how to hide a component if all sub-components are hidden ngIf












1















For example consider the code:



<div *ngIf="-------NOTEMPTY-------">
Parent
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0
</div>
</div>
</div>


I want Parent division's ngIf to be false if all its child divisions' ngIf are false.



Note : It is not possible to me to collect all the child conditions in the ts file.










share|improve this question

























  • offsprings.every(c => !c.condition)

    – bugs
    Nov 21 '18 at 10:13
















1















For example consider the code:



<div *ngIf="-------NOTEMPTY-------">
Parent
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0
</div>
</div>
</div>


I want Parent division's ngIf to be false if all its child divisions' ngIf are false.



Note : It is not possible to me to collect all the child conditions in the ts file.










share|improve this question

























  • offsprings.every(c => !c.condition)

    – bugs
    Nov 21 '18 at 10:13














1












1








1








For example consider the code:



<div *ngIf="-------NOTEMPTY-------">
Parent
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0
</div>
</div>
</div>


I want Parent division's ngIf to be false if all its child divisions' ngIf are false.



Note : It is not possible to me to collect all the child conditions in the ts file.










share|improve this question
















For example consider the code:



<div *ngIf="-------NOTEMPTY-------">
Parent
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0
</div>
</div>
</div>


I want Parent division's ngIf to be false if all its child divisions' ngIf are false.



Note : It is not possible to me to collect all the child conditions in the ts file.







javascript angular typescript ngif






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Nov 21 '18 at 10:46

























asked Nov 21 '18 at 10:10







user8401765




















  • offsprings.every(c => !c.condition)

    – bugs
    Nov 21 '18 at 10:13



















  • offsprings.every(c => !c.condition)

    – bugs
    Nov 21 '18 at 10:13

















offsprings.every(c => !c.condition)

– bugs
Nov 21 '18 at 10:13





offsprings.every(c => !c.condition)

– bugs
Nov 21 '18 at 10:13












2 Answers
2






active

oldest

votes


















1














Try adding in the Parent *ngIf condition



!offsprings.every(child => !conditions[child.name]);





share|improve this answer


























  • Edited the answer to search the condition in the conditions map

    – Nil Llisterri
    Nov 21 '18 at 11:00



















0














Used a function call as *ngIf = checkIfExists() on parent.



<div *ngIf="checkIfExists()">
Parent with children existing
<div *ngFor = 'let child of offsprings'>
<div name="c1" *ngIf="conditions[child.name]">
Child0 {{conditions[child.name]}}
</div>
</div>
</div>


Function For Parent ngIf:
Appraoch is to traverse every element of offsprings array,
and check if conditions[child.name] exists.



checkIfExists() {
let ifDefined: boolean;
this.offsprings.forEach(e=> {
if (this.conditions[e.name]) {
ifDefined = true;
}
});
return ifDefined;
}


StackBlitz Working Demo






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    2 Answers
    2






    active

    oldest

    votes








    2 Answers
    2






    active

    oldest

    votes









    active

    oldest

    votes






    active

    oldest

    votes









    1














    Try adding in the Parent *ngIf condition



    !offsprings.every(child => !conditions[child.name]);





    share|improve this answer


























    • Edited the answer to search the condition in the conditions map

      – Nil Llisterri
      Nov 21 '18 at 11:00
















    1














    Try adding in the Parent *ngIf condition



    !offsprings.every(child => !conditions[child.name]);





    share|improve this answer


























    • Edited the answer to search the condition in the conditions map

      – Nil Llisterri
      Nov 21 '18 at 11:00














    1












    1








    1







    Try adding in the Parent *ngIf condition



    !offsprings.every(child => !conditions[child.name]);





    share|improve this answer















    Try adding in the Parent *ngIf condition



    !offsprings.every(child => !conditions[child.name]);






    share|improve this answer














    share|improve this answer



    share|improve this answer








    edited Nov 21 '18 at 10:56

























    answered Nov 21 '18 at 10:13









    Nil LlisterriNil Llisterri

    452516




    452516













    • Edited the answer to search the condition in the conditions map

      – Nil Llisterri
      Nov 21 '18 at 11:00



















    • Edited the answer to search the condition in the conditions map

      – Nil Llisterri
      Nov 21 '18 at 11:00

















    Edited the answer to search the condition in the conditions map

    – Nil Llisterri
    Nov 21 '18 at 11:00





    Edited the answer to search the condition in the conditions map

    – Nil Llisterri
    Nov 21 '18 at 11:00













    0














    Used a function call as *ngIf = checkIfExists() on parent.



    <div *ngIf="checkIfExists()">
    Parent with children existing
    <div *ngFor = 'let child of offsprings'>
    <div name="c1" *ngIf="conditions[child.name]">
    Child0 {{conditions[child.name]}}
    </div>
    </div>
    </div>


    Function For Parent ngIf:
    Appraoch is to traverse every element of offsprings array,
    and check if conditions[child.name] exists.



    checkIfExists() {
    let ifDefined: boolean;
    this.offsprings.forEach(e=> {
    if (this.conditions[e.name]) {
    ifDefined = true;
    }
    });
    return ifDefined;
    }


    StackBlitz Working Demo






    share|improve this answer




























      0














      Used a function call as *ngIf = checkIfExists() on parent.



      <div *ngIf="checkIfExists()">
      Parent with children existing
      <div *ngFor = 'let child of offsprings'>
      <div name="c1" *ngIf="conditions[child.name]">
      Child0 {{conditions[child.name]}}
      </div>
      </div>
      </div>


      Function For Parent ngIf:
      Appraoch is to traverse every element of offsprings array,
      and check if conditions[child.name] exists.



      checkIfExists() {
      let ifDefined: boolean;
      this.offsprings.forEach(e=> {
      if (this.conditions[e.name]) {
      ifDefined = true;
      }
      });
      return ifDefined;
      }


      StackBlitz Working Demo






      share|improve this answer


























        0












        0








        0







        Used a function call as *ngIf = checkIfExists() on parent.



        <div *ngIf="checkIfExists()">
        Parent with children existing
        <div *ngFor = 'let child of offsprings'>
        <div name="c1" *ngIf="conditions[child.name]">
        Child0 {{conditions[child.name]}}
        </div>
        </div>
        </div>


        Function For Parent ngIf:
        Appraoch is to traverse every element of offsprings array,
        and check if conditions[child.name] exists.



        checkIfExists() {
        let ifDefined: boolean;
        this.offsprings.forEach(e=> {
        if (this.conditions[e.name]) {
        ifDefined = true;
        }
        });
        return ifDefined;
        }


        StackBlitz Working Demo






        share|improve this answer













        Used a function call as *ngIf = checkIfExists() on parent.



        <div *ngIf="checkIfExists()">
        Parent with children existing
        <div *ngFor = 'let child of offsprings'>
        <div name="c1" *ngIf="conditions[child.name]">
        Child0 {{conditions[child.name]}}
        </div>
        </div>
        </div>


        Function For Parent ngIf:
        Appraoch is to traverse every element of offsprings array,
        and check if conditions[child.name] exists.



        checkIfExists() {
        let ifDefined: boolean;
        this.offsprings.forEach(e=> {
        if (this.conditions[e.name]) {
        ifDefined = true;
        }
        });
        return ifDefined;
        }


        StackBlitz Working Demo







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered Nov 21 '18 at 11:41









        Abhishek KumarAbhishek Kumar

        1,214417




        1,214417






























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