Why does gnuplot complain about empty x range (and ruin the graph) when I apply missing data cutoff?
gnuplot 5.2.5 / centos7
Basically, I've configured a plot that I like but now I want to introduce a "cut off" in the lines when the data is missing. I've looked around a lot and there are easy solutions, if I only have 2 columns... However, I have a lot of columns. So, I am using a loop and can't just do ($2).
I've found solution to cut lines where there is no data in a loop but they don't work:
Warning: empty x range [2018:2018], adjusting to [1997.82:2038.18]
The configuration that caused the above:
set datafile separator ","
set xdata time
set timefmt "%Y-%m-%d.%H:%M:%S"
set datafile missing
set ylabel "% CPU"
set xlabel "Time Point"
set grid
set xtics rotate
set key autotitle columnheader
set terminal pngcairo
set output 'graph.png'
plot for [i=2:5] "data.csv" using ($1):(column(i)) with linespoints
And here's my data (notice the missing value on second row, second col):
col1,col2,col3,col4
2018-11-21.04:23:03,1,2,2,5
2018-11-21.04:24:03,,4,4,6
2018-11-21.04:25:03,3,6,8,7
2018-11-21.04:26:03,4,8,16,8
What should my plot command look like?
Update: I tried working around it with:
plot "data.csv" using 1:($2) with linespoints,
plot "data.csv" using 1:($3) with linespoints,
But it just plots the first line... This workaround is feasible for me but I don't know how to add more lines? Again, I cannot use the for [i=2:5] trick because that breaks my x range.
plot graph gnuplot
asked Nov 21 '18 at 12:39
Kiichiro MatsushitaKiichiro Matsushita
163
add a comment |
gnuplot 5.2.5 / centos7
Basically, I've configured a plot that I like but now I want to introduce a "cut off" in the lines when the data is missing. I've looked around a lot and there are easy solutions, if I only have 2 columns... However, I have a lot of columns. So, I am using a loop and can't just do ($2).
I've found solution to cut lines where there is no data in a loop but they don't work:
Warning: empty x range [2018:2018], adjusting to [1997.82:2038.18]
The configuration that caused the above:
set datafile separator ","
set xdata time
set timefmt "%Y-%m-%d.%H:%M:%S"
set datafile missing
set ylabel "% CPU"
set xlabel "Time Point"
set grid
set xtics rotate
set key autotitle columnheader
set terminal pngcairo
set output 'graph.png'
plot for [i=2:5] "data.csv" using ($1):(column(i)) with linespoints
And here's my data (notice the missing value on second row, second col):
col1,col2,col3,col4
2018-11-21.04:23:03,1,2,2,5
2018-11-21.04:24:03,,4,4,6
2018-11-21.04:25:03,3,6,8,7
2018-11-21.04:26:03,4,8,16,8
What should my plot command look like?
Update: I tried working around it with:
plot "data.csv" using 1:($2) with linespoints,
plot "data.csv" using 1:($3) with linespoints,
But it just plots the first line... This workaround is feasible for me but I don't know how to add more lines? Again, I cannot use the for [i=2:5] trick because that breaks my x range.
plot graph gnuplot
asked Nov 21 '18 at 12:39
Kiichiro MatsushitaKiichiro Matsushita
163
Instead of($1), just use1. Same with($2)etc.
– Michael O.
Nov 21 '18 at 18:11
Simply usingplot for [i=2:5] "data.csv" using 1:i with linespointsworks fine for me with 5.2.2, i.stack.imgur.com/zftPw.png
– Christoph
Nov 21 '18 at 18:36
add a comment |
gnuplot 5.2.5 / centos7
Basically, I've configured a plot that I like but now I want to introduce a "cut off" in the lines when the data is missing. I've looked around a lot and there are easy solutions, if I only have 2 columns... However, I have a lot of columns. So, I am using a loop and can't just do ($2).
I've found solution to cut lines where there is no data in a loop but they don't work:
Warning: empty x range [2018:2018], adjusting to [1997.82:2038.18]
The configuration that caused the above:
set datafile separator ","
set xdata time
set timefmt "%Y-%m-%d.%H:%M:%S"
set datafile missing
set ylabel "% CPU"
set xlabel "Time Point"
set grid
set xtics rotate
set key autotitle columnheader
set terminal pngcairo
set output 'graph.png'
plot for [i=2:5] "data.csv" using ($1):(column(i)) with linespoints
And here's my data (notice the missing value on second row, second col):
col1,col2,col3,col4
2018-11-21.04:23:03,1,2,2,5
2018-11-21.04:24:03,,4,4,6
2018-11-21.04:25:03,3,6,8,7
2018-11-21.04:26:03,4,8,16,8
What should my plot command look like?
