Allow JSON fragments with Decodable
import UIKit
class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!
struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?
private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}
var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]
@IBOutlet weak var tableView: UITableView!
fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"
guard let url = URL(string: jsonURL) else{return}
URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")
let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}
override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}
I am getting the error:
JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))
json swift
add a comment |
import UIKit
class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!
struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?
private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}
var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]
@IBOutlet weak var tableView: UITableView!
fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"
guard let url = URL(string: jsonURL) else{return}
URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")
let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}
override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}
I am getting the error:
JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))
json swift
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 at 6:20
add a comment |
import UIKit
class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!
struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?
private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}
var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]
@IBOutlet weak var tableView: UITableView!
fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"
guard let url = URL(string: jsonURL) else{return}
URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")
let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}
override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}
I am getting the error:
JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))
json swift
import UIKit
class ViewController: UIViewController,UITableViewDelegate,UITableViewDataSource {
//@IBOutlet weak var ingredientText: UILabel!
struct Recipes: Decodable {
let recipe_id:String?
let image_url:String?
let source_url:String?
let f2f_url:String?
let title:String?
let publisher:String?
let social_rank:Float64?
let page:Int?
let ingredients:[String]?
private enum CodingKeys: String, CodingKey{
case recipe_id = "recipe_id"
case image_url = "image_url"
case source_url = "source_url"
case f2f_url = "f2f_url"
case title = "title"
case publisher = "publisher"
case social_rank = "social_rank"
case page = "page"
case ingredients = "ingredients"
}
}
var recipes = [Recipes]()
var food = "chicken"
var food2 = "peas"
var food3 = "onions"
//var recipeData = [Recipe]
@IBOutlet weak var tableView: UITableView!
fileprivate func getRecipes() {
let jsonURL = "http://food2fork.com/api/search?key=264045e3ff7b84ee346eb20e1642d9d9264045e3ff7b84ee346eb20e1642d9d9&food=chicken&food2=onions&food3=peas"
guard let url = URL(string: jsonURL) else{return}
URLSession.shared.dataTask(with: url) {(data, _ , err) in
DispatchQueue.main.async {
if let err = err{
print("failed to get data from URL",err)
return
}
guard let data = data else{return}
do {
let decoder = JSONDecoder()
decoder.keyDecodingStrategy = .convertFromSnakeCase
self.recipes = try decoder.decode([Recipes].self, from: data)
self.tableView.reloadData()
}catch let jsonERR {
print("Failed to decode",jsonERR)
}
}
}.resume()
}
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return recipes.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = UITableViewCell(style: .subtitle, reuseIdentifier: "cell")
let recipe = recipes[indexPath.row]
cell.textLabel?.text = recipe.title
return cell
}
override func viewDidLoad() {
super.viewDidLoad()
navigationController?.navigationBar.prefersLargeTitles = true
navigationItem.title = "Ingredients"
getRecipes()
}
}
I am getting the error:
JSON text did not start with array or object and option to allow fragments not set." UserInfo={NSDebugDescription=JSON text did not start with array or object and option to allow fragments not set.})))
json swift
json swift
edited Nov 13 at 5:45
rmaddy
238k27309375
238k27309375
asked Nov 13 at 5:30
Jonathan Jordan
12
12
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 at 6:20
add a comment |
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 at 6:20
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 at 6:05
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 at 6:20
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 at 6:20
add a comment |
2 Answers
2
active
oldest
votes
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 at 7:56
add a comment |
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 at 6:43
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53274397%2fallow-json-fragments-with-decodable%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 at 7:56
add a comment |
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 at 7:56
add a comment |
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
JSONDecoder
doesn't provide any JSONSerialization.ReadingOptions
.
You could make a manual check whether the first byte of the data is an opening square bracket <5b>
or brace <7b>
guard let data = data, let firstByte = data.first else { return }
guard firstByte == 0x5b || firstByte == 0x7b else {
let string = String(data: data, encoding: .utf8)!
print(string)
return
}
However I'd recommend to use the response
parameter to check for status code 200
URLSession.shared.dataTask(with: url) { (data, response , error) in
if let response = response as? HTTPURLResponse, response.statusCode != 200 {
print(response.statusCode)
return
}
...
Note: If the CodingKeys match exactly the struct members you can omit the CodingKeys and as you are explicitly using .convertFromSnakeCase
you are encouraged to name the struct members recipeId
, imageUrl
, sourceUrl
etc.
edited Nov 13 at 6:12
answered Nov 13 at 5:59
vadian
142k13151168
142k13151168
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 at 7:56
add a comment |
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 at 6:17
If the root object is a dictionary you have to decodeRecipes.self
– vadian
Nov 13 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 at 7:51
In terms ofDecodable
every dictionary is a struct. So you need an extra struct for the root object.
– vadian
Nov 13 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 at 7:56
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 at 6:17
Vadian, Thank you for your answer that did help a lot. I used your response perameter and did get the error 403, but I changed my API key and the error changed to, Failed to decode typeMismatch(Swift.Array<Any>, Swift.DecodingError.Context(codingPath: , debugDescription: "Expected to decode Array<Any> but found a dictionary instead.", underlyingError: nil))
– Jonathan Jordan
Nov 13 at 6:17
If the root object is a dictionary you have to decode
Recipes.self
– vadian
Nov 13 at 7:34
If the root object is a dictionary you have to decode
Recipes.self
– vadian
Nov 13 at 7:34
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 at 7:51
The root object is a dictionary. Will I have to make a separate struct for the root? I am very new to swift and coding in general. I changed the [Recipes].self to Recipes.self and am now getting a type mismatch error.
– Jonathan Jordan
Nov 13 at 7:51
In terms of
Decodable
every dictionary is a struct. So you need an extra struct for the root object.– vadian
Nov 13 at 7:54
In terms of
Decodable
every dictionary is a struct. So you need an extra struct for the root object.– vadian
Nov 13 at 7:54
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 at 7:56
Thank you for your help. I will try this.
– Jonathan Jordan
Nov 13 at 7:56
add a comment |
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 at 6:43
add a comment |
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 at 6:43
add a comment |
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
You want to decode [Recipe]
, that is, an Array
of Recipe
. That mean the first (non-whitespace) character in data
has to be [
(to make it a JSON array), and it's not. So you need to figure out why you're getting the wrong response, and fix that problem. Try converting data
to a String
and printing it:
print(String(data: data, encoding: .utf8))
answered Nov 13 at 6:04
rob mayoff
290k41582637
290k41582637
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 at 6:43
add a comment |
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 at 6:43
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 at 6:43
I did that and it works. I get The top 30 recipes from food2fork api. However when I go to change the data to a string my self.recipes = try decoder.decode([Recipes].self, from: data) does not accept data as a string. Trying to look now but this was also a good point. Thank you. If you know of a post to fix this please link.
– Jonathan Jordan
Nov 13 at 6:43
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53274397%2fallow-json-fragments-with-decodable%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Your URL gives 403 FORBIDDEN Error..... check status code....
– Vishal Patel
Nov 13 at 6:05
Thanks Vishal. The wrong API key was given in the example.
– Jonathan Jordan
Nov 13 at 6:20