How to convert an array has special structure into an array of key-value pairs using PHP?
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-3
This is the source of what i am trying to do:
- source: a11993b18486c13240388
- What i vae done so far:
$array = preg_split("/(,?s+)|((?<=[a-z])(?=d))|((?<=d)(?=[a-z]))/i", $ref);
I am trying to convert the resulting $array into an object:
[
"a",
"11993",
"b",
"18486",
"c",
"13240388"
]
by grouping by 2 where first item is key and second is value:
Following is my desired outcome:
{
"a"=>"11993",
"b"=>"18486",
"c"=>"13240388"
}
Maybe there is even a better way to do that?
I would appreciate if someone kindly guide me about that.
php arrays regex
edited Nov 22 '18 at 13:45
Mohammad
16.1k123766
asked Nov 22 '18 at 13:23
jhon danojhon dano
315118
add a comment |
-3
This is the source of what i am trying to do:
- source: a11993b18486c13240388
- What i vae done so far:
$array = preg_split("/(,?s+)|((?<=[a-z])(?=d))|((?<=d)(?=[a-z]))/i", $ref);
I am trying to convert the resulting $array into an object:
[
"a",
"11993",
"b",
"18486",
"c",
"13240388"
]
by grouping by 2 where first item is key and second is value:
Following is my desired outcome:
{
"a"=>"11993",
"b"=>"18486",
"c"=>"13240388"
}
Maybe there is even a better way to do that?
I would appreciate if someone kindly guide me about that.
php arrays regex
edited Nov 22 '18 at 13:45
Mohammad
16.1k123766
asked Nov 22 '18 at 13:23
jhon danojhon dano
315118
add a comment |
-3
-3
-3
0
This is the source of what i am trying to do:
- source: a11993b18486c13240388
- What i vae done so far:
$array = preg_split("/(,?s+)|((?<=[a-z])(?=d))|((?<=d)(?=[a-z]))/i", $ref);
I am trying to convert the resulting $array into an object:
[
"a",
"11993",
"b",
"18486",
"c",
"13240388"
]
by grouping by 2 where first item is key and second is value:
Following is my desired outcome:
{
"a"=>"11993",
"b"=>"18486",
"c"=>"13240388"
}
Maybe there is even a better way to do that?
I would appreciate if someone kindly guide me about that.
php arrays regex
edited Nov 22 '18 at 13:45
Mohammad
16.1k123766
asked Nov 22 '18 at 13:23
jhon danojhon dano
315118
This is the source of what i am trying to do:
- source: a11993b18486c13240388
- What i vae done so far:
$array = preg_split("/(,?s+)|((?<=[a-z])(?=d))|((?<=d)(?=[a-z]))/i", $ref);
I am trying to convert the resulting $array into an object:
[
"a",
"11993",
"b",
"18486",
"c",
"13240388"
]
by grouping by 2 where first item is key and second is value:
Following is my desired outcome:
{
"a"=>"11993",
"b"=>"18486",
"c"=>"13240388"
}
Maybe there is even a better way to do that?
I would appreciate if someone kindly guide me about that.
php arrays regex
php arrays regex
edited Nov 22 '18 at 13:45
Mohammad
16.1k123766
asked Nov 22 '18 at 13:23
jhon danojhon dano
315118
edited Nov 22 '18 at 13:45
Mohammad
16.1k123766
asked Nov 22 '18 at 13:23
jhon danojhon dano
315118
edited Nov 22 '18 at 13:45
Mohammad
16.1k123766
edited Nov 22 '18 at 13:45
Mohammad
16.1k123766
edited Nov 22 '18 at 13:45
Mohammad
16.1k123766
16.1k123766
asked Nov 22 '18 at 13:23
jhon danojhon dano
315118
asked Nov 22 '18 at 13:23
jhon danojhon dano
315118
asked Nov 22 '18 at 13:23
jhon danojhon dano
315118
315118
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
1
You need to loop through array using for and in loop add values to new array.
$newArr = ;
for ($i=0; $i<count($arr); $i+=2)
$newArr[$arr[$i]] = $arr[$i+1];
Result
Array
(
[a] => 11993
[b] => 18486
[c] => 13240388
)
Check result in demo
Also if you want to do this using regex on string use
$ref = "a11993b18486c13240388";
preg_match_all("/([a-z])(d+)/i", $ref, $matches);
$newArr = array_combine($matches[1], $matches[2]);
Check result in demo
answered Nov 22 '18 at 13:28
MohammadMohammad
16.1k123766
this worked perfect, thanks! I was wondering if the same can be achieved through the regular expression so i can reduce it to just one line of code?
