Setting package in Scala REPL
Is there a way in the Scala REPL to set the "active" package scope ? Say I have a package com.package with class A, I want to be able to type new A() instead of new com.package.A() without explicitly doing import com.package.A. There might be a number of other classes in that package I'm interested into and I don't want to polute my REPL's global namespace by doing import com.package._.
Even better, I'd like to define class A without typing its fully qualified name. Something like:
package com.package // do this once
class A
class B
val a = new A()
val b = new B()
I'm aware of the :paste -raw command, but that would require me to type package com.package for each block; I'm really looking for a stateful command to change the "current working package", if you will.
scala read-eval-print-loop
asked Aug 16 '14 at 19:30
gsimardgsimard
381422
add a comment |
Is there a way in the Scala REPL to set the "active" package scope ? Say I have a package com.package with class A, I want to be able to type new A() instead of new com.package.A() without explicitly doing import com.package.A. There might be a number of other classes in that package I'm interested into and I don't want to polute my REPL's global namespace by doing import com.package._.
Even better, I'd like to define class A without typing its fully qualified name. Something like:
package com.package // do this once
class A
class B
val a = new A()
val b = new B()
I'm aware of the :paste -raw command, but that would require me to type package com.package for each block; I'm really looking for a stateful command to change the "current working package", if you will.
scala read-eval-print-loop
asked Aug 16 '14 at 19:30
gsimardgsimard
381422
So, I guess stackoverflow.com/a/18510229/6309 wouldn't be helpful either?
– VonC
Aug 16 '14 at 19:37
1
there is currently no support for that because packages are actually used in the internals of the REPL (classes defined in the REPL don't actually live in the root package), but that would make an interesting feature request...
– gourlaysama
Aug 16 '14 at 19:41
@VonC: No, this would not allow me to define new classes without a fully qualified name, as per my question.
– gsimard
Aug 16 '14 at 19:45
Ditto @gourlaysama The use case is testing existing classes with package-private access.
– som-snytt
Aug 18 '14 at 15:20
Possible duplicate of How to use members with default (package) or private access level in REPL?
– Jacek Laskowski
Oct 14 '15 at 9:26
add a comment |
Is there a way in the Scala REPL to set the "active" package scope ? Say I have a package com.package with class A, I want to be able to type new A() instead of new com.package.A() without explicitly doing import com.package.A. There might be a number of other classes in that package I'm interested into and I don't want to polute my REPL's global namespace by doing import com.package._.
Even better, I'd like to define class A without typing its fully qualified name. Something like:
package com.package // do this once
class A
class B
val a = new A()
val b = new B()
I'm aware of the :paste -raw command, but that would require me to type package com.package for each block; I'm really looking for a stateful command to change the "current working package", if you will.
scala read-eval-print-loop
asked Aug 16 '14 at 19:30
gsimardgsimard
381422
Is there a way in the Scala REPL to set the "active" package scope ? Say I have a package com.package with class A, I want to be able to type new A() instead of new com.package.A() without explicitly doing import com.package.A. There might be a number of other classes in that package I'm interested into and I don't want to polute my REPL's global namespace by doing import com.package._.
Even better, I'd like to define class A without typing its fully qualified name. Something like:
package com.package // do this once
class A
class B
val a = new A()
val b = new B()
I'm aware of the :paste -raw command, but that would require me to type package com.package for each block; I'm really looking for a stateful command to change the "current working package", if you will.
scala read-eval-print-loop
scala read-eval-print-loop
asked Aug 16 '14 at 19:30
gsimardgsimard
381422
asked Aug 16 '14 at 19:30
gsimardgsimard
381422
asked Aug 16 '14 at 19:30
gsimardgsimard
381422
asked Aug 16 '14 at 19:30
gsimardgsimard
381422
asked Aug 16 '14 at 19:30
gsimardgsimard
381422
381422
So, I guess stackoverflow.com/a/18510229/6309 wouldn't be helpful either?
– VonC
Aug 16 '14 at 19:37
1
there is currently no support for that because packages are actually used in the internals of the REPL (classes defined in the REPL don't actually live in the root package), but that would make an interesting feature request...
– gourlaysama
Aug 16 '14 at 19:41
@VonC: No, this would not allow me to define new classes without a fully qualified name, as per my question.
– gsimard
Aug 16 '14 at 19:45
Ditto @gourlaysama The use case is testing existing classes with package-private access.
– som-snytt
Aug 18 '14 at 15:20
Possible duplicate of How to use members with default (package) or private access level in REPL?
– Jacek Laskowski
Oct 14 '15 at 9:26
add a comment |
So, I guess stackoverflow.com/a/18510229/6309 wouldn't be helpful either?
– VonC
Aug 16 '14 at 19:37
1
there is currently no support for that because packages are actually used in the internals of the REPL (classes defined in the REPL don't actually live in the root package), but that would make an interesting feature request...
– gourlaysama
Aug 16 '14 at 19:41
@VonC: No, this would not allow me to define new classes without a fully qualified name, as per my question.
