Extract resources to current directory?
I want to extract the resources "cygz.dll" to the current directory where the program started right after the form is loaded.
Here is my code.
private static void extract(string nameSpace, string outDirectory, string internalFilePath, string resourceName)
{
Assembly assembly = Assembly.GetCallingAssembly();
using (Stream s = assembly.GetManifestResourceStream(nameSpace + "." + (internalFilePath == "" ? "" : internalFilePath + ".") + resourceName))
using (BinaryReader r = new BinaryReader(s))
using (FileStream fs = new FileStream(outDirectory + "\" + resourceName, FileMode.OpenOrCreate))
using (BinaryWriter w = new BinaryWriter(fs))
w.Write(r.ReadBytes((int)s.Length));
}
private void Form1_Load(object sender, EventArgs e)
{
extract("myNamespace", "\TEMP", "resources", "cygz.dll");
}
Instead of "\TEMP", I want to extract "cygz.dll" to the current directory
c# visual-studio
asked Nov 13 at 1:02
pxc
12
add a comment |
I want to extract the resources "cygz.dll" to the current directory where the program started right after the form is loaded.
Here is my code.
private static void extract(string nameSpace, string outDirectory, string internalFilePath, string resourceName)
{
Assembly assembly = Assembly.GetCallingAssembly();
using (Stream s = assembly.GetManifestResourceStream(nameSpace + "." + (internalFilePath == "" ? "" : internalFilePath + ".") + resourceName))
using (BinaryReader r = new BinaryReader(s))
using (FileStream fs = new FileStream(outDirectory + "\" + resourceName, FileMode.OpenOrCreate))
using (BinaryWriter w = new BinaryWriter(fs))
w.Write(r.ReadBytes((int)s.Length));
}
private void Form1_Load(object sender, EventArgs e)
{
extract("myNamespace", "\TEMP", "resources", "cygz.dll");
}
Instead of "\TEMP", I want to extract "cygz.dll" to the current directory
c# visual-studio
asked Nov 13 at 1:02
pxc
12
1
looks like c# code not c
– pm100
Nov 13 at 1:19
hint Environment.CurrentDirectory
– pm100
Nov 13 at 1:22
@pm100 Got it.. Using string as for the path. Thanks ;)
– pxc
Nov 13 at 9:04
add a comment |
I want to extract the resources "cygz.dll" to the current directory where the program started right after the form is loaded.
Here is my code.
private static void extract(string nameSpace, string outDirectory, string internalFilePath, string resourceName)
{
Assembly assembly = Assembly.GetCallingAssembly();
using (Stream s = assembly.GetManifestResourceStream(nameSpace + "." + (internalFilePath == "" ? "" : internalFilePath + ".") + resourceName))
using (BinaryReader r = new BinaryReader(s))
using (FileStream fs = new FileStream(outDirectory + "\" + resourceName, FileMode.OpenOrCreate))
using (BinaryWriter w = new BinaryWriter(fs))
w.Write(r.ReadBytes((int)s.Length));
}
private void Form1_Load(object sender, EventArgs e)
{
extract("myNamespace", "\TEMP", "resources", "cygz.dll");
}
Instead of "\TEMP", I want to extract "cygz.dll" to the current directory
c# visual-studio
asked Nov 13 at 1:02
pxc
12
I want to extract the resources "cygz.dll" to the current directory where the program started right after the form is loaded.
Here is my code.
private static void extract(string nameSpace, string outDirectory, string internalFilePath, string resourceName)
{
Assembly assembly = Assembly.GetCallingAssembly();
using (Stream s = assembly.GetManifestResourceStream(nameSpace + "." + (internalFilePath == "" ? "" : internalFilePath + ".") + resourceName))
using (BinaryReader r = new BinaryReader(s))
using (FileStream fs = new FileStream(outDirectory + "\" + resourceName, FileMode.OpenOrCreate))
using (BinaryWriter w = new BinaryWriter(fs))
w.Write(r.ReadBytes((int)s.Length));
}
private void Form1_Load(object sender, EventArgs e)
{
extract("myNamespace", "\TEMP", "resources", "cygz.dll");
}
Instead of "\TEMP", I want to extract "cygz.dll" to the current directory
c# visual-studio
c# visual-studio
asked Nov 13 at 1:02
pxc
12
asked Nov 13 at 1:02
pxc
12
edited Nov 13 at 5:33
asked Nov 13 at 1:02
pxc
12
asked Nov 13 at 1:02
pxc
12
asked Nov 13 at 1:02
pxc
12
12
1
looks like c# code not c
– pm100
Nov 13 at 1:19
hint Environment.CurrentDirectory
– pm100
Nov 13 at 1:22
@pm100 Got it.. Using string as for the path. Thanks ;)
– pxc
Nov 13 at 9:04
add a comment |
1
looks like c# code not c
– pm100
Nov 13 at 1:19
hint Environment.CurrentDirectory
– pm100
Nov 13 at 1:22
@pm100 Got it.. Using string as for the path. Thanks ;)
– pxc
Nov 13 at 9:04
1
1
looks like c# code not c
– pm100
Nov 13 at 1:19
looks like c# code not c
– pm100
Nov 13 at 1:19
hint Environment.CurrentDirectory
– pm100
Nov 13 at 1:22
hint Environment.CurrentDirectory
– pm100
Nov 13 at 1:22
@pm100 Got it.. Using string as for the path. Thanks ;)
– pxc
Nov 13 at 9:04
@pm100 Got it.. Using string as for the path. Thanks ;)
– pxc
Nov 13 at 9:04
add a comment |
2 Answers
2
active
oldest
votes
If by "current directory" you mean the path for the executable file that started the application, then you can use Application.ExecutablePath like this:
System.IO.Path.GetDirectoryName(Application.ExecutablePath);
You can find more details here: https://docs.microsoft.com/en-us/dotnet/api/system.windows.forms.application.executablepath?view=netframework-4.7.2
answered Nov 13 at 8:40
Sergiu Muresan
2996
executablepath != currentdirectory. use Environment.CurrentDirectory for that
– pm100
Nov 13 at 17:11
add a comment |
This solved my problem
private void Form1_Load(object sender, EventArgs e)
{
string path = Environment.CurrentDirectory;
extract("myNamespace", path, "resources", "cygz.dll");
}
answered Nov 14 at 10:16
pxc
12
Note that this could potentially break if the program is started with a different "startup directory" or if it changes to a different one after starting.
