using Spring property when initializing a class [duplicate]












0
















This question already has an answer here:




  • Spring @Autowired and @Value on property not working

    3 answers



  • Property values in bean class are null in constructor

    2 answers




The following produces a null error ("A" is null), but I am not sure why. Is the bean instantiated before the property value is set?



package org.ets.readtogether.queuing;

import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;

@Component("Abean")
public class Test {

@Value("${send.timeout.secs}")
public Integer A;

public int B = A * 1000;
}









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marked as duplicate by Sotirios Delimanolis java
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Nov 21 '18 at 15:03


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.



















  • Well yeah, how do you set a field without there being an object?

    – Sotirios Delimanolis
    Nov 21 '18 at 14:53











  • You can also use SpEL in the @Value annotation: @Value("#{systemProperties['send.timeout.secs'] * 1000}")

    – daniu
    Nov 21 '18 at 15:07


















0
















This question already has an answer here:




  • Spring @Autowired and @Value on property not working

    3 answers



  • Property values in bean class are null in constructor

    2 answers




The following produces a null error ("A" is null), but I am not sure why. Is the bean instantiated before the property value is set?



package org.ets.readtogether.queuing;

import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;

@Component("Abean")
public class Test {

@Value("${send.timeout.secs}")
public Integer A;

public int B = A * 1000;
}









share|improve this question













marked as duplicate by Sotirios Delimanolis java
Users with the  java badge can single-handedly close java questions as duplicates and reopen them as needed.

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Nov 21 '18 at 15:03


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.



















  • Well yeah, how do you set a field without there being an object?

    – Sotirios Delimanolis
    Nov 21 '18 at 14:53











  • You can also use SpEL in the @Value annotation: @Value("#{systemProperties['send.timeout.secs'] * 1000}")

    – daniu
    Nov 21 '18 at 15:07
















0












0








0









This question already has an answer here:




  • Spring @Autowired and @Value on property not working

    3 answers



  • Property values in bean class are null in constructor

    2 answers




The following produces a null error ("A" is null), but I am not sure why. Is the bean instantiated before the property value is set?



package org.ets.readtogether.queuing;

import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;

@Component("Abean")
public class Test {

@Value("${send.timeout.secs}")
public Integer A;

public int B = A * 1000;
}









share|improve this question















This question already has an answer here:




  • Spring @Autowired and @Value on property not working

    3 answers



  • Property values in bean class are null in constructor

    2 answers




The following produces a null error ("A" is null), but I am not sure why. Is the bean instantiated before the property value is set?



package org.ets.readtogether.queuing;

import org.springframework.beans.factory.annotation.Value;
import org.springframework.stereotype.Component;

@Component("Abean")
public class Test {

@Value("${send.timeout.secs}")
public Integer A;

public int B = A * 1000;
}




This question already has an answer here:




  • Spring @Autowired and @Value on property not working

    3 answers



  • Property values in bean class are null in constructor

    2 answers








java spring






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asked Nov 21 '18 at 14:52









Mr. MundkowskyMr. Mundkowsky

424




424




marked as duplicate by Sotirios Delimanolis java
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Nov 21 '18 at 15:03


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marked as duplicate by Sotirios Delimanolis java
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Nov 21 '18 at 15:03


This question has been asked before and already has an answer. If those answers do not fully address your question, please ask a new question.















  • Well yeah, how do you set a field without there being an object?

    – Sotirios Delimanolis
    Nov 21 '18 at 14:53











  • You can also use SpEL in the @Value annotation: @Value("#{systemProperties['send.timeout.secs'] * 1000}")

    – daniu
    Nov 21 '18 at 15:07





















  • Well yeah, how do you set a field without there being an object?

    – Sotirios Delimanolis
    Nov 21 '18 at 14:53











  • You can also use SpEL in the @Value annotation: @Value("#{systemProperties['send.timeout.secs'] * 1000}")

    – daniu
    Nov 21 '18 at 15:07



















Well yeah, how do you set a field without there being an object?

– Sotirios Delimanolis
Nov 21 '18 at 14:53





Well yeah, how do you set a field without there being an object?

– Sotirios Delimanolis
Nov 21 '18 at 14:53













You can also use SpEL in the @Value annotation: @Value("#{systemProperties['send.timeout.secs'] * 1000}")

– daniu
Nov 21 '18 at 15:07







You can also use SpEL in the @Value annotation: @Value("#{systemProperties['send.timeout.secs'] * 1000}")

– daniu
Nov 21 '18 at 15:07














2 Answers
2






active

oldest

votes


















1














Spring adds all the dependencies injected in an object after instantiating it. Object instantiation precedes any @Autowired dependency injection or @Value value assignment done by Spring.



