new operator and delete operator overloading












0















Can anyone explain what happens in the below program,



// CPP program to demonstrate  
// Overloading new and delete operator
// for a specific class
#include<iostream>
#include<stdlib.h>

using namespace std;
class student
{
string name;
int age;
public:
student()
{
cout<< "Constructor is calledn" ;
}
student(string name, int age)
{
this->name = name;
this->age = age;
}
void display()
{
cout<< "Name:" << name << endl;
cout<< "Age:" << age << endl;
}
void * operator new(size_t size)
{
cout<< "Overloading new operator with size: " << size << endl;
void * p = ::new student();
//void * p = malloc(size); will also work fine

return p;
}

void operator delete(void * p)
{
cout<< "Overloading delete operator " << endl;
free(p);
}
};

int main()
{
student * p = new student("Yash", 24);

p->display();
delete p;
}


What is the use of overloading the new operator, in my understanding of the above program the overloaded new operator is still allocating the memory using malloc, that can be done without overloading the new operator right?



Correct me if i' m wrong.



Thanks!










share|improve this question























  • Possible duplicate of stackoverflow.com/questions/7149461/…

    – P.W
    Nov 21 '18 at 5:05
















0















Can anyone explain what happens in the below program,



// CPP program to demonstrate  
// Overloading new and delete operator
// for a specific class
#include<iostream>
#include<stdlib.h>

using namespace std;
class student
{
string name;
int age;
public:
student()
{
cout<< "Constructor is calledn" ;
}
student(string name, int age)
{
this->name = name;
this->age = age;
}
void display()
{
cout<< "Name:" << name << endl;
cout<< "Age:" << age << endl;
}
void * operator new(size_t size)
{
cout<< "Overloading new operator with size: " << size << endl;
void * p = ::new student();
//void * p = malloc(size); will also work fine

return p;
}

void operator delete(void * p)
{
cout<< "Overloading delete operator " << endl;
free(p);
}
};

int main()
{
student * p = new student("Yash", 24);

p->display();
delete p;
}


What is the use of overloading the new operator, in my understanding of the above program the overloaded new operator is still allocating the memory using malloc, that can be done without overloading the new operator right?



Correct me if i' m wrong.



Thanks!










share|improve this question























  • Possible duplicate of stackoverflow.com/questions/7149461/…

    – P.W
    Nov 21 '18 at 5:05














0












0








0








Can anyone explain what happens in the below program,



// CPP program to demonstrate  
// Overloading new and delete operator
// for a specific class
#include<iostream>
#include<stdlib.h>

using namespace std;
class student
{
string name;
int age;
public:
student()
{
cout<< "Constructor is calledn" ;
}
student(string name, int age)
{
this->name = name;
this->age = age;
}
void display()
{
cout<< "Name:" << name << endl;
cout<< "Age:" << age << endl;
}
void * operator new(size_t size)
{
cout<< "Overloading new operator with size: " << size << endl;
void * p = ::new student();
//void * p = malloc(size); will also work fine

return p;
}

void operator delete(void * p)
{
cout<< "Overloading delete operator " << endl;
free(p);
}
};

int main()
{
student * p = new student("Yash", 24);

p->display();
delete p;
}


What is the use of overloading the new operator, in my understanding of the above program the overloaded new operator is still allocating the memory using malloc, that can be done without overloading the new operator right?



Correct me if i' m wrong.



Thanks!










share|improve this question














Can anyone explain what happens in the below program,



// CPP program to demonstrate  
// Overloading new and delete operator
// for a specific class
#include<iostream>
#include<stdlib.h>

using namespace std;
class student
{
string name;
int age;
public:
student()
{
cout<< "Constructor is calledn" ;
}
student(string name, int age)
{
this->name = name;
this->age = age;
}
void display()
{
cout<< "Name:" << name << endl;
cout<< "Age:" << age << endl;
}
void * operator new(size_t size)
{
cout<< "Overloading new operator with size: " << size << endl;
void * p = ::new student();
//void * p = malloc(size); will also work fine

return p;
}

void operator delete(void * p)
{
cout<< "Overloading delete operator " << endl;
free(p);
}
};

int main()
{
student * p = new student("Yash", 24);

p->display();
delete p;
}


What is the use of overloading the new operator, in my understanding of the above program the overloaded new operator is still allocating the memory using malloc, that can be done without overloading the new operator right?



Correct me if i' m wrong.



Thanks!







c++ operator-overloading new-operator






share|improve this question













share|improve this question











share|improve this question




share|improve this question










asked Nov 21 '18 at 4:37









JayakumarJayakumar

348




348













  • Possible duplicate of stackoverflow.com/questions/7149461/…

    – P.W
    Nov 21 '18 at 5:05



















  • Possible duplicate of stackoverflow.com/questions/7149461/…

    – P.W
    Nov 21 '18 at 5:05

















Possible duplicate of stackoverflow.com/questions/7149461/…

– P.W
Nov 21 '18 at 5:05





Possible duplicate of stackoverflow.com/questions/7149461/…

– P.W
Nov 21 '18 at 5:05












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