– jhon dano
Nov 22 '18 at 13:37
@jhondano Your content is in array but regex work on string. You should convert array to string and run regex and prepare target structure that cause write multiple line of code
– Mohammad
Nov 22 '18 at 13:41
i understand that but as you see in my question the source is string: a11993b18486c13240388, this needs to be split and grouped according to your example with for. Any idea how?
– jhon dano
Nov 22 '18 at 13:43
@jhondano Check update
– Mohammad
Nov 22 '18 at 13:49
add a comment |
0
try following :
$list = array(
"a",
"11993",
"b",
"18486",
"c",
"13240388"
);
$new_list = array();
for($i=0;$i<count($list);$i=$i+2) {
$new_list[$list[$i]] = $list[$i+1];
}
echo '<pre>'; print_r($new_list); echo '</pre>';
answered Nov 22 '18 at 13:32
Manoj SinghManoj Singh
23016
This is exact duplicate of my answer.
– Mohammad
Nov 22 '18 at 13:34
yes but seen after posting answer
– Manoj Singh
Nov 22 '18 at 13:36
add a comment |
0
i hope answer to your question is this, because you are looking for object:-
$arr=[
"a",
"11993",
"b",
"18486",
"c",
"13240388"
];
$arrForObj = ;
for ($i=0; $i<count($arr); $i+=2){
$arrForObj[$arr[$i]] = $arr[$i+1];
}
$obj=(object)$arrForObj;
echo "<pre>";
var_dump($obj);
answered Nov 22 '18 at 13:38
Parvej AlamParvej Alam
24118
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
1
You need to loop through array using for and in loop add values to new array.
$newArr = ;
for ($i=0; $i<count($arr); $i+=2)
$newArr[$arr[$i]] = $arr[$i+1];
Result
Array
(
[a] => 11993
[b] => 18486
[c] => 13240388
)
Check result in demo
Also if you want to do this using regex on string use
$ref = "a11993b18486c13240388";
preg_match_all("/([a-z])(d+)/i", $ref, $matches);
$newArr = array_combine($matches[1], $matches[2]);
Check result in demo
answered Nov 22 '18 at 13:28
MohammadMohammad
16.1k123766
this worked perfect, thanks! I was wondering if the same can be achieved through the regular expression so i can reduce it to just one line of code?
– jhon dano
Nov 22 '18 at 13:37
@jhondano Your content is in array but regex work on string. You should convert array to string and run regex and prepare target structure that cause write multiple line of code
– Mohammad
Nov 22 '18 at 13:41
i understand that but as you see in my question the source is string: a11993b18486c13240388, this needs to be split and grouped according to your example with for. Any idea how?
– jhon dano
Nov 22 '18 at 13:43
@jhondano Check update
– Mohammad
Nov 22 '18 at 13:49
add a comment |
1
You need to loop through array using for and in loop add values to new array.
$newArr = ;
for ($i=0; $i<count($arr); $i+=2)
$newArr[$arr[$i]] = $arr[$i+1];
Result
Array
(
[a] => 11993
[b] => 18486
[c] => 13240388
)
Check result in demo
Also if you want to do this using regex on string use
$ref = "a11993b18486c13240388";
preg_match_all("/([a-z])(d+)/i", $ref, $matches);
$newArr = array_combine($matches[1], $matches[2]);
Check result in demo
answered Nov 22 '18 at 13:28
MohammadMohammad
16.1k123766
this worked perfect, thanks! I was wondering if the same can be achieved through the regular expression so i can reduce it to just one line of code?
– jhon dano
Nov 22 '18 at 13:37
@jhondano Your content is in array but regex work on string. You should convert array to string and run regex and prepare target structure that cause write multiple line of code
– Mohammad
Nov 22 '18 at 13:41
i understand that but as you see in my question the source is string: a11993b18486c13240388, this needs to be split and grouped according to your example with for. Any idea how?
– jhon dano
Nov 22 '18 at 13:43
@jhondano Check update
– Mohammad
Nov 22 '18 at 13:49
add a comment |
1
1
1
You need to loop through array using for and in loop add values to new array.
