How to keep calculating even after equal buttons
I recently made a calculator and everything is working fine except for the equal button. While it is outputting the right answer, I would like to keep using operator even after pressing equals. How can I do that?
if(e.getSource() == btnEquals) {
num2 = 0;
char operator2 = 's';
try {
display.append("=" + "n");
for ( String line : display.getText().split("\n")) {
char operator1 = line.charAt(line.length()-1);
num1 = Double.parseDouble(line.substring(0, line.length()-1));
if (operator2 == 's') {
num2 = num1;
operator2 = operator1;
} else if (operator2 == '+') {
num2 = num2 + num1;
operator2 = operator1;
} else if (operator2 == '-') {
num2 = num2 - num1;
operator2 = operator1;
} else if (operator2 == '*') {
num2 = num2 * num1;
operator2 = operator1;
} else if (operator2 == '/') {
num2 = num2 / num1;
operator2 = operator1;
}
}
} catch (NumberFormatException a) {
display.setText("Error: Consecutive Operators " + " (=) " + " or no input" + "n");
return;
}
display.setText(display.getText() + num2);
}
}
java
asked Nov 21 '18 at 10:11
BobBob
163
add a comment |
I recently made a calculator and everything is working fine except for the equal button. While it is outputting the right answer, I would like to keep using operator even after pressing equals. How can I do that?
if(e.getSource() == btnEquals) {
num2 = 0;
char operator2 = 's';
try {
display.append("=" + "n");
for ( String line : display.getText().split("\n")) {
char operator1 = line.charAt(line.length()-1);
num1 = Double.parseDouble(line.substring(0, line.length()-1));
if (operator2 == 's') {
num2 = num1;
operator2 = operator1;
} else if (operator2 == '+') {
num2 = num2 + num1;
operator2 = operator1;
} else if (operator2 == '-') {
num2 = num2 - num1;
operator2 = operator1;
} else if (operator2 == '*') {
num2 = num2 * num1;
operator2 = operator1;
} else if (operator2 == '/') {
num2 = num2 / num1;
operator2 = operator1;
}
}
} catch (NumberFormatException a) {
display.setText("Error: Consecutive Operators " + " (=) " + " or no input" + "n");
return;
}
display.setText(display.getText() + num2);
}
}
java
asked Nov 21 '18 at 10:11
BobBob
163
To get to the current solution we need a little more information, specifically where this comparision is done (some event listener callback, I assume) and what you specifically mean with "keep using". Does the program terminate or freeze?
– Hauke Ingmar Schmidt
Nov 21 '18 at 10:21
add a comment |
I recently made a calculator and everything is working fine except for the equal button. While it is outputting the right answer, I would like to keep using operator even after pressing equals. How can I do that?
if(e.getSource() == btnEquals) {
num2 = 0;
char operator2 = 's';
try {
display.append("=" + "n");
for ( String line : display.getText().split("\n")) {
char operator1 = line.charAt(line.length()-1);
num1 = Double.parseDouble(line.substring(0, line.length()-1));
if (operator2 == 's') {
num2 = num1;
operator2 = operator1;
} else if (operator2 == '+') {
num2 = num2 + num1;
operator2 = operator1;
} else if (operator2 == '-') {
num2 = num2 - num1;
operator2 = operator1;
} else if (operator2 == '*') {
num2 = num2 * num1;
operator2 = operator1;
} else if (operator2 == '/') {
num2 = num2 / num1;
operator2 = operator1;
}
}
} catch (NumberFormatException a) {
display.setText("Error: Consecutive Operators " + " (=) " + " or no input" + "n");
return;
}
display.setText(display.getText() + num2);
}
}
java
asked Nov 21 '18 at 10:11
BobBob
163
I recently made a calculator and everything is working fine except for the equal button. While it is outputting the right answer, I would like to keep using operator even after pressing equals. How can I do that?
if(e.getSource() == btnEquals) {
num2 = 0;
char operator2 = 's';
try {
display.append("=" + "n");
for ( String line : display.getText().split("\n")) {
char operator1 = line.charAt(line.length()-1);
num1 = Double.parseDouble(line.substring(0, line.length()-1));
if (operator2 == 's') {
num2 = num1;
operator2 = operator1;
} else if (operator2 == '+') {
num2 = num2 + num1;
operator2 = operator1;
} else if (operator2 == '-') {
num2 = num2 - num1;
operator2 = operator1;
} else if (operator2 == '*') {
num2 = num2 * num1;
operator2 = operator1;
} else if (operator2 == '/') {
num2 = num2 / num1;
operator2 = operator1;
}
}
} catch (NumberFormatException a) {
display.setText("Error: Consecutive Operators " + " (=) " + " or no input" + "n");
return;
}
display.setText(display.getText() + num2);
}
}
java
java
asked Nov 21 '18 at 10:11
BobBob
163
asked Nov 21 '18 at 10:11
BobBob
163
asked Nov 21 '18 at 10:11
BobBob
163
asked Nov 21 '18 at 10:11
BobBob
163
asked Nov 21 '18 at 10:11
BobBob
163
163
To get to the current solution we need a little more information, specifically where this comparision is done (some event listener callback, I assume) and what you specifically mean with "keep using". Does the program terminate or freeze?
