Agfdhyk

I've got string as follows
"123 132 244" where that max value for an entry is 255

how can i convert that string to

unsigned char arr[3] = [123, ,132, ,244]

1. Step 1 : valid the string's format (number - one space - number - one
   space ...)


2. Step 2 : Count the number of space


3. Step 3 : Allocate the final array


4. Step 4 : use strtok to have token + sscanf to convert the string to number


5. Step 5 : return array (+ array size ? It's always useful).

In which step do you have difficulty ?

The expression "123 132 244" is a string literal. If you have access to string functions such as strtok() (defined in strings.h) then parse the string into three char values using strtok() and a string converter such as atoi() or strtol(). If you do not have access to strings.h, then the string to unsigned char conversion will need to be done another way. Here is one example:

const char str = {"123 132 244"};



void convertStr(const char *string, unsigned int ucArr[3], size_t size);



int main(void)

{

    unsigned int ucArray[3];

    convertStr(str, ucArray, sizeof(str)/sizeof(str[0]));



    return 0;

}



void convertStr(const char *string, unsigned int ucArr[3], size_t size)

{

    int i=0, j=0, k=0;

    int accum[3] = {0};//store numeric version of 3 alpha characters

    int ex = 0;//use in conversion of single digit value to place value.

    int acm = 0;//accumulate integer value of 3 successive integer values

                //stored in accum



        while(1)

        {

            if(isdigit(*string))

            {

                accum[i] = *string - '0';

                i++;

            }

            else

            {

                //convert

                for(k=i-1;k>=0;k--)

                {

                    ex = pow(10, k);

                    acm += accum[i-k-1]*ex;

                }

                ucArr[j] = acm;

                j++;

                i=0;

            }

            acm = 0;

            if(*string == NULL) break;

            *string++;

        }

}