MySQL: Joining to Subquery on YEAR(date)
Trying to create a table that summarizes data from another one. The summary is to be by year that is extracted from a date field. When I try to include a new field to the table with a subquery, I get a 1054 (unknown column) error in the ON clause. I have tried joining on date
and get the same error.
CREATE TABLE IF NOT EXISTS park_factor (
SELECT YEAR(games.date) AS year
, games.home_team
, sum(games.runs0) AS ht_runs
, sum(games.runs1) as away_runs
, round(leagues.rules_schedule_games_per_team/2,0) AS home_games
, x.home_losses
FROM games
INNER JOIN leagues ON games.league_id=leagues.league_id
INNER JOIN (
SELECT YEAR(games.date) as year
, games.home_team
, COUNT(*) as home_losses
FROM games
WHERE games.runs1>runs0
GROUP BY year, games.home_team
) AS x ON x.year=games.year AND x.home_team=games.home_team
GROUP BY year, games.home_team, home_games, home_losses );
mysql
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Trying to create a table that summarizes data from another one. The summary is to be by year that is extracted from a date field. When I try to include a new field to the table with a subquery, I get a 1054 (unknown column) error in the ON clause. I have tried joining on date
and get the same error.
CREATE TABLE IF NOT EXISTS park_factor (
SELECT YEAR(games.date) AS year
, games.home_team
, sum(games.runs0) AS ht_runs
, sum(games.runs1) as away_runs
, round(leagues.rules_schedule_games_per_team/2,0) AS home_games
, x.home_losses
FROM games
INNER JOIN leagues ON games.league_id=leagues.league_id
INNER JOIN (
SELECT YEAR(games.date) as year
, games.home_team
, COUNT(*) as home_losses
FROM games
WHERE games.runs1>runs0
GROUP BY year, games.home_team
) AS x ON x.year=games.year AND x.home_team=games.home_team
GROUP BY year, games.home_team, home_games, home_losses );
mysql
add a comment |
Trying to create a table that summarizes data from another one. The summary is to be by year that is extracted from a date field. When I try to include a new field to the table with a subquery, I get a 1054 (unknown column) error in the ON clause. I have tried joining on date
and get the same error.
CREATE TABLE IF NOT EXISTS park_factor (
SELECT YEAR(games.date) AS year
, games.home_team
, sum(games.runs0) AS ht_runs
, sum(games.runs1) as away_runs
, round(leagues.rules_schedule_games_per_team/2,0) AS home_games
, x.home_losses
FROM games
INNER JOIN leagues ON games.league_id=leagues.league_id
INNER JOIN (
SELECT YEAR(games.date) as year
, games.home_team
, COUNT(*) as home_losses
FROM games
WHERE games.runs1>runs0
GROUP BY year, games.home_team
) AS x ON x.year=games.year AND x.home_team=games.home_team
GROUP BY year, games.home_team, home_games, home_losses );
mysql
Trying to create a table that summarizes data from another one. The summary is to be by year that is extracted from a date field. When I try to include a new field to the table with a subquery, I get a 1054 (unknown column) error in the ON clause. I have tried joining on date
and get the same error.
CREATE TABLE IF NOT EXISTS park_factor (
SELECT YEAR(games.date) AS year
, games.home_team
, sum(games.runs0) AS ht_runs
, sum(games.runs1) as away_runs
, round(leagues.rules_schedule_games_per_team/2,0) AS home_games
, x.home_losses
FROM games
INNER JOIN leagues ON games.league_id=leagues.league_id
INNER JOIN (
SELECT YEAR(games.date) as year
, games.home_team
, COUNT(*) as home_losses
FROM games
WHERE games.runs1>runs0
GROUP BY year, games.home_team
) AS x ON x.year=games.year AND x.home_team=games.home_team
GROUP BY year, games.home_team, home_games, home_losses );
mysql
mysql
asked Nov 20 '18 at 23:44
JayCo741JayCo741
226
226
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2 Answers
2
active
oldest
votes
There is no games.year
column, which is what is causing your error. You need to JOIN
using
x.year = YEAR(games.date) AND x.home_team=games.home_team
add a comment |
I figured it out while @Nick was answering. The code that works is:
CREATE TABLE IF NOT EXISTS park_factor (
SELECT YEAR(games.date) AS `year`
, games.home_team
