using Max and Avg function together in SQL
I have the following four tables containing student information, lecture information, attending lectures information and exams.
using the
SELECT Student_id, AVG(marks) as average FROM exams GROUP BY Student_id;
I get a list of average marks obtained by each student.
How do i combine it with MAX function to get the ID, name, and average of students who has the highest average in the list?
students
student_id
student_name
lectures
lecture_id
lecture_name
ECTS
attending_lectures
id
student_id
lecture_id
exams
id
Student_id
Lecture_id
Marks
sql max average
asked Nov 21 '18 at 18:05
FaaeqFaaeq
61
add a comment |
I have the following four tables containing student information, lecture information, attending lectures information and exams.
using the
SELECT Student_id, AVG(marks) as average FROM exams GROUP BY Student_id;
I get a list of average marks obtained by each student.
How do i combine it with MAX function to get the ID, name, and average of students who has the highest average in the list?
students
student_id
student_name
lectures
lecture_id
lecture_name
ECTS
attending_lectures
id
student_id
lecture_id
exams
id
Student_id
Lecture_id
Marks
sql max average
asked Nov 21 '18 at 18:05
FaaeqFaaeq
61
Which DBMS are you using?
– Barbaros Özhan
Nov 21 '18 at 18:14
mysql and oracle
– Faaeq
Nov 21 '18 at 18:20
add a comment |
I have the following four tables containing student information, lecture information, attending lectures information and exams.
using the
SELECT Student_id, AVG(marks) as average FROM exams GROUP BY Student_id;
I get a list of average marks obtained by each student.
How do i combine it with MAX function to get the ID, name, and average of students who has the highest average in the list?
students
student_id
student_name
lectures
lecture_id
lecture_name
ECTS
attending_lectures
id
student_id
lecture_id
exams
id
Student_id
Lecture_id
Marks
sql max average
asked Nov 21 '18 at 18:05
FaaeqFaaeq
61
I have the following four tables containing student information, lecture information, attending lectures information and exams.
using the
SELECT Student_id, AVG(marks) as average FROM exams GROUP BY Student_id;
I get a list of average marks obtained by each student.
How do i combine it with MAX function to get the ID, name, and average of students who has the highest average in the list?
students
student_id
student_name
lectures
lecture_id
lecture_name
ECTS
attending_lectures
id
student_id
lecture_id
exams
id
Student_id
Lecture_id
Marks
sql max average
sql max average
asked Nov 21 '18 at 18:05
FaaeqFaaeq
61
asked Nov 21 '18 at 18:05
FaaeqFaaeq
61
asked Nov 21 '18 at 18:05
FaaeqFaaeq
61
asked Nov 21 '18 at 18:05
FaaeqFaaeq
61
asked Nov 21 '18 at 18:05
FaaeqFaaeq
61
61
Which DBMS are you using?
– Barbaros Özhan
Nov 21 '18 at 18:14
mysql and oracle
– Faaeq
Nov 21 '18 at 18:20
add a comment |
Which DBMS are you using?
– Barbaros Özhan
Nov 21 '18 at 18:14
mysql and oracle
– Faaeq
Nov 21 '18 at 18:20
Which DBMS are you using?
– Barbaros Özhan
Nov 21 '18 at 18:14
Which DBMS are you using?
– Barbaros Özhan
Nov 21 '18 at 18:14
mysql and oracle
– Faaeq
Nov 21 '18 at 18:20
mysql and oracle
– Faaeq
Nov 21 '18 at 18:20
add a comment |
1 Answer
1
active
oldest
votes
You may use such a SQL with an ORDER BY ... DESC clause to get MAX
For MySQL :
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
ORDER BY "average" DESC
LIMIT 1;
For Oracle :
SELECT * FROM
(
SELECT q.*, row_number() over (order by "average" desc) as rn
FROM
(
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
) q
)
WHERE rn = 1;
answered Nov 21 '18 at 18:12
Barbaros ÖzhanBarbaros Özhan
14.6k71634
thank you for your reply but its not returning what i'm looking for. two of the students has average of 4, but your solution returns the one with average of 2.3333
– Faaeq
Nov 21 '18 at 18:30
@Faaeq you're welcome. Edited the case for Oracle. Are you sure that you includeddesckeyword fororder byclause ?