Update: I tried working around it with:
plot "data.csv" using 1:($2) with linespoints,
plot "data.csv" using 1:($3) with linespoints,
But it just plots the first line... This workaround is feasible for me but I don't know how to add more lines? Again, I cannot use the for [i=2:5] trick because that breaks my x range.
plot graph gnuplot
asked Nov 21 '18 at 12:39
Kiichiro MatsushitaKiichiro Matsushita
163
gnuplot 5.2.5 / centos7
Basically, I've configured a plot that I like but now I want to introduce a "cut off" in the lines when the data is missing. I've looked around a lot and there are easy solutions, if I only have 2 columns... However, I have a lot of columns. So, I am using a loop and can't just do ($2).
I've found solution to cut lines where there is no data in a loop but they don't work:
Warning: empty x range [2018:2018], adjusting to [1997.82:2038.18]
The configuration that caused the above:
set datafile separator ","
set xdata time
set timefmt "%Y-%m-%d.%H:%M:%S"
set datafile missing
set ylabel "% CPU"
set xlabel "Time Point"
set grid
set xtics rotate
set key autotitle columnheader
set terminal pngcairo
set output 'graph.png'
plot for [i=2:5] "data.csv" using ($1):(column(i)) with linespoints
And here's my data (notice the missing value on second row, second col):
col1,col2,col3,col4
2018-11-21.04:23:03,1,2,2,5
2018-11-21.04:24:03,,4,4,6
2018-11-21.04:25:03,3,6,8,7
2018-11-21.04:26:03,4,8,16,8
What should my plot command look like?
Update: I tried working around it with:
plot "data.csv" using 1:($2) with linespoints,
plot "data.csv" using 1:($3) with linespoints,
But it just plots the first line... This workaround is feasible for me but I don't know how to add more lines? Again, I cannot use the for [i=2:5] trick because that breaks my x range.
plot graph gnuplot
plot graph gnuplot
asked Nov 21 '18 at 12:39
Kiichiro MatsushitaKiichiro Matsushita
163
asked Nov 21 '18 at 12:39
Kiichiro MatsushitaKiichiro Matsushita
163
edited Nov 21 '18 at 12:54
Kiichiro Matsushita
asked Nov 21 '18 at 12:39
Kiichiro MatsushitaKiichiro Matsushita
163
asked Nov 21 '18 at 12:39
Kiichiro MatsushitaKiichiro Matsushita
163
asked Nov 21 '18 at 12:39
Kiichiro MatsushitaKiichiro Matsushita
163
163
Instead of($1), just use1. Same with($2)etc.
– Michael O.
Nov 21 '18 at 18:11
Simply usingplot for [i=2:5] "data.csv" using 1:i with linespointsworks fine for me with 5.2.2, i.stack.imgur.com/zftPw.png
– Christoph
Nov 21 '18 at 18:36
add a comment |
Instead of($1), just use1. Same with($2)etc.
– Michael O.
Nov 21 '18 at 18:11
Simply usingplot for [i=2:5] "data.csv" using 1:i with linespointsworks fine for me with 5.2.2, i.stack.imgur.com/zftPw.png
– Christoph
Nov 21 '18 at 18:36
Instead of
($1), just use 1. Same with ($2) etc.– Michael O.
Nov 21 '18 at 18:11
Instead of
($1), just use 1. Same with ($2) etc.– Michael O.
Nov 21 '18 at 18:11
Simply using
plot for [i=2:5] "data.csv" using 1:i with linespoints works fine for me with 5.2.2, i.stack.imgur.com/zftPw.png– Christoph
Nov 21 '18 at 18:36
Simply using
plot for [i=2:5] "data.csv" using 1:i with linespoints works fine for me with 5.2.2, i.stack.imgur.com/zftPw.png– Christoph
Nov 21 '18 at 18:36
add a comment |
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Instead of
($1), just use1. Same with($2)etc.– Michael O.
Nov 21 '18 at 18:11
Simply using
plot for [i=2:5] "data.csv" using 1:i with linespointsworks fine for me with 5.2.2, i.stack.imgur.com/zftPw.png– Christoph
Nov 21 '18 at 18:36