Having the user guess a random number and loop until they get it right
up vote
0
down vote
favorite
I've been trying to figure this out for hours but I can't for some reason my output just shows "Sorry that number is too high" and "Sorry that number is too low" at the same time without looping or using a single answer.
import java.util.*;
public class RandomNumbers {
public static void main(String args) {
Scanner keyboard = new Scanner(System.in);
Random numGen = new Random();
int RanNum = numGen.nextInt(20) + 1;
System.out.println("Guess what number im thinking of");
int num ;
num = keyboard.nextInt();
if (num == RanNum)
System.out.println("Good Job");
else if (num > RanNum)
System.out.println("Sorry that number is too high");
else if (num < RanNum);
System.out.println("Sorry that number is too low");
}
}
java
add a comment |
up vote
0
down vote
favorite
I've been trying to figure this out for hours but I can't for some reason my output just shows "Sorry that number is too high" and "Sorry that number is too low" at the same time without looping or using a single answer.
import java.util.*;
public class RandomNumbers {
public static void main(String args) {
Scanner keyboard = new Scanner(System.in);
Random numGen = new Random();
int RanNum = numGen.nextInt(20) + 1;
System.out.println("Guess what number im thinking of");
int num ;
num = keyboard.nextInt();
if (num == RanNum)
System.out.println("Good Job");
else if (num > RanNum)
System.out.println("Sorry that number is too high");
else if (num < RanNum);
System.out.println("Sorry that number is too low");
}
}
java
The code indentation is actually correctly showing that lastprintln
statement is not covered by theelse if
statement, because you have a;
at the end of that line.
– Andreas
Nov 11 at 21:50
Possible duplicate of Guess a number program with Java
– jontro
Nov 11 at 21:56
add a comment |
up vote
0
down vote
favorite
up vote
0
down vote
favorite
I've been trying to figure this out for hours but I can't for some reason my output just shows "Sorry that number is too high" and "Sorry that number is too low" at the same time without looping or using a single answer.
import java.util.*;
public class RandomNumbers {
public static void main(String args) {
Scanner keyboard = new Scanner(System.in);
Random numGen = new Random();
int RanNum = numGen.nextInt(20) + 1;
System.out.println("Guess what number im thinking of");
int num ;
num = keyboard.nextInt();
if (num == RanNum)
System.out.println("Good Job");
else if (num > RanNum)
System.out.println("Sorry that number is too high");
else if (num < RanNum);
System.out.println("Sorry that number is too low");
}
}
java
I've been trying to figure this out for hours but I can't for some reason my output just shows "Sorry that number is too high" and "Sorry that number is too low" at the same time without looping or using a single answer.
import java.util.*;
public class RandomNumbers {
public static void main(String args) {
Scanner keyboard = new Scanner(System.in);
Random numGen = new Random();
int RanNum = numGen.nextInt(20) + 1;
System.out.println("Guess what number im thinking of");
int num ;
num = keyboard.nextInt();
if (num == RanNum)
System.out.println("Good Job");
else if (num > RanNum)
System.out.println("Sorry that number is too high");
else if (num < RanNum);
System.out.println("Sorry that number is too low");
}
}
java
java
edited Nov 12 at 4:26
Trooper Z
687424
687424
asked Nov 11 at 21:47
Ian Stacy
32
32
The code indentation is actually correctly showing that lastprintln
statement is not covered by theelse if
statement, because you have a;
at the end of that line.
– Andreas
Nov 11 at 21:50
Possible duplicate of Guess a number program with Java
– jontro
Nov 11 at 21:56
add a comment |
The code indentation is actually correctly showing that lastprintln
statement is not covered by theelse if
statement, because you have a;
at the end of that line.
