Agfdhyk

So, I'm trying to have an item for list1 printed once, then the first element of item2 dictates how many items from list 3 are printed, then the next loop around, it starts where it left off. Then repeat until I run out of items from list1.. I think I have all the lists formatted right because list1 is a list of strings, list2 is a list of integers and list3 is another list of strings

prevval = 0

for i in list1:

    print(i)

    for j in list2:

        val = j

        print(list3[prevval:val])

        prevval = val   

it prints out the first x amount of items from list 3, a total of 8 times (which is how many elements are in list 2)

Sample:

list1 = ["test","please"]

list2 = [2, 4, 6]

list3 = ["hard", "to", "come", "up","with","values"]

it will print:

test

hard to

hard to

hard to

hard to come

expected would be:

test

hard to

please

come up with values

etc

For each word in list1 you want to print a slice of list3 determined by the corresponding value in list2. You can do that by zipping list1 and list2 and computing the appropriate slices:

list1 = ["test","please"]

list2 = [2, 4, 6]

list3 = ["hard", "to", "come", "up","with","values"]



prevval = 0

for w1, i in zip(list1, list2):

    print(w1)

    if prevval < len(list3): 

        print(list3[prevval:prevval + i])

        prevval += i

Output

test

['hard', 'to']

please

['come', 'up', 'with', 'values']

If you want to format the lists as a string, you can use join:

' '.join(print(list3[prevval:prevval + i]))

This will destroy list3:

list1 = ["test","please"]

list2 = [2, 4, 6]

list3 = ["hard", "to", "come", "up","with","values"]



l1_idx = 0

l2_idx = 0



while l3_idx < len(list3):

  print(list1[l1_idx])

  l1_idx += 1

  outarr = 

  for x in range(list2[l2_idx]):

    try:

      outarr.append(list3.pop(0))

    except IndexError:

      break

  print(" ".join(outarr))

  l2_idx += 1

The shortest one here:

prevval=0

for x,y in zip(list1,list2):

   print(x)

   print(' '.join(list3[prevval:prevval+y]))

   prevval+=y

The output is:

test

hard to

please

come up with values

zip them and iterate over, add prevval as usual, and remove the inner loop, that's all the changes, note that it makes it shorter (by far).

#!/bin/python



list1 = ["test","please"]

list2 = [2, 4, 6]

list3 = ["hard", "to", "come", "up","with","values"]



for i in list1:

    print(i)

    s = 

    for j in range(list2.pop(0)):

        s.append(list3.pop(0))

    print(" ".join(s))

Output:

test

hard to

please

come up with values

list1 = ['test', 'please', 'this', 'works']

list2 = [2,4,6]

list3 = tmp = ['hard', 'to', 'come', 'up', 'with', 'values', 'because', 'it', 'is', 'simple', 'with', 'python']

for index, item in enumerate(list1):

    try:

       print(tmp[:list2[index]])

       tmp = tmp[list2[index]:]

    except:

       break

prevval = 0



val=0



for i in list1:



    print(i)



    val=list2[val]



    print(list3[prevval:val])



    prevval = val