rainfall seasonality index in R
This is probably a more general question of how to code equations in R, but I'll apply the concept to what's been on my to-do list. We are examining the rainfall seasonality of a monthly time series of rainfall, which measures how one month in a given year rainfall differs than if each month received 1/12 of the annual rainfall. The equation can be found here: http://leddris.aegean.gr/ses-parameters/293-rainfall-seasonality.html but re-written here: rainfall seasonality
Where Si is the annual seasonality index, Ri is the total annual precipitation for the particular year under study and Xin is the actual monthly precipitation for month n.
Our data has the below structure and continues monthly through water year 2014
head(monthlyRain)
MonthofYr WaterYear monthlyRain
1 1983 289.2
2 1983 150.8
3 1983 134.3
4 1983 16.1
5 1983 490.3
6 1983 328.9
As mentioned above, this is a more general question about how to solve slightly complex equations in R, using an example I have at hand. Let me know if this cross-posted or if there are other links to solve without being redundant here. Thanks!
r equation
asked Nov 21 '18 at 2:30
Nick MarzolfNick Marzolf
62
add a comment |
This is probably a more general question of how to code equations in R, but I'll apply the concept to what's been on my to-do list. We are examining the rainfall seasonality of a monthly time series of rainfall, which measures how one month in a given year rainfall differs than if each month received 1/12 of the annual rainfall. The equation can be found here: http://leddris.aegean.gr/ses-parameters/293-rainfall-seasonality.html but re-written here: rainfall seasonality
Where Si is the annual seasonality index, Ri is the total annual precipitation for the particular year under study and Xin is the actual monthly precipitation for month n.
Our data has the below structure and continues monthly through water year 2014
head(monthlyRain)
MonthofYr WaterYear monthlyRain
1 1983 289.2
2 1983 150.8
3 1983 134.3
4 1983 16.1
5 1983 490.3
6 1983 328.9
As mentioned above, this is a more general question about how to solve slightly complex equations in R, using an example I have at hand. Let me know if this cross-posted or if there are other links to solve without being redundant here. Thanks!
r equation
asked Nov 21 '18 at 2:30
Nick MarzolfNick Marzolf
62
add a comment |
This is probably a more general question of how to code equations in R, but I'll apply the concept to what's been on my to-do list. We are examining the rainfall seasonality of a monthly time series of rainfall, which measures how one month in a given year rainfall differs than if each month received 1/12 of the annual rainfall. The equation can be found here: http://leddris.aegean.gr/ses-parameters/293-rainfall-seasonality.html but re-written here: rainfall seasonality
Where Si is the annual seasonality index, Ri is the total annual precipitation for the particular year under study and Xin is the actual monthly precipitation for month n.
Our data has the below structure and continues monthly through water year 2014
head(monthlyRain)
MonthofYr WaterYear monthlyRain
1 1983 289.2
2 1983 150.8
3 1983 134.3
4 1983 16.1
5 1983 490.3
6 1983 328.9
As mentioned above, this is a more general question about how to solve slightly complex equations in R, using an example I have at hand. Let me know if this cross-posted or if there are other links to solve without being redundant here. Thanks!
r equation
asked Nov 21 '18 at 2:30
Nick MarzolfNick Marzolf
62
This is probably a more general question of how to code equations in R, but I'll apply the concept to what's been on my to-do list. We are examining the rainfall seasonality of a monthly time series of rainfall, which measures how one month in a given year rainfall differs than if each month received 1/12 of the annual rainfall. The equation can be found here: http://leddris.aegean.gr/ses-parameters/293-rainfall-seasonality.html but re-written here: rainfall seasonality
Where Si is the annual seasonality index, Ri is the total annual precipitation for the particular year under study and Xin is the actual monthly precipitation for month n.
Our data has the below structure and continues monthly through water year 2014
head(monthlyRain)
MonthofYr WaterYear monthlyRain
1 1983 289.2
2 1983 150.8
3 1983 134.3
4 1983 16.1
5 1983 490.3
6 1983 328.9
As mentioned above, this is a more general question about how to solve slightly complex equations in R, using an example I have at hand. Let me know if this cross-posted or if there are other links to solve without being redundant here. Thanks!
r equation
r equation
asked Nov 21 '18 at 2:30
Nick MarzolfNick Marzolf
62
asked Nov 21 '18 at 2:30
Nick MarzolfNick Marzolf
62
asked Nov 21 '18 at 2:30
Nick MarzolfNick Marzolf
62
asked Nov 21 '18 at 2:30
Nick MarzolfNick Marzolf
62
asked Nov 21 '18 at 2:30
Nick MarzolfNick Marzolf
62
62
add a comment |
add a comment |
1 Answer
1
active
oldest
votes
If you are interested in understanding seasonality, monthplot and/or stl functions are good options in R.
https://www.rdocumentation.org/packages/stats/versions/3.5.1/topics/monthplot
https://otexts.org/fpp2/seasonal-subseries-plots.html
answered Nov 21 '18 at 4:47
Prasanna SPrasanna S
806
add a comment |
Your Answer
StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53404507%2frainfall-seasonality-index-in-r%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
If you are interested in understanding seasonality, monthplot and/or stl functions are good options in R.
https://www.rdocumentation.org/packages/stats/versions/3.5.1/topics/monthplot
https://otexts.org/fpp2/seasonal-subseries-plots.html
answered Nov 21 '18 at 4:47
Prasanna SPrasanna S
806
add a comment |
If you are interested in understanding seasonality, monthplot and/or stl functions are good options in R.
https://www.rdocumentation.org/packages/stats/versions/3.5.1/topics/monthplot
https://otexts.org/fpp2/seasonal-subseries-plots.html
answered Nov 21 '18 at 4:47
Prasanna SPrasanna S
806
add a comment |
If you are interested in understanding seasonality, monthplot and/or stl functions are good options in R.
https://www.rdocumentation.org/packages/stats/versions/3.5.1/topics/monthplot
https://otexts.org/fpp2/seasonal-subseries-plots.html
answered Nov 21 '18 at 4:47
Prasanna SPrasanna S
806
If you are interested in understanding seasonality, monthplot and/or stl functions are good options in R.
https://www.rdocumentation.org/packages/stats/versions/3.5.1/topics/monthplot
https://otexts.org/fpp2/seasonal-subseries-plots.html
answered Nov 21 '18 at 4:47
Prasanna SPrasanna S
806
answered Nov 21 '18 at 4:47
Prasanna SPrasanna S
806
answered Nov 21 '18 at 4:47
Prasanna SPrasanna S
806
answered Nov 21 '18 at 4:47
Prasanna SPrasanna S
806
806
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53404507%2frainfall-seasonality-index-in-r%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