– gsimard
Aug 16 '14 at 19:45
Ditto @gourlaysama The use case is testing existing classes with package-private access.
– som-snytt
Aug 18 '14 at 15:20
Possible duplicate of How to use members with default (package) or private access level in REPL?
– Jacek Laskowski
Oct 14 '15 at 9:26
So, I guess stackoverflow.com/a/18510229/6309 wouldn't be helpful either?
– VonC
Aug 16 '14 at 19:37
So, I guess stackoverflow.com/a/18510229/6309 wouldn't be helpful either?
– VonC
Aug 16 '14 at 19:37
1
1
there is currently no support for that because packages are actually used in the internals of the REPL (classes defined in the REPL don't actually live in the root package), but that would make an interesting feature request...
– gourlaysama
Aug 16 '14 at 19:41
there is currently no support for that because packages are actually used in the internals of the REPL (classes defined in the REPL don't actually live in the root package), but that would make an interesting feature request...
– gourlaysama
Aug 16 '14 at 19:41
@VonC: No, this would not allow me to define new classes without a fully qualified name, as per my question.
– gsimard
Aug 16 '14 at 19:45
@VonC: No, this would not allow me to define new classes without a fully qualified name, as per my question.
– gsimard
Aug 16 '14 at 19:45
Ditto @gourlaysama The use case is testing existing classes with package-private access.
– som-snytt
Aug 18 '14 at 15:20
Ditto @gourlaysama The use case is testing existing classes with package-private access.
– som-snytt
Aug 18 '14 at 15:20
Possible duplicate of How to use members with default (package) or private access level in REPL?
– Jacek Laskowski
Oct 14 '15 at 9:26
Possible duplicate of How to use members with default (package) or private access level in REPL?
– Jacek Laskowski
Oct 14 '15 at 9:26
add a comment |
1 Answer
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Simply put, you cannot.
Each command in the scala REPL is wrapped into a newly generated package, as explained here.
Also, there was a ticket asking package { } support in the REPL, but it was dismissed as :paste -raw was considered enough for the purpose.
edited May 23 '17 at 12:10
Community♦
11
answered Aug 16 '14 at 19:45
Gabriele PetronellaGabriele Petronella
92.2k18181213
add a comment |
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Simply put, you cannot.
Each command in the scala REPL is wrapped into a newly generated package, as explained here.
Also, there was a ticket asking package { } support in the REPL, but it was dismissed as :paste -raw was considered enough for the purpose.
edited May 23 '17 at 12:10
Community♦
11
answered Aug 16 '14 at 19:45
Gabriele PetronellaGabriele Petronella
92.2k18181213
add a comment |
Simply put, you cannot.
Each command in the scala REPL is wrapped into a newly generated package, as explained here.
Also, there was a ticket asking package { } support in the REPL, but it was dismissed as :paste -raw was considered enough for the purpose.
edited May 23 '17 at 12:10
Community♦
11
answered Aug 16 '14 at 19:45
Gabriele PetronellaGabriele Petronella
92.2k18181213
add a comment |
Simply put, you cannot.
Each command in the scala REPL is wrapped into a newly generated package, as explained here.
Also, there was a ticket asking package { } support in the REPL, but it was dismissed as :paste -raw was considered enough for the purpose.
edited May 23 '17 at 12:10
Community♦
11
answered Aug 16 '14 at 19:45
Gabriele PetronellaGabriele Petronella
92.2k18181213
Simply put, you cannot.
Each command in the scala REPL is wrapped into a newly generated package, as explained here.
Also, there was a ticket asking package { } support in the REPL, but it was dismissed as :paste -raw was considered enough for the purpose.
edited May 23 '17 at 12:10
Community♦
11
answered Aug 16 '14 at 19:45
Gabriele PetronellaGabriele Petronella
92.2k18181213
edited May 23 '17 at 12:10
Community♦
11
edited May 23 '17 at 12:10
Community♦
11
edited May 23 '17 at 12:10
Community♦
11
11
answered Aug 16 '14 at 19:45
Gabriele PetronellaGabriele Petronella
92.2k18181213
answered Aug 16 '14 at 19:45
Gabriele PetronellaGabriele Petronella
92.2k18181213
answered Aug 16 '14 at 19:45
Gabriele PetronellaGabriele Petronella
92.2k18181213
92.2k18181213
add a comment |
add a comment |
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So, I guess stackoverflow.com/a/18510229/6309 wouldn't be helpful either?
– VonC
Aug 16 '14 at 19:37
1
there is currently no support for that because packages are actually used in the internals of the REPL (classes defined in the REPL don't actually live in the root package), but that would make an interesting feature request...
– gourlaysama
Aug 16 '14 at 19:41
@VonC: No, this would not allow me to define new classes without a fully qualified name, as per my question.
– gsimard
Aug 16 '14 at 19:45
Ditto @gourlaysama The use case is testing existing classes with package-private access.
– som-snytt
Aug 18 '14 at 15:20
Possible duplicate of How to use members with default (package) or private access level in REPL?
– Jacek Laskowski
Oct 14 '15 at 9:26