– Andreas
Nov 11 at 21:50
Possible duplicate of Guess a number program with Java
– jontro
Nov 11 at 21:56
The code indentation is actually correctly showing that last
println
statement is not covered by the else if
statement, because you have a ;
at the end of that line.– Andreas
Nov 11 at 21:50
The code indentation is actually correctly showing that last
println
statement is not covered by the else if
statement, because you have a ;
at the end of that line.– Andreas
Nov 11 at 21:50
Possible duplicate of Guess a number program with Java
– jontro
Nov 11 at 21:56
Possible duplicate of Guess a number program with Java
– jontro
Nov 11 at 21:56
add a comment |
3 Answers
3
active
oldest
votes
up vote
3
down vote
accepted
Semicolon after else if (num < RanNum)
is your problem
Hi i have another question ive been trying to loop this program so that it asks the user again after telling them there answer is too high or too low and im having no success is there any chance you could throw some advice my way
– Ian Stacy
Nov 11 at 22:37
Oh sure, here's the main method: pastebin.com/b98Ghtrg
– sand_storm_of_code.txt
Nov 12 at 1:05
add a comment |
up vote
0
down vote
you misplaced a semicolon at the end of your third if.
You should still get the Good Job message though.
public static void main(String args)
{
Scanner keyboard = new Scanner(System.in);
Random numGen = new Random();
int RanNum = numGen.nextInt(1) + 1;
System.out.println("Guess what number im thinking of");
int num ;
num = keyboard.nextInt();
if (num == RanNum)
System.out.println("Good Job");
else if (num > RanNum)
System.out.println("Sorry that number is too high");
else if (num < RanNum)
System.out.println("Sorry that number is too low");
}
edit: sorry, too late :)
add a comment |
up vote
0
down vote
To keep prompting the user use a while loop to check whether they guessed correct or not. I would also recommend adding another input check for exiting without getting it correct. Brief example:
boolean incorrect = true;
while(incorrect) {
//Code to prompt for input
if(userIsCorrect || input == -1){
incorrect = false;
//Program will exit loop when this is set to false
}
}
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
up vote
3
down vote
accepted
Semicolon after else if (num < RanNum)
is your problem
Hi i have another question ive been trying to loop this program so that it asks the user again after telling them there answer is too high or too low and im having no success is there any chance you could throw some advice my way
– Ian Stacy
Nov 11 at 22:37
Oh sure, here's the main method: pastebin.com/b98Ghtrg
– sand_storm_of_code.txt
Nov 12 at 1:05
add a comment |
up vote
3
down vote
accepted
Semicolon after else if (num < RanNum)
is your problem
Hi i have another question ive been trying to loop this program so that it asks the user again after telling them there answer is too high or too low and im having no success is there any chance you could throw some advice my way
– Ian Stacy
Nov 11 at 22:37
Oh sure, here's the main method: pastebin.com/b98Ghtrg
– sand_storm_of_code.txt
Nov 12 at 1:05
add a comment |
up vote
3
down vote
accepted
up vote
3
down vote
accepted
Semicolon after else if (num < RanNum)
is your problem
Semicolon after else if (num < RanNum)
is your problem
answered Nov 11 at 21:49
sand_storm_of_code.txt
1,01911829
1,01911829
Hi i have another question ive been trying to loop this program so that it asks the user again after telling them there answer is too high or too low and im having no success is there any chance you could throw some advice my way
– Ian Stacy
Nov 11 at 22:37
Oh sure, here's the main method: pastebin.com/b98Ghtrg
– sand_storm_of_code.txt
Nov 12 at 1:05
add a comment |
Hi i have another question ive been trying to loop this program so that it asks the user again after telling them there answer is too high or too low and im having no success is there any chance you could throw some advice my way
– Ian Stacy
Nov 11 at 22:37
Oh sure, here's the main method: pastebin.com/b98Ghtrg
– sand_storm_of_code.txt
Nov 12 at 1:05
Hi i have another question ive been trying to loop this program so that it asks the user again after telling them there answer is too high or too low and im having no success is there any chance you could throw some advice my way
– Ian Stacy
Nov 11 at 22:37
Hi i have another question ive been trying to loop this program so that it asks the user again after telling them there answer is too high or too low and im having no success is there any chance you could throw some advice my way
– Ian Stacy
Nov 11 at 22:37
Oh sure, here's the main method: pastebin.com/b98Ghtrg
– sand_storm_of_code.txt
Nov 12 at 1:05
Oh sure, here's the main method: pastebin.com/b98Ghtrg
– sand_storm_of_code.txt
Nov 12 at 1:05
add a comment |
up vote
0
down vote
you misplaced a semicolon at the end of your third if.
