angular Ui grid aggregation value
hi i am working on angular ui grid for an about couple of days
And now my is question is that if the sum of total is negative then the color of that particular footer must be in red color
examples total= -50000
-5000 must be in red color and remaining colors must be asusual
angular angular-ui-grid
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hi i am working on angular ui grid for an about couple of days
And now my is question is that if the sum of total is negative then the color of that particular footer must be in red color
examples total= -50000
-5000 must be in red color and remaining colors must be asusual
angular angular-ui-grid
add a comment |
hi i am working on angular ui grid for an about couple of days
And now my is question is that if the sum of total is negative then the color of that particular footer must be in red color
examples total= -50000
-5000 must be in red color and remaining colors must be asusual
angular angular-ui-grid
hi i am working on angular ui grid for an about couple of days
And now my is question is that if the sum of total is negative then the color of that particular footer must be in red color
examples total= -50000
-5000 must be in red color and remaining colors must be asusual
angular angular-ui-grid
angular angular-ui-grid
asked Nov 19 '18 at 6:57
ronaldinoronaldino
498
498
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1 Answer
1
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You can use the cellClass
property of the column in the column defs. This property can take either a static class name or a function.
For example (taken from: http://brianhann.com/customize-ui-grid-with-dynamic-cell-classes/):
$scope.gridOptions = {
enableSorting: true,
columnDefs: [
{ field: 'name' },
{ field: 'gender',
cellClass: function(grid, row, col, rowRenderIndex, colRenderIndex) {
if (grid.getCellValue(row ,col).toLowerCase() === 'male') {
return 'red';
}
}
}
]
};
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You can use the cellClass
property of the column in the column defs. This property can take either a static class name or a function.
For example (taken from: http://brianhann.com/customize-ui-grid-with-dynamic-cell-classes/):
$scope.gridOptions = {
enableSorting: true,
columnDefs: [
{ field: 'name' },
{ field: 'gender',
cellClass: function(grid, row, col, rowRenderIndex, colRenderIndex) {
if (grid.getCellValue(row ,col).toLowerCase() === 'male') {
return 'red';
}
}
}
]
};
add a comment |
You can use the cellClass
property of the column in the column defs. This property can take either a static class name or a function.
For example (taken from: http://brianhann.com/customize-ui-grid-with-dynamic-cell-classes/):
$scope.gridOptions = {
enableSorting: true,
columnDefs: [
{ field: 'name' },
{ field: 'gender',
cellClass: function(grid, row, col, rowRenderIndex, colRenderIndex) {
if (grid.getCellValue(row ,col).toLowerCase() === 'male') {
return 'red';
}
}
}
]
};
add a comment |
You can use the cellClass
property of the column in the column defs. This property can take either a static class name or a function.
For example (taken from: http://brianhann.com/customize-ui-grid-with-dynamic-cell-classes/):
$scope.gridOptions = {
enableSorting: true,
columnDefs: [
{ field: 'name' },
{ field: 'gender',
cellClass: function(grid, row, col, rowRenderIndex, colRenderIndex) {
if (grid.getCellValue(row ,col).toLowerCase() === 'male') {
return 'red';
}
}
}
]
};
You can use the cellClass
property of the column in the column defs. This property can take either a static class name or a function.
For example (taken from: http://brianhann.com/customize-ui-grid-with-dynamic-cell-classes/):
$scope.gridOptions = {
enableSorting: true,
columnDefs: [
{ field: 'name' },
{ field: 'gender',
cellClass: function(grid, row, col, rowRenderIndex, colRenderIndex) {
if (grid.getCellValue(row ,col).toLowerCase() === 'male') {
return 'red';
}
}
}
]
};
answered Nov 20 '18 at 7:42
ArielGroArielGro
3811416
3811416
add a comment |
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