_children = sorted([c.i for c in keyword_token.children] + [keyword_token.i],reverse=False)
print('keyphrase:',doc[min(sorted_children):max(sorted_children)+1])
start_char = doc[min(sorted_children):max(sorted_children)+1].start_char
end_char = doc[min(sorted_children):max(sorted_children)+1].end_char
span = doc.char_span(start_char, end_char,label='CARPHRASE')
if span != None:
spans.append(span)
return doc
edited Nov 21 '18 at 2:40
answered Nov 21 '18 at 2:21
Aus_10Aus_10
13318
13318
add a comment |
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