– Hauke Ingmar Schmidt
Nov 21 '18 at 10:21
add a comment |
To get to the current solution we need a little more information, specifically where this comparision is done (some event listener callback, I assume) and what you specifically mean with "keep using". Does the program terminate or freeze?
– Hauke Ingmar Schmidt
Nov 21 '18 at 10:21
To get to the current solution we need a little more information, specifically where this comparision is done (some event listener callback, I assume) and what you specifically mean with "keep using". Does the program terminate or freeze?
– Hauke Ingmar Schmidt
Nov 21 '18 at 10:21
To get to the current solution we need a little more information, specifically where this comparision is done (some event listener callback, I assume) and what you specifically mean with "keep using". Does the program terminate or freeze?
– Hauke Ingmar Schmidt
Nov 21 '18 at 10:21
add a comment |
2 Answers
2
active
oldest
votes
When you press the button (I assume it is a Swing JButton) all the work is done in a specific thread of execution which is called event dispatch thread. As the name implies it is not the right thread for doing the heavy lifting, i.e. your current work. While you are using it it can't dispatch events for other GUI elements so you can't use any other elements.
So you need to put your business work into an extra thread and thus deal with concurrency in Swing. You can read about it here.
answered Nov 21 '18 at 10:19
Hauke Ingmar SchmidtHauke Ingmar Schmidt
10.6k13248
add a comment |
Wrap it with while(True) statement and will run till the exit.
answered Nov 21 '18 at 10:17
RarblackRarblack
2,98341227
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
When you press the button (I assume it is a Swing JButton) all the work is done in a specific thread of execution which is called event dispatch thread. As the name implies it is not the right thread for doing the heavy lifting, i.e. your current work. While you are using it it can't dispatch events for other GUI elements so you can't use any other elements.
So you need to put your business work into an extra thread and thus deal with concurrency in Swing. You can read about it here.
answered Nov 21 '18 at 10:19
Hauke Ingmar SchmidtHauke Ingmar Schmidt
10.6k13248
add a comment |
When you press the button (I assume it is a Swing JButton) all the work is done in a specific thread of execution which is called event dispatch thread. As the name implies it is not the right thread for doing the heavy lifting, i.e. your current work. While you are using it it can't dispatch events for other GUI elements so you can't use any other elements.
So you need to put your business work into an extra thread and thus deal with concurrency in Swing. You can read about it here.
answered Nov 21 '18 at 10:19
Hauke Ingmar SchmidtHauke Ingmar Schmidt
10.6k13248
add a comment |
When you press the button (I assume it is a Swing JButton) all the work is done in a specific thread of execution which is called event dispatch thread. As the name implies it is not the right thread for doing the heavy lifting, i.e. your current work. While you are using it it can't dispatch events for other GUI elements so you can't use any other elements.
So you need to put your business work into an extra thread and thus deal with concurrency in Swing. You can read about it here.
answered Nov 21 '18 at 10:19
Hauke Ingmar SchmidtHauke Ingmar Schmidt
10.6k13248
When you press the button (I assume it is a Swing JButton) all the work is done in a specific thread of execution which is called event dispatch thread. As the name implies it is not the right thread for doing the heavy lifting, i.e. your current work. While you are using it it can't dispatch events for other GUI elements so you can't use any other elements.
So you need to put your business work into an extra thread and thus deal with concurrency in Swing. You can read about it here.
answered Nov 21 '18 at 10:19
Hauke Ingmar SchmidtHauke Ingmar Schmidt
10.6k13248
answered Nov 21 '18 at 10:19
Hauke Ingmar SchmidtHauke Ingmar Schmidt
10.6k13248
answered Nov 21 '18 at 10:19
Hauke Ingmar SchmidtHauke Ingmar Schmidt
10.6k13248
answered Nov 21 '18 at 10:19
Hauke Ingmar SchmidtHauke Ingmar Schmidt
10.6k13248
10.6k13248
add a comment |
add a comment |
Wrap it with while(True) statement and will run till the exit.
answered Nov 21 '18 at 10:17
RarblackRarblack
2,98341227
add a comment |
Wrap it with while(True) statement and will run till the exit.
answered Nov 21 '18 at 10:17
RarblackRarblack
2,98341227
add a comment |
Wrap it with while(True) statement and will run till the exit.
answered Nov 21 '18 at 10:17
RarblackRarblack
2,98341227
Wrap it with while(True) statement and will run till the exit.
answered Nov 21 '18 at 10:17
RarblackRarblack
2,98341227
answered Nov 21 '18 at 10:17
RarblackRarblack
2,98341227
answered Nov 21 '18 at 10:17
RarblackRarblack
2,98341227
answered Nov 21 '18 at 10:17
RarblackRarblack
2,98341227
2,98341227
add a comment |
add a comment |
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To get to the current solution we need a little more information, specifically where this comparision is done (some event listener callback, I assume) and what you specifically mean with "keep using". Does the program terminate or freeze?
– Hauke Ingmar Schmidt
Nov 21 '18 at 10:21