The instantiation of your class's object fails even before Spring has the object to inject dependencies because the statement public int B = A * 1000; is called during object instantiation.



In order to assign the variable B a value after Spring has finished all injections, perform the operation in either a @PostConstruct method or in an @AutoWired constructor.



   public int B; // remove the assignment here.

@PostConstruct
public void postConstruct () {
this.B = A * 1000;
}


The above method would be called after the object has been instantiated and after Spring has done its work.






share|improve this answer































    1














    Try this:



    @Component("Abean")
    public class Test {

    @Value("${send.timeout.secs}")
    public Integer A;

    public int B;

    @PostConstruct
    public void init() {
    B = A * 1000;
    }
    }


    Good example here






    share|improve this answer
































      2 Answers
      2






      active

      oldest

      votes








      2 Answers
      2






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      1














      Spring adds all the dependencies injected in an object after instantiating it. Object instantiation precedes any @Autowired dependency injection or @Value value assignment done by Spring.



      The instantiation of your class's object fails even before Spring has the object to inject dependencies because the statement public int B = A * 1000; is called during object instantiation.



      In order to assign the variable B a value after Spring has finished all injections, perform the operation in either a @PostConstruct method or in an @AutoWired constructor.



         public int B; // remove the assignment here.

      @PostConstruct
      public void postConstruct () {
      this.B = A * 1000;
      }


      The above method would be called after the object has been instantiated and after Spring has done its work.






      share|improve this answer




























        1














        Spring adds all the dependencies injected in an object after instantiating it. Object instantiation precedes any @Autowired dependency injection or @Value value assignment done by Spring.



        The instantiation of your class's object fails even before Spring has the object to inject dependencies because the statement public int B = A * 1000; is called during object instantiation.



        In order to assign the variable B a value after Spring has finished all injections, perform the operation in either a @PostConstruct method or in an @AutoWired constructor.



           public int B; // remove the assignment here.

        @PostConstruct
        public void postConstruct () {
        this.B = A * 1000;
        }


        The above method would be called after the object has been instantiated and after Spring has done its work.






        share|improve this answer


























          1












          1








          1







          Spring adds all the dependencies injected in an object after instantiating it. Object instantiation precedes any @Autowired dependency injection or @Value value assignment done by Spring.



          The instantiation of your class's object fails even before Spring has the object to inject dependencies because the statement public int B = A * 1000; is called during object instantiation.



          In order to assign the variable B a value after Spring has finished all injections, perform the operation in either a @PostConstruct method or in an @AutoWired constructor.



             public int B; // remove the assignment here.

          @PostConstruct
          public void postConstruct () {
          this.B = A * 1000;
          }


          The above method would be called after the object has been instantiated and after Spring has done its work.






          share|improve this answer













          Spring adds all the dependencies injected in an object after instantiating it. Object instantiation precedes any @Autowired dependency injection or @Value value assignment done by Spring.



          The instantiation of your class's object fails even before Spring has the object to inject dependencies because the statement public int B = A * 1000; is called during object instantiation.



          In order to assign the variable B a value after Spring has finished all injections, perform the operation in either a @PostConstruct method or in an @AutoWired constructor.



             public int B; // remove the assignment here.

          @PostConstruct
          public void postConstruct () {
          this.B = A * 1000;
          }


          The above method would be called after the object has been instantiated and after Spring has done its work.







          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered Nov 21 '18 at 15:03









          PranjalPranjal

          1363




          1363

























              1














              Try this:



              @Component("Abean")
              public class Test {

              @Value("${send.timeout.secs}")
              public Integer A;

              public int B;

              @PostConstruct
              public void init() {
              B = A * 1000;
              }
              }


              Good example here






              share|improve this answer






























                1














                Try this:



                @Component("Abean")
                public class Test {

                @Value("${send.timeout.secs}")
                public Integer A;

                public int B;

                @PostConstruct
                public void init() {
                B = A * 1000;
                }
                }


                Good example here






                share|improve this answer




























                  1












                  1








                  1







                  Try this:



                  @Component("Abean")
                  public class Test {

                  @Value("${send.timeout.secs}")
                  public Integer A;

                  public int B;

                  @PostConstruct
                  public void init() {
                  B = A * 1000;
                  }
                  }


                  Good example here






                  share|improve this answer















                  Try this:



                  @Component("Abean")
                  public class Test {

                  @Value("${send.timeout.secs}")
                  public Integer A;

                  public int B;

                  @PostConstruct
                  public void init() {
                  B = A * 1000;
                  }
                  }


                  Good example here







                  share|improve this answer














                  share|improve this answer



                  share|improve this answer








                  edited Nov 21 '18 at 15:05

























                  answered Nov 21 '18 at 14:55









                  Essex BoyEssex Boy

                  4,7531816




                  4,7531816















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