How to loop over a slice in GJSON
How to looping range or regex #[1 - 12] to display based # in Library GJSON gjson library
example like this, I have picture json in below :
enter image description here
and I have try to looping like below
tempPayments:="Envelope.Body.GetCustomReportResponse.GetCustomReportResult.ContractSummary.PaymentCalendarList.PaymentCalendar."
resultPriod1 := gjson.Get(jsonString,tempPayments + "#.Date")
for _, datePriod := range resultPriod1.Array() {
println(datePriod[1].String())
}
how to I can display result between range [1-10] ,in "#" ?
json go
add a comment |
How to looping range or regex #[1 - 12] to display based # in Library GJSON gjson library
example like this, I have picture json in below :
enter image description here
and I have try to looping like below
tempPayments:="Envelope.Body.GetCustomReportResponse.GetCustomReportResult.ContractSummary.PaymentCalendarList.PaymentCalendar."
resultPriod1 := gjson.Get(jsonString,tempPayments + "#.Date")
for _, datePriod := range resultPriod1.Array() {
println(datePriod[1].String())
}
how to I can display result between range [1-10] ,in "#" ?
json go
add a comment |
How to looping range or regex #[1 - 12] to display based # in Library GJSON gjson library
example like this, I have picture json in below :
enter image description here
and I have try to looping like below
tempPayments:="Envelope.Body.GetCustomReportResponse.GetCustomReportResult.ContractSummary.PaymentCalendarList.PaymentCalendar."
resultPriod1 := gjson.Get(jsonString,tempPayments + "#.Date")
for _, datePriod := range resultPriod1.Array() {
println(datePriod[1].String())
}
how to I can display result between range [1-10] ,in "#" ?
json go
How to looping range or regex #[1 - 12] to display based # in Library GJSON gjson library
example like this, I have picture json in below :
enter image description here
and I have try to looping like below
tempPayments:="Envelope.Body.GetCustomReportResponse.GetCustomReportResult.ContractSummary.PaymentCalendarList.PaymentCalendar."
resultPriod1 := gjson.Get(jsonString,tempPayments + "#.Date")
for _, datePriod := range resultPriod1.Array() {
println(datePriod[1].String())
}
how to I can display result between range [1-10] ,in "#" ?
json go
json go
edited Nov 21 '18 at 15:38
ssemilla
3,097525
3,097525
asked Nov 21 '18 at 4:23
testertester
117
117
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
Result.Array()
converts the current result to a slice of Result
(Result
). Hence, you can just take a slice for your desired range. e.g. resultPriod.Array()[0:12]
to get the first 12 elements.
Take this simplified version as an example:
func main() {
jsonString := `
{
"PaymentCalendarList": {
"PaymentCalendar": [
{"ContractSubmitted": 10,
"Date": "2018-01-01T01:01:01"},
{"ContractSubmitted": 20,
"Date": "2018-01-01T02:02:02"},
{"ContractSubmitted": 30,
"Date": "2018-01-01T03:03:03"}
{"ContractSubmitted": 40,
"Date": "2018-01-01T04:04:04"}
{"ContractSubmitted": 50,
"Date": "2018-01-01T05:05:05"}
]
}
}`
tempPayments := "PaymentCalendarList.PaymentCalendar."
resultPeriod := gjson.Get(jsonString, tempPayments+"#.Date")
# Take the first 3 results
for _, datePeriod := range resultPeriod.Array()[0:3] {
fmt.Println(datePeriod)
}
}
Playground
I have another problem , how to print variabel for, in outside for var datePriodGlobal string for _, DatePeriod := range resultMapPriodTest.Array()[1:13] { datePriodGlobal = fmt.Sprintln("%s", DatePeriod) } var contractsSubmittedGlobal string for _, ContractsSubmitted := range resultContractsSubmittedTest.Array()[1:13]{ contractsSubmittedGlobal =fmt.Sprintln("%s", ContractsSubmitted) } fmt.Printf("%s | %s t|",datePriodGlobal, contractsSubmittedGlobal)
– tester
Nov 21 '18 at 10:06
It would be better if you ask another question for that. The comments lacks the proper formatting to read larger amounts of code.
– ssemilla
Nov 21 '18 at 10:12
If this answer already answers your original question and you are satisfied with it, mark it as accepted and post another question.
– ssemilla
Nov 21 '18 at 10:16
add a comment |
Your Answer
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1 Answer
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1 Answer
1
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oldest
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active
oldest
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active
oldest
votes
Result.Array()
converts the current result to a slice of Result
(Result
). Hence, you can just take a slice for your desired range. e.g. resultPriod.Array()[0:12]
to get the first 12 elements.