– Alejandro
Nov 16 at 16:14
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
If by "current directory" you mean the path for the executable file that started the application, then you can use Application.ExecutablePath like this:
System.IO.Path.GetDirectoryName(Application.ExecutablePath);
You can find more details here: https://docs.microsoft.com/en-us/dotnet/api/system.windows.forms.application.executablepath?view=netframework-4.7.2
answered Nov 13 at 8:40
Sergiu Muresan
2996
executablepath != currentdirectory. use Environment.CurrentDirectory for that
– pm100
Nov 13 at 17:11
add a comment |
If by "current directory" you mean the path for the executable file that started the application, then you can use Application.ExecutablePath like this:
System.IO.Path.GetDirectoryName(Application.ExecutablePath);
You can find more details here: https://docs.microsoft.com/en-us/dotnet/api/system.windows.forms.application.executablepath?view=netframework-4.7.2
answered Nov 13 at 8:40
Sergiu Muresan
2996
executablepath != currentdirectory. use Environment.CurrentDirectory for that
– pm100
Nov 13 at 17:11
add a comment |
If by "current directory" you mean the path for the executable file that started the application, then you can use Application.ExecutablePath like this:
System.IO.Path.GetDirectoryName(Application.ExecutablePath);
You can find more details here: https://docs.microsoft.com/en-us/dotnet/api/system.windows.forms.application.executablepath?view=netframework-4.7.2
answered Nov 13 at 8:40
Sergiu Muresan
2996
If by "current directory" you mean the path for the executable file that started the application, then you can use Application.ExecutablePath like this:
System.IO.Path.GetDirectoryName(Application.ExecutablePath);
You can find more details here: https://docs.microsoft.com/en-us/dotnet/api/system.windows.forms.application.executablepath?view=netframework-4.7.2
answered Nov 13 at 8:40
Sergiu Muresan
2996
answered Nov 13 at 8:40
Sergiu Muresan
2996
answered Nov 13 at 8:40
Sergiu Muresan
2996
answered Nov 13 at 8:40
Sergiu Muresan
2996
2996
executablepath != currentdirectory. use Environment.CurrentDirectory for that
– pm100
Nov 13 at 17:11
add a comment |
executablepath != currentdirectory. use Environment.CurrentDirectory for that
– pm100
Nov 13 at 17:11
executablepath != currentdirectory. use Environment.CurrentDirectory for that
– pm100
Nov 13 at 17:11
executablepath != currentdirectory. use Environment.CurrentDirectory for that
– pm100
Nov 13 at 17:11
add a comment |
This solved my problem
private void Form1_Load(object sender, EventArgs e)
{
string path = Environment.CurrentDirectory;
extract("myNamespace", path, "resources", "cygz.dll");
}
answered Nov 14 at 10:16
pxc
12
Note that this could potentially break if the program is started with a different "startup directory" or if it changes to a different one after starting.
– Alejandro
Nov 16 at 16:14
add a comment |
This solved my problem
private void Form1_Load(object sender, EventArgs e)
{
string path = Environment.CurrentDirectory;
extract("myNamespace", path, "resources", "cygz.dll");
}
answered Nov 14 at 10:16
pxc
12
Note that this could potentially break if the program is started with a different "startup directory" or if it changes to a different one after starting.
– Alejandro
Nov 16 at 16:14
add a comment |
This solved my problem
private void Form1_Load(object sender, EventArgs e)
{
string path = Environment.CurrentDirectory;
extract("myNamespace", path, "resources", "cygz.dll");
}
answered Nov 14 at 10:16
pxc
12
This solved my problem
private void Form1_Load(object sender, EventArgs e)
{
string path = Environment.CurrentDirectory;
extract("myNamespace", path, "resources", "cygz.dll");
}
answered Nov 14 at 10:16
pxc
12
edited Nov 16 at 16:03
answered Nov 14 at 10:16
pxc
12
answered Nov 14 at 10:16
pxc
12
answered Nov 14 at 10:16
pxc
12
12
Note that this could potentially break if the program is started with a different "startup directory" or if it changes to a different one after starting.
– Alejandro
Nov 16 at 16:14
add a comment |
Note that this could potentially break if the program is started with a different "startup directory" or if it changes to a different one after starting.
– Alejandro
Nov 16 at 16:14
Note that this could potentially break if the program is started with a different "startup directory" or if it changes to a different one after starting.
– Alejandro
Nov 16 at 16:14
Note that this could potentially break if the program is started with a different "startup directory" or if it changes to a different one after starting.
– Alejandro
Nov 16 at 16:14
add a comment |
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1
looks like c# code not c
– pm100
Nov 13 at 1:19
hint Environment.CurrentDirectory
– pm100
Nov 13 at 1:22
@pm100 Got it.. Using string as for the path. Thanks ;)
– pxc
Nov 13 at 9:04