$newArr = ;
for ($i=0; $i<count($arr); $i+=2)
$newArr[$arr[$i]] = $arr[$i+1];
Result
Array
(
[a] => 11993
[b] => 18486
[c] => 13240388
)
Check result in demo
Also if you want to do this using regex on string use
$ref = "a11993b18486c13240388";
preg_match_all("/([a-z])(d+)/i", $ref, $matches);
$newArr = array_combine($matches[1], $matches[2]);
Check result in demo
answered Nov 22 '18 at 13:28
MohammadMohammad
16.1k123766
You need to loop through array using for and in loop add values to new array.
$newArr = ;
for ($i=0; $i<count($arr); $i+=2)
$newArr[$arr[$i]] = $arr[$i+1];
Result
Array
(
[a] => 11993
[b] => 18486
[c] => 13240388
)
Check result in demo
Also if you want to do this using regex on string use
$ref = "a11993b18486c13240388";
preg_match_all("/([a-z])(d+)/i", $ref, $matches);
$newArr = array_combine($matches[1], $matches[2]);
Check result in demo
answered Nov 22 '18 at 13:28
MohammadMohammad
16.1k123766
edited Nov 22 '18 at 13:49
answered Nov 22 '18 at 13:28
MohammadMohammad
16.1k123766
answered Nov 22 '18 at 13:28
MohammadMohammad
16.1k123766
answered Nov 22 '18 at 13:28
MohammadMohammad
16.1k123766
16.1k123766
this worked perfect, thanks! I was wondering if the same can be achieved through the regular expression so i can reduce it to just one line of code?
– jhon dano
Nov 22 '18 at 13:37
@jhondano Your content is in array but regex work on string. You should convert array to string and run regex and prepare target structure that cause write multiple line of code
– Mohammad
Nov 22 '18 at 13:41
i understand that but as you see in my question the source is string: a11993b18486c13240388, this needs to be split and grouped according to your example with for. Any idea how?
– jhon dano
Nov 22 '18 at 13:43
@jhondano Check update
– Mohammad
Nov 22 '18 at 13:49
add a comment |
this worked perfect, thanks! I was wondering if the same can be achieved through the regular expression so i can reduce it to just one line of code?
– jhon dano
Nov 22 '18 at 13:37
@jhondano Your content is in array but regex work on string. You should convert array to string and run regex and prepare target structure that cause write multiple line of code
– Mohammad
Nov 22 '18 at 13:41
i understand that but as you see in my question the source is string: a11993b18486c13240388, this needs to be split and grouped according to your example with for. Any idea how?
– jhon dano
Nov 22 '18 at 13:43
@jhondano Check update
– Mohammad
Nov 22 '18 at 13:49
this worked perfect, thanks! I was wondering if the same can be achieved through the regular expression so i can reduce it to just one line of code?
– jhon dano
Nov 22 '18 at 13:37
this worked perfect, thanks! I was wondering if the same can be achieved through the regular expression so i can reduce it to just one line of code?
– jhon dano
Nov 22 '18 at 13:37
@jhondano Your content is in array but regex work on string. You should convert array to string and run regex and prepare target structure that cause write multiple line of code
– Mohammad
Nov 22 '18 at 13:41
@jhondano Your content is in array but regex work on string. You should convert array to string and run regex and prepare target structure that cause write multiple line of code
– Mohammad
Nov 22 '18 at 13:41
i understand that but as you see in my question the source is string: a11993b18486c13240388, this needs to be split and grouped according to your example with for. Any idea how?
– jhon dano
Nov 22 '18 at 13:43
i understand that but as you see in my question the source is string: a11993b18486c13240388, this needs to be split and grouped according to your example with for. Any idea how?
– jhon dano
Nov 22 '18 at 13:43
@jhondano Check update
– Mohammad
Nov 22 '18 at 13:49
@jhondano Check update
– Mohammad
Nov 22 '18 at 13:49
add a comment |
0
try following :
$list = array(
"a",
"11993",
"b",
"18486",
"c",
"13240388"
);
$new_list = array();
for($i=0;$i<count($list);$i=$i+2) {
$new_list[$list[$i]] = $list[$i+1];
}
echo '<pre>'; print_r($new_list); echo '</pre>';
answered Nov 22 '18 at 13:32
Manoj SinghManoj Singh
23016
This is exact duplicate of my answer.
– Mohammad
Nov 22 '18 at 13:34
yes but seen after posting answer
– Manoj Singh
Nov 22 '18 at 13:36
add a comment |
0
try following :
$list = array(
"a",
"11993",
"b",
"18486",
"c",
"13240388"
);
$new_list = array();
for($i=0;$i<count($list);$i=$i+2) {
$new_list[$list[$i]] = $list[$i+1];
}
echo '<pre>'; print_r($new_list); echo '</pre>';
answered Nov 22 '18 at 13:32
Manoj SinghManoj Singh
23016
This is exact duplicate of my answer.