Take this simplified version as an example:
func main() {
jsonString := `
{
"PaymentCalendarList": {
"PaymentCalendar": [
{"ContractSubmitted": 10,
"Date": "2018-01-01T01:01:01"},
{"ContractSubmitted": 20,
"Date": "2018-01-01T02:02:02"},
{"ContractSubmitted": 30,
"Date": "2018-01-01T03:03:03"}
{"ContractSubmitted": 40,
"Date": "2018-01-01T04:04:04"}
{"ContractSubmitted": 50,
"Date": "2018-01-01T05:05:05"}
]
}
}`
tempPayments := "PaymentCalendarList.PaymentCalendar."
resultPeriod := gjson.Get(jsonString, tempPayments+"#.Date")
# Take the first 3 results
for _, datePeriod := range resultPeriod.Array()[0:3] {
fmt.Println(datePeriod)
}
}
Playground
I have another problem , how to print variabel for, in outside for var datePriodGlobal string for _, DatePeriod := range resultMapPriodTest.Array()[1:13] { datePriodGlobal = fmt.Sprintln("%s", DatePeriod) } var contractsSubmittedGlobal string for _, ContractsSubmitted := range resultContractsSubmittedTest.Array()[1:13]{ contractsSubmittedGlobal =fmt.Sprintln("%s", ContractsSubmitted) } fmt.Printf("%s | %s t|",datePriodGlobal, contractsSubmittedGlobal)
– tester
Nov 21 '18 at 10:06
It would be better if you ask another question for that. The comments lacks the proper formatting to read larger amounts of code.
– ssemilla
Nov 21 '18 at 10:12
If this answer already answers your original question and you are satisfied with it, mark it as accepted and post another question.
– ssemilla
Nov 21 '18 at 10:16
add a comment |
Result.Array()
converts the current result to a slice of Result
(Result
). Hence, you can just take a slice for your desired range. e.g. resultPriod.Array()[0:12]
to get the first 12 elements.
Take this simplified version as an example:
func main() {
jsonString := `
{
"PaymentCalendarList": {
"PaymentCalendar": [
{"ContractSubmitted": 10,
"Date": "2018-01-01T01:01:01"},
{"ContractSubmitted": 20,
"Date": "2018-01-01T02:02:02"},
{"ContractSubmitted": 30,
"Date": "2018-01-01T03:03:03"}
{"ContractSubmitted": 40,
"Date": "2018-01-01T04:04:04"}
{"ContractSubmitted": 50,
"Date": "2018-01-01T05:05:05"}
]
}
}`
tempPayments := "PaymentCalendarList.PaymentCalendar."
resultPeriod := gjson.Get(jsonString, tempPayments+"#.Date")
# Take the first 3 results
for _, datePeriod := range resultPeriod.Array()[0:3] {
fmt.Println(datePeriod)
}
}
Playground
I have another problem , how to print variabel for, in outside for var datePriodGlobal string for _, DatePeriod := range resultMapPriodTest.Array()[1:13] { datePriodGlobal = fmt.Sprintln("%s", DatePeriod) } var contractsSubmittedGlobal string for _, ContractsSubmitted := range resultContractsSubmittedTest.Array()[1:13]{ contractsSubmittedGlobal =fmt.Sprintln("%s", ContractsSubmitted) } fmt.Printf("%s | %s t|",datePriodGlobal, contractsSubmittedGlobal)
– tester
Nov 21 '18 at 10:06
It would be better if you ask another question for that. The comments lacks the proper formatting to read larger amounts of code.
– ssemilla
Nov 21 '18 at 10:12
If this answer already answers your original question and you are satisfied with it, mark it as accepted and post another question.
– ssemilla
Nov 21 '18 at 10:16
add a comment |
Result.Array()
converts the current result to a slice of Result
(Result
). Hence, you can just take a slice for your desired range. e.g. resultPriod.Array()[0:12]
to get the first 12 elements.
Take this simplified version as an example:
func main() {
jsonString := `
{
"PaymentCalendarList": {
"PaymentCalendar": [
{"ContractSubmitted": 10,
"Date": "2018-01-01T01:01:01"},
{"ContractSubmitted": 20,
"Date": "2018-01-01T02:02:02"},
{"ContractSubmitted": 30,
"Date": "2018-01-01T03:03:03"}
{"ContractSubmitted": 40,
"Date": "2018-01-01T04:04:04"}
{"ContractSubmitted": 50,
"Date": "2018-01-01T05:05:05"}
]
}
}`
tempPayments := "PaymentCalendarList.PaymentCalendar."
resultPeriod := gjson.Get(jsonString, tempPayments+"#.Date")
# Take the first 3 results
for _, datePeriod := range resultPeriod.Array()[0:3] {
fmt.Println(datePeriod)
}
}
Playground
Result.Array()
converts the current result to a slice of Result
(Result
). Hence, you can just take a slice for your desired range. e.g. resultPriod.Array()[0:12]
to get the first 12 elements.
