In Python how do I use a for loop, to create nested list from dictionary?
2
This is homework:
fruits = {'banana':3,'apple':2, 'mango':1, 'kiwi':5}
This is the result I'm supposed to get:
fruits_list = [
['banana', 'banana', 'banana'],
['apple', 'apple'],
['mango'],
['kiwi', 'kiwi', 'kiwi', 'kiwi', 'kiwi']]
python-3.x loops dictionary for-loop nested
edited Nov 21 '18 at 0:14
Cheche
815219
asked Nov 20 '18 at 23:34
A J EA J E
335
add a comment |
2
This is homework:
fruits = {'banana':3,'apple':2, 'mango':1, 'kiwi':5}
This is the result I'm supposed to get:
fruits_list = [
['banana', 'banana', 'banana'],
['apple', 'apple'],
['mango'],
['kiwi', 'kiwi', 'kiwi', 'kiwi', 'kiwi']]
python-3.x loops dictionary for-loop nested
edited Nov 21 '18 at 0:14
Cheche
815219
asked Nov 20 '18 at 23:34
A J EA J E
335
Can you please tell us what have you tried?
– Cheche
Nov 20 '18 at 23:37
what I had tried was more like:
– A J E
Nov 21 '18 at 9:48
fruits_list = [key*value for key, value in fruits.items()]
– A J E
Nov 21 '18 at 9:48
Check posted answer. You're close but, in order to get a list with repeated items, you need to pass a list. Do[key]*value. If you just dokey*valueyou'll get a string concatenation, not a list.
– Cheche
Nov 21 '18 at 11:34
add a comment |
2
2
2
This is homework:
fruits = {'banana':3,'apple':2, 'mango':1, 'kiwi':5}
This is the result I'm supposed to get:
fruits_list = [
['banana', 'banana', 'banana'],
['apple', 'apple'],
['mango'],
['kiwi', 'kiwi', 'kiwi', 'kiwi', 'kiwi']]
python-3.x loops dictionary for-loop nested
edited Nov 21 '18 at 0:14
Cheche
815219
asked Nov 20 '18 at 23:34
A J EA J E
335
This is homework:
fruits = {'banana':3,'apple':2, 'mango':1, 'kiwi':5}
This is the result I'm supposed to get:
fruits_list = [
['banana', 'banana', 'banana'],
['apple', 'apple'],
['mango'],
['kiwi', 'kiwi', 'kiwi', 'kiwi', 'kiwi']]
python-3.x loops dictionary for-loop nested
python-3.x loops dictionary for-loop nested
edited Nov 21 '18 at 0:14
Cheche
815219
asked Nov 20 '18 at 23:34
A J EA J E
335
edited Nov 21 '18 at 0:14
Cheche
815219
asked Nov 20 '18 at 23:34
A J EA J E
335
edited Nov 21 '18 at 0:14
Cheche
815219
edited Nov 21 '18 at 0:14
Cheche
815219
edited Nov 21 '18 at 0:14
Cheche
815219
815219
asked Nov 20 '18 at 23:34
A J EA J E
335
asked Nov 20 '18 at 23:34
A J EA J E
335
asked Nov 20 '18 at 23:34
A J EA J E
335
335
Can you please tell us what have you tried?
– Cheche
Nov 20 '18 at 23:37
what I had tried was more like:
– A J E
Nov 21 '18 at 9:48
fruits_list = [key*value for key, value in fruits.items()]
– A J E
Nov 21 '18 at 9:48
Check posted answer. You're close but, in order to get a list with repeated items, you need to pass a list. Do[key]*value. If you just dokey*valueyou'll get a string concatenation, not a list.
– Cheche
Nov 21 '18 at 11:34
add a comment |
Can you please tell us what have you tried?
– Cheche
Nov 20 '18 at 23:37
what I had tried was more like:
– A J E
Nov 21 '18 at 9:48
fruits_list = [key*value for key, value in fruits.items()]
– A J E
Nov 21 '18 at 9:48
Check posted answer. You're close but, in order to get a list with repeated items, you need to pass a list. Do[key]*value. If you just dokey*valueyou'll get a string concatenation, not a list.
– Cheche
Nov 21 '18 at 11:34
Can you please tell us what have you tried?
– Cheche
Nov 20 '18 at 23:37
Can you please tell us what have you tried?
– Cheche
Nov 20 '18 at 23:37
what I had tried was more like:
– A J E
Nov 21 '18 at 9:48
what I had tried was more like:
– A J E
Nov 21 '18 at 9:48
fruits_list = [key*value for key, value in fruits.items()]
– A J E
Nov 21 '18 at 9:48
fruits_list = [key*value for key, value in fruits.items()]
– A J E
Nov 21 '18 at 9:48
Check posted answer. You're close but, in order to get a list with repeated items, you need to pass a list. Do
[key]*value. If you just do key*value you'll get a string concatenation, not a list.– Cheche
Nov 21 '18 at 11:34
Check posted answer. You're close but, in order to get a list with repeated items, you need to pass a list. Do
[key]*value. If you just do key*value you'll get a string concatenation, not a list.– Cheche
Nov 21 '18 at 11:34
add a comment |
1 Answer
1
active
oldest
votes
1
You need to iterate all over fruits keys and build a list repeating the key N=value times.
