Why substring “com.” in GoogleScript convert to “(class)”
Today, the Google script has stopped representing the line normally.
In case of occurrence of a line "com." or "org." - substring is replaced by a certain class "(class)". How to fix the problem?
function myFunction2() {
var t = "testcom.io";
t = t + '1';
t=t;
}
screenshot from editor https://i.stack.imgur.com/hldbz.png
The logger shows the result as well as you do. But during the debugging, the value of the variable T changes. Because of this error, URL Feth does not work. A full script was written a few months ago and worked until today.
You can look error on the next screenshot. We have var url = 'api.intercom.io';; When we try run function we see
error 406
and message where var url is changed to api.intercom.io';. In case of occurrence of a line "com." or "org." - substring is replaced by a certain class "(class)" or symbols .
function myFunction3() {
var url = 'https://api.intercom.io';
var response = UrlFetchApp.fetch(url,options);
Logger.log(response.getContentText());
}
look at screenshot
google-apps-script http-status-code-406 intercom
add a comment |
Today, the Google script has stopped representing the line normally.
In case of occurrence of a line "com." or "org." - substring is replaced by a certain class "(class)". How to fix the problem?
function myFunction2() {
var t = "testcom.io";
t = t + '1';
t=t;
}
screenshot from editor https://i.stack.imgur.com/hldbz.png
The logger shows the result as well as you do. But during the debugging, the value of the variable T changes. Because of this error, URL Feth does not work. A full script was written a few months ago and worked until today.
You can look error on the next screenshot. We have var url = 'api.intercom.io';; When we try run function we see
error 406
and message where var url is changed to api.intercom.io';. In case of occurrence of a line "com." or "org." - substring is replaced by a certain class "(class)" or symbols .
function myFunction3() {
var url = 'https://api.intercom.io';
var response = UrlFetchApp.fetch(url,options);
Logger.log(response.getContentText());
}
look at screenshot
google-apps-script http-status-code-406 intercom
1
Kindly fix your code typo and provide code where you're using the substring
– Mohammad Umair
Mar 14 '18 at 9:09
My bad, thx, done
– Сергей Дорошенко
Mar 14 '18 at 9:11
Possible duplicate of Google App Script external API return error 406
– TheMaster
Nov 21 '18 at 15:00
add a comment |
Today, the Google script has stopped representing the line normally.
In case of occurrence of a line "com." or "org." - substring is replaced by a certain class "(class)". How to fix the problem?
function myFunction2() {
var t = "testcom.io";
t = t + '1';
t=t;
}
screenshot from editor https://i.stack.imgur.com/hldbz.png
The logger shows the result as well as you do. But during the debugging, the value of the variable T changes. Because of this error, URL Feth does not work. A full script was written a few months ago and worked until today.
You can look error on the next screenshot. We have var url = 'api.intercom.io';; When we try run function we see
error 406
and message where var url is changed to api.intercom.io';. In case of occurrence of a line "com." or "org." - substring is replaced by a certain class "(class)" or symbols .
function myFunction3() {
var url = 'https://api.intercom.io';
var response = UrlFetchApp.fetch(url,options);
Logger.log(response.getContentText());
}
look at screenshot
google-apps-script http-status-code-406 intercom
Today, the Google script has stopped representing the line normally.
In case of occurrence of a line "com." or "org." - substring is replaced by a certain class "(class)". How to fix the problem?
function myFunction2() {
var t = "testcom.io";
t = t + '1';
t=t;
}
screenshot from editor https://i.stack.imgur.com/hldbz.png
The logger shows the result as well as you do. But during the debugging, the value of the variable T changes. Because of this error, URL Feth does not work. A full script was written a few months ago and worked until today.
You can look error on the next screenshot. We have var url = 'api.intercom.io';; When we try run function we see
error 406
and message where var url is changed to api.intercom.io';. In case of occurrence of a line "com." or "org." - substring is replaced by a certain class "(class)" or symbols .
function myFunction3() {
var url = 'https://api.intercom.io';
var response = UrlFetchApp.fetch(url,options);
Logger.log(response.getContentText());
}
look at screenshot
google-apps-script http-status-code-406 intercom
google-apps-script http-status-code-406 intercom
edited Nov 21 '18 at 14:56
TheMaster
10.6k3936
10.6k3936
asked Mar 14 '18 at 9:06
Сергей ДорошенкоСергей Дорошенко
62
62
1
Kindly fix your code typo and provide code where you're using the substring
– Mohammad Umair
Mar 14 '18 at 9:09
My bad, thx, done
– Сергей Дорошенко
Mar 14 '18 at 9:11
Possible duplicate of Google App Script external API return error 406
– TheMaster
Nov 21 '18 at 15:00
add a comment |
1
Kindly fix your code typo and provide code where you're using the substring
– Mohammad Umair
Mar 14 '18 at 9:09
My bad, thx, done
– Сергей Дорошенко
Mar 14 '18 at 9:11
Possible duplicate of Google App Script external API return error 406
– TheMaster
Nov 21 '18 at 15:00
1
1
Kindly fix your code typo and provide code where you're using the substring
– Mohammad Umair
Mar 14 '18 at 9:09
Kindly fix your code typo and provide code where you're using the substring
– Mohammad Umair
Mar 14 '18 at 9:09
My bad, thx, done
– Сергей Дорошенко
Mar 14 '18 at 9:11
My bad, thx, done
– Сергей Дорошенко
Mar 14 '18 at 9:11
Possible duplicate of Google App Script external API return error 406
– TheMaster
Nov 21 '18 at 15:00
Possible duplicate of Google App Script external API return error 406
– TheMaster
Nov 21 '18 at 15:00
add a comment |
1 Answer
1
active
oldest
votes
I think that test(class)
is not the value of t
rather that's the class to which this particular t variable belongs.
You can turn your function into something like this :
Then check the log to see value of t
Let me know if you need anymore help.
add a comment |
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1 Answer
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1 Answer
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active
oldest
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oldest
votes
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oldest
votes
I think that test(class)
is not the value of t
rather that's the class to which this particular t variable belongs.
You can turn your function into something like this :
Then check the log to see value of t
Let me know if you need anymore help.
add a comment |
I think that test(class)
is not the value of t
rather that's the class to which this particular t variable belongs.
You can turn your function into something like this :
Then check the log to see value of t
Let me know if you need anymore help.
add a comment |
I think that test(class)
is not the value of t
rather that's the class to which this particular t variable belongs.
You can turn your function into something like this :
Then check the log to see value of t
Let me know if you need anymore help.
I think that test(class)
is not the value of t
rather that's the class to which this particular t variable belongs.
You can turn your function into something like this :
Then check the log to see value of t
Let me know if you need anymore help.
answered Mar 14 '18 at 9:17
Mohammad UmairMohammad Umair
2,1931721
2,1931721
add a comment |
add a comment |
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1
Kindly fix your code typo and provide code where you're using the substring
– Mohammad Umair
Mar 14 '18 at 9:09
My bad, thx, done
– Сергей Дорошенко
Mar 14 '18 at 9:11
Possible duplicate of Google App Script external API return error 406
– TheMaster
Nov 21 '18 at 15:00