Take this simplified version as an example:
func main() {
jsonString := `
{
"PaymentCalendarList": {
"PaymentCalendar": [
{"ContractSubmitted": 10,
"Date": "2018-01-01T01:01:01"},
{"ContractSubmitted": 20,
"Date": "2018-01-01T02:02:02"},
{"ContractSubmitted": 30,
"Date": "2018-01-01T03:03:03"}
{"ContractSubmitted": 40,
"Date": "2018-01-01T04:04:04"}
{"ContractSubmitted": 50,
"Date": "2018-01-01T05:05:05"}
]
}
}`
tempPayments := "PaymentCalendarList.PaymentCalendar."
resultPeriod := gjson.Get(jsonString, tempPayments+"#.Date")
# Take the first 3 results
for _, datePeriod := range resultPeriod.Array()[0:3] {
fmt.Println(datePeriod)
}
}
Playground
edited Nov 21 '18 at 15:33
answered Nov 21 '18 at 8:15
ssemillassemilla
3,097525
3,097525
I have another problem , how to print variabel for, in outside for var datePriodGlobal string for _, DatePeriod := range resultMapPriodTest.Array()[1:13] { datePriodGlobal = fmt.Sprintln("%s", DatePeriod) } var contractsSubmittedGlobal string for _, ContractsSubmitted := range resultContractsSubmittedTest.Array()[1:13]{ contractsSubmittedGlobal =fmt.Sprintln("%s", ContractsSubmitted) } fmt.Printf("%s | %s t|",datePriodGlobal, contractsSubmittedGlobal)
– tester
Nov 21 '18 at 10:06
It would be better if you ask another question for that. The comments lacks the proper formatting to read larger amounts of code.
– ssemilla
Nov 21 '18 at 10:12
If this answer already answers your original question and you are satisfied with it, mark it as accepted and post another question.
– ssemilla
Nov 21 '18 at 10:16
add a comment |
I have another problem , how to print variabel for, in outside for var datePriodGlobal string for _, DatePeriod := range resultMapPriodTest.Array()[1:13] { datePriodGlobal = fmt.Sprintln("%s", DatePeriod) } var contractsSubmittedGlobal string for _, ContractsSubmitted := range resultContractsSubmittedTest.Array()[1:13]{ contractsSubmittedGlobal =fmt.Sprintln("%s", ContractsSubmitted) } fmt.Printf("%s | %s t|",datePriodGlobal, contractsSubmittedGlobal)
– tester
Nov 21 '18 at 10:06
It would be better if you ask another question for that. The comments lacks the proper formatting to read larger amounts of code.
– ssemilla
Nov 21 '18 at 10:12
If this answer already answers your original question and you are satisfied with it, mark it as accepted and post another question.
– ssemilla
Nov 21 '18 at 10:16
I have another problem , how to print variabel for, in outside for var datePriodGlobal string for _, DatePeriod := range resultMapPriodTest.Array()[1:13] { datePriodGlobal = fmt.Sprintln("%s", DatePeriod) } var contractsSubmittedGlobal string for _, ContractsSubmitted := range resultContractsSubmittedTest.Array()[1:13]{ contractsSubmittedGlobal =fmt.Sprintln("%s", ContractsSubmitted) } fmt.Printf("%s | %s t|",datePriodGlobal, contractsSubmittedGlobal)
– tester
Nov 21 '18 at 10:06
I have another problem , how to print variabel for, in outside for var datePriodGlobal string for _, DatePeriod := range resultMapPriodTest.Array()[1:13] { datePriodGlobal = fmt.Sprintln("%s", DatePeriod) } var contractsSubmittedGlobal string for _, ContractsSubmitted := range resultContractsSubmittedTest.Array()[1:13]{ contractsSubmittedGlobal =fmt.Sprintln("%s", ContractsSubmitted) } fmt.Printf("%s | %s t|",datePriodGlobal, contractsSubmittedGlobal)
– tester
Nov 21 '18 at 10:06
It would be better if you ask another question for that. The comments lacks the proper formatting to read larger amounts of code.
– ssemilla
Nov 21 '18 at 10:12
It would be better if you ask another question for that. The comments lacks the proper formatting to read larger amounts of code.
– ssemilla
Nov 21 '18 at 10:12
If this answer already answers your original question and you are satisfied with it, mark it as accepted and post another question.
– ssemilla
Nov 21 '18 at 10:16
If this answer already answers your original question and you are satisfied with it, mark it as accepted and post another question.
– ssemilla
Nov 21 '18 at 10:16
add a comment |
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