– Mohammad
Nov 22 '18 at 13:34
yes but seen after posting answer
– Manoj Singh
Nov 22 '18 at 13:36
add a comment |
0
0
0
try following :
$list = array(
"a",
"11993",
"b",
"18486",
"c",
"13240388"
);
$new_list = array();
for($i=0;$i<count($list);$i=$i+2) {
$new_list[$list[$i]] = $list[$i+1];
}
echo '<pre>'; print_r($new_list); echo '</pre>';
answered Nov 22 '18 at 13:32
Manoj SinghManoj Singh
23016
try following :
$list = array(
"a",
"11993",
"b",
"18486",
"c",
"13240388"
);
$new_list = array();
for($i=0;$i<count($list);$i=$i+2) {
$new_list[$list[$i]] = $list[$i+1];
}
echo '<pre>'; print_r($new_list); echo '</pre>';
answered Nov 22 '18 at 13:32
Manoj SinghManoj Singh
23016
answered Nov 22 '18 at 13:32
Manoj SinghManoj Singh
23016
answered Nov 22 '18 at 13:32
Manoj SinghManoj Singh
23016
answered Nov 22 '18 at 13:32
Manoj SinghManoj Singh
23016
23016
This is exact duplicate of my answer.
– Mohammad
Nov 22 '18 at 13:34
yes but seen after posting answer
– Manoj Singh
Nov 22 '18 at 13:36
add a comment |
This is exact duplicate of my answer.
– Mohammad
Nov 22 '18 at 13:34
yes but seen after posting answer
– Manoj Singh
Nov 22 '18 at 13:36
This is exact duplicate of my answer.
– Mohammad
Nov 22 '18 at 13:34
This is exact duplicate of my answer.
– Mohammad
Nov 22 '18 at 13:34
yes but seen after posting answer
– Manoj Singh
Nov 22 '18 at 13:36
yes but seen after posting answer
– Manoj Singh
Nov 22 '18 at 13:36
add a comment |
0
i hope answer to your question is this, because you are looking for object:-
$arr=[
"a",
"11993",
"b",
"18486",
"c",
"13240388"
];
$arrForObj = ;
for ($i=0; $i<count($arr); $i+=2){
$arrForObj[$arr[$i]] = $arr[$i+1];
}
$obj=(object)$arrForObj;
echo "<pre>";
var_dump($obj);
answered Nov 22 '18 at 13:38
Parvej AlamParvej Alam
24118
add a comment |
0
i hope answer to your question is this, because you are looking for object:-
$arr=[
"a",
"11993",
"b",
"18486",
"c",
"13240388"
];
$arrForObj = ;
for ($i=0; $i<count($arr); $i+=2){
$arrForObj[$arr[$i]] = $arr[$i+1];
}
$obj=(object)$arrForObj;
echo "<pre>";
var_dump($obj);
answered Nov 22 '18 at 13:38
Parvej AlamParvej Alam
24118
add a comment |
0
0
0
i hope answer to your question is this, because you are looking for object:-
$arr=[
"a",
"11993",
"b",
"18486",
"c",
"13240388"
];
$arrForObj = ;
for ($i=0; $i<count($arr); $i+=2){
$arrForObj[$arr[$i]] = $arr[$i+1];
}
$obj=(object)$arrForObj;
echo "<pre>";
var_dump($obj);
answered Nov 22 '18 at 13:38
Parvej AlamParvej Alam
24118
i hope answer to your question is this, because you are looking for object:-
$arr=[
"a",
"11993",
"b",
"18486",
"c",
"13240388"
];
$arrForObj = ;
for ($i=0; $i<count($arr); $i+=2){
$arrForObj[$arr[$i]] = $arr[$i+1];
}
$obj=(object)$arrForObj;
echo "<pre>";
var_dump($obj);
answered Nov 22 '18 at 13:38
Parvej AlamParvej Alam
24118
answered Nov 22 '18 at 13:38
Parvej AlamParvej Alam
24118
answered Nov 22 '18 at 13:38
Parvej AlamParvej Alam
24118
answered Nov 22 '18 at 13:38
Parvej AlamParvej Alam
24118
24118
add a comment |
add a comment |
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