You can accomplish this with a list comprehension.
- To iterate all over dict items you'll need
fruits.items(). - To build a list repeating each key N times do:
[key]*N. - As dict values indicate how many times to repeat, do:
[key]*value.
Finally:
fruits_list = [[key]*value for key, value in fruits.items()]
Then print(fruit_list) gives you:
Python 3.6.1 (default, Dec 2015, 13:05:11)
[GCC 4.8.2] on linux
[['banana', 'banana', 'banana'], ['apple', 'apple'], ['mango'], ['kiwi', 'kiwi', 'kiwi', 'kiwi', 'kiwi']]
answered Nov 21 '18 at 1:00
ChecheCheche
815219
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You need to iterate all over fruits keys and build a list repeating the key N=value times.
You can accomplish this with a list comprehension.
- To iterate all over dict items you'll need
fruits.items(). - To build a list repeating each key N times do:
[key]*N. - As dict values indicate how many times to repeat, do:
[key]*value.
Finally:
fruits_list = [[key]*value for key, value in fruits.items()]
Then print(fruit_list) gives you:
Python 3.6.1 (default, Dec 2015, 13:05:11)
[GCC 4.8.2] on linux
[['banana', 'banana', 'banana'], ['apple', 'apple'], ['mango'], ['kiwi', 'kiwi', 'kiwi', 'kiwi', 'kiwi']]
answered Nov 21 '18 at 1:00
ChecheCheche
815219
add a comment |
1
You need to iterate all over fruits keys and build a list repeating the key N=value times.
You can accomplish this with a list comprehension.
- To iterate all over dict items you'll need
fruits.items(). - To build a list repeating each key N times do:
[key]*N. - As dict values indicate how many times to repeat, do:
[key]*value.
Finally:
fruits_list = [[key]*value for key, value in fruits.items()]
Then print(fruit_list) gives you:
Python 3.6.1 (default, Dec 2015, 13:05:11)
[GCC 4.8.2] on linux
[['banana', 'banana', 'banana'], ['apple', 'apple'], ['mango'], ['kiwi', 'kiwi', 'kiwi', 'kiwi', 'kiwi']]
answered Nov 21 '18 at 1:00
ChecheCheche
815219
add a comment |
1
1
1
You need to iterate all over fruits keys and build a list repeating the key N=value times.
You can accomplish this with a list comprehension.
- To iterate all over dict items you'll need
fruits.items(). - To build a list repeating each key N times do:
[key]*N. - As dict values indicate how many times to repeat, do:
[key]*value.
Finally:
fruits_list = [[key]*value for key, value in fruits.items()]
Then print(fruit_list) gives you:
Python 3.6.1 (default, Dec 2015, 13:05:11)
[GCC 4.8.2] on linux
[['banana', 'banana', 'banana'], ['apple', 'apple'], ['mango'], ['kiwi', 'kiwi', 'kiwi', 'kiwi', 'kiwi']]
answered Nov 21 '18 at 1:00
ChecheCheche
815219
You need to iterate all over fruits keys and build a list repeating the key N=value times.
You can accomplish this with a list comprehension.
- To iterate all over dict items you'll need
fruits.items(). - To build a list repeating each key N times do:
[key]*N. - As dict values indicate how many times to repeat, do:
[key]*value.
Finally:
fruits_list = [[key]*value for key, value in fruits.items()]
Then print(fruit_list) gives you:
Python 3.6.1 (default, Dec 2015, 13:05:11)
[GCC 4.8.2] on linux
[['banana', 'banana', 'banana'], ['apple', 'apple'], ['mango'], ['kiwi', 'kiwi', 'kiwi', 'kiwi', 'kiwi']]
answered Nov 21 '18 at 1:00
ChecheCheche
815219
edited Nov 21 '18 at 21:55
answered Nov 21 '18 at 1:00
ChecheCheche
815219
answered Nov 21 '18 at 1:00
ChecheCheche
815219
answered Nov 21 '18 at 1:00
ChecheCheche
815219
815219
add a comment |
add a comment |
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Can you please tell us what have you tried?
– Cheche
Nov 20 '18 at 23:37
what I had tried was more like:
– A J E
Nov 21 '18 at 9:48
fruits_list = [key*value for key, value in fruits.items()]
– A J E
Nov 21 '18 at 9:48
Check posted answer. You're close but, in order to get a list with repeated items, you need to pass a list. Do
[key]*value. If you just dokey*valueyou'll get a string concatenation, not a list.– Cheche
Nov 21 '18 at 11:34