– Barbaros Özhan
Nov 21 '18 at 18:36
add a comment |
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1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
You may use such a SQL with an ORDER BY ... DESC clause to get MAX
For MySQL :
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
ORDER BY "average" DESC
LIMIT 1;
For Oracle :
SELECT * FROM
(
SELECT q.*, row_number() over (order by "average" desc) as rn
FROM
(
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
) q
)
WHERE rn = 1;
answered Nov 21 '18 at 18:12
Barbaros ÖzhanBarbaros Özhan
14.6k71634
thank you for your reply but its not returning what i'm looking for. two of the students has average of 4, but your solution returns the one with average of 2.3333
– Faaeq
Nov 21 '18 at 18:30
@Faaeq you're welcome. Edited the case for Oracle. Are you sure that you includeddesckeyword fororder byclause ?
– Barbaros Özhan
Nov 21 '18 at 18:36
add a comment |
You may use such a SQL with an ORDER BY ... DESC clause to get MAX
For MySQL :
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
ORDER BY "average" DESC
LIMIT 1;
For Oracle :
SELECT * FROM
(
SELECT q.*, row_number() over (order by "average" desc) as rn
FROM
(
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
) q
)
WHERE rn = 1;
answered Nov 21 '18 at 18:12
Barbaros ÖzhanBarbaros Özhan
14.6k71634
thank you for your reply but its not returning what i'm looking for. two of the students has average of 4, but your solution returns the one with average of 2.3333
– Faaeq
Nov 21 '18 at 18:30
@Faaeq you're welcome. Edited the case for Oracle. Are you sure that you includeddesckeyword fororder byclause ?
– Barbaros Özhan
Nov 21 '18 at 18:36
add a comment |
You may use such a SQL with an ORDER BY ... DESC clause to get MAX
For MySQL :
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
ORDER BY "average" DESC
LIMIT 1;
For Oracle :
SELECT * FROM
(
SELECT q.*, row_number() over (order by "average" desc) as rn
FROM
(
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
) q
)
WHERE rn = 1;
answered Nov 21 '18 at 18:12
Barbaros ÖzhanBarbaros Özhan
14.6k71634
You may use such a SQL with an ORDER BY ... DESC clause to get MAX
For MySQL :
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
ORDER BY "average" DESC
LIMIT 1;
For Oracle :
SELECT * FROM
(
SELECT q.*, row_number() over (order by "average" desc) as rn
FROM
(
SELECT e.Student_id, s.student_name, AVG(marks) as "average"
FROM exams e
LEFT JOIN students s ON e.Student_id = s.Student_id
GROUP BY e.Student_id, s.student_name
) q
)
WHERE rn = 1;
answered Nov 21 '18 at 18:12
Barbaros ÖzhanBarbaros Özhan
14.6k71634
edited Nov 21 '18 at 18:36
answered Nov 21 '18 at 18:12
Barbaros ÖzhanBarbaros Özhan
14.6k71634
answered Nov 21 '18 at 18:12
Barbaros ÖzhanBarbaros Özhan
14.6k71634
answered Nov 21 '18 at 18:12
Barbaros ÖzhanBarbaros Özhan
14.6k71634
14.6k71634
thank you for your reply but its not returning what i'm looking for. two of the students has average of 4, but your solution returns the one with average of 2.3333
– Faaeq
Nov 21 '18 at 18:30
@Faaeq you're welcome. Edited the case for Oracle. Are you sure that you includeddesckeyword fororder byclause ?
– Barbaros Özhan
Nov 21 '18 at 18:36
add a comment |
thank you for your reply but its not returning what i'm looking for. two of the students has average of 4, but your solution returns the one with average of 2.3333
– Faaeq
Nov 21 '18 at 18:30
@Faaeq you're welcome. Edited the case for Oracle. Are you sure that you includeddesckeyword fororder byclause ?
– Barbaros Özhan
Nov 21 '18 at 18:36
thank you for your reply but its not returning what i'm looking for. two of the students has average of 4, but your solution returns the one with average of 2.3333
– Faaeq
Nov 21 '18 at 18:30
thank you for your reply but its not returning what i'm looking for. two of the students has average of 4, but your solution returns the one with average of 2.3333
– Faaeq
Nov 21 '18 at 18:30
@Faaeq you're welcome. Edited the case for Oracle. Are you sure that you included
desc keyword for order by clause ?– Barbaros Özhan
Nov 21 '18 at 18:36
@Faaeq you're welcome. Edited the case for Oracle. Are you sure that you included
desc keyword for order by clause ?– Barbaros Özhan
Nov 21 '18 at 18:36
add a comment |
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Which DBMS are you using?
– Barbaros Özhan
Nov 21 '18 at 18:14
mysql and oracle
– Faaeq
Nov 21 '18 at 18:20