You should still get the Good Job message though.
public static void main(String args)
{
Scanner keyboard = new Scanner(System.in);
Random numGen = new Random();
int RanNum = numGen.nextInt(1) + 1;
System.out.println("Guess what number im thinking of");
int num ;
num = keyboard.nextInt();
if (num == RanNum)
System.out.println("Good Job");
else if (num > RanNum)
System.out.println("Sorry that number is too high");
else if (num < RanNum)
System.out.println("Sorry that number is too low");
}
edit: sorry, too late :)
add a comment |
up vote
0
down vote
you misplaced a semicolon at the end of your third if.
You should still get the Good Job message though.
public static void main(String args)
{
Scanner keyboard = new Scanner(System.in);
Random numGen = new Random();
int RanNum = numGen.nextInt(1) + 1;
System.out.println("Guess what number im thinking of");
int num ;
num = keyboard.nextInt();
if (num == RanNum)
System.out.println("Good Job");
else if (num > RanNum)
System.out.println("Sorry that number is too high");
else if (num < RanNum)
System.out.println("Sorry that number is too low");
}
edit: sorry, too late :)
add a comment |
up vote
0
down vote
up vote
0
down vote
you misplaced a semicolon at the end of your third if.
You should still get the Good Job message though.
public static void main(String args)
{
Scanner keyboard = new Scanner(System.in);
Random numGen = new Random();
int RanNum = numGen.nextInt(1) + 1;
System.out.println("Guess what number im thinking of");
int num ;
num = keyboard.nextInt();
if (num == RanNum)
System.out.println("Good Job");
else if (num > RanNum)
System.out.println("Sorry that number is too high");
else if (num < RanNum)
System.out.println("Sorry that number is too low");
}
edit: sorry, too late :)
you misplaced a semicolon at the end of your third if.
You should still get the Good Job message though.
public static void main(String args)
{
Scanner keyboard = new Scanner(System.in);
Random numGen = new Random();
int RanNum = numGen.nextInt(1) + 1;
System.out.println("Guess what number im thinking of");
int num ;
num = keyboard.nextInt();
if (num == RanNum)
System.out.println("Good Job");
else if (num > RanNum)
System.out.println("Sorry that number is too high");
else if (num < RanNum)
System.out.println("Sorry that number is too low");
}
edit: sorry, too late :)
answered Nov 11 at 21:55
TKler
93
93
add a comment |
add a comment |
up vote
0
down vote
To keep prompting the user use a while loop to check whether they guessed correct or not. I would also recommend adding another input check for exiting without getting it correct. Brief example:
boolean incorrect = true;
while(incorrect) {
//Code to prompt for input
if(userIsCorrect || input == -1){
incorrect = false;
//Program will exit loop when this is set to false
}
}
add a comment |
up vote
0
down vote
To keep prompting the user use a while loop to check whether they guessed correct or not. I would also recommend adding another input check for exiting without getting it correct. Brief example:
boolean incorrect = true;
while(incorrect) {
//Code to prompt for input
if(userIsCorrect || input == -1){
incorrect = false;
//Program will exit loop when this is set to false
}
}
add a comment |
up vote
0
down vote
up vote
0
down vote
To keep prompting the user use a while loop to check whether they guessed correct or not. I would also recommend adding another input check for exiting without getting it correct. Brief example:
boolean incorrect = true;
while(incorrect) {
//Code to prompt for input
if(userIsCorrect || input == -1){
incorrect = false;
//Program will exit loop when this is set to false
}
}
To keep prompting the user use a while loop to check whether they guessed correct or not. I would also recommend adding another input check for exiting without getting it correct. Brief example:
boolean incorrect = true;
while(incorrect) {
//Code to prompt for input
if(userIsCorrect || input == -1){
incorrect = false;
//Program will exit loop when this is set to false
}
}
edited Nov 11 at 22:53
answered Nov 11 at 22:48
Tim Hunter
665
665
add a comment |
add a comment |
Thanks for contributing an answer to Stack Overflow!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Some of your past answers have not been well-received, and you're in danger of being blocked from answering.
Please pay close attention to the following guidance:
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f53253575%2fhaving-the-user-guess-a-random-number-and-loop-until-they-get-it-right%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
The code indentation is actually correctly showing that last
println
statement is not covered by theelse if
statement, because you have a;
at the end of that line.– Andreas
Nov 11 at 21:50
Possible duplicate of Guess a number program with Java
– jontro
Nov 11 at 21:56