, sum(games.runs0) AS ht_runs
, sum(games.runs1) as away_runs
, round(leagues.rules_schedule_games_per_team/2,0) AS home_games
, x.home_losses
FROM games
INNER JOIN leagues ON games.league_id=leagues.league_id
INNER JOIN (
SELECT YEAR(games.date) as `year`
, games.home_team
, COUNT(*) as home_losses
FROM games
WHERE games.runs1>runs0
GROUP BY year, games.home_team
) AS x ON x.`year`=YEAR(games.date) AND x.home_team=games.home_team
GROUP BY YEAR(games.date), games.home_team, home_games, home_losses );
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
There is no games.year
column, which is what is causing your error. You need to JOIN
using
x.year = YEAR(games.date) AND x.home_team=games.home_team
add a comment |
There is no games.year
column, which is what is causing your error. You need to JOIN
using
x.year = YEAR(games.date) AND x.home_team=games.home_team
add a comment |
There is no games.year
column, which is what is causing your error. You need to JOIN
using
x.year = YEAR(games.date) AND x.home_team=games.home_team
There is no games.year
column, which is what is causing your error. You need to JOIN
using
x.year = YEAR(games.date) AND x.home_team=games.home_team
answered Nov 20 '18 at 23:53
NickNick
35k132143
35k132143
add a comment |
add a comment |
I figured it out while @Nick was answering. The code that works is:
CREATE TABLE IF NOT EXISTS park_factor (
SELECT YEAR(games.date) AS `year`
, games.home_team
, sum(games.runs0) AS ht_runs
, sum(games.runs1) as away_runs
, round(leagues.rules_schedule_games_per_team/2,0) AS home_games
, x.home_losses
FROM games
INNER JOIN leagues ON games.league_id=leagues.league_id
INNER JOIN (
SELECT YEAR(games.date) as `year`
, games.home_team
, COUNT(*) as home_losses
FROM games
WHERE games.runs1>runs0
GROUP BY year, games.home_team
) AS x ON x.`year`=YEAR(games.date) AND x.home_team=games.home_team
GROUP BY YEAR(games.date), games.home_team, home_games, home_losses );
add a comment |
I figured it out while @Nick was answering. The code that works is:
CREATE TABLE IF NOT EXISTS park_factor (
SELECT YEAR(games.date) AS `year`
, games.home_team
, sum(games.runs0) AS ht_runs
, sum(games.runs1) as away_runs
, round(leagues.rules_schedule_games_per_team/2,0) AS home_games
, x.home_losses
FROM games
INNER JOIN leagues ON games.league_id=leagues.league_id
INNER JOIN (
SELECT YEAR(games.date) as `year`
, games.home_team
, COUNT(*) as home_losses
FROM games
WHERE games.runs1>runs0
GROUP BY year, games.home_team
) AS x ON x.`year`=YEAR(games.date) AND x.home_team=games.home_team
GROUP BY YEAR(games.date), games.home_team, home_games, home_losses );
add a comment |
I figured it out while @Nick was answering. The code that works is:
CREATE TABLE IF NOT EXISTS park_factor (
SELECT YEAR(games.date) AS `year`
, games.home_team
, sum(games.runs0) AS ht_runs
, sum(games.runs1) as away_runs
, round(leagues.rules_schedule_games_per_team/2,0) AS home_games
, x.home_losses
FROM games
INNER JOIN leagues ON games.league_id=leagues.league_id
INNER JOIN (
SELECT YEAR(games.date) as `year`
, games.home_team
, COUNT(*) as home_losses
FROM games
WHERE games.runs1>runs0
GROUP BY year, games.home_team
) AS x ON x.`year`=YEAR(games.date) AND x.home_team=games.home_team
GROUP BY YEAR(games.date), games.home_team, home_games, home_losses );
I figured it out while @Nick was answering. The code that works is:
CREATE TABLE IF NOT EXISTS park_factor (
SELECT YEAR(games.date) AS `year`
, games.home_team
, sum(games.runs0) AS ht_runs
, sum(games.runs1) as away_runs
, round(leagues.rules_schedule_games_per_team/2,0) AS home_games
, x.home_losses
FROM games
INNER JOIN leagues ON games.league_id=leagues.league_id
INNER JOIN (
SELECT YEAR(games.date) as `year`
, games.home_team
, COUNT(*) as home_losses
FROM games
WHERE games.runs1>runs0
GROUP BY year, games.home_team
) AS x ON x.`year`=YEAR(games.date) AND x.home_team=games.home_team
GROUP BY YEAR(games.date), games.home_team, home_games, home_losses );
answered Nov 20 '18 at 23:58
JayCo741JayCo741
226
226
add a comment |
add a comment |
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