jQuery get data as object or array

I would like to get all elements with class .my-data-tid and data-tid values into an object or array

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

with

var tid = $('.my-data-tid').data('tid');

I get only the first value

edited Nov 16 '18 at 14:41

Mohammad

15.4k123461

asked Nov 16 '18 at 14:35

al404IT

5501931

add a comment |

I would like to get all elements with class .my-data-tid and data-tid values into an object or array

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

with

var tid = $('.my-data-tid').data('tid');

I get only the first value

edited Nov 16 '18 at 14:41

Mohammad

15.4k123461

asked Nov 16 '18 at 14:35

al404IT

5501931

add a comment |

I would like to get all elements with class .my-data-tid and data-tid values into an object or array

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

with

var tid = $('.my-data-tid').data('tid');

I get only the first value

edited Nov 16 '18 at 14:41

Mohammad

15.4k123461

asked Nov 16 '18 at 14:35

al404IT

5501931

I would like to get all elements with class .my-data-tid and data-tid values into an object or array

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

with

var tid = $('.my-data-tid').data('tid');

I get only the first value

javascript jquery arrays custom-data-attribute

edited Nov 16 '18 at 14:41

Mohammad

15.4k123461

asked Nov 16 '18 at 14:35

al404IT

5501931

edited Nov 16 '18 at 14:41

Mohammad

15.4k123461

asked Nov 16 '18 at 14:35

al404IT

5501931

edited Nov 16 '18 at 14:41

Mohammad

15.4k123461

edited Nov 16 '18 at 14:41

Mohammad

15.4k123461

edited Nov 16 '18 at 14:41

Mohammad

15.4k123461

asked Nov 16 '18 at 14:35

al404IT

5501931

asked Nov 16 '18 at 14:35

al404IT

5501931

asked Nov 16 '18 at 14:35

al404IT

5501931

add a comment |

1 Answer
1

active

oldest

votes

You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.

var tid = $('.my-data-tid').map(function(){

  return $(this).data('tid');

}).toArray();

console.log(tid);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

answered Nov 16 '18 at 14:36

Mohammad

15.4k123461

add a comment |

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1 Answer
1

active

oldest

votes

1 Answer
1

active

oldest

votes

You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.

var tid = $('.my-data-tid').map(function(){

  return $(this).data('tid');

}).toArray();

console.log(tid);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

answered Nov 16 '18 at 14:36

Mohammad

15.4k123461

add a comment |

You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.

var tid = $('.my-data-tid').map(function(){

  return $(this).data('tid');

}).toArray();

console.log(tid);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

answered Nov 16 '18 at 14:36

Mohammad

15.4k123461

add a comment |

You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.

var tid = $('.my-data-tid').map(function(){

  return $(this).data('tid');

}).toArray();

console.log(tid);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

answered Nov 16 '18 at 14:36

Mohammad

15.4k123461

You need to use .map() to convert jquery selector object to object contain target values and use .toArray() to convert result to array.

var tid = $('.my-data-tid').map(function(){

  return $(this).data('tid');

}).toArray();

console.log(tid);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

var tid = $('.my-data-tid').map(function(){

  return $(this).data('tid');

}).toArray();

console.log(tid);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

var tid = $('.my-data-tid').map(function(){

  return $(this).data('tid');

}).toArray();

console.log(tid);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>

<div class="my-data-tid" data-tid="1">1</div>

<div class="my-data-tid" data-tid="2">2</div>

<div class="my-data-tid" data-tid="3">3</div>

<div class="my-data-tid" data-tid="4">4</div>

answered Nov 16 '18 at 14:36

Mohammad

15.4k123461

answered Nov 16 '18 at 14:36

Mohammad

15.4k123461

answered Nov 16 '18 at 14:36

Mohammad

15.4k123461

answered Nov 16 '18 at 14:36

Mohammad

15.4k123461

add a comment |

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